How can I enter a dictionary inside an another empty dictionary? - python-3.x

Question

The example code -
innerdict = {}
outerdict = {}
for line in range(1, 10, 2):
for j in range(1, 10, 2):
line_tuple = ("Item" + str( line ), int( line ))
key = line_tuple[1]
if line ==j:
outerdict[key] = dict( innerdict )
outerdict[key] = {'Name': '{0}'.format( "item"+str(j) ), 'Price': '{0}'.format( j )}
print(outerdict)
The ouput comes out like this-
{1: {'Name': 'item1', 'Price': '1'}, 3: {'Name': 'item3', 'Price': '3'}, 5: {'Name': 'item5', 'Price': '5'}, 7: {'Name': 'item7', 'Price': '7'}, 9: {'Name': 'item9', 'Price': '9'}}
The above output is achievable since it is conventional. I found a lot of online suggestions regarding nested dictionary comprehension.
But I want the output to come out like below-
{{'Name': 'item1', 'Price': '1'}, {'Name': 'item3', 'Price': '3'}, {'Name': 'item5', 'Price': '5'}, {'Name': 'item7', 'Price': '7'}, {'Name': 'item9', 'Price': '9'}}
Thanks in advance!

Answer 1

This is not possible, as the dict objects are not hashable.
{{1:2}} would mean putting a dict {1:2} into a set, which is not possible because of the un-hashability of the objects mentioned above. Better put them in a list:
[{1:2}, {2:3}]

Answer 2

What you want is something like a list of dictionaries. And this {{'Name': 'item1', 'Price': '1'}, {'Name': 'item3', 'Price': '3'}, {'Name': 'item5', 'Price': '5'}, {'Name': 'item7', 'Price': '7'}, {'Name': 'item9', 'Price': '9'}} is invalid as dictionary is considered to be a key-value pair and there is no key in this.
It can be checked by assigning the above to a variable and then checking its type.
d = {{'Name': 'item1', 'Price': '1'}, {'Name': 'item3', 'Price': '3'}, {'Name': 'item5', 'Price': '5'}, {'Name': 'item7', 'Price': '7'}, {'Name': 'item9', 'Price': '9'}}
print(type(d))
It will result in an error saying it's unhashable.