Linux Bash: List interfaces with IPs and Mac addresses - linux

Question

I am working on a CentOS. This is my first time messing around in a UNIX-based OS, and having a hard time getting used to it. I have more solid experience with Powershell.
Anyway, my task is to list all the Interfaces and their corresponding IP and MAC addresses. Is there a simple way to do this?
I discovered that
ip addr
apparently has all the information I need, but I have no idea how could I "cut out" the information I need from the string. I want to list them in some readable format, like this:
interfacename ipaddress macaddress

Answer 1

Write a script like this:
#!/bin/bash
printf '%10s %32s %32s\n' interface ipaddress macaddress
printf '%s\n' '----------------------------------------------------------------------------'
for each in $(ip address | grep -oP '(^[\d]+:\s)\K[\d\w]+'); do
mac=$(ip address show ${each} | grep -oP '(?<=link/ether\s)\K[\da-f:]+|(?<=link/loopback\s)\K[\da-f:]+')
for address in $(ip address show ${each} | grep -oP '(?<=inet\s)\K[\d.]+|(?<=inet6\s)\K[\da-f:]+'); do
printf '%10s %32s %32s\n' ${each} ${address} ${mac}
done
done
Output:
interface ipaddress macaddress
----------------------------------------------------------------------------
lo 127.0.0.1 00:00:00:00:00:00
lo ::1 00:00:00:00:00:00
wlo1 192.168.0.7 c8:aa:bb:cc:dd:ee
wlo1 fe80::7aec:8287:9f45:d833 c8:aa:bb:cc:dd:ee
docker0 172.17.0.1 02:42:0d:0d:0d:0d
tap0 10.1.30.2 16:50:cc:cc:cc:cc
tap0 fe80::10a9:d3ff:fece:57d7 16:50:cc:cc:cc:cc