I'm trying to provide basic keyboard interaction for my gnuplot script.
With gnuplot 5.4 patchlevel 1 I'm using MOUSE_CHAR as documented, I believe, however with the simplest script below, I get an error no matter what key I press.
while (1) {
pause mouse keypress
show variable MOUSE_
if (exists("MOUSE_CHAR")) {
if (MOUSE_CHAR == "w") {
print "w"
}
} # <-- line 114
replot
}
The output shows the correct key pressed, for example:
MOUSE_KEY = 119
MOUSE_CHAR = "w"
or
MOUSE_KEY = 114
MOUSE_CHAR = "r"
But immediately after I get
"hrtp.gp" line 114: Non-numeric string found where a numeric expression was expected
The test for string equality is eq not ==, so you want if (MOUSE_CHAR eq "w") { print "w" }.
Related
I am running a simple code with a GPS sensor and Raspberry Pi 3b+ and want to perform some calculations with the readings and the only errors I'm getting is "SyntaxError: invalid character in identifier" but the line looks straightforward.
def Tasks():
def CalculateSpeed():
if x[-1] and y[-1] == even:
ChangeInLatitude=x1-x
DistanceConversion=ChangeInLatitude*111111
Speed=DistanceConversion/TimeElapsed
Speed=str(speed) + meters/interval
print (“The object this module is attached to is moving at “ + Speed)
The error code is placing the error marker at the end of "the" in the 8th line
You have unicode quotes.
foo = “bar“
is not valid nor is
foo = “bar”
but single or double "basic" quotes are:
foo = "bar"
I am completely new to programming and python so i wanted to know if there is any way to for the program to recognize when i have pressed a specific key and continue rather than using input() function where i have to press enter after i have entered my data.
I've tried using the getch() but the program just continues without waiting for a key to be pressed.
from msvcrt import getch
x=0
while ord(getch() == 117):
print("worked")
TypeError: ord() expected string of length 1, but bool found
You wrote this expression:
ord(getch() == 117)
Instead, use one of these (equivalent) expressions:
ord(getch()) == 117
getch() == chr(117)
getch() == 'u'
I am presently working on a file to open one by one .txt documents, extract data, to finally fill a .excel document.
Because I did not know how it is possible to write multiple times on the same line of my Excel document after one write statement (because it jumps to the next line), I have created a string of characters which is filled time after time :
Data (data_limite(x),x=1,8)/10, 9, 10, 7, 9, 8, 8, 9/
do file_descr = 1,nombre_fichier,1
taille_data1 = data_limite(file_descr)
nvari = taille_data1-7
write (new_data1,"(A30,A3,A11,A3,F5.1,A3,A7,F4.1,<nvari>(A3))") description,char(9),'T-isotherme',char(9),T_trait,char(9),'d_gamma',taille_Gam,(char(9),i=1,nvari)
ecriture_descr = ecriture_descr//new_data1
end do
Main issue was I want to adapt char(9) amount with the data_limite value so I built a write statement with a variable amount of char(9).
At the end of the do-loop, I have a very complex format of ecriture_descr which has no periodic format due to the change of the nvari value
Now I want to add this to the first line of my .excel :
Open(Unit= 20 ,File='resultats.RES',status='replace')
write(20,100) 'param',char(9),char(9),char(9),char(9),char(9),'*',char(9),'nuances',char(9),'*',char(9),ecriture_descr
100 format (a5,5(a3),a,a3,a7,a,a3,???)
but I do not know how to write this format. It would have been easier if, at each iteration of the do-loop I could fill the first line of my excel and continue to fill the first line at each new new_data1 value.
EDIT : maybe adding advance='no' in my write statement would help me, I am presently trying to add it
EDIT 2 : it did not work with advance='no' but adding a '$' at the end of my format write statement disable the return of my function. By moving it to my do-loop, I guess I can solve my problem :). I am presently trying to add it
First of all, your line
ecriture_descr = ecriture_descr//new_data1
Is almost certainly not doing what you expect it to do. I assume that both ecriture_descr and new_data are of type CHARACTER(len=<some value>) -- that is a fixed length string. If you assign anything to such a string, the string is cut to length (if the assigned is too long), or padded with spaces (if the assigned is too short:
program strings
implicit none
character(len=8) :: h
h = "Hello"
print *, "|" // h // "|" ! Prints "|Hello |"
h = "Hello World"
print *, "|" // h // "|" ! Prints "|Hello Wo|"
end program strings
And this combination will work against you: ecriture_descr will already be padded to the max with spaces, so when you append new_data1 it will be just outside the range of ecriture_descr, a bit like this:
h = "Hello" ! h is actually "Hello "
h = h // "World" ! equiv to h = "Hello " // "World"
! = "Hello World"
! ^^^^^^^^^
! Only this is assigned to h => no change
If you want a string aggregator, you need to use the trim function which removes all trailing spaces:
h = trim(h) // " World"
Secondly, if you want to write to a file, but don't want to have a newline, you can add the option advance='no' into the write statement:
do i = 1, 100
write(*, '(I4)', advance='no') i
end do
This should make your job a lot easier than to create one very long string in memory and then write it all out in one go.
