How to get the upload speed from cURL? - linux

Question

When I run below curl upload command it gives me big output. How can I cut short this to just show the final upload speed?
curl --upload-file /tmp/testlocal -v -u tu**r:******#*23 http://nexus3-core:8081/nexus3/repository/tes******/tes*****
* Expire in 0 ms for 6 (transfer 0x558e6c881f50)
* Expire in 1 ms for 1 (transfer 0x558e6c881f50)
% Total % Received % Xferd Average Speed Time Time Time Current
Dload Upload Total Spent Left Speed
0 0 0 0 0 0 0 0 --:--:-- --:--:-- --:--:-- 0* Expire in 0 ms for 1 (transfer 0x558e6c881f50)
* Expire in 2 ms for 1 (transfer 0x558e6c881f50)
* Expire in 0 ms for 1 (transfer 0x558e6c881f50)
* Expire in 1 ms for 1 (transfer 0x558e6c881f50)
* Expire in 1 ms for 1 (transfer 0x558e6c881f50)
* Expire in 1 ms for 1 (transfer 0x558e6c881f50)
* Trying 172.30.51.207...
* TCP_NODELAY set
* Expire in 200 ms for 4 (transfer 0x558e6c881f50)
* Connected to nexus3-core (172.30.51.207) port 8081 (#0)
* Server auth using Basic with user 'tu****'
> PUT /nexus3/repository/testu****/tes**** HTTP/1.1
> Host: nexus3-core:8081
> Authorization: Basic dHVzZXI6VHVzZXJAMTIz
> User-Agent: curl/7.64.0
> Accept: */*
> Content-Length: 1048576000
> Expect: 100-continue
>
* Expire in 1000 ms for 0 (transfer 0x558e6c881f50)
< HTTP/1.1 100 Continue
} [41940 bytes data]
4 1000M 0 0 4 45.5M 0 50.7M 0:00:19 --:--:-- 0:00:19 50.6M
8 1000M 0 0 8 89.7M 0 47.3M 0:00:21 0:00:01 0:00:20 47.2M
13 1000M 0 0 13 139M 0 48.2M 0:00:20 0:00:02 0:00:18 48.2M
19 1000M 0 0 19 193M 0 49.6M 0:00:20 0:00:03 0:00:17 49.6M
23 1000M 0 0 23 234M 0 47.9M 0:00:20 0:00:04 0:00:16 47.9M
29 1000M 0 0 29 291M 0 49.4M 0:00:20 0:00:05 0:00:15 49.2M
34 1000M 0 0 34 346M 0 50.1M 0:00:19 0:00:06 0:00:13 51.2M
40 1000M 0 0 40 408M 0 51.7M 0:00:19 0:00:07 0:00:12 53.8M
46 1000M 0 0 46 465M 0 52.3M 0:00:19 0:00:08 0:00:11 54.3M
52 1000M 0 0 52 520M 0 52.5M 0:00:19 0:00:09 0:00:10 57.1M
58 1000M 0 0 58 587M 0 53.9M 0:00:18 0:00:10 0:00:08 59.1M
64 1000M 0 0 64 648M 0 54.4M 0:00:18 0:00:11 0:00:07 60.3M
70 1000M 0 0 70 706M 0 54.7M 0:00:18 0:00:12 0:00:06 59.5M
76 1000M 0 0 76 763M 0 54.9M 0:00:18 0:00:13 0:00:05 59.5M
78 1000M 0 0 78 781M 0 51.2M 0:00:19 0:00:15 0:00:04 48.7M
79 1000M 0 0 79 791M 0 49.7M 0:00:20 0:00:15 0:00:05 40.7M
83 1000M 0 0 83 839M 0 49.6M 0:00:20 0:00:16 0:00:04 38.2M
89 1000M 0 0 89 895M 0 50.0M 0:00:19 0:00:17 0:00:02 37.8M
95 1000M 0 0 95 957M 0 50.6M 0:00:19 0:00:18 0:00:01 38.9M* We are completely uploaded and fine
100 1000M 0 0 100 1000M 0 48.6M 0:00:20 0:00:20 --:--:-- 41.0M< HTTP/1.1 201 Created
< Date: Fri, 08 Jan 2021 06:52:32 GMT
< Server: Nexus/3.23.0-03 (OSS)
< X-Content-Type-Options: nosniff
< Content-Security-Policy: sandbox allow-forms allow-modals allow-popups allow-presentation allow-scripts allow-top-navigation
< X-XSS-Protection: 1; mode=block
< Content-Length: 0
<
100 1000M 0 0 100 1000M 0 47.9M 0:00:20 0:00:20 --:--:-- 41.9M
My desired out put is as below
Curl upload speed : 41.9M
I know curl prints stderr and I am struggling to get that output with grep

Answer 1

Not exactly answering your question but perhaps a better way to get the average upload speed is to use the dedicated option for it? Try this:
curl -w 'Speed: %{speed_upload}\n' -T local-file http://...target...
That -w option string will then output the average upload speed (in bytes/sec) after a successful transfer.

Answer 2

With your shown samples, could you please try following. Couldn't test it(because of the curl command), it should work ok IMHO.
These commands are printing last field of your output's last line.
your_curl_command |
tac |
awk 'FNR==1{print $NF;next}'
OR with-in single awk try:
your_curl_command |
awk '{val=$NF} END{print val}'

Answer 3

If you are always interested only in last line last field, you might combine tail -1 with awk to get it following way:
curl_command | tail -1 | awk '{print $NF}'