I'm on my research project to find the last price for a security at IPO and 20 trading days after for 5 years. I use =BDP($A$1, "EQY_INIT_PO_DT") to get the IPO trading date and its fine. The issue happened when I use =BADDPERIODS(A2, "NumberOfPeriods", "20", "CDR", "ID JA", "BusDayAdj", "1") it still include the non trading days. So when I use =BDH($A$1, "PX_LAST", A6, A6) it shows #N/A N/A. I guess =baddperiods() function outputted the non trading days and the =bdh() unable to get the price. How can I obtain the correct 20 trading days (exclude weekends and any public / non-trading days) after a certain date?
Reference:
A1= Company Ticker
A2= IPO Date
A3= =BADDPERIODS(A2, "NumberOfPeriods", "20", "CDR", "ID JA", "BusDayAdj", "1")
...
A6= =BADDPERIODS(A5, "NumberOfPeriods", "20", "CDR", "ID JA", "BusDayAdj", "1")
The BDH() worksheet function has optional parameters that specify how the timeseries data is returned. These come after the start and end date parameters. One of these allows a calendar to be specified. Specifying a calendar prompts Bloomberg to look back and find the closest (but earlier) 'good' value for the date requested.
The short, but inefficient answer is to use this formula in cell B6:
=BDH($A$1,"PX_LAST",A6,A6,"CDR","JA")
It is inefficient because each cell is making a relatively expensive call to Bloomberg for one day's history. It is better to pull back all the history from the start date to today in a single call, and put it in some spare columns. Then look your date up (using INDEX/MATCH) to find the price value.
Related
I have the following dataset in tibco spotfire:
Original data
I want to bring the amount of item in the beginning of each month for each row and get the following result:
Image
Any suggestions?
The dataset looks like this: I have got maximum amount for previous month, but I want to get the amount of the last day of the previous month.
enter image description here
I could do it via an intermediate column (as Spotfire's OVER does not accept expressions).
First calculate the year and month like this:
(assuming the format of your date is known and stable)
[YearMonth] is :
Integer(Concatenate(Substring(String([Date]),7,4),Substring(String([Date]),4,2)))
then your [Previous Month] is:
Max([Amount]) over (Intersect(Previous([YearMonth]),[BRANCH],[CLASS]))
and your [Diff] is:
[Amount] - [Previous Month]
Revised after comment 19 August:
change the Max to ValueForMax and insert the day of the month, so that the formula calculates the value
corresponding to the last recorded day for that month:
ValueForMax(DayOfMonth([Date]),[Amount]) over (Intersect(Previous([YearMonth]),[BRANCH],[CLASS]))
Revised after comments 6 October:
if Substring(..) is not available, here is an alternative solution:
Create a new column (to make the expressions understandable): [StringMonth] as:
If(LongInteger(Month([Date]))>10,String(LongInteger(Month([Date]))), Concatenate('0',String(LongInteger(Month([Date])))))
Then calculate your [YearMonth] as:
Integer(Concatenate(Year([Date]),[StringMonth]))
I have a table that has a series of Columns with data I need to split out. Example below
STATUS#10/16 12:00:00 (CODE)
I've been able to split it easy enough and when I originally tried to set the date on an older dataset it identified it as a date e.g. 16th Oct 2021 However I started to get errors on this date column and trying with different datasets (10/12, 10/13, 10/14) it is not finding the date. I tried the following query code but I'm receiving errors
[STATUS DATE] is split to 10/14, 10/15 etc
#date( Date.Year(DateTime.LocalNow), Date.Month(Text.End([STATUS DATE]), 2), Date.Day(Text.Start([STATUS DATE]),2))
However I'm getting a function error so I tried
Date.From(Date.Day(Text.Start([STATUS DATE]),2) & Date.Month(Text.End([STATUS DATE]),2) & Date.Year(DateTime.LocalNow)
I have also tried to do this from an example column however the query created is looking at the cell value e.g. if 10/14 then 14/10/2021 else if 13/10 then 14/10/2021. This method i feel is prone for error once I include a larger dataset.
Is there anyway I can determine the date value based on mm/dd format? But with year end in mind, make the YYYY be determined by current year unless we move into Jan and then I don't want the Oct, Nov, Dec value showing as 2022.
You don't really show what your original data looks like.
But if it is like:
Source
Then you can use this code in the Add Custom Column dialog:
let
split=Text.SplitAny([STATUS DATE],"#/ "),
mnth = Number.From(split{1}),
dy = Number.From(split{2})
in
#date(Date.Year(DateTime.LocalNow()),mnth,dy)
The Text.SplitAny function lets you input a list of delimiters and the text will split on all of them. So it is relatively simple to extract the month and day values
to create:
Split [STATUS DATE] one more time into [Month] and [Day] column, using the "/" as a separator. Then you don't have to bother with 1 or 2 digit numbers and you can simply use this formula:
#date(Date.Year(DateTime.LocalNow()), [Month], [Day])
DateTime.LocalNow() is a function, so you need to add the brackets.
