When using Easymotion, I use 2 characters about 90% of the time and I have it mapped to s, so I will type in something like re:
Is there a way to use a wildcard character? For example, something like r* or *e? I know there is a second command in Easymotion to search for one character only, but I only want to use a single shortcut of s for everything. Is this possible?
Yep just enter 1 character and then hit enter. so to search r* just enter r<cr>
Related
I want search one invisible character(control character, such as 0x05) using less command in Linux.
I find the character is displayed as ^E in less. I can not search it by directly using the characters "^E" . Neither ctrl+vctrl+e in VI or just search by /\0x05.
CtrlE means something special at the beginning of the search field regardless of how it is entered. Type another non-"special" character first, then press the sequence, then remove the first character.
How would you search for the following string in vim?
http://my.url.com/a/b/c
I've tried (a la Very No Magic)
:/\Vhttp://my.url.com/a/b/c
But it gives me:
E492 not an editor command: /\Vhttp://my.url.com/a/b/c
You would think there'd be a simple way to search a string literally... I'm not too interested in slash escaping every slash, or writing a complicated search, because I have to rapidly search different URLs in a text file.
I'm not sure why you get not an editor command since I don't. The simplest way to search without having to escape slashes is to use ? instead, e.g.
:?http://my.url.com/a/b/c
" or since the : is not necessary
?http://my.url.com/a/b/c
This does search in the other direction, so just keep that in mind
another way to search forward (from the position of your cursor) without escaping is use :s command.
you could do:
:%s#http://my.url.com/a/b/c##n
then press n to navigate matched text forward, N backwards
If you want to know how many matches in the buffer, use gn instead of n
note that, I said "without escaping", I was talking about the slash, if you want to do search precisely, you have to escape the period. .. since in regex, . means any char.
Can also set the search register directly.
:let #/='\Vhttp://my.url.com/a/b/c'
Then you can use n and N like normal.
Use MacVim (or GVim). Open the non-regex GUI search using ⌘f (or ctrlf on Windows). This is the recommended way to do a non-regex search in Vim. GUI Vim has many improvements over terminal vim like this one and I would highly suggest using it full time if you aren't already.
Searching in vim is just /, not :/. You can search for that string escaping only the slashes: /http:\/\/my.url.com\/a\/b\/c
Let's say I have a line like this:
pick 22086f5 do something....
I can put my cursor on the "p" in pick and delete word, however the line then looks like:
22086f5 do something....
and I can do a replace on 2 and replace it with an "s", but that's not really what I want. What I want is a simple way to insert 1 character without going into insert mode.
It is probably easiest to just put the cursor on the p and do ces<esc>. If you have the letter s in a buffer, say in buffer a, you could do: de"aP. If you are always replacing the word pick, you could also do dtkrs.
You can use vehdrs to delete all letters without last one and then replace the last one with s. Or if space is not needed then ders will work nicely.
I would also normally use ces<Esc>, but sometimes muscle memory prefers two distinct actions. For these cases, a mapping like the following may be helpful:
:nnoremap <Space> i$<Esc>r
I have the following characters being repeated at the end of every line:
^[[00m
How can I remove them from each line using the Vim editor?
When I give the command :%s/^[[00m//g, it doesn't work.
You could use :%s/.\{6}$// to literally delete 6 characters off the end of each line.
The : starts ex mode which lets you execute a command. % is a range that specifies that this command should operate on the whole file. The s stands for substitute and is followed by a pattern and replace string in the format s/pattern/replacement/. Our pattern in this case is .\{6}$ which means match any character (.) exactly 6 times (\{6}) followed by the end of the line ($) and replace it with our replacement string, which is nothing. Therefore, as I said above, this matches the last 6 characters of every line and replaces them with nothing.
I would use the global command.
Try this:
:g/$/norm $xxxxxx
or even:
:g/$/norm $5Xx
I think the key to this problem is to keep it generic and not specific to the characters you are trying to delete. That way the technique you learn will be applicable to many other situations.
Assuming this is an ANSI escape sequence, the ^[ stands for a single <Esc> character. You have to enter it by pressing Ctrl + V (or Ctrl + Q) on many Windows Vim installations), followed by Esc. Notice how this is then highlighted in a slightly different color, too.
It's easy enough to replace the last six characters of every line being agnostic to what those characters are, but it leaves considerable room for error so I wouldn't recommend it. Also, if ^[ is an escape character, you're really looking for five characters.
