node.js - detect exit of external process by PID - node.js

Provided I have the PID for an already running process, how can I detect the exit of that process in Node.js?
For example:
var pid = 1200; // any PID
getProcessByPID(pid).onExit = () => {
// Code on exit goes here
};

I know its an old post, just needed the information myself. You can do code on a process exiting by listening for the 'exit' keyword. 'code' is the exit code of the process.
const forked = fork(`${__dirname}/file.js`)
forked.on('message', (msg) => {
console.log('message from child = ', msg)
})
forked.on('exit', (code) => {
console.log('Exiting worker with code =', code)
})

Related

Not able to take the MongoDB backup/dump using node js

When executing the written script, it exit with code 'one' while it should save the dump of the database
const cron = require('node-cron');
const { exit } = require('process');
const spawn = require('child_process').spawn;
let backupProcess = spawn('mongodump', [
'--host=localhost',
'--port=27017',
'--out=.',
'--db=testdb',
], {shell: true});
backupProcess.on('exit', (code, signal) => {
console.log('Function called');
if(code)
console.log('Backup process exited with code ', code);
else if (signal)
console.error('Backup process was killed with singal ', signal);
else
console.log('Successfully backedup the database')
});
while executing the same through VS code terminal, getting following error,
Function called
Backup process exited with code 1 while should save the dump at given location`your text`
Actual Result : Backup process exited with code 1
Expected result : Must dump the database

Node.js Spawn: How to check if the process Exited Immediately

In my app, I need to spawn a debugger process given a dump file to debug, say "example.dmp". If the dump file is not found or not it is not a dump file. The process will be successfully spawned but it will exit immediately. I would like to throw an error message in an async function which can be try catched later.
const spawnDebuggerProcess = (debuggerConfigs) => {
let debuggerProcess = spawn(config.debuggerName, debuggerConfigs)
debuggerProcess.on('exit', (code, signal) => {
console.log('pid ' + `${debuggerProcess.pid}`)
console.log('child process exited with ' + `code ${code} and signal ${signal}`)
})
debuggerProcess.on('error', (error) => {})
if (debuggerProcess.pid !== undefined) {
return debuggerProcess
}
throw externalError.createError({
name: externalError.SPAWN_DEBUGGER_PROCESS_ERROR,
description: 'Failed to spawn debugging process'
})
}
One of my thought is to time give this function a time window before returning. If the process exited before the time window I should throw an error. But since node.js is async. I don't have an idea of how can this be realized. Thanks!
==== EDIT =====
const spawnDebuggerProcess = async (debuggerConfigs) => {
let debuggerProcess = spawn(config.debuggerProcess.debuggerName, debuggerConfigs)
/** added a flag */
let exited = false
debuggerProcess.on('exit', (code, signal) => {
console.log('pid ' + `${debuggerProcess.pid}`)
console.log('child process exited with ' + `code ${code} and signal ${signal}`)
/** set flag to true if exited */
exited = true
})
debuggerProcess.on('error', (error) => {})
if (debuggerProcess.pid !== undefined) {
/** delay this promise for a certain amount of time, act as the time window */
await delay(config.debuggerProcess.immediateExitDelay)
/** check the flag */
if (exited) {
throw externalError.createError({
name: externalError.SPAWN_DEBUGGER_PROCESS_ERROR,
description: 'Process exited immediately'
})
}
return debuggerProcess
}
throw externalError.createError({
name: externalError.SPAWN_DEBUGGER_PROCESS_ERROR,
description: 'Failed to spawn debugging process'
})
}
It seems to be working, but I am not sure if it is a good practice.

How to detect if a Node spawned process is still running?

