I have a list of addresses, such as this:
Lake Havasu, Lake Havasu City, Arizona.
St. Johns River, Palatka, Florida.
Tennessee River, Knoxville, Tennessee.
I would like to extract the State from these addresses and then have a column showing the abbreviated State name (AZ, FL, TN etc.).
I have a table that has the States with their abbreviation and once I extract the State, doing a simple INDEX MATCH to get the abbreviation is easy. I don't want to use text-to-columns because this file will constantly have values added to it and it would be much easier to just have a formula that does the extraction for me.
The ways I've tried to approach this that have failed so far are:
Some kind of SEARCH() function that looks at the full State list and tries to find a value that exists in the cell
A MID or RIGHT approach to only capture the last section but I can't work out how to have FIND only look for the second ", "
A version of INDEX MATCH but that fails because I can't find a good way to search or find the values as per approach (1)
Any help would be appreciated!
Please try this formula, where A2 is the original text.
=FILTERXML("<data><a>" & SUBSTITUTE(A2,", ","</a><a>") & "</a></data>","data/a[3]")
An alternative would be to look for the 2nd comma as shown below. Note that the "50" in the formula is an irrelevant number required by the MID() function. It shouldn't be smaller than the number of characters you need to return, however.
Char(160) is a character that wouldn't (shouldn't) naturally occur in your text, as it might if the text comes from a UNIX database. You can replace it with another one that fits the description.
=TRIM(MID(A2, FIND(CHAR(160),SUBSTITUTE(A2,",",CHAR(160),2)) + 1,50))
The following variation of the above would remove the final period. It will fail if there is anything following the period, such as an unwanted blank. That could be accommodated within the formula as well but it would be easier to treat the original data, if that is an option for you.
=TRIM(MID(LEFT(A2, LEN(A2)-1), FIND(CHAR(160),SUBSTITUTE(A2,",",CHAR(160),2)) + 1,50))
To find the abbreviation I would recommend to use VLOOKUP rather than INDEX/MATCH.
Use this (screenshot refers):
=MID(MID(B3,1,LEN(B3)-1),SEARCH(",",B3,SEARCH(",",B3,1)+1)+3,LEN(B3))
Related
The attached image (link: https://i.stack.imgur.com/w0pEw.png) shows a range of cells (B1:B7) from a table I imported from the web. I need a formula that allows me to extract the names from each cell. In this case, my objective is to generate the following list of names, where each name is in its own cell: Erik Karlsson, P.K. Subban, John Tavares, Matthew Tkachuk, Steven Stamkos, Dustin Brown, Shea Weber.
I have been reading about left, right, and mid functions, but I'm confused by the irregular spacing and special characters (i.e. the box with question mark beside some names).
Can anyone help me extract the names? Thanks
Assuming that your cells follow the same format, you can use a variety of text functions to get the name.
This function requires the following format:
Some initial text, followed by
2 new lines in Excel (represented by CHAR(10)
The name, which consists of a first name, a space, then a last name
A second space on the same line as the name, followed by some additional text.
With this format, you can use the following formula (assuming your data is in an Excel table, with the column of initial data named Text):
=MID([#Text],SEARCH(CHAR(10),[#Text],SEARCH(CHAR(10),[#Text])+1)+1,SEARCH(" ",MID([#Text],SEARCH(CHAR(10),[#Text],SEARCH(CHAR(10),[#Text])+1)+1,LEN([#Text])),SEARCH(" ",MID([#Text],SEARCH(CHAR(10),[#Text],SEARCH(CHAR(10),[#Text])+1)+1,LEN([#Text])))+1)-1)
To come up with this formula, we take the following steps:
First, we figure out where the name starts. We know this occurs after the 2 new lines, so we use:
=SEARCH(CHAR(10),[#Text],SEARCH(CHAR(10),[#Text])+1)+1
The inner (occurring second) SEARCH finds the first new line, and the outer (occurring first) finds the 2nd new line.
Now that we have that value, we can use it to determine the rest of the string (after the 2 new lines). Let's say that the previous formula was stored in a table column called Start of Name. The 2nd formula will then be:
=MID([#Text],[#[Start of Name]],LEN([#Text]))
Note that we're using the length of the entire text, which by definition is more than we need. However, that's not an issue, since Excel returns the smaller amount between the last argument to MID and the actual length of the text.
