I want to share something (like a text, image, etc) using a link with Android Intents.
For example:
Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, someTextView.getText());
sendIntent.setType("text/plain");
Intent shareIntent = Intent.createChooser(sendIntent, null);
startActivity(shareIntent);
This code allows me to share a text. But I want that this content will be shared with a link, like this:
https://my-aplication/someText
And then, when the user enters in the page, gets the current shared text.
How can I do that? I investigated about using Android App Links, but I didn't understand very well.
Also I tried to search in other places but I didn't find anything.
Thanks for helping!
After investigating about this topic, I found Google Firebase Dynamic Links. I watched some videos about this topic. This code generates a key which can be shared by a link. First, you must create a dynamic link in you firebase console. Then, you add these methods. Here's the first method to get Dynamic link data:
FirebaseDynamicLinks.getInstance().getDynamicLink(getIntent()).addOnSuccessListener(this, new OnSuccessListener<PendingDynamicLinkData>() {
#Override
public void onSuccess(PendingDynamicLinkData pendingDynamicLinkData) {
// getting deep link
Uri deeplink = null;
if(pendingDynamicLinkData != null){
deeplink = pendingDynamicLinkData.getLink();
}
// getting deeplink content
if(deeplink != null)
{
String sharedList = deeplink.getQueryParameter("sharedList");
userReference[0] = database.getReference(sharedList);
}
else userReference[0] = database.getReference().push();
}
}).addOnFailureListener(new OnFailureListener() {
#Override
public void onFailure(#NonNull Exception e) {
Toast.makeText(MainActivity.this, "Ooops, we couldn't get the link data :(", Toast.LENGTH_SHORT).show();
}
});
And here's the second one, to generate a link:
// generating dynamic link
private void GenerateLink(String listId) {
System.out.println("Generating link: " + listId);
DynamicLink dynamicLink = FirebaseDynamicLinks.getInstance().createDynamicLink()
.setLink(Uri.parse("https://www.your_dynamic_link.com/?your_variable_to_share=" + value))
.setDomainUriPrefix("https://your_short_url.page.link")
.setAndroidParameters(
new DynamicLink.AndroidParameters.Builder("com.example.your_package")
.setMinimumVersion(1)
.build())
.buildDynamicLink();
Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, "I share you my list: " + dynamicLink.getUri());
sendIntent.setType("text/plain");
startActivity(sendIntent);
}
Related
I need your help.
I have created a new screen, where I am calling all invoices pending release.
I have problems to release, I send a message where you request (you want to release).
It shows me the infinite message.
Only once should you ask me, then you should go out and follow the normal process.
public ProcessDocNew()
{
// Acuminator disable once PX1008 LongOperationDelegateSynchronousExecution [Justification]
Document.SetProcessDelegate(
delegate (List<ARInvoice> list)
{
List<ARRegister> newlist = new List<ARRegister>(list.Count);
foreach (ARInvoice doc in list)
{
newlist.Add(doc);
}
ProcessDoc(newlist, true);
}
);
Document.SetProcessCaption(ActionsMensje.Process);
Document.SetProcessAllCaption(ActionsMensje.ProcessAll);
}
public virtual void ProcessDoc(List<ARRegister> list, bool isMassProcess)
{
string title = "Test";
string sms = "¿Stamp?";
var Graph = PXGraph.CreateInstance<ARInvoiceEntry>();
ARInvoice document = Document.Current;
PEFEStampDocument timbrar = new PEFEStampDocument();/*This is a class where it is, all my method*/
if (isMassProcess == true)
{
Document.Ask(title, sms, MessageButtons.YesNo, MessageIcon.Question);
{
PXLongOperation.StartOperation(Graph, delegate
{
timbrar.Stamp(document, Graph); /*here I have my release method*/
});
}
}
}
public static class ActionsMensje
{
public const string Process = "Process";
public const string ProcessAll = "Process All";
}
I await your comments
Only once should you ask me, then you should go out and follow the
normal process.
That is not how the processing pattern works. The process delegate is called for each record and is therefore not a valid location to display a message that should be shown only once.
You would need to add a custom action to achieve that behavior. The scenario you're looking for should be implemented with a processing filter checkbox and processing filter to comply with best practices:
Documentation on processing screens implementation is available here:
https://help-2019r2.acumatica.com/Help?ScreenId=ShowWiki&pageid=a007b57b-af69-4c0f-9fd1-f5d98351035f
i am doing video chat now in my app, i found some code in the Quickblox for android, i am not able to get the userlist for chat i am getting the following error message like "QBResponseException : Entity you are looking for was not found", i am stuck this for a day, i went through lot of search but i am not able to find any suitable solution for it, can anyone help me with this.