I can spawn a process like:
var spawn = require('child_process').spawn;
var topicListener = spawn('python', ['topic_listener.py','Node.js'], {env: {
TWITTER_CONSUMER_SECRET: process.env.TWITTER_CONSUMER_SECRET,
TWITTER_CONSUMER_KEY: process.env.TWITTER_CONSUMER_KEY,
TWITTER_TOKEN_SECRET: process.env.TWITTER_TOKEN_SECRET,
TWITTER_ACCESS_TOKEN: process.env.TWITTER_ACCESS_TOKEN
}});
topicListener.stdout.on('data', function (data) {
console.log(data.toString());
});
topicListener.stderr.on('data', function (data) {
console.log(data.toString());
});
topicListener.on('close', function (code) {
console.log("EXITED " + code);
});
So of course I can control it all asycnchronously with .on(close, ...) but is there any other way to control if a process is still alive?
topicListener.on('exit', function (code) {
topicListener = null;
console.log("EXITED " + code);
});
If topiclistener is null, the process is gone
spawn('python', ['topic_listener.py','Node.js'].. Return Child process Object. Use topicListener.pid to find unique ID associated with the process if it's alive.

Node Kue and Child Process - get error from spawned process

I try to spawn a child process performing cpu intensive calculations through a job queue with Kue. My code at the moment looks like this:
consumer.js
var kue = require('kue');
var util = require('util');
var spawn = require('child_process').spawn;
var jobs = kue.createQueue();
jobs.process('calc', 2, function(job, done){
var work = spawn('Rscript', ['opti2.R', job.data.file]);
work.stderr.on('data', function (data) {
job.log('stderr: ' + data);
});
work.stdout.on('data', function (data) {
job.log('stdout: ' + data);
});
work.on('exit', function (code, signal) {
console.log('child process exited with code ' + code + ' with singal ' + signal);
if(code != 0){
done(****How to get the stderr of the child process as an error here***);
} else {
done(Error());
}
});
});
The code somewhat do what i would like it to do, but is there a better way to report the job as failed (to Kue) and get the stderr from the spawned process?
You can use job.log method to send data directly to Kue.
I would also recommend you to switch from .spawn to .exec, because it returns stdout and stderr as strings in its final callback along with a good error, which suits your needs well:
var exec = require('child_process').exec;
jobs.process('calc', 2, function(job, done){
exec('Rscript opti2.R ' + job.data.file, function (error, stdout, stderr) {
if (stdout.length > 0) job.log('stdout: ' + stdout);
if (stderr.length > 0) job.log('stderr: ' + stderr);
done(error);
});
});
Though solution should work with .spawn as well: simply replace each console.log call in your code with job.log.
Though, you may want to bufferize your stderr in order to send it to Kue in one chunk:
jobs.process('calc', 2, function(job, done){
var work = spawn('Rscript', ['opti2.R', job.data.file]);
var stderr = '';
work.stderr.on('data', function (data) {
stderr += data;
});
work.stdout.on('data', function (data) {
job.log(data); // sending arriving `stdout` chunks as normal log events
});
work.on('close', function (code, signal) {
console.log('child process exited with code ' + code + ' with singal ' + signal);
if(code != 0){
done(stderr); // sending all collected stderr as an explanation
} else {
done();
}
});
});
I would also recommend using close event instead of exit, because it waits for child's stdio streams.
For more information see Event: 'exit' docs:
This event is emitted after the child process ends.
Note that the child process stdio streams might still be open.
and Event: 'close' docs:
This event is emitted when the stdio streams of a child process have
all terminated.

