Save in mongodb and pass created object to a function - node.js

Question

I'm beginner at programing and I don't know how can I do something with the mongoose save result.
In my post endpoint I would like to not save and directly return but instead of it I would like to do something with the result of save method like take the _id value of the new object created and pass to a function.
Here's what my post endpoint is doing and I would like to after saving not return but instead call a function passing the checkout object created:
router.post('/', async function(req, res) {
const { checkinId, eventId, email } = req.body;
let CheckoutTest = {
checkinId: checkinId,
eventId: eventId,
email: email,
}
const newCheckout = new Checkout(CheckoutTest);
await newCheckout.save((err, checkout) => {
if(err) {
return res.status(400)
.send(err);
}else {
return res.status(200)
.json({message: "Checkout successfully added!", checkout});
}
})
});

Answer 1

An elegant way to do this would be to add a try...catch block
router.post('/', async function(req, res) {
const { checkinId, eventId, email } = req.body;
let CheckoutTest = {
checkinId: checkinId,
eventId: eventId,
email: email,
}
const newCheckout = new Checkout(CheckoutTest);
try {
const newCheckoutObject = await newCheckout.save()
// Call the function that you wanted to after the save.
// You can pass in the "_id" of the object as shown here
const newData = await functionToBeCalled(newCheckoutObject._id)
return res.status(200).json({message: "Checkout successfully added!", newData});
} catch (err) {
return res.status(400).send(err);
}
}