Apologies if this is a duplicate. I have a helper function called inputString() that takes user input and returns a String. I want to proceed based on whether an upper or lowercase character was entered. Here is my code:
print("What do you want to do today? Enter 'D' for Deposit or 'W' for Withdrawl.")
operation = inputString()
if operation == "D" || operation == "d" {
print("Enter the amount to deposit.")
My program quits after the first print function, but gives no compiler errors. I don't know what I'm doing wrong.
It's important to keep in mind that there is a whole slew of purely whitespace characters that show up in strings, and sometimes, those whitespace characters can lead to problems just like this.
So, whenever you are certain that two strings should be equal, it can be useful to print them with some sort of non-whitespace character on either end of them.
For example:
print("Your input was <\(operation)>")
That should print the user input with angle brackets on either side of the input.
And if you stick that line into your program, you'll see it prints something like this:
Your input was <D
>
So it turns out that your inputString() method is capturing the newline character (\n) that the user presses to submit their input. You should improve your inputString() method to go ahead and trim that newline character before returning its value.
I feel it's really important to mention here that your inputString method is really clunky and requires importing modules. But there's a way simpler pure Swift approach: readLine().
Swift's readLine() method does exactly what your inputString() method is supposed to be doing, and by default, it strips the newline character off the end for you (there's an optional parameter you can pass to prevent the method from stripping the newline).
My version of your code looks like this:
func fetchInput(prompt: String? = nil) -> String? {
if let prompt = prompt {
print(prompt, terminator: "")
}
return readLine()
}
if let input = fetchInput("Enter some input: ") {
if input == "X" {
print("it matches X")
}
}
the cause of the error that you experienced is explained at Swift how to compare string which come from NSString. Essentially, we need to remove any whitespace or non-printing characters such as newline etc.
I also used .uppercaseString to simplify the comparison
the amended code is as follows:
func inputString() -> String {
var keyboard = NSFileHandle.fileHandleWithStandardInput()
var inputData = keyboard.availableData
let str: String = (NSString(data: inputData, encoding: NSUTF8StringEncoding)?.stringByTrimmingCharactersInSet(
NSCharacterSet.whitespaceAndNewlineCharacterSet()))!
return str
}
print("What do you want to do today? Enter 'D' for Deposit or 'W' for Withdrawl.")
let operation = inputString()
if operation.uppercaseString == "D" {
print("Enter the amount to deposit.")
}
I am reading in a text file and parsing the words into a map to count numbers of occurrences of each word on each line. I am required to ignore all non-alphabetic chars (punctuation, digits, white space, etc) except for apostrophes. I can figure out how to delete all of these characters using the following code, but that causes incorrect words, like "one-two" comes out as "onetwo", which should be two words, "one" and "two".
Instead, I am trying to now replace all of these values with spaces instead of simply deleting, but can't figure out how to do this. I figured the replace-if algorithm would be a good algorithm to use, but can't figure out the proper syntax to accomplish this. C++11 is fine. Any suggestions?
Sample output would be the following:
"first second" = "first" and "second"
"one-two" = "one" and "two"
"last.First" = "last" and "first"
"you're" = "you're"
"great! A" = "great" and "A"
// What I initially used to delete non-alpha and white space (apostrophe's not working currently, though)
// Read file one line at a time
while (getline(text, line)){
istringstream iss(line);
// Parse line on white space, storing values into tokens map
while (iss >> word){
word.erase(remove_if(word.begin(), word.end(), my_predicate), word.end());
++tokens[word][linenum];
}
++linenum;
}
bool my_predicate(char c){
return c == '\'' || !isalpha(c); // This line's not working properly for apostrophe's yet
}
bool my_predicate(char c){
return c == '\'' || !isalpha(c);
}
Here you're writing that you want to remove the char if it is and apostrophe or if it is not an alphabetical character.
Since you want to replace these, you should use std::replace_if() :
std::replace_if(std::begin(word), std::end(word), my_predicate, ' ');
And you should correct your predicate too :
return !isalpha(c) && c != '\'';
You could use std::replace_if to pre-process the input line before sending it to the istringstream. This will also simplify your inner loop.
while (getline(text, line)){
replace_if(line.begin(), line.end(), my_predicate, ' ');
istringstream iss(line);
// Parse line on white space, storing values into tokens map
while (iss >> word){
++tokens[word][linenum];
}
++linenum;
}