how to separate date and time from datetime column if you have the format as below :
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I am trying int(datetime column) for fetching date ; Datetime column - int(datetime column) for fetching time column
Your formula cannot work because your data is a text string (note that it has a letter included) and not a number.
So first convert the string into a "real" time with:
=substitute(a2,"T"," ")
You can then use:
Date: =INT(SUBSTITUTE(A2,"T"," "))
Time: =MOD(SUBSTITUTE(A2,"T"," "),1)
and be sure to format the results as desired:
If your column is formatted true date then use to separate date
=TEXT(A1,"yyyy-mm-dd")
For time
=TEXT(A1,"hh:mm:ss")
If data is in text string or output by TEXT() function then try below functions.
for date =TEXT(FILTERXML("<t><s>"&SUBSTITUTE(A1,"T","</s><s>")&"</s></t>","//s[1]"),"yyyy-mm-dd")
for time =TEXT(FILTERXML("<t><s>"&SUBSTITUTE(A1,"T","</s><s>")&"</s></t>","//s[last()]"),"hh:mm:ss")
For date
=LEFT(A2,FIND("T",A2)-1)
For time
=RIGHT(A2,LEN(A2)-FIND("T",A2))
Related
I have a column in my Excel sheet called "Start_Time" and the data in the column is in "HH:MM:SS" format, for example "10:13:20".
But when I use pandas.read_excel() function to load the data. The "Start_Time" column showed decimal values (for example: 0.425925925925926) with data type as "object".
How could make the df["Start_Time"] to display as "10:13:20"?
I tried pd.Timedelta(), but it works for only one value at a time. I want to convert all values in that column.
Start Time
End Time
16:24:50
16:32:27
10:35:53
15:06:46
15:21:43
6:39:50
6:39:50
21:55:02
3:29:04
3:29:13
0:53:06
0:53:06
10:21:13
10:25:18
16:15:25
16:19:31
Excel stores the date as a serial number counting from a starting date.
When you choose a format it converts that serial number to the format demanded.
If you want Pandas to display the correct date then you have to convert the serial number.
i have a set of data for couple of days and the names of the data files like this
name='Newyork20200915'
which is for the 15th of September and i want to export only the date to excel like shown below
So how can i get the date from the name string ?
Thanks in advance
Assuming that the other part of name will not contain any digits besides the date, you can use regexp to get all the digits from the character array:
name = 'Newyork20200915'
date_only = regexp(name, '\d*', 'match')
Next, you can convert this date string to a serial date number using datenum, by providing the format in which the date is currently. And then use datestr to format it to your desired format.
date_formatted = datestr(datenum(date_only, 'yyyymmdd'), 'dd. mmm')
date_formatted =
'15. Sep'
I am looking to read data from a column in my CSV file.
All of the data in this column are dates. (DD/MM/YYYY).
I want my program to read the Dates column, and if the date is within 3 days of the current date, I want to add variables to all of the values in that row.
Ex.
Date,Name,LaterDate
1/1/19,John Smith, 2/21/19
If I run my program on 2/19/2019, I want an email sent that says "John Smith's case is closing on "2/21/2019".
I understand how to send an email. The part that I get stuck on is:
Reading the CSV column specifically.
If the date is within 3 days,
Assign variables to the values in the ROW,
Use those variables to send a custom email.
I see a lot of "Use Pandas" but I might need the individual steps broken down.
Thank you.
First things first, you need to read all the values of the csv file and store it in a variable (old_df). Then you need to save all the dates in the Series (dates). Next we create an empty DataFrame with the same columns. From here we create a simple for loop for each date in dates and it's index i. Turn date into a datetime object from the datetime library. Then we subtract amount of days between the current date and date. Take the absolute value of days so we always get a positive amount of days. Then add the index of that particular date in old_df to new_df.
import pandas as pd
from datetime import datetime
old_df = pd.read_csv('example.csv')
dates = old_df['LaterDate']
new_df = pd.DataFrame(columns=['Date', 'Name', 'LaterDate'])
for i, date in enumerate(dates):
date = datetime.strptime(date, '%m/%d/%y')
days = (datetime.now() - date).days
if abs(days) <= 3:
new_df = new_df.append(old_df.loc[i, :])
print(new_df)
I'm using today to aquire todays date and then adding a static value to the end of it using the following:
=TODAY()&"T23:00:00"
Which Returns 43202T23:00:00
I really need it in the format 2018-04-12T23:00:00
Any help on this would be great!
There are a couple ways to accomplish this, depending on whether your goal is a formatted String (to display) or a numeric value (such as data type Date) for storing or using with calculations.
If you want a formatted date/time result (to display to the user)...
Use the TEXT worksheet function:
=TEXT(TODAY(),"yyyy-mm-dd")&"T23:00:00"
...the reason this works is because TODAY() returns a Date data type, which is basically just a number representing the date/time, (where 1 = midnight on January 1, 1900, 2 = midnight on January 2, 1900, 2.5 = noon on January 2, 1900,etc).
You can convert the date type to a String (text) with the TEXT function, in whatever format you like. The example above will display today's date as 2018-04-12.
If, for example, you wanted the date portion of the string displayed asApril 12, 2018 then you would instead use:
TEXT(TODAY(),"mmmm d, yyyy")
Note that the TEXT worksheet function (and VBA's Format function) always return Strings, ready to be concatenated with the rest of the String that you're trying to add ("T23:00:00").
If you want to use the result in calculations...
If you instead want the result to be in a Date type, then instead of concatenating a string (produced by the TEXT function) to a string (from "T23:00:00"), you could instead add a date to a date:
=TODAY()+TIME(23,0,0)
or
=TODAY()+TIMEVALUE("23:00")
..and then you can format it as you like to show or hide Y/M/D/H/M/S as necessary with Number Formats (shortcut: Ctrl+1).
More Information:
MSDN : TEXT Function (Excel)
MSDN : TIMEVALUE Function (Excel)
MSDN : TIME Function (Excel)
Id appreciate if someone can help.
I have a column with the following values:
DATETIME
1401032014
1401032014
1401010629
1401032011
1401010629
1401032011
The cell is a number (or can be displayed as text). It shows the datetime. Example:
1401032011:
year: 14
month:01
day:03
hours: 20
minutes: 11
How can I split the value and concatenate into datetime? Notice i have only two last digits of the year - 14, so the full datetime should have the format like this "2014-01-03 20:11"
Thanks a lot in advance.
If you only want the formula to return text use:
="20"&LEFT(A1;2)&"-"&MID(A1;3;2)&"-"&MID(A1;5;2) & " " & MID(A1;7;2) &":"&MID(A1;9;2)
If you want the formula to return a datetime value use:
=DATE(2000+LEFT(A1;2);MID(A1;3;2);MID(A1;5;2))+(MID(A1;7;2)*60+MID(A1;9;2))/1440
And then (for the last one) format the datetime value at will.
I always prefer, when possible, to use date instead of datevalue because datevalue interprets date_text argument based on regional settings and will return an error with different Regional Settings.