Below i have attached my code:
QBPagedRequestBuilder requestBuilder = new QBPagedRequestBuilder();
requestBuilder.setPerPage(getResources().getInteger(10));
List<String> tags = new LinkedList<>();
tags.add("webrtcusers");
QBUsers.getUsersByTags(tags, requestBuilder, new QBEntityCallbackImpl<ArrayList<QBUser>>() {
#Override
public void onSuccess(ArrayList<QBUser> qbUsers, Bundle bundle)
{
System.out.println("INSIDE LISt");
showProgress(false);
users.clear();
users.addAll(DataHolder.createUsersList(qbUsers));
initUsersList();
}
#Override
public void onError(QBResponseException exc) {
showProgress(false);
/* Toaster.longToast("Error while loading users");*/
Toast.makeText(getApplicationContext(), "Error while loading users",
Toast.LENGTH_SHORT).show();
Log.d(TAG, "onError()"+exc.toString());
}
});
Response goes to OnError with above exception. It tells me to look at the QuickBlox at dashboard Admin panel to look for correct Account Key, guys i am counting on you to get grid of these.
This error means that the requested resource could not be found. So check that you really have users with tag "webrtcusers" in your app.
I have somewhat lost touch with custom search engines ever since Google switched from its more legacy search engine api in favor of the google custom search api. I'm hoping someone might be able to tell me whether a (pretty simple) goal can be accomplished with the new framework, and potentially any starting help would be great.
Specifically, I am looking to write a program which will read in text from a text file, then use five words from said document in a google search - the point being to figure out how many results accrue from said search.
An example input/output would be:
Input: "This is my search term" -- quotations included in the search!
Output: there were 7 total results
Thanks so much, all, for your time/help
First you need to create a Google Custom Search project inside you google account.
From this project you must obtain a Custom Search Engine ID , known as cx parameter. You must also obtain a API key parameter. Both of these are available from your Google Custom Search API project inside your google account.
Then, if you prefer Java , here's a working example:
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
public class GoogleCustonSearchAPI {
public static void main(String[] args) throws Exception {
String key="your_key";
String qry="your_query";
String cx = "your_cx";
//Fetch urls
URL url = new URL(
"https://www.googleapis.com/customsearch/v1?key="+key+"&cx="+cx+"&q="+ qry +"&alt=json&queriefields=queries(request(totalResults))");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept", "application/json");
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
//Remove comments if you need to output in JSON format
/*String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}*/
//Print the urls and domains from Google Custom Search String searchResult;
while ((searchResult = output.readLine()) != null) {
int startPos=searchResult.indexOf("\"link\": \"")+("\"link\": \"").length();
int endPos=searchResult.indexOf("\",");
if(searchResult.contains("\"link\": \"") && (endPos>startPos)){
String link=searchResult.substring(startPos,endPos);
if(link.contains(",")){
String tempLink = "\"";
tempLink+=link;
tempLink+="\"";
System.out.println(tempLink);
}
else{
System.out.println(link);
}
System.out.println(getDomainName(link));
}
}
conn.disconnect();
}
public static String getDomainName(String url) throws URISyntaxException {
URI uri = new URI(url);
String domain = uri.getHost();
return domain.startsWith("www.") ? domain.substring(4) : domain;
}
The "&queriefields=queries(request(totalResults))" is what makes the difference and gives sou what you need. But keep in mind that you can perform only 100 queries per day for free and that the results of Custom Search API are sometimes quite different from the those returned from Google.com search
If anybody would still need some example of CSE (Google Custom Search Engine) API, this is working method
public static List<Result> search(String keyword){
Customsearch customsearch= null;
try {
customsearch = new Customsearch(new NetHttpTransport(),new JacksonFactory(), new HttpRequestInitializer() {
public void initialize(HttpRequest httpRequest) {
try {
// set connect and read timeouts
httpRequest.setConnectTimeout(HTTP_REQUEST_TIMEOUT);
httpRequest.setReadTimeout(HTTP_REQUEST_TIMEOUT);
} catch (Exception ex) {
ex.printStackTrace();
}
}
});
} catch (Exception e) {
e.printStackTrace();
}
List<Result> resultList=null;
try {
Customsearch.Cse.List list=customsearch.cse().list(keyword);
list.setKey(GOOGLE_API_KEY);
list.setCx(SEARCH_ENGINE_ID);
Search results=list.execute();
resultList=results.getItems();
}
catch ( Exception e) {
e.printStackTrace();
}
return resultList;
}
This method returns List of Result Objects, so you can iterate through it
List<Result> results = new ArrayList<>();
try {
results = search(QUERY);
} catch (Exception e) {
e.printStackTrace();
}
for(Result result : results){
System.out.println(result.getDisplayLink());
System.out.println(result.getTitle());
// all attributes
System.out.println(result.toString());
}
I use gradle dependencies
dependencies {
compile 'com.google.apis:google-api-services-customsearch:v1-rev57-1.23.0'
}
Don't forget to define your own GOOGLE_API_KEY, SEARCH_ENGINE_ID (cx), QUERY and HTTP_REQUEST_TIMEOUT (ie private static final int HTTP_REQUEST_TIMEOUT = 3 * 600000;)
my web application offers a download. Javascript creats at the click the url (it depends on the user input) and the browser should open it, so that the page isn't reloaded.
