I want to obtain documents (products in this case) using find() with two filters, the first one is state = true and the second one is if the product belong to a category received in the request.
I'm making the filter this way
let categories = req.body;
Product.find({ state: true, "category": {$in : categories} }...
This filter brings me the products that belong to a certain category but don't respect if the product has a state = true or false.
What I'm doing wrong?
Thx.
For example:
{
"_id" : ObjectId("601b9ef73faa662db0b29204"),
"state" : true,
"code" : "APE700JAGE",
"category" : ObjectId("601b98853faa662db0b291e5"),
}
{
"_id" : ObjectId("601b9ef73faa662db0b29204"),
"state" : false,
"code" : "PRU123FAKK",
"category" : ObjectId("601b98853faa662db0b291e5"),
}
Request:
{
categories: [ '601b98853faa662db0b291e5' ]
}
There are few fixes:
you are passing whole req.body in categories variable, you just need to pass only req.body.categories
let categories = req.body.categories;
the categories are array of string ids you need to convert it to object id using mongoose.Types.ObjectId because category is object id in document
let categories = req.body.categories.map(c => mongoose.Types.ObjectId(c));
Related
I am connecting to the Yelp API using the RapidAPI module in Nodejs. I am able to request a token, connect, and request data, retrieve that data, and insert the relevant information for each result it into mongodb. Here's where it gets complicated...
Let's say I make a Yelp API request and search for bars. I get a list of bars and insert them into the database. Let's say one of these in the list is "Joe's Bar & Grill". One of the fields in my mongodb is "type" and it's an array. So now, this particular document will look something like this:
{
id: 'joes-bar-and-grill',
name: 'Joe\'s Bar & Grill',
type: ['bar']
}
But then I run another request on the Yelp API on "restaurants", and in this list "Joe's Bar & Grill" shows up again. Instead of inserting a new duplicate document into mongodb, I'd like the existing document to end up looking like this:
{
id: 'joes-bar-and-grill',
name: 'Joe\'s Bar & Grill',
type: ['bar', 'restaurant']
}
In addition to this, let's say I run another request again for "bars", and "Joe's Bar & Grill" comes up again. I don't want it to automatically insert "bar" into the type array again, if "bar" already exists in its array.
I've tried findOneAndUpdate with upsert: true and a $push of new data into the array, but I cannot get it to work at all. Does anyone have any ideas?
You can use findOneAndUpdate, combined with $addToSet (to make sure that an entry in the array only exists once) and $each (to allow passing arrays to $addToSet):
Bar.findOneAndUpdate({ id : 'joes-bar-and-grill' }, {
id : 'joes-bar-and-grill',
name : 'Joe\'s Bar & Grill',
$addToSet : { type : { $each : [ 'restaurant' ] } }
}, { upsert : true })
EDIT: now that you posted your entire code, the problem becomes more obvious.
For one, I'm not sure if the third and fourth arguments that you're passing to Location.update() make sense. As far as I know, the third should be an option object, and the fourth an async function.
Secondly, it looks like you're just ignoring any update errors.
And lastly, this isn't going to work:
for (var i = 0; i < payload.businesses.length; i++) { Location.update(...) }
Because Location.update() is asynchronous, the i variable will get clobbered (you should browse around on SO to find the explanation for that; for example, see this question).
You're going to need a library that will provide you with better async support, and preferably one that will also help limiting the number of update queries.
Once such library is async, and using it, your code would become something like this:
const async = require('async');
...
async.eachLimit(payload.businesses, 5, function(business, callback) {
Location.update({ yelpID : business.id }, {
name : business.name,
latitude : business.location.latitude,
longitude : business.location.longitude,
address1 : business.location.address1,
address2 : business.location.address2,
address3 : business.location.address3,
city : business.location.city,
state : business.location.state,
zip_code : business.location.zip_code,
country : business.location.country,
timezone : 'CST'
$addToSet : { type : 'bar' }
}, { upsert : true }, callback);
}, function(err) {
if (err) {
console.error(err);
} else {
console.log('All documents inserted');
}
});
You may use $addToSet operator
The $addToSet operator adds a value to an array unless the value is
already present, in which case $addToSet does nothing to that array.
