I am trying to make a name generator. I am using F string to concatenate the first and the last names. But instead of getting them together, I am getting them in a new line.
print(f"Random Name Generated is:\n{random.choice(firstname_list)}{random.choice(surname_list)}")
This give the output as:
Random Name Generated is:
Yung
heady
Instead of:
Random Name Generated is:
Yung heady
Can someone please explain why so?
The code seems right, perhaps could be of newlines (\n) characters in element of list.
Check the strings of lists.
import random
if __name__ == '__main__':
firstname_list = ["yung1", "yung2", "yung3"]
surname_list = ["heady1", "heady2", "heady3"]
firstname_list = [name.replace('\n', '') for name in firstname_list]
print(f"Random Name Generated is:\n{random.choice(firstname_list)} {random.choice(surname_list)}")
Output:
Random Name Generated is:
yung3 heady2
Since I had pulled these values from UTF-8 encoded .txt file, the readlines() did convert the names to list elements but they had a hidden '\xa0\n' in it.
This caused this particular printing problem. Using .strip() helped to remove the spaces.
print(f"Random Name Generated is:\n{random.choice(firstname_list).strip()} {random.choice(surname_list).strip()}")
Related
I have a text file containing random strings. I want to use specific criterias to extract the strings that match these criterias.
Example text :
B311-SG-1700-ASJND83-ANSDN762
BAKSJD873-JAN-1293
Example criteria :
All the strings that contains characters seperated by hyphens this way : XXX-XX-XXXX
Output : 'B311-SG-1700'
I tried creating a function but I can't seem to know how to use criterias for string specifically and how to apply them.
Based on your comment here is a python script that might do what you want (I'm not that familiar with python).
import re
p = re.compile(r'\b(.{4}-.{2}-.{4})')
results = p.findall('B111-SG-1700-ASJND83-ANSDN762 BAKSJD873-JAN-1293\nB211-SG-1700-ASJND83-ANSDN762 BAKSJD873-JAN-1293 B311-SG-1700-ASJND83-ANSDN762 BAKSJD873-JAN-1293')
print(results)
Output:
['B111-SG-1700', 'B211-SG-1700', 'B311-SG-1700']
You can read a file as a string like this
text_file = open("file.txt", "r")
data = text_file.read()
And use findall over that. Depending on the size of the file it might require a bit more work (e.g. reading line by line for example
You can use re module to extract the pattern from text:
import re
text = """\
B311-SG-1700-ASJND83-ANSDN762 BAKSJD873-JAN-1293
BAKSJD873-JAN-1293 B312-SG-1700-ASJND83-ANSDN762"""
for m in re.findall(r"\b.{4}-.{2}-.{4}", text):
print(m)
Prints:
B311-SG-1700
B312-SG-1700
so i'm currently learning about mail merging and was issued a challenge on it. The idea is to open a names file, read the name on the current line and then replace it in the letter and save that letter as a new item.
I figured a good idea to do this would be a for loop.
Open file > for loop > append names to list > loop the list and replace ect.
Except when I try to actually append the names to the list, i get this:
['Aang\nZuko\nAppa\nKatara\nSokka\nMomo\nUncle Iroh\nToph']
The code I am using is:
invited_names = []
with open ("./Input/Names/invited_names.txt") as names:
invited_names.append(names.read())
for item in invited_names:
new_names = [str.strip("\n") for str in invited_names]
print(new_names)
Have tried to replace the \n and now .strip but I have not been able to remove the \n. Any ideas?
EDIT: not sure if it helps but the .txt file for the names looks like this:
Aang
Zuko
Appa
Katara
Sokka
Momo
Uncle Iroh
Toph
As you can see, read() only returns a giant string of what you have in your invited_names.txt file. But instead, you can use readlines() which returns a list which contains strings of every line (Thanks to codeflush.dev for the comment). Then use extend() method to add this list to another list invited_names.
Again, you are using for loop and list comprehension at the same time. As a result, you are running the same list comprehension code for many times. So, you can cut off any of them. But I prefer you should keep the list comprehension because it is efficient.
Try this code:
invited_names = []
with open ("./Input/Names/invited_names.txt") as names:
invited_names.extend(names.readlines()) # <--
new_names = [str.strip("\n") for str in invited_names]
print(new_names)
I used 3 lines of codes which worked well. Then I try to contract them into one line, which I believe can be done by putting two variables together. But for some reason, the contracted codes only returned 0 instead of the actual sum that can be computed before. What's gone wrong in the contracted codes?
hand = open('xxxxxx.txt')
# This is a text file that contains many numbers in random positions
import re
num = re.findall('[0-9]+', hand.read())
# I used regular expression on variable 'num' to extract all numbers from the file and put them into a list
numi = [int(i) for i in num]
# I used variable 'numi' to convert all numbers in string form to integer form
print(sum(numi))
# Successfully printed out the sum of all integers
print(sum([int(i) for i in re.findall('[0-9]+', hand.read())]))
# Here is the problem. I attempted to contract variables 'num' and 'numi' into one line of codes. But I only got 0 instead of the actual sum from it`enter code here`
if you execute all the code like I see up there, it is normal to get 0 because you didn't re-open the file after using it the first time, just re-open the file "hand" or leave the final line that you want to use and delete the three lines before it.
This code works fine for me -
hand = open('xxxxx.txt')
import re
print(sum([int(i) for i in re.findall('[0-9]+', hand.read())]))
You have to close the file and reopen it before running the last line.
So we were given an assignment to create a code that would sort through a long message filled with special characters (ie. [,{,%,$,*) with only a few alphabet characters throughout the entire thing to make a special message.
I've been searching on this site for a while and haven't found anything specific enough that would work.
I put the text file into a pastebin if you want to see it
https://pastebin.com/48BTWB3B
Anywho, this is what I've come up with for code so far
code = open('code.txt', 'r')
lettersList = code.readlines()
lettersList.sort()
for letters in lettersList:
print(letters)
It prints the code.txt out but into short lists, essentially cutting it into smaller pieces. I want it to find and sort out the alphabet characters into a list and print the decoded message.
This is something you can do pretty easily with regex.
import re
with open('code.txt', 'r') as filehandle:
contents = filehandle.read()
letters = re.findall("[a-zA-Z]+", contents)
if you want to condense the list into a single string, you can use a join:
single_str = ''.join(letters)
I have a csv file that gets read into my code where arrays are generated out of each row of the file. I want to ignore all the array elements with letters in them and only worry about changing the elements containing numbers into floats. How can I change code like this:
myValues = []
data = open(text_file,"r")
for line in data.readlines()[1:]:
myValues.append([float(f) for f in line.strip('\n').strip('\r').split(',')])
so that the last line knows to only try converting numbers into floats, and to skip the letters entirely?
Put another way, given this list,
list = ['2','z','y','3','4']
what command should be given so the code knows not to try converting letters into floats?
You could use try: except:
for i in list:
try:
myVal.append(float(i))
except:
pass