Node.js spawn child process and get terminal output live

I have a script that outputs 'hi', sleeps for a second, outputs 'hi', sleeps for 1 second, and so on and so forth. Now I thought I would be able to tackle this problem with this model.
var spawn = require('child_process').spawn,
temp = spawn('PATH TO SCRIPT WITH THE ABOVE BEHAVIOUR');
temp.stdout.pipe(process.stdout);
Now the problem is that the task needs to be finished in order for the output to be displayed. As I am understanding it, this is due to the fact that the newly spawned process takes execution control. Obviously node.js does not support threads so any solutions? My idea was to possibly run two instances, first one for the specific purpose of creating the task and have it pipe the output to process of the second instance, considering this can be achieved.
It's much easier now (6 years later)!
Spawn returns a childObject, which you can then listen for events with. The events are:
Class: ChildProcess
Event: 'error'
Event: 'exit'
Event: 'close'
Event: 'disconnect'
Event: 'message'
There are also a bunch of objects from childObject, they are:
Class: ChildProcess
child.stdin
child.stdout
child.stderr
child.stdio
child.pid
child.connected
child.kill([signal])
child.send(message[, sendHandle][, callback])
child.disconnect()
See more information here about childObject: https://nodejs.org/api/child_process.html
Asynchronous
If you want to run your process in the background while node is still able to continue to execute, use the asynchronous method. You can still choose to perform actions after your process completes, and when the process has any output (for example if you want to send a script's output to the client).
child_process.spawn(...); (Node v0.1.90)
var spawn = require('child_process').spawn;
var child = spawn('node ./commands/server.js');
// You can also use a variable to save the output
// for when the script closes later
var scriptOutput = "";
child.stdout.setEncoding('utf8');
child.stdout.on('data', function(data) {
//Here is where the output goes
console.log('stdout: ' + data);
data=data.toString();
scriptOutput+=data;
});
child.stderr.setEncoding('utf8');
child.stderr.on('data', function(data) {
//Here is where the error output goes
console.log('stderr: ' + data);
data=data.toString();
scriptOutput+=data;
});
child.on('close', function(code) {
//Here you can get the exit code of the script
console.log('closing code: ' + code);
console.log('Full output of script: ',scriptOutput);
});
Here's how you would use a callback + asynchronous method:
var child_process = require('child_process');
console.log("Node Version: ", process.version);
run_script("ls", ["-l", "/home"], function(output, exit_code) {
console.log("Process Finished.");
console.log('closing code: ' + exit_code);
console.log('Full output of script: ',output);
});
console.log ("Continuing to do node things while the process runs at the same time...");
// This function will output the lines from the script
// AS is runs, AND will return the full combined output
// as well as exit code when it's done (using the callback).
function run_script(command, args, callback) {
console.log("Starting Process.");
var child = child_process.spawn(command, args);
var scriptOutput = "";
child.stdout.setEncoding('utf8');
child.stdout.on('data', function(data) {
console.log('stdout: ' + data);
data=data.toString();
scriptOutput+=data;
});
child.stderr.setEncoding('utf8');
child.stderr.on('data', function(data) {
console.log('stderr: ' + data);
data=data.toString();
scriptOutput+=data;
});
child.on('close', function(code) {
callback(scriptOutput,code);
});
}
Using the method above, you can send every line of output from the script to the client (for example using Socket.io to send each line when you receive events on stdout or stderr).
Synchronous
If you want node to stop what it's doing and wait until the script completes, you can use the synchronous version:
child_process.spawnSync(...); (Node v0.11.12+)
Issues with this method:
If the script takes a while to complete, your server will hang for
that amount of time!
The stdout will only be returned once the script
has finished running. Because it's synchronous, it cannot continue
until the current line has finished. Therefore it's unable to capture
the 'stdout' event until the spawn line has finished.
How to use it:
var child_process = require('child_process');
var child = child_process.spawnSync("ls", ["-l", "/home"], { encoding : 'utf8' });
console.log("Process finished.");
if(child.error) {
console.log("ERROR: ",child.error);
}
console.log("stdout: ",child.stdout);
console.log("stderr: ",child.stderr);
console.log("exist code: ",child.status);
I'm still getting my feet wet with Node.js, but I have a few ideas. first, I believe you need to use execFile instead of spawn; execFile is for when you have the path to a script, whereas spawn is for executing a well-known command that Node.js can resolve against your system path.
1. Provide a callback to process the buffered output:
var child = require('child_process').execFile('path/to/script', [
'arg1', 'arg2', 'arg3',
], function(err, stdout, stderr) {
// Node.js will invoke this callback when process terminates.
