I wanted to write the file path into a variable so i used the str to do that and got that:
\f inside of the path
and that happens often so how do i solve this issue?
Replace all your \ with \\.
From the Python docs:
The backslash (\) character is used to escape characters that otherwise have a special meaning, such as newline, backslash itself, or the quote character.
Related
I'm trying to use a ZShell function to replace forward- and backslashes with a hyphen. So that "Hello/Every\Person" becomes "Hello-Every-Person". I can do it for the forward slash using
arg=${arg:gs/\//-}
but when I try the same syntax for the backslash it fails. Running
arg=${arg:gs/\//-}
arg=${arg:gs/\\/-}
produces "Hello-EveryPerson". It strips out the backslash, but doesn't do the replacement. I was expecting the normal rules of escaping characters to apply, so the double backslash would resolve to a character.
Can anyone tell me what I'm missing?
Works in zsh version 5.8 exactly as you expected.
The below is my code and on executing got the error message: line 1
SyntaxError: EOL while scanning string literal.
Help me in identifying the issue.
code is::
sessions=os.listdir('\Downloads\Rawdata\')
sessions=sessions[3:]
files=[]
for _ in sessions:
dire=os.listdir('\Downloads\Rawdata\')
for __ in dire:
files+=os.listdir('Downloads\Rawdata\'+__)
print(files)
The error is thrown by unescaped backslashes in your path. If you're lucky, your script may run without any issues but I would prefer to use the raw string literal in this case i.e. the 'r'-prefix before your path string. Also, do take note that you should not end your string with a '\' i.e. before the closing quote.
sessions=os.listdir(r'Downloads\Rawdata')
I also noticed that your path strings begin with a '\'. If you plan to navigate relative to your root, just define your path without beginning it with a backslash. r'child_folder\grandchild_folder'
Further reading
I am using the touch command to try and create a file with the name "\?$*'KwaMe'*$?\" (quotation marks included as part of the file name). However when I type touch "\?$*'KwaMe'*$?\" in the Terminal, it doesn't give me the result I am expecting. How can I create this file?
You need to escape special characters with the backslash symbol (\).
This command will create a file named "\?$*'KwaMe'*$?\":
touch \"\\\?\$\*\'KwaMe\'\*\$\?\\\"
Explanation
Double your \, like this: \\, so that your shell does not interpret the backslashes from your filename as escape characters.
Escape " and ', like this: \", \', so that your shell interprets the double quotes as part of the filename.
Escape $, like this: \$, otherwise your shell will think you're using a variable.
Escape ? and *, like this: \?, \*, to prevent filename expansion.
I have a TeX file that contains lines like
\[ De = 0 \]
Now my boss wants equation numbers so I want them to be like
\begin{equation}De = 0\end{equation}
I tried the following command by escaping the backslash with a backslash.
:%s#\\[#\\begin{equation}#gc
I think this should work but I am getting pattern not found error.
I have looked at
How to include forward slash in vi search & replace
and
http://vim.wikia.com/wiki/Search_and_replace
Can somebody tell what am I doing wrong?
You have to escape both characters: :%s_\\\[ _\\begin{equation}_g.
EDIT: Since you also asked for an explanation:
Why escape the \?
Vim supports different pattern matching styles (see :help /magic), but escape characters have to be escaped in all of them.
Why escape the [?
[] in patterns are used as collections. Thus you have to escape the [ to match it literally.
Inside of my Linux directory, I have a file named TopSample$Config.class.
Whenever I try to copy this file to another location/directory, it is not allowing me to do so.
I am doing it this way:
cp TopSample$Config.class /home/praveen/com/config/
Please let me know if this isn't possible.
The shell will interpret $Config as a variable. And it will expand to empty string.
You can put single quotes around to keep the literal value:
cp 'TopSample$Config.class' /home/praveen/com/config/
Another way is to escape the $(dollar sign) by using \(backslash)
cp TopSample\$Config.class /home/praveen/com/config/
Put single quotes around the filename.
cp 'TopSample$Config.class' /home/praveen/com/config
Or replace the offending character with the filename metacharacter of '?', meaning "any one character". Note that while this might be more convenient and requires the fewest keystrokes, be aware that a filename of TopSample?Config.class will also match TopSampleaConfig.class, TopSamplebConfig.class, TopSamplecConfig.class, etc.