$addToSet only ensures that there are no duplicate items added to the
set and does not affect existing duplicate elements. $addToSet does
not guarantee a particular ordering of elements in the modified set.
If the field is absent in the document to update, $addToSet creates
the array field with the specified value as its element.
If the field is not an array, the operation will fail.
The below solution assumes that on each update, you receive a single type and not an array. If the input document is an array itself, you may use robertklep's solution with $each operator
db.mycoll.update(
{ "id" : "joes-bar-and-grill" },
{
$set:{
name : 'Joe\'s Bar & Grill',
},
$addToSet : { type : 'restaurant' }
},
true, false);
I have also used $set operator.
The $set operator replaces the value of a field with the specified
value.
The $set operator expression has the following form:
{ $set: { field1: value1, ... } }
Here is the mongo shell output to explain it further :
> db.mycoll.find({ "id" : "joes-bar-and-grill" });
// NO RESULT
> db.mycoll.update(
... { "id" : "joes-bar-and-grill" },
... {
... $set:{
... name : 'Joe\'s Bar & Grill',
... },
... $addToSet : { type : 'restaurant' }
... },
... true, false);
WriteResult({
"nMatched" : 0,
"nUpserted" : 1,
"nModified" : 0,
"_id" : ObjectId("58e719b4d543c5e30d615d59")
})
// INSERTED A NEW DOCUMENT AS IT DOES NOT EXIST
> db.mycoll.find({ "id" : "joes-bar-and-grill" }); // FINDING THE OBJECT
{ "_id" : ObjectId("58e719b4d543c5e30d615d59"), "id" : "joes-bar-and-grill", "name" : "Joe's Bar & Grill", "type" : [ "restaurant" ] }
> db.mycoll.update(
... { "id" : "joes-bar-and-grill" },
... {
... $set:{
... name : 'Joe\'s Bar & Grill',
... },
... $addToSet : { type : 'bar' }
... },
... true, false);
WriteResult({ "nMatched" : 1, "nUpserted" : 0, "nModified" : 1 })
// UPDATING THE DOCUMENT WITH NEW TYPE : "bar"
> db.mycoll.findOne({ "id" : "joes-bar-and-grill" });
{
"_id" : ObjectId("58e719b4d543c5e30d615d59"),
"id" : "joes-bar-and-grill",
"name" : "Joe's Bar & Grill",
"type" : [
"restaurant",
"bar"
]
}
If I $pull the last member out of the members array, can I then remove that room? Given the document below, I would want rooms to end up being an empty array.
var query = {game:'/donut_fun', 'rooms.roomname': 'Joey\'s Room'};
var update = {$pull: {'rooms.$.members': player}};
GamesModel.findOneAndUpdate(query, update, function(err, doc){...
And here's my resulting document after that update. Note that the room no longer has any members so I want rooms to just be an empty array now. I don't care about Joey's Room anymore.
{
"_id" : ObjectId("588e4d64c23324935a061123"),
"game" : "/donut_fun",
"__v" : 0,
"rooms" : [
{
"members" : [ ],
"timestamp" : 1485720932863,
"roomname" : "Joey's Room"
}
]
}
I am trying to count the number of models in a collection based on a property:
I have an upvote model, that has: post (objectId) and a few other properties.
First, is this good design? Posts could get many upvotes, so I didn’t want to store them in the Post model.
Regardless, I want to count the number of upvotes on posts with a specific property with the following and it’s not working. Any suggestions?
upvote.count({‘post.specialProperty’: mongoose.Types.ObjectId(“id”), function (err, count) {
console.log(count);
});
Post Schema Design
In regards to design. I would design the posts collection for documents to be structured as such:
{
"_id" : ObjectId(),
"proprerty1" : "some value",
"property2" : "some value",
"voteCount" : 1,
"votes": [
{
"voter": ObjectId()// voter Id,
other properties...
}
]
}
You will have an array that will hold objects that can contain info such as voter id and other properties.