console.log(stdout);
});
2. Add a listener to the child process' stdout stream (9thport.net)
var child = require('child_process').execFile('path/to/script', [
'arg1', 'arg2', 'arg3' ]);
// use event hooks to provide a callback to execute when data are available:
child.stdout.on('data', function(data) {
console.log(data.toString());
});
Further, there appear to be options whereby you can detach the spawned process from Node's controlling terminal, which would allow it to run asynchronously. I haven't tested this yet, but there are examples in the API docs that go something like this:
child = require('child_process').execFile('path/to/script', [
'arg1', 'arg2', 'arg3',
], {
// detachment and ignored stdin are the key here:
detached: true,
stdio: [ 'ignore', 1, 2 ]
});
// and unref() somehow disentangles the child's event loop from the parent's:
child.unref();
child.stdout.on('data', function(data) {
console.log(data.toString());
});
Here is the cleanest approach I've found:
require("child_process").spawn('bash', ['./script.sh'], {
cwd: process.cwd(),
detached: true,
stdio: "inherit"
});
I had a little trouble getting logging output from the "npm install" command when I spawned npm in a child process. The realtime logging of dependencies did not show in the parent console.
The simplest way to do what the original poster wants seems to be this (spawn npm on windows and log everything to parent console):
var args = ['install'];
var options = {
stdio: 'inherit' //feed all child process logging into parent process
};
var childProcess = spawn('npm.cmd', args, options);
childProcess.on('close', function(code) {
process.stdout.write('"npm install" finished with code ' + code + '\n');
});
PHP-like passthru
import { spawn } from 'child_process';
export default async function passthru(exe, args, options) {
return new Promise((resolve, reject) => {
const env = Object.create(process.env);
const child = spawn(exe, args, {
...options,
env: {
...env,
...options.env,
},
});
child.stdout.setEncoding('utf8');
child.stderr.setEncoding('utf8');
child.stdout.on('data', data => console.log(data));
child.stderr.on('data', data => console.log(data));
child.on('error', error => reject(error));
child.on('close', exitCode => {
console.log('Exit code:', exitCode);
resolve(exitCode);
});
});
}
Usage
const exitCode = await passthru('ls', ['-al'], { cwd: '/var/www/html' })
child:
setInterval(function() {
process.stdout.write("hi");
}, 1000); // or however else you want to run a timer
parent:
require('child_process').fork('./childfile.js');
// fork'd children use the parent's stdio
I found myself requiring this functionality often enough that I packaged it into a library called std-pour. It should let you execute a command and view the output in real time. To install simply:
npm install std-pour
Then it's simple enough to execute a command and see the output in realtime:
const { pour } = require('std-pour');
pour('ping', ['8.8.8.8', '-c', '4']).then(code => console.log(`Error Code: ${code}`));
It's promised based so you can chain multiple commands. It's even function signature-compatible with child_process.spawn so it should be a drop in replacement anywhere you're using it.
Adding a sample for exec as I too had needed live feedback and wasn't getting any until after the script finished. exec does return an EventEmitter, contrary to the many claims that only spawn works in such a way.
This supplements the comment I made to the accepted answer more thoroughly.
The interface for exec is similar to spawn:
// INCLUDES
import * as childProcess from 'child_process'; // ES6 Syntax
// DEFINES
let exec = childProcess.exec; // Use 'var' for more proper
// semantics, or 'const' it all
// if that's your thing; though 'let' is
// true-to-scope;
// Return an EventEmitter to work with, though
// you can also chain stdout too:
// (i.e. exec( ... ).stdout.on( ... ); )
let childProcess = exec
(
'./binary command -- --argument argumentValue',
( error, stdout, stderr ) =>
{ // When the process completes:
if( error )
{
console.log( `${error.name}: ${error.message}` );
console.log( `[STACK] ${error.stack}` );
}
console.log( stdout );
console.log( stderr );
callback(); // Gulp stuff
}
);
Now its as simple as registering an event handler for stdout:
childProcess.stdout.on( 'data', data => console.log( data ) );
And for stderr:
childProcess.stderr.on( 'data', data => console.log( `[ERROR]: ${data}` ) );
You can also pipe stdout to the main process' stdout:
childProcess.stdout.pipe( process.stdout );
Not too bad at all - HTH
I was interested into running a script that gets the input and outputs from my terminal, and that will close my process once the child script finishes.
import { spawn } from 'node:child_process'
import process from 'node:process'
const script = spawn('path/to/script', { stdio: 'inherit' })
script.on('close', process.exit)
I ran into a situation where none of the above worked when I was spawning a Python 3 script. I would get data from stdout, but only once the child terminated.
As it turns out, Python buffers stdout by default. It's possible to disable stdout buffering by including -u as a command line parameter to python3.

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