Okay so my question is how do i use IF with 3 arguments while one of the arguments is "Ignore blanks".
If A1 is "Escalation_complaint or "Escalation_request" B1 must show "Escalated".
If A1 is any other text, B1 must show "Solved"
If A1 is blank, B1 must remain empty.
Can someone please help me figure this out?
Your first test must be whether the A1 is empty or not. This must be the first because if you test whether an empty string is contained in another string the answer is always yes. =SEARCH("","Something") returns 1. So, How do you test for an empty cell? I recommend Excel's COUNTA() function but you may prefer testing for "". So, let's say, your first test is this.
=IF(COUNTA(A1), True, False)
Some would say IF(COUNTA(A1)>0, True, False) and that is equivalent. The simple IF(COUNTA(A1) tests for non-zero. Any number other than zero returns True.
So, now you got your basic function. What's supposed to happen if the result is True? What do you want to happen if the result is False? The latter is easy. If the result is False you want a null string returns. So, now your formula looks like this:-
=IF(COUNTA(A1), True, "")
Observe that we simply replaced the False with the desired output. So, what do you want to happen if A1 has something in it, if the first test resulted in True? There are two possibilities. That makes the problem solvable with a single IF. IF A1 has something starting with "Escalation" in it the result should be "escalate", else it should be "solved". So, how do you test for cell content?
=Find("escalation", A1) will not find "Escalation" (with a capital E). Therefore I recommend SEARCH(), which does.
=SEARCH("escalation", A1) should return 1. If it returns 1 your problem is solved because if it returns any other number its not "escalated" but "solved". Unfortunately, there is a third option. It might return an error. In fact it will return an error every time the word isn't found. That gives you a 3-way possibility (1, bigger than 1, or Error) which can't be solved with a single IF. So, I suggest to avoid the error.
=Find("escalation", A1 & "escalation") will find the word "escalation" every time. But it will find it in first position only if the conditions for "Escalate" is met. Therefore the formula for the True condition in the basic formula must be this:-
IF(SEARCH("escalation", A1 & "escalation") = 1, "Escalated", "Solved")
That's it. Assemble the second IF into the first and you're done.
So, using two if(), and minimising the testing you need :
=IF(left(A1,3)="Esc","Escalated",IF(A1="","","Solved"))
Edit: Based on a comment to another answer, if testing for "esc" only could lead to problems then how about:
=IF(left(A1,5)="Escal","Escalated",IF(A1="","","Solved"))
Which will avoid words like "escaped" or "escargot"...
If you know that the text will always be Escalation_complaint or Escalation_request, you can do this with a nested IF query. =IF in Excel takes three parameters: what to verify, result if true, and result if false. You can have another IF statement in the what to do if it returns false section. We can also do an OR() statement to verify both Escalation_complaint and Escalation_request. The result looks like this:
=IF(OR(A1="Escalation_complaint",A1="Escalation_request"),"Escalated",IF(A1="","","Solved"))
The order here is important because you want the "for all other cases" to be in the final IF statement.
If you have a situation where you could also have "Request_escalation" or "complaint_escalation", you should make a more general solution that uses SEARCH or FIND which would allow you to do a more general lookup that allows for more values without having to hardcode them. Here is an example that makes it possible to find the word Escalation anywhere in the cell:
=IF(IFERROR(SEARCH("escalation",A1,1),0)>0, "Escalated", IF(A1="","","Solved"))
Excel have maximum 30 arguments in a formula.
= if (A1=1, "True",if(B1>2,"True", "false"))
Understand this pattern. easy way.
If you no longer understand this, or if your problem has not been resolved, attach a file or screenshot that relates to your problem.
Related
=IF(AND(F2=N2;G2>O2);"No Notificar";"Notificar";IF(AND(F2=N3;G2>O3);"No Notificar";"Notificar";IF(AND(F2=N4;G2>O4);"No Notificar";"Notificar";IF(AND(F2=N5;G2>O5);"No Notificar";"Notificar";IF(AND(F2=N6;G2>O6);"No Notificar";"Notificar";IF(AND(F2=N7;G2>O7);"No Notificar";"Notificar")))))
As #KromeWing said - you've entered too many parameters for an IF formula.
It should have a logical calculation that would return TRUE/FALSE and then what to do if it's TRUE and what to do if it's FALSE.
