Problem: I am working with 2 list. One called HYPHEN and one called CAS Number in columns A and B respectively.
Column C uses a formula that combines column A and B and sorts them such that if a hyphen is present in column A, this is inserted before the adjacent CAS number which is then inserted below and the sequence continues so that all hyphens and CAS numbers are included. I've attached an image to better explain this and the Formula to replicate this is given below.
A CAS number is a unique Identify for a material/chemical and usually is written as 000-00-0, however occasionally you get materials with CAS numbers of 0000-00-0 (or other variations).
For the most part column C is correct because all but one CAS numbers are in the usual format. However As highlighted in red 6132-04-3 is being converted to 1545801.
What I have tried:
I have realised that 6132-04-3 is being converted to 03/04/6132 so I'm pretty sure that this is being recognised as a date which is causing the problem. I have tried to format the cells to all be a text format, I have added a comma before the CAS number but nothing returns the desired value of 6132-04-3 and instead always returns 1545801.
To replicate the issue: Column A and B can have any data entered. To replicate the output of column C the formula is given below:
Formula for Column C:
=FILTERXML(""&SUBSTITUTE(TEXTJOIN(",",TRUE,A2:B26),",","")&"","//b")
(Formula provided by #Gary's Student on Stack Overflow)
Any thoughts on how to prevent the red CAS number being converted when it is sorted in Column C would be really appreciated.
This is a crude way to fix it by adding then removing an arbitrary character:
=MID(FILTERXML("<a><b>"&SUBSTITUTE(TEXTJOIN(",",TRUE,IF(A2:B26="","","x"&A2:B26)),",","</b><b>")&"</b></a>","//b"),2,99)
If you have the issue of some of your strings containing a comma, just use a different separator:
=MID(FILTERXML("<a><b>"&SUBSTITUTE(TEXTJOIN("|",TRUE,IF(A2:B26="","","x"&A2:B26)),"|","</b><b>")&"</b></a>","//b"),2,99)
Looks like you could use:
Formula in D2:
=SUBSTITUTE(FILTERXML("<t><s>'"&TEXTJOIN("</s><s>'",,A2:B10)&"</s></t>","//s"),"'","")
Or:
=MID(FILTERXML("<t><s>'"&TEXTJOIN("</s><s>'",,A2:B10)&"</s></t>","//s"),2,99)
I can suggest you this:
Go to Format Cells ---> Number ---> Custom ---> Type
In this "Type" field write this #000-00-0
Press "OK"
Related
I have an Excel file which includes lots of rows of information. I have actually a single problem which is I can't get the parent of each cells according to the information in the cell. It looks like this
In the image, you can see that A has no parent and its' children are A01 and AB and more and more like AC and AD. Is there any way for handling this issue with excel-formulas?
Assuming that your sample data is true to the format of all your data (there is either 2 numbers at the end of each parent or only an extra letter) then the following formula will work:
Given formula is set to look at data in cell A1, you will have to drag and auto fill the formula down for all rows.
=IF(OR(RIGHT(A1,1)="0",RIGHT(A1,1)="1",RIGHT(A1,1)="2",RIGHT(A1,1)="3",RIGHT(A1,1)="4",RIGHT(A1,1)="5",RIGHT(A1,1)="6",RIGHT(A1,1)="7",RIGHT(A1,1)="8",RIGHT(A1,1)="9")=TRUE,LEFT(A1,LEN(A1)-2),LEFT(A1,LEN(A1)-1))
It works by checking if the last character is a number (with this data excel treats it as text so we have to check for each number as if it is text), if it matches a number then show the parent minus the two right characters otherwise show the parent minus one character.
Okey I think I found the answer. Here is my formula
=IF(LEN(B2)=1;"NULL";IF(LEN(B2)=2;LEN(B2;0);IF(LEN(B2)=3;LEFT(B2;1);IF(LEN(B2)=4;LEFT(B2;3);IF(LEN(B2)=5;LEFT(B2;4);IF(LEN(B2)=7;IF(B2;5)))))))
With this formula, I check the length of the characters in cell and get the first part of that string instead of deleting the last indexes because of there are also some string values.
Because of there are some rules with my product codes, I figured out how they are changing and I got the part of the code by their sizes. Thanks for replies, they helped to find this solution.
I have around 30 numbers which are either 1, 2 or 3 digits which are codes. These codes are attached in front of other numbers. I want to know what code is in front of a number, for example for the number 35467036 the first two digits matches with the code 35. So I want the output for that to be 1.5.
This is my current setup, I have a table with all the codes followed by the output in the next column. If all the codes were three digits long I could just do this =VLOOKUP((LEFT(E6,3)&"*"),D1:E3,2,FALSE) but they are unfortunately not.
I have also tried using nested IF statements but I can only go so far as 7 levels.
Will this only be possible in VBS or is there anther way?
Edit:
The code column is formatted to text. If I enter the value 3 into LEFT it does not work for two digits. Is there anyway I can make it work for 1, 2 and 3 digit codes? Also the codes do not overlap, for example, there isn't going to be 96 and 965 in the code table.
Seven nested IFs as a limit points to a very old version of Excel. You may want to consider upgrading to a version that is still supported in this millennium.
But your main problem is that the data type of your lookup value is text, because you concatenate a string with a wildcard. Whereas your Lookup Table's first column is probably made up of numbers.
In order to solve this you will need to add a Text column to your lookup table that represents the numeric value as a text value.
IF you want to use Vlookup, that helper column will need to be the first column of your lookup range.
You can use an Index/Match instead of Vlookup to be independent of the column order, as this screenshot shows:
Column H shows the formula that has been applied in column G.
