consider the following records:
user record
{
"_id" : ObjectId("5234ccb7687ea597eabee677"),
"class" : [
{ "_id" : ObjectId("5234ccb7687ea597eabee671", "num" : 10, "color" : "blue" },
{ "_id" : ObjectId("5234ccb7687ea597eabee672", "num" : 100, "color" : "blue" }
]
}
this user has two class sub records, now I need a query that finds all users that have class property where "class._id" has a value of at least one users "class._id"
here is a more detail example:
suppose there is four user:
A:{_id:432645624232345,class:[{_id:123,name:'foo'}]}
B:{_id:432645624232555,class:[{_id:555,name:'foo'},{_id:123,name:'foo'}]}
C:{_id:432645344232345,class:[{_id:555,name:'foo'},{_id:111,name:'www'}]}
D:{_id:432644444232345,class:[{_id:222,name:'sss'},{_id:555,name:'www'},{_id:123,name:'foo'}]}
now if B login , I need to query all the user whose class subdocument contains at least one document which's _id==555 or _id==123 (555 and 123 come from B user), in this case the query result should be:
A:{_id:432645624232345,class:[{_id:123,name:'foo'}]} // match _id=123
B:{_id:432645624232555,class:[{_id:555,name:'foo'},{_id:123,name:'foo'}]} //match _id=123 and _id=555
C:{_id:432645344232345,class:[{_id:555,name:'foo'},{_id:111,name:'www'}]} //match _id=555
D:{_id:432644444232345,class:[{_id:222,name:'sss'},{_id:555,name:'www'},{_id:123,name:'foo'}]} ///match _id=123 and _id=555
which is all the user.
so far i get this:
{"class._id" : { $in : ["5234ccb7687ea597eabee671", "5234ccb7687ea597eabee672"] } }
but when different user login the class._id query condition is different. So is there any operator to do this
{"class._id" : { $in : req.user.class } }
hope I made myself clear.
In order to achieve what you want, first you must isolate the class _ids in an array, and then use it in the query argument.
var classIds = [];
var i = 0;
while (i < req.user.class.length) {
classIds.push(req.user.class[i]._id);
i++;
}
After that you can use classIds array in the query:
{"class._id" : { $in : classIds } }
The following query condition would give you all the users that have at least one class with id equal to any of the elements in the given array:
{"class._id" : { $in : ["5234ccb7687ea597eabee671", "5234ccb7687ea597eabee672"] } }
In the array for the $in clause you may provide any id's you needed , comma separated.
In addition, if you needed such, the below query condition should check for existence of nested document within "class" property that has a property "_id" :
{ "class._id" : { $exists : true } }
Both conditions should work no matter if "class._id" is a single-valued property or an array (mongo supports that).
Related
I want to obtain documents (products in this case) using find() with two filters, the first one is state = true and the second one is if the product belong to a category received in the request.
I'm making the filter this way
let categories = req.body;
Product.find({ state: true, "category": {$in : categories} }...
This filter brings me the products that belong to a certain category but don't respect if the product has a state = true or false.
What I'm doing wrong?
Thx.
For example:
{
"_id" : ObjectId("601b9ef73faa662db0b29204"),
"state" : true,
"code" : "APE700JAGE",
"category" : ObjectId("601b98853faa662db0b291e5"),
}
{
"_id" : ObjectId("601b9ef73faa662db0b29204"),
"state" : false,
"code" : "PRU123FAKK",
"category" : ObjectId("601b98853faa662db0b291e5"),
}
Request:
{
categories: [ '601b98853faa662db0b291e5' ]
}
There are few fixes:
you are passing whole req.body in categories variable, you just need to pass only req.body.categories
let categories = req.body.categories;
the categories are array of string ids you need to convert it to object id using mongoose.Types.ObjectId because category is object id in document
let categories = req.body.categories.map(c => mongoose.Types.ObjectId(c));
I'm fairly new to mongo and while I can manage to do most basic operations with the $in, $or, $all, ect I can't make what I want to work.
I'll basically put a simple form of my problem. Part of my documents are list of number, eg :
{_id:1,list:[1,4,3,2]}
{_id:2,list:[1]}
{_id:3,list:[1,3,4,6]}
I want a query that given a list(lets call it L), would return me every document where their entire list is in L
for example with the given list L = [1,2,3,4,5] I want document with _id 1 and 2 to be returned. 3 musn't be returned since 6 isn't in L.
