trying to break apart a string in rust - rust

Question

I have this string
abcdef x y z
or this one
"ab cd ef" x y z
I am trying to parse this in rust to
s1 = "abcdef"
arr = ["x","y","z"]
or
s1 = "ab cd ef"
arr = ["x","y","z"]
I tried the following (str is the starting string)
let chars = str.chars().peekable();
let s1:String = if *chars.peek().expect("value isnt empty") == '\"'{
chars.skip(1).take_while(|c| *c!= '\"').collect()
}else{
chars.take_while(|c| *c!= ' ').collect()
};
let remainder_str = chars.collect::<String>();
let remainder = remainder_str.split_whitespace();
let mut arr: Vec<&OsStr> =
remainder.map(|s| OsStr::new(s)).collect();
Ie create an iterator of the chars and walk it down the string pulling bits out as I go.
Doesnt work becuase the first collect eats 'chars'. I am sure I could do it via walking down the array of chars with an index inspecting each one in turn (aka, brute force) but that doesnt seem like idiomatic rust.
Can anybody suggest a better way.

Answer 1

Your idea taken to compilation:
fn doit(str: String) -> (String, Vec<String>) {
let mut chars = str.chars().peekable();
let s1:String = if *chars.by_ref().peek().expect("value isnt empty") == '\"'{
chars.by_ref().skip(1).take_while(|c| *c!= '\"').collect()
}else{
chars.by_ref().take_while(|c| *c!= ' ').collect()
};
let remainder_str = chars.collect::<String>();
let remainder = remainder_str.split_whitespace();
let arr: Vec<String> =
remainder.map(|s| s.to_string()).collect();
(s1, arr)
}
by_ref is possibly your friend here.
Note, however, that this method is very likely not what you actually want, as it allocates stuff all over the place (all the Strings, etc.).
You could be better off using only string slices that refer to the original string.