I am trying to build a hackernews scraper but when i ran my code
import requests
from bs4 import BeautifulSoup
res = requests.get("https://news.ycombinator.com/")
soup = BeautifulSoup(res.text,'html.parser')
print(soup.find(id="score_23174015"))
I am Not getting that why beautifulsoup is returning none all the time to me i am still learning so yeah i am new to python3 as well
I checked the url, but there is no element with id = 23174015.
Anyway, try this code if you want to find element with attributes.
soup.find(attrs = {'id':"score_23167794"})
Related
While comparing response from code and chrome source code. I observe that response returned from beautifulsoup does not match with page source code. I want to fetch class="rc"and I can see the class with "rc" on page source code, but could not find it in the response printed. I checked with "lxml" and "html.parser" too.
I am beginner in python so my question might sound basic. Also, I already checked few articles related to my problem(BeautifulSoup returning different html than view source) but could not find solution.
Below is my code:
import sys, requests
import re
import docx
import webbrowser
from bs4 import BeautifulSoup
query = sys.argv
url = "https://google.com/search?q=" + "+".join(query[1:])
print(url)
res = requests.get(url)
# print(res[:1000])
if res.status_code == 200:
soup = BeautifulSoup(res.text, "html5lib")
print(type(soup))
all_select = soup.select("div", {"class": "rc"})
print("All Select ", all_select)
I had the same problem, try using another parser such as "lxml" instead of "html5lib".
I'm trying to track the price for a product on amazon using python in jupyter notebook. I've imported bs4 and requests for this task.
When I inspect HTML in the product page I can see <span id="productTitle" class="a-size-large">
However when I try to search for it using soup.find(id = "productTitle") The results come out as None
I've tried using soup.find other id and classes but the results are still None
title = soup.find(id="productTitle")
This is my code to find the id
If I fix this I hope to be able to get the name of my product whose price I will be tracking
That info is stored in various places in return html. Have you check your response to see you are not blocked or getting an unexpected response?
I found it with that id using and strip
import requests
from bs4 import BeautifulSoup as bs
r = requests.get('https://www.amazon.com/dp/B00M4LWO8O/')
soup = bs(r.content, 'lxml')
print(soup.select_one('#productTitle').text.strip())
Also,
import requests
from bs4 import BeautifulSoup as bs
r = requests.get('https://www.amazon.com/dp/B00M4LWO8O/')
soup = bs(r.content, 'lxml')
print(soup.select_one('#imgTagWrapperId img[alt]')['alt'])
I'm very new to programming in general and I'm trying to write my own little torrent leecher. I'm using Beautifulsoup In order to extract the title and the magnet link of a torrent file. However find() element keeps returning none no matter what I do. The page is correct. I've also tested with find_next_sibling and read all the similar questions but to no avail. Since there are no errors I have no idea what my mistake is.
Any help would be much appreciated. Below is my code:
import urllib3
from bs4 import BeautifulSoup
print("Please enter the movie name: \n")
search_string = input("")
search_string.rstrip()
search_string.lstrip()
open_page = ('https://www.yify-torrent.org/search/' + search_string + '/s-1/all/all/') # get link - creates a search string with input value
print(open_page)
urllib3.disable_warnings(urllib3.exceptions.InsecureRequestWarning)
manager = urllib3.PoolManager(10)
page_content = manager.urlopen('GET',open_page)
soup = BeautifulSoup(page_content,'html.parser')
magnet = soup.find('a', attrs={'class': 'movielink'}, href=True)
print(magnet)
Check out the following script which does exactly what you wanna achieve. I used requests library instead of urllib3. The main mistake you made is that you looked for the magnet link in the wrong place. You need to go one layer deep to dig out that link. Try using quote instead of string manipulation to fit your search query within the url.
Give this a shot:
import requests
from urllib.parse import urljoin
from urllib.parse import quote
from bs4 import BeautifulSoup
keyword = 'The Last Of The Mohicans'
url = 'https://www.yify-torrent.org/search/'
base = f"{url}{quote(keyword)}{'/p-1/all/all/'}"
res = requests.get(base)
soup = BeautifulSoup(res.text,'html.parser')
tlink = urljoin(url,soup.select_one(".img-item .movielink").get("href"))
req = requests.get(tlink)
sauce = BeautifulSoup(req.text,"html.parser")
title = sauce.select_one("h1[itemprop='name']").text
magnet = sauce.select_one("a#dm").get("href")
print(f"{title}\n{magnet}")
So 2 days ago i was trying to parse the data between two same classes and Keyur helped me a lot then after he left other problems behind.. :D
Page link
Now I want to get the links under a specific class, here is my code, and here are the errors.