Once we have the text from the start of the name on, we need to calculate the position of the 2nd space (where the name ends). To do that, we need to calculate the position of the first space. This is similar to how we calculated the start of the name earlier (which starts after 2 new lines). The function we need is:
=SEARCH(" ",[#[Rest of String]],SEARCH(" ",[#[Rest of String]])+1)-1
So now, we know where the name starts (after 2 new lines), and where it ends (after the 2nd space). Assuming we have these numbers stored in columns named Start of Name and To Second Space respectively, we can use the following formula to get the name:
=MID([#Text],[#[Start of Name]],[#[To Second Space]])
This is equivalent to the first formula: The difference is that the first formula doesn't use any "helper columns".
Of course, if any cell doesn't match this format, then you'll be out of luck. Using Excel formulas to parse text can be finicky and inflexible. For example, if someone has a middle name, or someone has a initials with spaces (e.g. P.K. Subban was P. K. Subban), or there was a Jr. or something, your job would be a lot harder.
Another alternative is to use regular expressions to get the data you want. I would recommend this thorough answer as a primer. Although you still have the same issues with name formats.
Finally, there's the obligatory Falsehoods Programmers Believe About Names as a warning against assuming any kind of standardized name format.
What is the best way to find the right column for the travelled miles using visual basic coding or some excel function and return the price from that column? HLOOKUP can't be used here because the lookup value isn't exact and the ranges in the table are also not with specific intervals (If they were, I could use e.g. FLOOR(travelled miles/100)*100 and find the price with HLOOKUP). Obviously, it's easy to find the price manually with a small table but with a big table computer will be faster.
Note that, if x is between a and b, then MEDIAN(x,a,b)=x. Combine this with some nested IFs:
=IF(MEDIAN(B5,B1,C1-1)=B5,B2,IF(MEDIAN(B5,C1,D1-1)=B5,C2,IF(MEDIAN(B5,D1,E1-1)=B5,D2)))
I'm on my phone, so just done the first three cases, but hopefully you can see how it continues.
(should note you need to remove the dashes for this to work)
Edit:
I also want to answer your question in the comments above. You can use the following to keep the dash, but get a number to work with.
Assume cell A1 has got the value 10-. We can use the FIND function to work out where the - occurs and then use the LEFT function to only return the characters from before the dash:
=LEFT(A1,FIND("-",A1)-1)
This will return the value 10, but it will return it as a string, not a number - basically Excel will think it is text. To force Excel to consider it as a number, we can simply multiply the value by one. Our formula above therefore becomes:
=(LEFT(A1,FIND("-",A1)-1))*1
You may also see people use a double minus sign, like this:
=--LEFT(A1,FIND("-",A1)-1)
I don't recommend this because it's a bit complex, but combining with the formula above would give:
=IF(MEDIAN(B5,--LEFT(B1,FIND("-",B1)-1),--LEFT(C1,FIND("-",C1)-1)-1)=B5,B2,IF(MEDIAN(B5,--LEFT(C1,FIND("-",C1)-1,--LEFT(D1,FIND("-",D1)-1-1)=B5,C2,IF(MEDIAN(B5,--LEFT(D1,FIND("-",D1)-1,--LEFT(E1,FIND("-",E1)-1-1)=B5,D2)))
I have 2 column data in Excel like this:
Can somebody help me write a formula in column C that will take the first name or the last name from column A and match it with column B and paste the values in column C. The following picture will give you the exact idea what I am trying to do. Thanks
Since your data is not "regular", you can try this formula which uses wild card to look for just the last name.
=INDEX($B$1:$B$4,MATCH("*" &MID(A1,FIND(" ",A1)+1,99)&"*",$B$1:$B$4,0))
It would be simpler if the first part followed some rule, but some have the first initial of the first name at the beginning; and others at the end.
Edit: (explanation added)
The FIND returns the character number of the first space
Add 1 to that to get the character number of the next word
Use MID to extract that word
Use that word in MATCH (with wild-cards before and after), to find it in the array of email addresses. This will return it's position in the array (row number)
Use that row number as an argument to the INDEX function to return the actual email address.
If you want to first examine the email address, you will need to determine which of the letters comprise the last name. Since this is not regular according to your example, you will need to check both options.
You will not be able to look for the first name from the email, as it is not present.
