Original Question
Please refer to the original question above. I was told to ask a new question.
Ron Rosenfeld's solution works great on numbers but how would the formula change if my two lists are alphanumeric e.g. P1234,C4321,P0123,P0678?
Formula:
=TEXTJOIN(",",TRUE,IFERROR(1/(1/(ISNUMBER(FIND(","&TRIM(MID(SUBSTITUTE(B2,",",REPT(" ",99)),seq_99,99))&",",","&A2&","))))*TRIM(MID(SUBSTITUTE(B2,",",REPT(" ",99)),seq_99,99)),""))
Before the second TRIM, if I just add "0"& the results work but each has a 0 before it. For example:
))))*"0"&TRIM(MID(SUBSTITUTE
Results in something like 0C4321,0P0123,0P0678.
It can be modified as such:
=TEXTJOIN(",",TRUE,IF(ISNUMBER(FIND(","&TRIM(MID(SUBSTITUTE(B1,",",REPT(" ",99)),seq_99,99))&",",","&A1&",")),TRIM(MID(SUBSTITUTE(B1,",",REPT(" ",99)),seq_99,99)),""))
But there is a shorter version that does not require the named range.
=TEXTJOIN(",",TRUE,FILTERXML("<a><b>"&SUBSTITUTE(B2,",","</b><b>")&"</b></a>","//b[contains(',"&A2&",',concat(',', ., ','))]"))
Depending on one's version these may need to be confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode.
You could try:
Formula in C1:
=TEXTJOIN(",",,FILTERXML("<t><s>"&SUBSTITUTE(A1&","&B1,",","</s><s>")&"</s></t>","//s[preceding::*=.]"))
Related
I have a problem with an excel file.
I am trying to extract information from a column. This information appears randomly, before a ".", "-" or ":". So an example would be:
CELL
EXPECTED RESULT
hi.this is:
hi
maybe I- this works
maybe I
Who is: what. like-
Who is
I am using the formula:
=MID(A1,1,FIND("-",A1,1)-1)
Using this one, I get the information I need, but I am not able to add the other characters (".", ":",...) to the formula. Also I have the problem that in a same cell, I can have several of this characters, and I only want the information before the FIRST character (of all posible kinds) that appears in the cell.
I dont know if somebody can help me here.
Thank you very much in advance!
You can try:
Formula in B1:
=TEXTBEFORE(A1:A3,{".","-",":"})
If you don't yet have acces to TEXTBEFORE() then try:
=LEFT(A1,MIN(FIND({".","-",":"},A1&".-:"))-1)
I suppose this is an array-entered formula in versions prior to ms365.
How to extract the capitalized full words from a string in excel ? Refer the first Image, I have used the following formula to extract the CAPITAL / BLOCK LETTER WORDS From a string in a cell, it works perfectly,
• Formula used in cell B2
=TEXTJOIN(" ",,
FILTERXML("<a><b>"&SUBSTITUTE(A2," ","</b><b>")
&"</b></a>","//b[translate(.,'abcdefghijklmnopqrstuvwxyz',
'ABCDEFGHIJKLMNOPQRSTUVWXYZ')=.]"))
The above formula works perfectly as longs as there is no numerical, but it doesn't give proper output when there are some numbers, refer the Image below, may be I am missing something, using O365
Refer the cells those green colored backgrounds, it should bring only the CAPITAL WORDS but it carries also the numbers. What should be the right way here. Thank You!
Courtesy : I have learnt & used FILTERXML formula by following the post of JvdV Sir, and it really helped me a lot, Thank you very much Sir for this wonderful piece.!
Workbook_OneDrive_Link
As per the given sample data:
=TEXTJOIN(" ",,FILTERXML("<t><s>"&SUBSTITUTE(A2," ","</s><s>")&"</s></t>","//s[translate(., 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', '')='']"))
This would check when all uppercase alpha-chars are translated to nothing the node would equal nothing, meaning all characters were uppercase alpha.
How could I extract only the numbers from a text string in Excel or Google Sheets? For example:
A1 - a1b23eg67
A2 - 15dgrgr156
Result desired is
B1 - 12367
B2 - 15156
You can do it with capture groups in Google Sheets
=REGEXREPLACE(A1,ʺ(\d)|.ʺ,ʺ$1ʺ)
Anything which matches the contents of the brackets (a digit) will be copied to the output, anything else replaced by an empty string.
Please see #Max Makhrov's answer to this question
or
=regexreplace(A1,ʺ[^\d]ʺ,ʺʺ)
to remove anything which isn't a digit.
Because you asked for Excel also,
If you have a subscription to office 365 Excel then you can use this array formula:
=--TEXTJOIN("",TRUE,IF(ISNUMBER(--MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)),MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1),""))
Being an array formula it needs to be confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode. If done correctly then Excel will put {} around the formula.
I would imagine there is a way to pull this off with =RegexExtract but I can't figure out how to get it to repeat the search after the first hit. Often with these regex function implementations there is a third parameter to repeat, but it doesn't look like google implemented it.
At any rate, the following formula will do the trick. It's just a little roundabout:
=concatenate(SPLIT( LOWER(A1) , "abcdefghijklmnopqrstuvwxyz" ))
This is converting the string to lower case, then splitting the string using any letter of the alphabet. This will return an array of the numbers left over, which we concatenate back together.
Update, switched over to =REGEXREPLACE() instead of extract...:
=regexreplace(A1, "[a-z]", "")
That's a much cleaner and obvious way of doing it than that concat(split()) nonsense.