from bs4 import BeautifulSoup
import urllib.request
import datetime
headers = {} # Headers gives information about you like your operation system, your browser etc.
headers['User-Agent'] = 'Mozilla/5.0' # I defined a user agent because HLTV perceive my connection as bot.
hltv = urllib.request.Request('https://www.hltv.org/matches', headers=headers) # Basically connecting to website
session = urllib.request.urlopen(hltv)
sauce = session.read() # Getting the source of website
soup = BeautifulSoup(sauce, 'lxml')
a = 0
b = 1
# Getting the match pages' links.
for x in soup.find('span', text=datetime.date.today()).parent:
print(x.find('a'))
Error:
Actually there isn't any error but it outputs like:
None
None
None
-1
None
None
-1
Then i researched and saw that if there isn't any data to give, find function gives you nothing which is none.
Then i tried to use find_all
Code:
print(x.find_all('a'))
Output:
AttributeError: 'NavigableString' object has no attribute 'find_all'
This is the class name:
<div class="standard-headline">2018-05-01</div>
I don't want to post all the code to here so here is the link hltv.org/matches/ so you can check the classes more easily.
I'm not quite sure I could understand what links OP really wants to grab. However, I took a guess. The links are within compound classes a-reset block upcoming-match standard-box and if you can spot the right class then one individual calss will suffice to fetch you the data like selectors do. Give it a shot.
from bs4 import BeautifulSoup
from urllib.request import Request, urlopen
from urllib.parse import urljoin
import datetime
url = 'https://www.hltv.org/matches'
req = Request(url, headers={"User-Agent":"Mozilla/5.0"})
res = urlopen(req).read()
soup = BeautifulSoup(res, 'lxml')
for links in soup.find(class_="standard-headline",text=(datetime.date.today())).find_parent().find_all(class_="upcoming-match")[:-2]:
print(urljoin(url,links.get('href')))
Output:
https://www.hltv.org/matches/2322508/yeah-vs-sharks-ggbet-ascenso
https://www.hltv.org/matches/2322633/team-australia-vs-team-uk-showmatch-csgo
https://www.hltv.org/matches/2322638/sydney-saints-vs-control-fe-lil-suzi-winner-esl-womens-sydney-open-finals
https://www.hltv.org/matches/2322426/faze-vs-astralis-iem-sydney-2018
https://www.hltv.org/matches/2322601/max-vs-fierce-tiger-starseries-i-league-season-5-asian-qualifier
and so on ------
I'm trying to scrape the Stack Overflow jobs page using Beautiful Soup 4 and URLLIB as a personal project. I'm facing an issue where I'm trying to scrape all the links to the 50 jobs listed on each page. I'm using a regex to identify these links. Even though I reference the tag properly, I am facing these two specific issues:
Instead of the 50 links clearly visible in the source code, I get only 25 results each time as my output(after accounting for an removing an initial irrelevant link)
There's a difference between how the links are ordered in the source code and my output.
Here's my code. Any help on this will be greatly appreciated:
import bs4
import urllib.request
import re
#Obtaining source code to parse
sauce = urllib.request.urlopen('https://stackoverflow.com/jobs?med=site-ui&ref=jobs-tab&sort=p&pg=0').read()
soup = bs4.BeautifulSoup(sauce, 'html.parser')
snippet = soup.find_all("script",type="application/ld+json")
strsnippet = str(snippet)
print(strsnippet)
joburls = re.findall('https://(?:[a-zA-Z]|[0-9]|[$-_#.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+', strsnippet)
print("Urls: ",joburls)
print(len(joburls))
Disclaimer: I did some asking of my own for a part of this answer.
from bs4 import BeautifulSoup
import requests
import json
# note: link is slightly different; yours just redirects here
link = 'https://stackoverflow.com/jobs?med=site-ui&ref=jobs-tab&sort=p'
r = requests.get(link)
soup = BeautifulSoup(r.text, 'html.parser')
s = soup.find('script', type='application/ld+json')
urls = [el['url'] for el in json.loads(s.text)['itemListElement']]
print(len(urls))
50
Process:
Use soup.find rather than soup.find_all. This will give a JSON bs4.element.Tag
json.loads(s.text) is a nested dict. Access the values for itemListElement key to get a dict of urls, and convert to list.