Updating
When a posts is updated you could simply increment or decrement the voteCountaccordingly. You can increment by 1 like this:
db.posts.update(
{"_id" : postId},
{
$inc: { voteCount: 1},
$push : {
"votes" : {"voter":ObjectId, "otherproperty": "some value"}
}
}
)
The $inc modifier can be used to change the value for an existing key or to create a new key if it does not already exist. Its very useful for updating votes.
Totaling votes of particular Post Criteria
If you want to total the amount for posts fitting a certain criteria, you must use the Aggregation Framework.
You can get the total like this:
db.posts.aggregate(
[
{
$match : {property1: "some value"}
},
{
$group : {
_id : null,
totalNumberOfVotes : {$sum : "$voteCount" }
}
}
]
)
consider the following records:
user record
{
"_id" : ObjectId("5234ccb7687ea597eabee677"),
"class" : [
{ "_id" : ObjectId("5234ccb7687ea597eabee671", "num" : 10, "color" : "blue" },
{ "_id" : ObjectId("5234ccb7687ea597eabee672", "num" : 100, "color" : "blue" }
]
}
this user has two class sub records, now I need a query that finds all users that have class property where "class._id" has a value of at least one users "class._id"
here is a more detail example:
suppose there is four user:
A:{_id:432645624232345,class:[{_id:123,name:'foo'}]}
B:{_id:432645624232555,class:[{_id:555,name:'foo'},{_id:123,name:'foo'}]}
C:{_id:432645344232345,class:[{_id:555,name:'foo'},{_id:111,name:'www'}]}
D:{_id:432644444232345,class:[{_id:222,name:'sss'},{_id:555,name:'www'},{_id:123,name:'foo'}]}
now if B login , I need to query all the user whose class subdocument contains at least one document which's _id==555 or _id==123 (555 and 123 come from B user), in this case the query result should be:
A:{_id:432645624232345,class:[{_id:123,name:'foo'}]} // match _id=123
B:{_id:432645624232555,class:[{_id:555,name:'foo'},{_id:123,name:'foo'}]} //match _id=123 and _id=555
C:{_id:432645344232345,class:[{_id:555,name:'foo'},{_id:111,name:'www'}]} //match _id=555
D:{_id:432644444232345,class:[{_id:222,name:'sss'},{_id:555,name:'www'},{_id:123,name:'foo'}]} ///match _id=123 and _id=555
which is all the user.
so far i get this:
{"class._id" : { $in : ["5234ccb7687ea597eabee671", "5234ccb7687ea597eabee672"] } }
but when different user login the class._id query condition is different. So is there any operator to do this
{"class._id" : { $in : req.user.class } }
hope I made myself clear.
In order to achieve what you want, first you must isolate the class _ids in an array, and then use it in the query argument.
var classIds = [];
var i = 0;
while (i < req.user.class.length) {
classIds.push(req.user.class[i]._id);
i++;
}
After that you can use classIds array in the query:
{"class._id" : { $in : classIds } }
The following query condition would give you all the users that have at least one class with id equal to any of the elements in the given array:
{"class._id" : { $in : ["5234ccb7687ea597eabee671", "5234ccb7687ea597eabee672"] } }
In the array for the $in clause you may provide any id's you needed , comma separated.
In addition, if you needed such, the below query condition should check for existence of nested document within "class" property that has a property "_id" :
{ "class._id" : { $exists : true } }
Both conditions should work no matter if "class._id" is a single-valued property or an array (mongo supports that).
I am looking for a CouchDB equivalent to "SQL joins".
In my example there are CouchDB documents that are list elements:
{ "type" : "el", "id" : "1", "content" : "first" }
{ "type" : "el", "id" : "2", "content" : "second" }
{ "type" : "el", "id" : "3", "content" : "third" }
There is one document that defines the list:
{ "type" : "list", "elements" : ["2","1"] , "id" : "abc123" }
As you can see the third element was deleted, it is no longer part of the list. So it must not be part of the result. Now I want a view that returns the content elements including the right order.