"$in" doesn't work because it would also return _id 3 and "$all" doesn't work either because it would only return _id 1.
I then thought of "$where" but I can't seem to find how to bound an external variable to the js code. What I call by that is that for example :
var L = [1,2,3,4,5];
db.collections('myCollection').find({$where:function(l){
// return something with the list "l" there
}.bind(null,list)})
I tried to bind list to the function as showed up there but to no avail ...
I'd glady appreciate any hint concerning this issue, thanks.
There's a related question Check if every element in array matches condition with an answer with a nice approach for this scenario. It refers to an array of embedded documents but can be adapted for your scenario like this:
db.list.find({
"list" : { $not : { $elemMatch : { $nin : [1,2,3,4,5] } } },
"list.0" : { $exists: true }
})
ie. the list must not have any element that is not in [1,2,3,4,5] and the list must exist with at least 1 element (assuming that's also a requirement).
You could try using the aggregation framework for this where you can make use of the set operators to achieve this, in particular you would need the $setIsSubset operator which returns true if all elements of the first set appear in the second set, including when the first set equals the second set; i.e. not a strict subset.
For example:
var L = [1,2,3,4,5];
db.collections('myCollection').aggregate([
{
"$project": {
"list": 1,
"isSubsetofL": {
"$setIsSubset": [ "$list", L ]
}
}
},
{
"$match": {
"isSubsetofL": true
}
}
])
Result:
/* 0 */
{
"result" : [
{
"_id" : 1,
"list" : [
1,
4,
3,
2
],
"isSubsetofL" : true
},
{
"_id" : 2,
"list" : [
1
],
"isSubsetofL" : true
}
],
"ok" : 1
}
I have an array and it contains duplicate values in BOTH the ID's, is there a way to remove one of the duplicate array item?
userName: "abc",
_id: 10239201141,
rounds:
[{
"roundId": "foo",
"money": "123
},// Keep one of these
{// Keep one of these
"roundId": "foo",
"money": "123
},
{
"roundId": "foo",
"money": "321 // Not a duplicate.
}]
I'd like to remove one of the first two, and keep the third because the id and money are not duplicated in the array.
Thank you in advance!
Edit I found:
db.users.ensureIndex({'rounds.roundId':1, 'rounds.money':1}, {unique:true, dropDups:true})
This doesn't help me. Can someone help me? I spent hours trying to figure this out.
The thing is, I ran my node.js website on two machines so it was pushing the same data twice. Knowing this, the duplicate data should be 1 index away. I made a simple for loop that can detect if there is duplicate data in my situation, how could I implement this with mongodb so it removes an array object AT that array index?
for (var i in data){
var tempRounds = data[i]['rounds'];
for (var ii in data[i]['rounds']){
var currentArrayItem = data[i]['rounds'][ii - 1];
if (tempRounds[ii - 1]) {
if (currentArrayItem.roundId == tempRounds[ii - 1].roundId && currentArrayItem.money == tempRounds[ii - 1].money) {
console.log("Found a match");
}
}
}
}
Use an aggregation framework to compute a deduplicated version of each document:
db.test.aggregate([
{ "$unwind" : "$stats" },
{ "$group" : { "_id" : "$_id", "stats" : { "$addToSet" : "$stats" } } }, // use $first to add in other document fields here
{ "$out" : "some_other_collection_name" }
])
Use $out to put the results in another collection, since aggregation cannot update documents. You can use db.collection.renameCollection with dropTarget to replace the old collection with the new deduplicated one. Be sure you're doing the right thing before you scrap the old data, though.
Warnings:
1: This does not preserve the order of elements in the stats array. If you need to preserve order, you will have retrieve each document from the database, manually deduplicate the array client-side, then update the document in the database.