Currently your formula reads as:
=IF(AND(F2=N2,G2>O2),"No Notificar","Notificar",
IF(AND(F2=N3,G2>O3),"No Notificar","Notificar",
IF(AND(F2=N4,G2>O4),"No Notificar","Notificar",
IF(AND(F2=N5,G2>O5),"No Notificar","Notificar",
IF(AND(F2=N6,G2>O6),"No Notificar","Notificar",
IF(AND(F2=N7,G2>O7),"No Notificar","Notificar")))))
It should look more like:
=IF(AND(F2=N2,G2>O2),"No Notificar",
IF(AND(F2=N3,G2>O3),"No Notificar",
IF(AND(F2=N4,G2>O4),"No Notificar",
IF(AND(F2=N5,G2>O5),"No Notificar",
IF(AND(F2=N6,G2>O6),"No Notificar",
IF(AND(F2=N7,G2>O7),"No Notificar","Notificar"))))))
So if the first equation is TRUE it will show No Notificar, otherwise it will test the second equation. If all equations return FALSE then it will return Notificar.
IF has only 3 parameters.
Your consecutive IF should be the 3rd parameter, there is no 4th parameter in this formula.
You are expecting IF() to accept four arguments instead of three.
I often get messed up by nested ifs, too, and it's usually from having to think too hard.
To make things easier on yourself, both today and next month when you come back to this and have to try to figure out what the heck you were trying to do, try using alt-enter to add a new line within your formula, allowing you to format your formula like this:
=IF(test, valueIfTest,
IF(test2, valueIfTest2,
IF(test3, valueIfTest3,
...
valueIfAllTestsFail
)))
I find that as long as I stick to this format, the hardest part of the syntax is reduced to having the right number of closing parentheses at the end, but thanks to how Excel color-codes matching parentheses, I can manage that even when I'm caffeine-deprived!
I would like to set a multiple IF statement for my formula.
The reason behind it is, that I need to switch off the values (mark them as N/A and NA) which are equal to the other certain values as follows:
LP372/24/60+1=($NO372-720)/24/60+1 => mark them as N/A - the values, which don't happen during the midnight
and
LP372/24/60+1=$NO372/24/60+1 => mark them as NA - the values, that don't happen during the midday
The problem is, that I can't keep them under one IF statement, because I need the division.
So far I used only one IF statement (the nested one), which looks as follows:
=IF(OR((LP372/24/60+1)=(($NO372-720)/24/60+1), OR((LP372/24/60+1)=($NO372/24/60+1))),"N/A",LP372/24/60+1).
The value of NO372 corresponds to the rough time of the local midday. Substracting the 720 we are getting the rough midday for this location, knowing that the single day counts 24 hours x 60mins = 1440mins.
The formula above gives a nice result, but without the division between midday and midnight, which I am talking about.
Following my older query about the similar issue:
Double nested IF statement formula in Excel
I tried to solve it like this:
=IF(COUNTA(E1116:E1481),IF(OR((LP372/24/60+1)=(($NO372-720)/24/60+1),OR((LP372/24/60+1)=($NO372/24/60+1))),"N/A",LP372/24/60+1),"NA")
where the range E1116:E1481 corresponds to the whole year period (1.01 - 31.12).
Unfortunately I got nothing, similarity to this formula:
=IF(COUNTA(E1116:BC1116),IF(OR((LP372/24/60+1)=(($NO372-720)/24/60+1),OR((LP372/24/60+1)=($NO372/24/60+1))),"N/A",LQ510/24/60+1),"NA"),
where the E:1116:BC1116 range correspond to the all columns - circumstances as occur on January 1.
This formula was still not correct.
I found something on the web about the multiple IF statements:
which led me to the following formula
=IF((LP372/24/60+1)=(($NO372-720)/24/60+1);"N/A";IF((LP372/24/60+1)=($NO372/24/60+1);"NA")LP372/24/60+1)
Unfortunately again not correct.
The last attempt was an answer provided here:
Multiple IF statements in Excel
on which basis I built up another formula
=IF((LP372/24/60+1)=(($NO372-720)/24/60+1),"N/A",LP372/24/60+1,IF((LP372/24/60+1)=($NO372/24/60+1),"NA"))
this time Excel said, that I've entered too many arguments.
Is there a way to set up multiple IF statements?
I need to:
make the values equal to midnight as N/A,
make the values equal to midday as NA
keep the other values as they stand
This question was answered in the comments, but I thought I would add an answer with an example of how to nest IF statements for anyone that found this question because they are having issues with nesting IF statements.
