I have four columns of data (day and time A; precipitation amount; day and time B; temperature) the two day and time columns (A and C) should match up (i.e. 16:00 12/10/19 in both columns). However, column A and C have duplicates which are not consistent (e.g. two 16:00 in column A but only one in column C) and I need to retain the duplicates as they contain variations in precipitation or temperature (e.g. A has two reads for precipitation that are biologically important but B does not).
Is there any way I can merge these four columns together by:
-(a) linking A with precipitation amount and C with temperature; and
-(b) without deleting the duplicates but instead placing spaces in either columns where there is space?
Here is my data - red represents duplicates (a tiny subset - I have 365 days and four years of data):
This is what I'd like it to look like (so there is a gap in second column where there isn't a duplicate):
Thank you very very much for any help!! :)
If the duplicate dates are only in column A, then you can recreate the dates and temp values in a helper column. In column E, start in row 2 to pull only the unique dates.
=IF(A5=A4,"",A5)
Copy down. Then in cell F2, use a lookup formula to pull the matching temperature
=XLOOKUP(E5,C:C,D:D,"")
Or, if you don't have Office 365 with the new Xlookup, use Vlookup
=IF(ISNUMBER(E5),VLOOKUP(E5,C:D,2,FALSE),"")
Copy down.
You can then copy the result and use Paste Special > Values to overwrite the original data.
In C2, add this formula, and then fill it down:
=IF(A2=A1,"",A2)
This says if date in the row above it is the same, then return a blank. Otherwise, return the date.
Related
I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)
I want to calculate work days between two dates. NETWORKDAYS will do the trick, however I am having difficulty structuring the IF statement components.
I have 5 columns, Column A will always have a start date; the other 4 columns might not. What I want to calculate is the network days between Column A and B, but if B is blank then Column A and C, and if C is blank, then Column A and D and so forth
Use this formula:
=NETWORKDAYS(A1,INDEX(A1:E1,AGGREGATE(15,6,COLUMN(B1:E1)/(B1:E1<>""),1)))
The INDEX/AGGREGATE will find the first cell in B:E that is not empty and return that as the end date to the NETWORKDAYS.
=IF(A1<>"",NETWORKDAYS(A1, B1), IF(C1<>"", NETWORKDAYS(A1, C1)))
This does the trick, I could not get AGGREGATE/INDEXto work
I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)
Ok so I did this in LibreOffice but now I have to duplicate it to excel for my Pay Roll department since they use excel. So I am having to figure out how to convert the formulas to Excel. This is only 1 of two totaling formulas that did not convert when I saved it as Excel format.
I have the following sheet called DailyReport
I am currently calculating Column M with =SUMPRODUCT(A2:A200=A2, G2:G200)
Then on a secondary sheet I have the following second sheet WeeklyReport
Now what I want to do is if WeeklyReport Column A2 == DailyReport Column A then take the date in DailyReport Column B and test it to fall in the date range in WeeklyReport Column B and Column C with =IF(AND(DailyReport.B2>=B2,DailyReport.B2<=C2),1, 0) and if that is true add the Total Daily Hours to the total in WeeklyReports Column D from DailyReports Column M
I hope this is clear enough if not please let me know what else I can do to make my question more clear.
Thanks in advance!
So, to me it sounds like:
You want a sum of all hours, for a specific employee (defined by the A column value weekly report), in between the dates specified (also defined by weekly report, b & c column) - and you want the end result to be in WeeklyReport column D and all of it to relate to the same row as the result?
sumproduct will do the trick. I am renaming your sheets to DR and WR for my sanity's sake.
=sumproduct((DR!G$2:G$200)*(DR!A$2:A$200=A2)*(DR!B$2:B$200>=B2)*(DR!B$2:B$200<C2))
Now, if you want a new daily report sheet every day it gets a bit trickier to do with formulas alone, you should then have a macro to store the "current" value and add the "new" value, or for simplicity's sake create more columns (one for each working day) and duplicate the formula to all daily columns, or have as many named dailyreports as there are working days in a week and increase the formula to check multiple sheets. I would add columns - least amount of work and the dumbest solution often proves the most resilient.
Did that help in any way?
I have two columns in a table that are known as S and D, where S is a date, and D is a duration.
E.g.:
'S' Column
January
February
March
April
'D' Column
60
30
45
30
On a separate sheet, imagine that Row 1 contains a sequence of dates (variable, depends on user menu selection).
Row 2 requires the following calculation:
[(x - s1)/d1 + (x-s2)/d2 + ... + (x-sn)/dn] / n
...where "x" is any date along Row 1.
The calculation would only be done when multiple criteria are matched.
My initial attempt involved creating a separate table, but I think this can be done in a one-cell formula in Row 2. I don't think a sum(index(match)) type would work here considering d1, d2, ..., dn are denominators with different values.
Here is an example attempt:
=SUM((SelectedDate-INDEX(Table[StartDates],MATCH(Criteria1&Criteria2,Range1&Range2,0))/INDEX(Table[Durations],MATCH(Criteria1&Criteria2,Range1&Range2,0))))
It may be important to note that I am able to do this in a two-step fashion. First, I create a table that does the calculation on each row. Then, I reference the table. It would be nice if I can eliminate the need of a "calculation table" in favour of an array-type formula.
I took a guess before most of the comments and suggest the following mainly in case it provides ay ideas or is of help in specifying the requirement more closely. This is "two-step" because the average formula is separate from that for each column, so I appreciate may well be not what is required.
Assuming S and D are labelled data in Sheet2 ColumnsA:B.
Assuming Row1 data rows are labelled in ColumnA.
Assuming dates are not strings (eg January is actually Jan 1) and the differences are in days and always positive, etc.
=(B$1-CHOOSE(COLUMN(),Sheet2!$A1,Sheet2!$A2,Sheet2!$A3,Sheet2!$A4))/CHOOSE(COLUMN(),Sheet2!$B1,Sheet2!$B2,Sheet2!$B3,Sheet2!$B4)
in Row2 to suit and if four data columns, in F2 and copied down to suit :
=AVERAGE(B2:E2)