2: The following two objects won't be considered duplicates of each other:
{ "id" : "foo", "price" : 123 }
{ "price" : 123, "id" : foo" }
If you think you have mixed key orders, use a $project to enforce a key order between the $unwind stage and the $group stage:
{ "$project" : { "stats" : { "id_" : "$stats.id", "price_" : "$stats.price" } } }
Make sure to change id -> id_ and price -> price_ in the rest of the pipeline and rename them back to id and price at the end, or rename them in another $project after the swap. I discovered that, if you do not give different names to the fields in the project, it doesn't reorder them, even though key order is meaningful in an object in MongoDB:
> db.test.drop()
> db.test.insert({ "a" : { "x" : 1, "y" : 2 } })
> db.test.aggregate([
{ "$project" : { "_id" : 0, "a" : { "y" : "$a.y", "x" : "$a.x" } } }
])
{ "a" : { "x" : 1, "y" : 2 } }
> db.test.aggregate([
{ "$project" : { "_id" : 0, "a" : { "y_" : "$a.y", "x_" : "$a.x" } } }
])
{ "a" : { "y_" : 2, "x_" : 1 } }
Since the key order is meaningful, I'd consider this a bug, but it's easy to work around.
i have collection of objects inside an invitation, having hard time to filter particular object and trigger it's boolean field.
Document:
"Invitation" : [
{
"__v" : 0,
"userID" : ObjectId("54afaabd88694dc019d3b628"),//ObjectId of personA
"__t" : "USER",
"_id" : ObjectId("54b5022b583973580c706784"),
"Accepted" : false
},
{
"__v" : 0,
"userID" : ObjectId("54af6ce091324fd00f97a15f"),//ObjectId of personB
"__t" : "USER",
"_id" : ObjectId("54bde39cdd55dd9016271f14"),
"Accepted" : false
}
]
here i have only two objects inside Invitation array,it can be more than two.
Let's say personA and personB send me Invitation, so two different invitation objects are inserted into database having different fields, with objectId of both persons(userID in above document), now if i accept only invitation of personA, it should trigger accepted field of personA object only, here is what i tried so far, but not working as per expectation.
Controller:
User.find({_id: req.user._id},'Invitation',function(err,docs) {
if (err) {
console.log(err);
}
var results = [];
async.each(docs,function(doc,callback) {
async.each(doc.Invitation,function(invite,callback) {
User.findOneAndUpdate(
{'_id': doc._id, 'Invitation._id': invite._id},
{'$set': {'Invitation.$.Accepted': !invite.Accepted}},
function(err,doc) {
results.push(doc);
callback(err);
}
);
},callback);
},function(err) {
if (err)
console.log(err);
console.log('end'+results);
});
});
finally i am looking for a query which can be used to filter a single element or object, like if i accept invitation of personA then Accepted field of personA object should be set to true.
i would be really helpful if some logic is provided.
Thank you
Not a very clear question. But it seems all you really need to do here is just match the only sub-document you want to update in the first place:
User.find(
{
"_id": "req.user._id",
"Invitation._id": personA.id
},
{ "Invitation.$": 1 },
function(err,docs) {
// and continue
}
);
This is the form of the positional $ operator in a "projection" context. Where only the "singular" matched element is returned.
Once you have a "singular" result, then all the other code works as designed.
I should know after all because I wrote it for you. Not that you are paying any decent respect to that.
Update on Aggregate in Mongodb
Toggle boolean value of subdocuments
Or personA.userID or whatever makes it work.
Just use the unique identifier for the "user" where you expect that to match the query conditions.
You can do this:
db.user.update({"invitation.userID": 1}, {"$set" : {"invitation.$.Accepted" : true}});
Replacing the value 1 with the user ID you want to update.
The code is in the syntax of MongoShell, simply convert to driver syntax you are using
The operator used was the $. According to the documentation: The positional $ operator identifies an element in an array to update without explicitly specifying the position of the element in the array. To project, or return, an array element from a read operation, see the $ projection operator.
For more details see: http://docs.mongodb.org/manual/reference/operator/update/positional/
I am looking for a CouchDB equivalent to "SQL joins".
In my example there are CouchDB documents that are list elements:
{ "type" : "el", "id" : "1", "content" : "first" }
{ "type" : "el", "id" : "2", "content" : "second" }
{ "type" : "el", "id" : "3", "content" : "third" }
There is one document that defines the list:
{ "type" : "list", "elements" : ["2","1"] , "id" : "abc123" }
As you can see the third element was deleted, it is no longer part of the list. So it must not be part of the result. Now I want a view that returns the content elements including the right order.
