Validating if user input is already sanitised - python-3.x

Question

I've been working on a mini project with Python3 and tkinter recently that is used to sanitise URLs and IP addresses. I've hit a roadblock with my function that I cannot workout. What I am trying to achieve is:
Has a user entered a URL such as http://www.google.com or https://www.google.com and if so, sanitise as:
hxxp[:]//www[.]google[.]com or hxxps[:]//www[.]google[.]com
Has a user entered an IP address such as 192.168.1.1 or http://192.168.1.1 and sanitise as:
192[.]168[.]1[.]1 or hxxp[:]//192[.]168[.]1[.]1
Has a user entered already sanitised input? Is there unsanitised input along with it? If so, just sanitise the unsanitised input and print them to the results output Textbox.
I have included a screenshot of what is currently happening to my normal input, after input is sanitised and how I want to handle the above issues.
Also: Is the .strip() in the OutputTextbox.insert line redundant?
I appreciate any help and recommendations!
def printOut():
outputTextbox.delete("1.0", "end")
url = inputTextbox.get("1.0", "end-1c")
if len(url) == 0:
tk.messagebox.showerror("Error", "Please enter content to sanitise")
if "hxxp" and "[:]" and "[.]" in url or "hxxps" and "[:]" and "[.]" in url:
outputTextbox.insert("1.0", url, "\n".strip())
pass
elif "http" and ":" and "." in url:
url = url.replace("http", "hxxp")
url = url.replace(":", "[:]")
url = url.replace(".", "[.]")
outputTextbox.insert("1.0", url, "\n".strip())
elif "https" and ":" and "." in url:
url = url.replace("https", "hxxps")
url = url.replace(":", "[:]")
url = url.replace(".", "[.]")
outputTextbox.insert("1.0", url, "\n".strip())
elif "http" and ":" and range(0, 10) and "." in url or range(0, 10) and "." in url:
url = url.replace("http", "hxxp")
url = url.replace(".", "[.]")
outputTextbox.insert("1.0", url, "\n".strip())

Answer 1

The expression like A AND B AND C IN URL will has result like A AND B AND (C IN URL), not what you expect that A, B, C are all found in URL.
You can use re (regex module) to achieve what you want:
import re
def printOut():
outputTextbox.delete("1.0", "end")
url = inputTextbox.get("1.0", "end-1c")
if len(url) == 0:
messagebox.showerror("Error", "Please enter content to sanitise")
result = url.replace("http", "hxxp")
result = re.sub(r"([^\[]):([^\]])", r"\1[:]\2", result)
result = re.sub(r"([^\[])\.([^\]])", r"\1[.]\2", result)
outputTextbox.insert("end", result, "\n")
There may be better regex for that.