How do I fetch host and pass from file in linux - linux

Question

#!/bin/bash
hosts=(sarv savana simra punit)
pass=(sarva 1save xvyw23 asdwe87)
for i in "${!hosts[#]}"; do
sshpass -p "${pass[i]}" ssh-copy-id -f root#"${hostnames[i]}" -p 22
done
Is it possible to fetch the password and hostname from a different file which consists of all hosts and their corresponding passwords in the following format:
host pass
sarv sarva
savana 1save
simra xvyw23
punit asdwe87
I apologize for not describing it properly.
The first word of each line in the file is the host-name and the second word is it's password.
Instead of writing hosts=(sarv savana simra punit) pass=(sarva 1save xvyw23 asdwe87) in the script.

Answer 1

Reading them from a file which combines both host and password could be done like this:
while IFS=' ' read -r host pass
do
# your command using them goes here:
echo "$host=$pass"
done < hostpass-list.txt
IFS=' ' sets the input field separator to a space. The first space delimited word will be put in host and the rest of the line will be put in pass.
You may want to read all hosts/passwords first and use them later. In that case you could use an associative array.
# declare an associative array
declare -A hp
# fill the array
while IFS=' ' read -r host pass
do
hp["$host"]="$pass"
done < hostpass-list.txt
# use the array
for host in "${!hp[#]}"
do
pass="${hp["$host"]}"
# your command using them goes here:
echo "$host=$pass"
done
For reading from separate files (if that becomes necessary) I suggest using readarray:
readarray -t hosts < hosts-list.txt
readarray -t pass < passwords-list.txt
The -t means:
Remove a trailing delim (default newline) from each line read.

Answer 2

Of course:
#!/bin/bash
hosts=$(cat hosts-list.txt)
pass=$(cat passwords-list.txt)
for i in "${!hosts[#]}"; do
sshpass -p "${pass[i]}" ssh-copy-id -f root#"${hostnames[i]}" -p 22
done