How can I emphasize an impex macro if it is part of a string?
We can do something like this:
$prefix=alpha
$contentCatalog=$prefixContentCatalog
... and $contentCatalog will return "alphaContentCatalog".
Can I make the macro more explicit with something like:
$contentCatalog={$prefix}ContentCatalog
... so that I can immediately see that the macro is $prefix? Is there a syntax for this? (NOTE: The curly brace is just an example. This syntax/symbol doesn't exist for this purpose)
Another example: If I have something like below, it becomes confusing:
$prefix=electronics
$contentCatalog=$prefixContentCatalog
$contentCatalogFolderName=$contentCatalogFolder
But it can be easier to understand if it can be written as:
$prefix=electronics
$contentCatalog={$prefix}ContentCatalog
$contentCatalogFolderName={$contentCatalog}Folder
Hhmmm, unfortunately I don't think there is anything for this. I only see some workarounds like special naming for macro variables:
$_prefix_=electronics
$_contentCatalog_=$_prefix_ContentCatalog
$contentCatalogFolderName=$_contentCatalog_Folder
there is an alternate way to customize the micro via injecting property in local.properties and using ConfigPropertyImportProcessor.
UPDATE GenericItem[processor = de.hybris.platform.commerceservices.impex.impl.ConfigPropertyImportProcessor]; pk[unique = true]
$contentCatalog = $config-ly.br.content.catalog
$contentCV = catalogVersion(CatalogVersion.catalog(Catalog.id[default = $contentCatalog]), CatalogVersion.version[default = Staged])[default = $contentCatalog:Staged]
and entries should be added in local.properties.
ly.br.content.catalog=TestContentCatalog
Note:This is useful when we have multi-country.
Related
I need to update one field of a very large default record.
As the default may change I don't want to rebuild the entire record manually.
Now I have come across the following way of doing this, but I am not sure how it works:
unaggregate :: MyResult -> MyResult
unaggregate calc#MyResult{..} = calc{ the_defaults = the_override
`mappend` the_defaults }
where
the_override = create ("aggregation" := False)
I have tried searching for 'Haskell # operator' in Google but it does not return immediately useful information.
I saw somewhere calc#MyResult{..} does pattern matching on variables but I don't see what variable calc does for the MyResult record...
Also I have looked up mappend (and Monoids) and I am not sure how these work either...
Thank you for any help
The # symbol is called an "as-pattern". In the example above, you can use calc to mean the whole record. Usually you'd use it like this: calc#(MyResult someResult) -- so you can have both the whole thing and the pieces that you're matching. You can do the same thing with lists (myList#(myHead:myTail)) or tuples (myTuple#(myFst, mySnd). It's pretty handy!
MyResult{..} uses RecordWildcards. Which is a neat extension! BUT RecordWildcards doesn't help you update just one field of a record.
You can do this instead: calc { theFieldYouWantToUpdate = somethingNew }.
Which setting(s) in Resharper 8 are reformatting my object initializer like this? (i.e. with the comma on it's own line).
var snowDepthProcessor = new DataProcessor<SnowDepthModel>
{
Name = "Snow Depth"
,
DataRetriever = snowReportRetriever
,
Parser = new SnowDepthParser()
,
...
};
I've tried every combination of settings I can find/think of; I do want the lines chopped but I don't want the comma to be on its own line.
I share your pain. I've to admit my solution is just partial because it needs change style from what you'd like to use to
List<string> demo = new List<string>
{
"a",
"b",
"c"
}
Then formatting is not changed. I'd also much rather use syntax you've described so I've created R# ticket https://youtrack.jetbrains.com/issue/RSRP-453704 but until it's resolved this is only way how suppress that (it behave in same way even in latest R#10)
EDIT: Good news. Seems to be fixed since R# 2017.1
I know the title is confusing, but I can't figure our how to word it properly. I'm trying to figure out how to properly format a compound conditional in an IF statement in Excel. It's for a school project that's due tomorrow.
I already have something like this
=if(AND(b152="oval.jpg",c152="q'")OR(AND(b152="triangle.jpg", c153="p'")), "Correct", "Incorrect")
In psuedocode I want it to run something like this:
if (b152=="oval.jpg" && c152=="q'") or (b152=="triangle.jpg", c153="p'"):
print("YES!")
else
print("False!")
I know I'm missing something here. My current excel code returns false even if the conditions are true. Thanks ahead of time!
OR is a function in Excel, like AND. Try something like this:
=if(OR(AND(b152 = "oval.jpg", c152 = "q'"), AND(b152 = "triangle.jpg", c153 = "p'")), "Correct", "Incorrect")
As in Effect.shadow() is deprecated in PlayN1.3.So i had something like this before :
TextFormat textFormat = new TextFormat(myFont, textWidth, Alignment.LEFT, colorCode, Effect.shadow(-16777216, shadowX, shadowY));
So i changed it to this :
TextFormat textFormat = new TextFormat();
textFormat.withFont(myFont);
textFormat.withWrapping(textWidth, Alignment.LEFT);
I dont want shadow now.It's ok but i did not get previous like result.Hold on.dont think now.Then i changed this code to this:
TextFormat textFormat = new TextFormat().withFont(myFont).withWrapping(textWidth, Alignment.LEFT);
It gives me result as previous except shadow which i dont care now.If i am not wrong this is one line representation of above code.Is not it?
So why it worked and above code did not.Any conceptual difference is there? Anyone can explain please!
//note: dont worry about variables(textWidth,myFont)they are nothing to do with this.
TextFormat objects are immutable. When you call textFormat.withFont(myFont) that returns a new TextFormat instance, which the code above is throwing away. If you want the first code to work you need to write it like this:
TextFormat format = new TextFormat();
format = format.withFont(myFont);
format = format.withWrapping(textWidth, Alignment.LEFT);
Do you know of any way to reference an object in the replacement part of preg_replace. I'm trying to replace placeholders (delimited with precentage signs) in a string with the values of attributes of an object. This will be executed in the object itself, so I tried all kinds of ways to refer to $this with the /e modifier. Something like this:
/* for instance, I'm trying to replace
* %firstName% with $this->firstName
* %lastName% with $this->lastName
* etc..
*/
$result = preg_replace( '~(%(.*?)%)~e', "${'this}->{'\\2'}", $template );
I can't get any variation on this theme to work. One of the messages I've been getting is: Can't convert object Model_User to string.
But of course, it's not my intention to convert the object represented by $this to a string... I want to grab the attribute of the object that matches the placeholder (without the percentage signs of course).
I think I'm on the right track with the /e modifier. But not entirely sure about this either. Maybe this can be achieved much more simple?
Any ideas about this? Thank you in advance.
Like I commented to Paul's answer: in the meanwhile I found the solution myself. The solution is much more simple than I thought. I shouldn't have used double quotes.
The solution is as simple as this:
$result = preg_replace( '~(%(.*?)%)~e', '$this->\\2', $template );
Hope this helps anyone else for future reference.
Cheers.
Check out preg_replace_callback - here's how you might use it.
class YourObject
{
...
//add a method like this to your class to act as a callback
//for preg_replace_callback...
function doReplace($matches)
{
return $this->{$matches[2]};
}
}
//here's how you might use it
$result = preg_replace_callback(
'~(%(.*?)%)~e',
array($yourObj, "doReplace"),
$template);
Alternatively, using the /e modifier, you could maybe try this. I think the only way to make it work for your case would be to put your object into global scope
$GLOBALS['yourObj']=$this;
$result = preg_replace( '~(%(.*?)%)~e', "\$GLOBALS['yourObj']->\\2", $template );