For that, I think I have to alternatives:
// Alt1:
window.open(pathToFile);
// Alt2:
var downloadFrame = document.getElementById('downloads');
if (downloadFrame === null) {
downloadFrame = document.createElement('iframe');
downloadFrame.id = 'downloads';
downloadFrame.style.display = 'none';
document.body.appendChild(downloadFrame);
}
downloadFrame.src = pathToFile;
Both works under Firefox. Problem with open new window method: If the creation of the file at the server needs more time, the new empty tab will be closed late.
Problem with iframe: If there is an error at the server, no feedback is given.
I think at firefox the iframe is the better solution. But the web application must run with an JavaFX WebView, too. JavaFX haven't a download feature, I have to write it. One possible way is to listen on the location property:
final WebView webView = new WebView();
webView.getEngine().locationProperty().addListener(new ChangeListener<String>() {
#Override public void changed(ObservableValue<? extends String> observableValue, String oldLoc, String newLoc) {
if (newLoc.cotains("/download")) {
FileChooser chooser = new FileChooser();
chooser.setTitle("Save " + newLoc);
File saveFile = chooser.showSaveDialog(webView.getEngine().getScene().getWindow());
if (saveFile != null) {
BufferedInputStream is = null;
BufferedOutputStream os = null;
try {
is = new BufferedInputStream(new URL(newLoc).openStream());
os = new BufferedOutputStream(new FileOutputStream(saveFile));
while ((readBytes = is.read()) != -1) {
os.write(b);
}
} finally {
try { if (is != null) is.close(); } catch (IOException e) {}
try { if (os != null) os.close(); } catch (IOException e) {}
}
}
}
}
}
There are some problems:
The download start depends on a part of the url, because JafaFX supports no access to the http headers (that is bearable)
If the user starts the download with the same url two times, only the first download works (the change event only fires, if the url is new). I can crate unique urls (with #1, #2 and so on at the end). But this is ugly.
Only the "window.open(pathToFile);" method works. Loading an iframe don't fire the change location event of the website. That is expectable but I haven't found the right Listener.
Can someone help me to solve 2. or 3.?
Thank you!
PS: Sorry for my bad english.
edit:
For 2. I found a way. I don't know if it is a good one, if it is performant, if the new webview is deleted or is in the cache after download, ....
And the user don't get an feedback, when some a problem is raised:
webView.getEngine().setCreatePopupHandler(new Callback<PopupFeatures, WebEngine>() {
#Override public WebEngine call(PopupFeatures config) {
final WebView downloader = new WebView();
downloader.getEngine().locationProperty().addListener(/* The Listener from above */);
return downloader.getEngine();
}
}
I think you may just need to use copyURLtoFile to get the file...call that when the location changes or just call that using a registered java class. Something like this:
org.apache.commons.io.FileUtils.copyURLToFile(new URL(newLoc), new File(System.getProperty("user.home")+filename));
Using copyURLToFile the current page doesn't have to serve the file. I think registering the class is probably the easiest way to go... something like this:
PHP Code:
Download $filename
Java (in-line class in your javafx class/window... in this case my javafx window is inside of a jframe):
public class JavaApp {
JFrame cloudFrameREF;
JavaApp(JFrame cloudFrameREF)
{
this.cloudFrameREF = cloudFrameREF;
}
public void getfile(String filename) {
String newLoc = "http://your_web_site.com/send_file.php?filename=" + filename;
org.apache.commons.io.FileUtils.copyURLToFile(new URL(newLoc), new File(System.getProperty("user.home")+filename));
}
}
This part would go in the main javafx class:
Platform.runLater(new Runnable() {
#Override
public void run() {
browser2 = new WebView();
webEngine = browser2.getEngine();
appREF = new JavaApp(cloudFrame);
webEngine.getLoadWorker().stateProperty().addListener(
new ChangeListener<State>() {
#Override public void changed(ObservableValue ov, State oldState, State newState) {
if (newState == Worker.State.SUCCEEDED) {
JSObject win
= (JSObject) webEngine.executeScript("window");
// this next line registers the JavaApp class with the page... you can then call it from javascript using "app.method_name".
win.setMember("app", appREF);
}
}
});
You may not need the frame reference... I was hacking some of my own code to test this out and the ref was useful for other things...