Edit:
According to the screenshot you posted, you want to look up from the table in columns E to F and this table only has the short codes. Therefore, it makes no sense to add a wildcard to the lookup value. You just need to extract the value you want to use for the lookup.
If you want to lookup only two digits, then you need to extract only two digits. Adding a wildcard does nothing to remove the third digit.
In the screenshot below, a helper column feeds the LEFT() function the number of characters to extract, then uses that value in the VLookup.
=VLOOKUP(LEFT(A1,B1),$E$1:$F$5,2,FALSE)
=INDEX($G$2:$G$5,
SMALL(
IF(LEFT(A1,3)*1=$F$2:$F$5,ROW($G$2:$G$5)-1,
IF(LEFT(A1,2)*1=$F$2:$F$5,ROW($G$2:$G$5)-1,
IF(LEFT(A1,1)*1=$F$2:$F$5,ROW($G$2:$G$5)-1))),1))
=INDEX(LookupValues,Small(ArrayOfRowsFromIfStatements,FirstRow))
This is an array formula so you will need to use Ctrl+Shift+Enter while still in the formula bar.
We use If to build an array of Row numbers where the conditions match or return FALSE if not. The Small function then returns the smallest result in the array which will be the first row where conditions match.
We then index the results returning that row number (-1 deducted from rows to offset the headers).
If your numbers in column A are always 6 digits + the code length you can use this:
=VLOOKUP(--LEFT(A1,LEN(A1)-6),E2:F5,2,FALSE)
In Excel 2013 I have two tables.
The first contains alpha numeric codes that vary in length.
Some examples from first table:
12345.12345
12346-12345
12AB1234
123.123
23456.123
A1234567.012
01234.12345
The second table contains alpha numeric codes I need to match with the beginning of the codes in the first table. Any numeric codes are currently stored as text.
Some examples from second table:
12345
12346
123
23456
A1234567
01234
How do I return a value from a different column in the second table containing any value? And for some context, the return column from the second table contains a description of for the codes.
I did not jet manage to find a solution using vlookup or match.
Also looked at using wildcards, but this only works one way, the wrong way.
The quickest solution, assuming you dont care about letters, is to use a LEFT(FIND( with substitution. If letters need to be excluded, then explanation will need to be provided how the format should be presented.
Solution: =IFERROR(LEFT(A2,FIND(".",SUBSTITUTE(A2,"-","."))-1),A2)
This formula will find the first "." or "-" and present all characters prior to. If none are found, then it will display the full ID.
If letters need to be removed as well, however, it should be noted that the use of some serious substitute nesting, or VBA script will be required.
A1 is the first cell in your column, in B1 write the following:
=LEFT(A1,MATCH(TRUE,ISERROR(VALUE(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1))),0)-1)
press Ctrl+Shift+Enter at the same time (Array Formula)
it will return the first numeric part of your Data
you can copy paste values in column C and compare with the second table
To have the result in Table1 directly in B1 use:
=IFERROR(INDEX(Sheet2!$A$1:$A$4,MATCH(VALUE(LEFT(A1,MATCH(TRUE,ISERROR(VALUE(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1))),0)-1)),Sheet2!$A$1:$A$4,0)),"")
press Ctrl+Shift+Enter at the same time (Array Formula)
It will return the corresponding number from Table2 (sheet2) if matched or "" empty if no match
Change A1:A4 to correspond all your Numbers in Table2 and keep the $ to fix the references when you drag down the formula
I have two columns in excel A and B from 1 - 1400
The value in column A is 10 characters, "K0123456789" and column B is 9 characters "0123456789"
I need to compare the value in column B is the same value as column A without the "k" and highlight it if they do not match. I am not familiar with excel too much, so any information here would help so I do not have to go through all these lines myself on a daily basis.
Thanks for any help!
GenZade
You can put a formula in column C such as (For cell C1):
=IF(A1="K"&B1,"Match","No Match")
Of course, you could also add conditional formatting with a similar formula if you want to literally highlight it.
i would have just commented on neelsg post, but i don't have enough reputation for that, apologies. his solution works based on string values rather than numerical values. Some kind of preceding zeros might not work nicely with it. to compare actual numerical values you can use the following:
=IF(RIGHT(A1,LEN(A1)-1)*1=B1,"match","no match")
so depends if you want to match them as strings or actual numbers
Because of floating point values, I cannot add a string of cells that contain values such as:
0.08178502
0.09262585
0.13261762
0.13016377
0.12302067
0.1136332
0.12176183
0.11430552
0.09971409
0.125285
Even if I try adding the first two through a sum formula or auto sum through selecting them, excel spits out an error. I have googled this like crazy and tried to change number formats. Is there a function that can allow me to add this information ?
Screenshot:
The spreadsheet is available on my Dropbox.
Those numbers are all preceded by a NBSP (Char Code 160). So, in order to sum them, you have to remove that. Many solutions. Here's one:
=SUMPRODUCT(--SUBSTITUTE(A1:A18,CHAR(160),""))
If a formula like:
=A1+A2+A3+A4+A5+A6+A7+A8+A9+A10
produces:
#VALUE!
then your "numbers" cells contain non-visible characters.
They must be removed before the formula will work.
If the cells contain text strings and not actual values you will need to convert the text to numeric values before performing any calculations. The function "=value(cell)" will bring the numeric value.
e.g.: A1 contains "000.12345678" (or some other non-numeric presentation of numerals)
In cell B1 type: =value(a1)
Cell B1 now operates as the real number 0.12345678
Oddly enough, the fact that it said 0.xxxxx in all numbers vs. .xxxxx is what the issue was. I'm just sharing that for folks who google/search and have same issue.
All I had to do was select that whole row and do a search in replace for "0." and make it just "." and now my numbers were usable in equations. For some reason the adjustment of formating as many searches suggested wasn't working