Escape code
Using ga on the character ^[ you can determine whether it's an escape code, in which case the status bar would display
<^[> 27, Hex 1b, Octal 033
Assuming it is, you can replace everything using
:%s/\%x1b\[00m$//gc
With \%x1b coming from the hex value above. Note also that you have to escape the bracket ([) because it's a reserved character in Vim regex. $ makes sure it occurs at the end of a line, and the /gc flags will make it global and confirm each replacement (you can press a to replace all).
Not escape code
It's a simple matter of escaping then. You can use either of the two below:
:%s/\^\[\[00m$//gc
:%s/\V^[[00m\$//gc
If they are all aligning, you can do a visual-block selection and delete it then.
Otherwise, if you have a sequence unknown how to input, you can visually select it by pressing v, then mark and yank it y (per default into register "). Then you type :%s/<C-R>"//g to delete it.
Note:
<C-R>" puts the content of register " at the cursor position.
If you yanked it into another register, say "ay (yank to register a - the piglatin yank, as I call it) and forgot where you put it, you can look at the contents of your registers with :reg.
<C-R> is Vim speak for Ctrl+R
This seems to work fine when the line is more than 5 chars long:
:perldo $_ = substr $_, 0, -5
but when the line is 5 or less chars long it does nothing.
Maybe there is a easy way in perl to delete the last 5 chars of a string, but I don't really know it:)
Use this to delete:
:%s/^[[00m//gc
My previous question seems to be a bit ambiguous, I will rephrase it:
I have a file like this:
copythis abc
replacethis1 xyz
qwerty replacethis2
hasfshd replacethis3 fslfs
And so on...
NOTE: replacethis1, replacethis2, replacethis3, ... could be any words
How do I replace "replacethis1","replacethis2","replacethis3",.. word by "copythis" word by using minimum vim commands.
One way I can do is by these steps:
delete "replacethis1","replacethis2","replacethis3",.. by using 'dw'
copy "copythis" using 'yw'
move cursor to where "replacethis1" was and do 'p'; move cursor to where "replacethis2" was and do 'p' and so on...
Is there a better way to do this in VIM (using less number of vim commands)?
Since you changed your question, I'd do it this way:
Move to the first "replacethis1" and type cw (change word), then type "copythis" manually.
Move to the next "replacethis", hit . (repeat last operation)
Move to the next "replacethis", hit .,
and so on, and so on.
If "copythis" is a small word, I think this is the best solution.
The digit needs to be included, and there could be more than one instance per line:
:%s/replacethis\d/copythis/g
Given that "replacethis[1-3]" can be arbitrary unrelated words, the quickest/simplest way to do this globally would be:
:%s/replacethis1\|replacethis2\|replacethis3/copythis/g
(Note that you need to use \| to get the pipes to function as "or". Otherwise, vim will look for the literal | character.)
I've been struggling with this for a long time too, I think I just worked out the cleanest way:
Use whichever command is cleanest to put copythis into register r:
/copythis
"rye
Then go to the replacement and replace it with the contents of r:
/replacethis
cw<CTRL-R>r<ESC>
Then you can just n.n.n.n.n.n.n. for the rest of them, or if they're wildly different just go to the beginning of each and hit .
The key is replacing and pasting in one step so you can use . later.
:%s/copythis/replacethis/g
To replace all occurrences of copythis with replacethis. Or you can specify a range of line numbers like:
:8,10 s/copythis/replacethis/g
Note, the /g on the end will tell it to replace all occurrences. If you leave that off it will just do the first one.
create this mapping:
:map z cwcopythis^[
( ^[ is the escape character, you can type it in vim using Ctrl+V Ctrl+[ )
go to each word you want to replace and press z
if u need to do essentially the same action multiple times - swap 1st word of one line with second word of the next line, I say you could record a macro and call it whenever you need to
Have you tried string replacement?
%s/replacethis/copythis
A host of other parameters are possible to fine-tune the replacement. Dive into the Vim help for more details. Some more examples here.
You can remap e.g. the m key in normal mode to delete the word under the cursor and paste the buffer: :nnoremap m "_diwP.
Then you can just copy the desired word, move the cursor anywhere onto the to-be-replaced word and type m.
EDIT: Mapping to m is a bad idea since it is used to mark locations. But you can use e.g. ; anyway.