I want to be able to detect when a user signs on to my application using passive acs, so that I can add them to my database if this is the first time using my app. Right now I am subscribing to WSFederationAuthenticationModule.SignedIn but I feel I'm missing something. Mainly I'm not sure the best place to subscribe to the event, I got it to work inside PostAuthenticateRequest but its a bit hacky. Any suggestions?
this code is from global.asax
public override void Init()
{
base.Init();
PostAuthenticateRequest += (s, e) =>
{
try
{
FederatedAuthentication.WSFederationAuthenticationModule.SignedIn -= SignedIn;
}
finally
{
FederatedAuthentication.WSFederationAuthenticationModule.SignedIn += SignedIn;
}
};
}
private void SignedIn(object sender, EventArgs e)
{
//do something
}
EDIT:
For now I'm going to use a flag variable to make sure I only subscribe once to SignedIn. Unless someone has any other suggestions that is :) thanks for the help Sandrino. Here is what I have at the moment.
private static bool isFirstRequest = true;
public override void Init()
{
base.Init();
PostAuthenticateRequest += (s, e) => {
if (isFirstRequest)
{
FederatedAuthentication
.WSFederationAuthenticationModule.SignedIn += SignedIn;
isFirstRequest = false;
}
};
}
private void SignedIn(object sender, EventArgs e)
{
//do something
}
EDIT:
A little more info. This problem happens if I'm using the azure emulator, it probably happens when deployed as well but I haven't tried that. I have tested if I am just not able to debug by trying to write to a text file and no text file was created.
Why do you subscribe to the SignedIn event each time the PostAuthenticateRequest event is raised? You can simple subscribe to it when the application starts (in the Global.asax) and it will be raised for each user that signed in:
public class MvcApplication : System.Web.HttpApplication
{
...
protected void Application_Start()
{
...
FederatedAuthentication.ServiceConfigurationCreated += (s, e) =>
{
FederatedAuthentication.WSFederationAuthenticationModule.SignedIn += new EventHandler(OnUserSignedIn);
};
}
private void OnUserSignedIn(object sender, EventArgs e)
{
// Custom logic here.
}
}
The SignedIn event is the best way to detect a user sign in before the application continues. Take a look at the following diagram. Before redirecting back to a page, the SignedIn event is raised to allow you to detect an user sign in:
Reference: http://msdn.microsoft.com/en-us/library/ee517293.aspx
I created a class that derives from ClaimsAuthenticationManager. There is only one method that you have to override, which is
public virtual IClaimsPrincipal Authenticate(string resourceName, IClaimsPrincipal incomingPrincipal);
In my app, I use this method to check if the user, who has successfully authenticated, is really a user of my app (i.e. they exist in my database). If not, I direct them to a signup page.
My class looks something like this:
public override IClaimsPrincipal Authenticate(string resourceName, IClaimsPrincipal incomingPrincipal)
{
if (incomingPrincipal.Identity.IsAuthenticated)
{
var identity = incomingPrincipal.Identity as IClaimsIdentity;
User user = null;
// Get name identifier and identity provider
var nameIdentifierClaim = identity.Claims.SingleOrDefault(c => c.ClaimType.Equals(ClaimTypes.NameIdentifier, StringComparison.OrdinalIgnoreCase));
var identityProviderClaim = identity.Claims.SingleOrDefault(c => c.ClaimType.Equals(CustomClaimTypes.IdentityProviderClaimType, StringComparison.OrdinalIgnoreCase));
if (nameIdentifierClaim == null || identityProviderClaim == null)
{
throw new AuthenticationErrorException("Invalid claims", "The claims provided by your Identity Provider are invalid. Please contact your administrator.");
}
try
{
//checking the database here...
using (var context = new CloudContext())
{
user = (from u in context.Users
where u.IdentityProvider == identityProviderClaim.Value &&
u.NameIdentifier == nameIdentifierClaim.Value &&
!u.Account.PendingDelete
select u).FirstOrDefault();
}
}
catch (System.Data.DataException ex)
{
Console.WriteLine(ex.Message);
if (ex.InnerException != null)
Console.WriteLine(ex.InnerException);
throw;
}
}
return incomingPrincipal;
}
Then, in your web.config, you add a section to the <microsoft.identitymodel> area, as so:
<claimsAuthenticationManager type="CloudAnalyzer.UI.Security.CloudAnalyzerClaimsAuthenticationManager" />
I learned this trick from the sample app located here: Windows Azure Marketplace. Even if you're not going to publish in the Window Azure Marketplace it's a good sample with some helpful code snippets you can use for ACS integration.