If you can guarantee that the first part will be follow the rule of one or the other, eg: either
FirstInitialLastName or
LastNameFirstInitial
Then you can try this:
=IFERROR(INDEX($B$1:$B$4,MATCH(MID(A1,FIND(" ",A1)+1,99)& LEFT(A1,1) &"*",$B$1:$B$4,0)),
INDEX($B$1:$B$4,MATCH( LEFT(A1,1)&MID(A1,FIND(" ",A1)+1,99) &"*",$B$1:$B$4,0)))
This seems to do what you want.
=IFERROR(VLOOKUP(LOWER(MID(A1,(SEARCH(" ",A1)+1),LEN(A1)))&LOWER(MID(A1,1,1))&"*",$B$1:$B$4,1,FALSE),VLOOKUP(LOWER(MID(A1,1,1))&LOWER(MID(A1,(SEARCH(" ",A1)+1),LEN(A1)))&"*",$B$1:$B$4,1,FALSE))
Its pretty crazy long and would likely be easier to digest and debug broken up into columns instead of one huge formula.
It basically makes FLast and FirstL out of the name field by splitting on the space.
LastF:
=LOWER(MID(A1,(SEARCH(" ",A1)+1),LEN(A1)))&LOWER(MID(A1,1,1))
And FirstL:
=LOWER(MID(A1,1,1))&LOWER(MID(A1,(SEARCH(" ",A1)+1),LEN(A1)))
We then make 2 vlookups for these by using wildcards:
LastF:
=VLOOKUP([lastfirst equation from above]&"*",$B$1:$B$4,1,FALSE)
And FirstL:
=VLOOKUP([firstlast equation from above]&"*",$B$1:$B$4,1,FALSE)
And then wrap those in IfError so they both get tried:
=IfError([firstLast vlookup],[lastfirst vlookup])
The rub is that's going to be hell to edit if you ever need to, which is why I suggest doing each piece in another column then referencing the previous one.
You also need to be aware that this answer will get tripped up by essentially the same name - e.g. Sam Smith and Sasha Smith would both match whatever the first entry for ssmith was. Any solution here will likely have the same pitfall.
I have a large spreadsheet with column data like:
ABC:1:I.0
ABC:1:I.1
ABC:1:I.2
ABC:1:I.3
ABC:2:I.0
ABC:2:I.1
ABC:2:I.2
ABC:2:I.3
ABC:3:I.0
ABC:3:I.2
ABC:3:I.3
ABC:4:I.0
ABC:4:I.1
ABC:4:I.2
ABC:4:I.3
ABC:5:I.0
ABC:5:I.1
ABC:5:I.2
ABC:5:I.3
ETC.
I need to replace the above with the following:
ABC:I.Data[1].0
ABC:I.Data[1].1
ABC:I.Data[1].2
ABC:I.Data[1].3
ABC:I.Data[2].0
ABC:I.Data[2].1
ABC:I.Data[2].2
ABC:I.Data[2].3
ABC:I.Data[3].0
ABC:I.Data[3].2
ABC:I.Data[3].3
ABC:I.Data[4].0
ABC:I.Data[4].1
ABC:I.Data[4].2
ABC:I.Data[4].3
ABC:I.Data[5].0
ABC:I.Data[5].1
ABC:I.Data[5].2
ABC:I.Data[5].3
ETC.
Here is a sample of the data, most of the data follows a similar format with the exception of the naming "ABC", which can vary in size, so it might be "ABCD" and also with the exception of the letter "I", it can be "O" as well. Also, some might be missing some values such as ABC:3:I.1 which is missing from the data. I am not too familiar with excel formulas or VBA code. Does anyone know how to do this? I have no preference on which method it has to be done in as I don't mind learning some VBA code if someone provides me with a VBA solution.
I was thinking of using some sort of loop along with some conditional statements.
Thanks!
Please try:
=LEFT(F11,FIND(":",F11))&MID(F11,FIND(":",F11,6)+1,1)&".Data["&MID(F11,FIND(":",F11,2)+1,1)&"]."&RIGHT(F11,1)
copied down to suit, assuming placed in Row11 and your data is in ColumnF starting in Row11.
Curiosities:
When this A was first posted it attempted to address only the tabulated example input and output. I temporarily deleted that version while addressing that what was in the table as ABC might at times be ABCD and that what was I might at times be O.