The result could be:
{ "content" : ["second", "first"] }
In this case the order of the elements is already as it should be. Another possible result:
{ "content" : [{"content" : "first", "order" : 2},{"content" : "second", "order" : 1}] }
I started writing the map function:
map = function (doc) {
if (doc.type === 'el') {
emit(doc.id, {"content" : doc.content}); //emit the id and the content
exit;
}
if (doc.type === 'list') {
for ( var i=0, l=doc.elements.length; i<l; ++i ){
emit(doc.elements[i], { "order" : i }); //emit the id and the order
}
}
}
This is as far as I can get. Can you correct my mistakes and write a reduce function? Remember that the third document must not be part of the result.
Of course you can write a different map function also. But the structure of the documents (one definig element document and an entry document for each entry) cannot be changed.
EDIT: Do not miss JasonSmith's comment to his answer, where he describes how to do this shorter.
Thank you! This is a great example to show off CouchDB 0.11's new
features!
You must use the fetch-related-data feature to reference documents
in the view. Optionally, for more convenient JSON, use a _list function to
clean up the results. See Couchio's writeup on "JOIN"s for details.
Here is the plan:
Firstly, you have a uniqueness contstraint on your el documents. If two of
them have id=2, that's a problem. It is necessary to use
the _id field instead if id. CouchDB will guarantee uniqueness, but also,
the rest of this plan requires _id in order to fetch documents by ID.
{ "type" : "el", "_id" : "1", "content" : "first" }
{ "type" : "el", "_id" : "2", "content" : "second" }
{ "type" : "el", "_id" : "3", "content" : "third" }
If changing the documents to use _id is absolutely impossible, you can
create a simple view to emit(doc.id, doc) and then re-insert that into a
temporary database. This converts id to _id but adds some complexity.
The view emits {"_id": content_id} data keyed on
[list_id, sort_number], to "clump" the lists with their content.
function(doc) {
if(doc.type == 'list') {
for (var i in doc.elements) {
// Link to the el document's id.
var id = doc.elements[i];
emit([doc.id, i], {'_id': id});
}
}
}
Now there is a simple list of el documents, in the correct order. You can
use startkey and endkey if you want to see only a particular list.
curl localhost:5984/x/_design/myapp/_view/els
{"total_rows":2,"offset":0,"rows":[
{"id":"036f3614aeee05344cdfb66fa1002db6","key":["abc123","0"],"value":{"_id":"2"}},
{"id":"036f3614aeee05344cdfb66fa1002db6","key":["abc123","1"],"value":{"_id":"1"}}
]}
To get the el content, query with include_docs=true. Through the magic of
_id, the el documents will load.
curl localhost:5984/x/_design/myapp/_view/els?include_docs=true
{"total_rows":2,"offset":0,"rows":[
{"id":"036f3614aeee05344cdfb66fa1002db6","key":["abc123","0"],"value":{"_id":"2"},"doc":{"_id":"2","_rev":"1-4530dc6946d78f1e97f56568de5a85d9","type":"el","content":"second"}},
{"id":"036f3614aeee05344cdfb66fa1002db6","key":["abc123","1"],"value":{"_id":"1"},"doc":{"_id":"1","_rev":"1-852badd683f22ad4705ed9fcdea5b814","type":"el","content":"first"}}
]}
Notice, this is already all the information you need. If your client is
flexible, you can parse the information out of this JSON. The next optional
step simply reformats it to match what you need.
Use a _list function, which simply reformats the view output. People use them to output XML or HTML however we will make
the JSON more convenient.
function(head, req) {
var headers = {'Content-Type': 'application/json'};
var result;
if(req.query.include_docs != 'true') {
start({'code': 400, headers: headers});
result = {'error': 'I require include_docs=true'};
} else {
start({'headers': headers});
result = {'content': []};
while(row = getRow()) {
result.content.push(row.doc.content);
}
}
send(JSON.stringify(result));
}
The results match. Of course in production you will need startkey and endkey to specify the list you want.
curl -g 'localhost:5984/x/_design/myapp/_list/pretty/els?include_docs=true&startkey=["abc123",""]&endkey=["abc123",{}]'
{"content":["second","first"]}