How to check routes on template? - python-3.x

Question

Does anyone know how to check if a template is being accessed through a url route with the django template language?
Here is my situation: There's this template article.html, that shows all posts of a blog when accessed through blog-home url route, and that also shows only posts of a given user through user-posts url route.
This template works like that because what defines which posts will be shown are the classes in views.py.
That being said, here is what I tried to do: (I know its wrong)
{% if url == 'user-posts' %}
"Some HTML h1 tag I want do be shown only when this template is accessed via 'user-posts' url"
{% endif %}
How would be the correct way, if there's any, to write this if statement?

Answer 1

When Django matches a url pattern a ResolverMatch object is created and made available on the request object at request.resolver_match. This ResolverMatch object can be queried in your template to acheive what you want, the url_name attribute is the name of the url pattern that was matched
{% if request.resolver_match.url_name == 'user-posts' %}

Answer 2

You should create a custom templatetag,
my_app/templatetags/utils.py
from django import template
register = template.Library()
#register.simple_tag(takes_context=True)
def is_active_view(context, *view_names):
request = context.get('request')
for view_name in view_names:
if getattr(request.resolver_match, 'view_name', False) and request.resolver_match.view_name == view_name:
return True
return ''
And use it in your template this way, assuming blog-home is the url name you gave to your url :
blog-home.html
{% load utils %}
{% is_active_view 'blog-home' as display_blog_home_section %}
{% if display_blog_home_section %}
<!-- Your code -->
{% endif %}
NB : this template tag can check after multiple view names at once and support namespaced url :
{% is_active_view 'front:blog-home' 'front:blog-categories' as display %}

Answer 3

Here is a more optimized version of this if you are using boostrap and trying to make the menu options "active" when you are on that URL
from django import template
register = template.Library()
#register.simple_tag(takes_context=True)
def is_active_tab(context, *view_names):
request = context.get('request')
for view_name in view_names:
if getattr(request.resolver_match, 'view_name', '') == view_name:
return 'active'
return ''
And you use it like
<li class="nav-item {% is_active_tab 'games:list' %}">
<a class="nav-link" href="{% url 'games:list' %}">
{% translate "My Quizzes" %}
</a>
</li>
<li class="nav-item {% is_active_tab 'games:create' %}">
<a class="nav-link" href="{% url 'games:create' %}">
{% translate "New Game" %}
</a>
</li>
It adds an extra active classname to the class of the element if any of the view_names match the current view name. Makes the template writing much cleaner