OP has posted an answer that I edited to make no visible change but which shows as the deletion of two characters. A copy of the OP’s formula exhibited a syntax error prior to my edit.
OP suggested an edit to my answer but this was rejected by the review process. As it happens, I think the edit suggestion was incorrect.
I have edited my answer again to include these ‘curiosities’ and to match the cell reference used by the OP in his answer.
=LEFT(A1,SEARCH(":",A1)) & MID(A1, SEARCH(".",A1)-1, 2) &
"Data[" & MID(A1,SEARCH(":",A1)+1,1) & "]" & RIGHT(A1,2)
With the help of pnuts I was able to come up with my own solution:
=LEFT(F11,LEN(F11)-5)&MID(F11,LEN(F11)-2,2)&"Data["&MID(F11,LEN(F11)-4,1)&"]"&RIGHT(F11,2)
My solution works based on the fact that the length of the last six values in the string ABC:1:I:0 will always be the same in size for all the data I have, hence you see LEN(F11)-some number in my code. The only part of the string that changes in size is the first part, in this case ABC which can also be ABCDEF, etc.
If you'd like to use formulas rather than VBA, an easy option is to split the data into 4 columns, using the Text To Columns option - first split using the colon as a delimiter, then using a full-stop / period as a delimiter.
Once you have 4 columns of data (one for each block), you can use the Concatenate function to join them and add in the extra characters: =CONCATENATE(A1,":",C1,".","Data[",B1,"].",D1)
This should still work if you have extra / alternative characters (eg ABCD instead of ABC), as long as you have the same delimiters, but obviously you'd need to test to make sure.
Seems like it would be a simple thing really (and it may be), but I'm trying to take the string data of a column and then through a calculated column, replace all the spaces with %20's so that the HTML link in the workflow produced email will actually not break off at the first space.
For example, we have this in our source column:
file:///Z:/data/This is our report.rpt
And would like to end up with this in the calculated column:
file:///Z:/data/This%20is%20our%20report.rpt
Already used the REPLACE, and made up a ghastly super nested REPLACE/SEARCH version, but the problem there is that you have to nest for EACH potential space, and if you don't know how many up front, it doesn't work, or will miss some.
Have any of you come across this scenario and how did you handle it?
Thanks in advance!
As far as I know there is no generic solution using the calculated-column syntax. The standard solution for this situation is using an ItemAdded (/ItemUpdated) event and initializing the field value from code.
I was able to solve this issue for my circumstances by using a series of calculated columns.
In the first calculated column (C1) I entered a formula to remove the first space, something like this:
=IF(ISNUMBER(FIND(" ",[Title])),REPLACE([Title],FIND(" ",[Title]),1,"%20"),[Title])
In the second Calculated column (C2) I used:
=IF(ISNUMBER(FIND(" ",[C1])),REPLACE([C1],FIND(" ",[C1]),1,"%20"),[C1]).
In my case, I wanted to encode upto four spaces, so I used 3 calculated columns (C1, C2, C3) in the same fashion and got the desired result.
This is not as efficient as using a single calculated column, but if SUBSTITUTE will not work in your SharePoint environment, and you cannot use an event handler or workflow, it may offer a workable alternative.
I actually used a slightly different formula, but it was on a work machine to which I don't have access at the moment, so I just grabbed this formula from a similar S.O. question. Any formula that will replace the first occurrence of a space with "%20" will work, the trick is to a) make sure the formula returns the original string unchanged if it does not have more spaces in it, and b) test, test, test. Create a view of your list that has the field you are trying to encode, plus the calculated fields, and see if you are getting the results you want.
so that the HTML link in the workflow produced email will actually not break off at the first space.
The browser only does this if you have not enclosed your link in quotes
If you wrap the link in quotes, it does not cut off at the first space
In a SharePoint Formula it would be:
="""file:///Z:/data/This is our report.rpt"""
becuase two quotes are the SP escape notation to output a quote
You can use this formula (Start trim for 1, in my case was 4):
=IF(ISBLANK([EUR Amount]),"",(TRIM(MID([EUR Amount],4,2))&TRIM(MID([EUR Amount],6,2))&TRIM(MID([EUR Amount],8,2))&TRIM(MID([EUR Amount],10,2))&TRIM(MID([EUR Amount],12,2))&TRIM(MID([EUR Amount],14,2)))*1)