Column A has a sorted-descending list of some bum's Top-250 movies, in the following format: Apocalypse Now (1979)
Column B has a sorted list of My Top-100, in the same format.
Both lists have been copied and pasted into a Notepad text doc to confirm they are similar simple ASCI text – no extra spaces at the end – etc. - and then pasted back into LibreofficeCalc.
I need a function for Column C that shows any of MY movies (B) that he has NOT listed in (A).
Psudo code:
C1 = The cell value in B1 – is it anywhere in A1:A8000? If not – put B1 value into C1, otherwise leave blank.
C2 = The cell value in B2 – is it anywhere in A1:A8000? If not – put B2 value into C2, otherwise leave blank.
Etc.
I have searched and found these functions – none of which work, for whatever reason. I've modified them to 8000 as the upper range which I don't think I'll ever approach.
=IF(ISERROR(MATCH(B1,$A$1:$A$8000,0))=1,B1,"")
=IFERROR(MATCH(B1;$A$1:$A$8000;0);"")
=IFNA(VLOOKUP($B1;$A$1:$A$8000;1;0);"")
=IF(ISNA(VLOOKUP($B1;$A$1:$A$8000;1;0));"";VLOOKUP($B1;$A$1:$A$8000;1;0))
=IF(ISNA(VLOOKUP($B1,$A$1:$A$8000,1,0)),"",VLOOKUP($B1,$A$1:$A$8000,1,0))
=VLOOKUP(B1,$A$1:$A$8000,1,)
=MATCH($B1;$A$1:$A$999;0)
I'd prefer it to be a single cell function, and not VBA.
I actually solved this back in like 2001 using Excel. The trick then was I had to edit the cell and use Ctrl-Shift-Enter to create a “dynamic array”, so the function was bracketed in {} curly brackets. But now I'm using the latest LibreOffice Calc and can't get the ##$# syntax correct.
Thank you!!
Edit NOTE: testing with "A" and "00001" numbers produces very different results. Values have to look like this in both columns:
Alice (1988)
Barfly (1987)
Clueless (1995)
etc.
OK I've tested these in Open Office with the following results:-
=IF(ISERROR(MATCH(B1,$A$1:$A$8000,0))=1,B1,"")
Gives Error 508 because the commas need changing to semicolons.
**=IF(ISERROR(MATCH(B1;$A$1:$A$8000;0))=1;B1;"")**
is fine.
=IFERROR(MATCH(B1;$A$1:$A$8000;0);"")
Gives #Name? because IFERROR isn't recognised.
=IFNA(VLOOKUP($B1;$A$1:$A$8000;1;0);"")
Gives #Name? because IFNA isn't recognised.
=IF(ISNA(VLOOKUP($B1;$A$1:$A$8000;1;0));"";VLOOKUP($B1;$A$1:$A$8000;1;0))
Works but gives the opposite result.
**=IF(ISNA(VLOOKUP($B1;$A$1:$A$8000;1;0));B1;"")**
would be fine.
=IF(ISNA(VLOOKUP($B1,$A$1:$A$8000,1,0)),"",VLOOKUP($B1,$A$1:$A$8000,1,0))
Commas
=VLOOKUP(B1,$A$1:$A$8000,1,)
Commas
=MATCH($B1;$A$1:$A$999;0)
Works but just gives the position of the match.
Probably the easiest way of doing it is:-
**=IF(COUNTIF(A$1:A$8000;B1);"";B1)**
Unfortunately it does seem that strings with brackets in are giving spurious matches in Libre/Open Office. You could get round it by a substitution I guess
=IF(COUNTIF(SUBSTITUTE(SUBSTITUTE(A$1:A$10;"(";"<");")";">");SUBSTITUTE(SUBSTITUTE(B1;"(";"<");")";">"));"";B1)
entered as an array formula and copied (rather than pulled) down or of course global edit all the brackets :-(.
Now that I know the root cause of this thanks to #Lyrl, there is a further option of turning off the regular expressions as suggested or you could escape the brackets:-
=IF(COUNTIF(A$2:A$11;SUBSTITUTE(SUBSTITUTE(B2;"(";"\(");")";"\)"));"";B2)
See documentation on Regex in Open Office here
This should do it,
=IF(ISNUMBER(MATCH(B1,$A$1:$A$8000,0)),"",B1)
Tested formula
=IF(ISNA(MATCH(B1,$A$1:$A$8000,0))=TRUE(),B1,"")
In Excel, how do I write a formula that will partially delete a cell (from a certain point onwards).
For example, if A1 is "23432 Vol 23432". I want B1 to just be "23432 " (everything from Vol onwards is removed). Thanks.
you cannot delete cells with formulas in Excel.
you can modify the content of a cell by using formulas. you may use LEFT(), RIGHT(), MID() and other similar string processing functions.
is there any rule about the number? If for example the number is always 5 digits long, you can return "23432" out of "23432 Vol 23432" by typing =LEFT(A1;5)
you might also want to look for the space. think the english equivalent for the german FINDEN-function is FIND(keyword;text;[first charindex]). if splitting by space, you find the number by =LEFT(A1;FIND(" ";A1))
please post detailed information about your problem if you need further assistance.
EDIT: you may also use VBA if your problem needs a custom formula or custom actions taken out on a cell.
EDIT2, SOLUTION:
=LEFT(A1;FIND(" Vol";A1))
is the solution to your problem, iff "Vol" and the rest needs to be removed in any case without condition. Remember that if you have any condition attached to this, you might nest this expression (without the '=' though) in a "IF()"-formula.
hope that helped you.
best regards