The result could be:
{ "content" : ["second", "first"] }
In this case the order of the elements is already as it should be. Another possible result:
{ "content" : [{"content" : "first", "order" : 2},{"content" : "second", "order" : 1}] }
I started writing the map function:
map = function (doc) {
if (doc.type === 'el') {
emit(doc.id, {"content" : doc.content}); //emit the id and the content
exit;
}
if (doc.type === 'list') {
for ( var i=0, l=doc.elements.length; i<l; ++i ){
emit(doc.elements[i], { "order" : i }); //emit the id and the order
}
}
}
This is as far as I can get. Can you correct my mistakes and write a reduce function? Remember that the third document must not be part of the result.
Of course you can write a different map function also. But the structure of the documents (one definig element document and an entry document for each entry) cannot be changed.
EDIT: Do not miss JasonSmith's comment to his answer, where he describes how to do this shorter.
Thank you! This is a great example to show off CouchDB 0.11's new
features!
You must use the fetch-related-data feature to reference documents
in the view. Optionally, for more convenient JSON, use a _list function to
clean up the results. See Couchio's writeup on "JOIN"s for details.
Here is the plan:
Firstly, you have a uniqueness contstraint on your el documents. If two of
them have id=2, that's a problem. It is necessary to use
the _id field instead if id. CouchDB will guarantee uniqueness, but also,
the rest of this plan requires _id in order to fetch documents by ID.
{ "type" : "el", "_id" : "1", "content" : "first" }
{ "type" : "el", "_id" : "2", "content" : "second" }
{ "type" : "el", "_id" : "3", "content" : "third" }
If changing the documents to use _id is absolutely impossible, you can
create a simple view to emit(doc.id, doc) and then re-insert that into a
temporary database. This converts id to _id but adds some complexity.
The view emits {"_id": content_id} data keyed on
[list_id, sort_number], to "clump" the lists with their content.
function(doc) {
if(doc.type == 'list') {
for (var i in doc.elements) {
// Link to the el document's id.
var id = doc.elements[i];
emit([doc.id, i], {'_id': id});
}
}
}
Now there is a simple list of el documents, in the correct order. You can
use startkey and endkey if you want to see only a particular list.
curl localhost:5984/x/_design/myapp/_view/els
{"total_rows":2,"offset":0,"rows":[
{"id":"036f3614aeee05344cdfb66fa1002db6","key":["abc123","0"],"value":{"_id":"2"}},
{"id":"036f3614aeee05344cdfb66fa1002db6","key":["abc123","1"],"value":{"_id":"1"}}
]}
To get the el content, query with include_docs=true. Through the magic of
_id, the el documents will load.
curl localhost:5984/x/_design/myapp/_view/els?include_docs=true
{"total_rows":2,"offset":0,"rows":[
{"id":"036f3614aeee05344cdfb66fa1002db6","key":["abc123","0"],"value":{"_id":"2"},"doc":{"_id":"2","_rev":"1-4530dc6946d78f1e97f56568de5a85d9","type":"el","content":"second"}},
{"id":"036f3614aeee05344cdfb66fa1002db6","key":["abc123","1"],"value":{"_id":"1"},"doc":{"_id":"1","_rev":"1-852badd683f22ad4705ed9fcdea5b814","type":"el","content":"first"}}
]}
Notice, this is already all the information you need. If your client is
flexible, you can parse the information out of this JSON. The next optional
step simply reformats it to match what you need.
Use a _list function, which simply reformats the view output. People use them to output XML or HTML however we will make
the JSON more convenient.
function(head, req) {
var headers = {'Content-Type': 'application/json'};
var result;
if(req.query.include_docs != 'true') {
start({'code': 400, headers: headers});
result = {'error': 'I require include_docs=true'};
} else {
start({'headers': headers});
result = {'content': []};
while(row = getRow()) {
result.content.push(row.doc.content);
}
}
send(JSON.stringify(result));
}
The results match. Of course in production you will need startkey and endkey to specify the list you want.
curl -g 'localhost:5984/x/_design/myapp/_list/pretty/els?include_docs=true&startkey=["abc123",""]&endkey=["abc123",{}]'
{"content":["second","first"]}