[Month] and [Day] are numbers already, so you don't need the Date.Month() or Date.Day() functions.
I have this table in excel:
Date value
1/2/1970 100.00
1/5/1970 99.99
1/6/1970 100.37
1/7/1970 100.74
1/8/1970 101.26
1/9/1970 100.74
1/12/1970 100.79
1/13/1970 101.27
1/14/1970 101.95
1/15/1970 101.97
1/16/1970 101.76
1/19/1970 102.21
1/20/1970 102.70
1/21/1970 102.00
1/22/1970 101.46
1/23/1970 101.49
1/26/1970 100.97
1/27/1970 101.45
1/28/1970 101.70
1/29/1970 102.08
1/30/1970 102.19
2/2/1970 102.02
2/3/1970 101.85
These are values that I have daily, and I need to construct a sheet that takes a monthly index of the daily values, example below:
date index
1/31/1970 some_index
2/28/1970 some_index
3/31/1970 some_index
4/30/1970 some_index
I could only get this far when it came to getting the index of 30 days:
=AVERAGE(INDEX(B:B,1+30*(ROW()-ROW($C$1))):INDEX(B:B,30*(ROW()-ROW($C$1)+1)))
I'm just not sure how to structure this in the most efficient, yet correct way possible. Not all months are the same amount of days, so I was hoping to check to get all the next n rows where the date starts with a "1" for example, sometimes certain days are also missing. I can't think of a catch all approach.
With 1/31/1970 in C1 try this,
=averageifs(daily!b:b, daily!a:a, "<="&c1, daily!a:a, ">="&eomonth(c1, -1)+1)
A PivotTable might be more convenient:
I have a list of cost figures with start dates and end dates which I need to split between months, I have searched for the solution to this problem but cannot seem to find one that will work with partial months i.e.( startdate:01/01/2015 enddate: 15/04/2015 cost:10000) which would leave figures like Jan:2857, Feb:2857, Mar:2857, Apr:1429.
I have been trying to modify this example: http://www.excel-university.com/excel-formula-to-allocate-an-amount-into-monthly-columns/ but having no luck getting the partial months working.
Any suggestions or help would be most welcome. Thanks in Advance
if you calculate it on daily basis, would it be ok? the result would be:
01.01.2015 01.02.2015 01.03.2015 15.04.2015
2.857,14 2.857,14 2.857,14 1.428,57
your daily amount is:
=10.000/(DAYS360(startdate;enddate;TRUE)+1)
(be carefull of true and false argument)
under the dates or instead of 2.857,14 etc. insert the formula:
=IF(DAY("your date")>1;DAY("your date");30) * daily amount
This formula assumes that you want to have 30 days in each month:
=IF(DAY(01.01.2015)>1;DAY(01.01.2015);30)
result = 30
=IF(DAY(15.04.2015)>1;DAY(15.04.2015);30)
result = 15
so if months begins with a date different from the 1st it will give you the number of days.
if you want to match months with your startdate and enddate (if i understood your comment correctly), you could do:
=IF(OR(
AND(MONTH(startdate)=MONTH(your date);YEAR(startdate)=YEAR(your date));
AND(MONTH(enddate)=MONTH(your date);YEAR(enddate)=YEAR(your date))
);"match";"no match")
by this you make sure that month and year correspond.
If you want to get the number of days in a month automatically, you could use:
=DAY(DATE(YEAR("your date");MONTH("your date")+1;1)-1)
but this does not assume anymore 30 days, you can change it with if statement
I hope this helps,
Best - AB
In cell A1 we have this:
=CUBEMEMBER("OurCube","TAIL([Date].[Date - Calendar Month].[Calendar Day].MEMBERS,1).item(0)","TargetMember")
It works fine and returns a single member that is yesterday.
In A2 we have a formula that is attempting to return the actual date - so I thought the CUBEMEMBERPROPERTY function would work:
=CUBEMEMBERPROPERTY("OurCube",A1,"member_caption")
The above returns #N/A
I don't know what CUBEMEMBERPRPERTY does but apparently it doesn't mean what you think it means!
If you need to get a certain property of a field according to another field, this is the way to do it:
Let's say, I wanted the Financial Year's month name (FY Month Name) based on a certain date key (I live in Australia, the financial year finishes at June):
=CUBEMEMBER("ThisWorkbookDataModel", "EXISTS([Dim Period].[FY Month Name].Children, [Dim Period].[Datekey].[20160731])")
And if the value of "20160731" has been in a certain cell, it would go like this:
=CUBEMEMBER("ThisWorkbookDataModel", "EXISTS([Dim Period].[FY Month Name].Children, [Dim Period].[Datekey].["&A8&"])")
Both would give me the correct answer: 01 - July
And I would like to thank the following posts for their help:
https://wessexbi.wordpress.com/2014/02/16/a-cubememberproperty-equivalent-with-powerpivot/
http://www.mrexcel.com/forum/power-bi/730287-function-cubememberproperty-always-return-n.html