When you add an IF statement to a formula in excel, you have to keep in mind that IF statements have 3 parts separated with commas:
The first value is the condition you are going to check
The second value is the value you want returned if that condition is true
The third value is the value you want returned if that condition is false
So here's an example that illustrates that:
=IF(condition to check, value if condition is true, value if condition is false)
Here is an example IF statement:
=IF(A1="Hello","World","something else")
If you are getting FALSE returned then your IF statement probably looks like this:
=IF(A1="Hello","World")
Notice that there are only 2 values inside this IF statement: the condition you are checking (A1="Hello") and what you want displayed if that is true ("World"). FALSE would be displayed if the value in A1 is something other than Hello because you haven't included the third value in the IF that defines what you want displayed if A1 is not Hello (this value is listed as something else in the example above)
It's best to try and avoid nesting IF statements if you can because they can be hard to keep track of. I would suggest using AND() or OR() instead if you can. They are very similar to each other, you list multiple conditions within the parens separated by commas that you will be checking against, and both evaluate to either True or False. The only difference is that for AND() every condition within the parens needs to be true for it to evaluate to True where OR() only one of the conditions listed in the parens needs to be true for it to return True.
So, for example, if you wanted to display World if A1 is Hello or Hi and you were to use nested IF statements it would look like this:
=IF(A1="Hello","World",IF(A1="Hi","World","something else"))
which in my opinion is really ugly. however, if you used OR() instead of nesting IF statements it would look like this:
=IF(OR(A1="Hello",A1="Hi"),"World","something else")
AND() works the same way, but instead of just needing one condition within the parens to be true to return True as OR() does, with AND() all conditions inside of the AND() need to be true to display your value instead of just one. here's an example AND():
=IF(AND(A1="Hello",B1=""),"World","something else")
in this case "World" would be displayed only if A1 is Hello AND B1 is empty
for both AND() and OR() you can have more than just 2 values inside if you need to check for more than 2 conditions, you just need to separate them each with commas, like this:
AND(condition1, condition2, condition3, ....)
OR(condition1, condition2, condition3, .....)
but, if you have to use nested IF statements, the easiest way I've found is to type IF( , , ) first thing to make sure you are allowing for all 3 values that need to be inside of the IF and you have the right amount of values inside the IF. If you are getting the message You've entered too many arguments for this function it is because you have entered more than 3 values inside your IF, like this:
=IF(A1="Hello","World","something else","this value is causing the issue")
so, to properly nest an IF in your formula, type IF( , , ) first off where you want the IF statement to be in your formula and then just fill in the blanks, then you avoid entering too few values which results in FALSE being displayed if your condition is not true or You've entered too many arguments for this function because you entered more than 3 values in your IF
Hope this helps to understand IF statements and how to nest them properly.
I have column I as a calulation column and this is what I currently wrote.
and this gives me nothing.
=IF(B2<>""&D2<>"",B2*D2,IF(B2<>""&D2=""&C2<>"",B2*C2,IF(A2<>""&C2<>""&AND(B2&D2=""),A2*C2,IF(A2<>""&C2=""&D2<>""&B2="",A2*D2,A2*C2))))
The logic is if B2 and D2 are not null multiply b2*d2
if B2 is not null and D2 null then b2*c2
If B2 is null and D2 is not null then a2*d2
else a2*c2
Is any ways to make this code work?
Thank you
Alternative ways or rewriting your formula:
=IF(AND(B2<>"",D2<>""),B2*D2,IF(D2="",IF(B2<>"",B2*C2,A2*C2),IF(D2<>"",A2*D2,A2*C2)))
=IF(AND(B2<>"",D2<>""),B2*D2,IF(AND(B2="",D2=""),A2*C2,IF(D2="",B2*C2,A2*D2)))
They will make negligible difference in performance and what not. BruceWayne's answer is probably more readable in terms of following your logic and therefore easier to maintain or understand in the future. The above answers should provide the same results but are a few characters shorter in length.
And as a wacky alternative for thinking potentially outside the box:
=CHOOSE(SUM((B2<>"")*2+(D2<>""))+1,A2*C2,A2*D2,B2*C2,B2*D2)
Expanding (not just my waist size)
I had time on my hands so I was fooling around with the concept of TRUE and FALSE being equal to 1 and 0 when sent through a math operation. When I started looking at the options this reminded me of how a binary number works. Not that I have bgiven it too much thought, but I think it works because the options for each cell are binary or TRUE/FALSE. Since every possible combination was covered with a unique out come, I just had to come up with a formula that would produce unique results. In this case I just took the converting a a binary number approach. The key is TRUE = 1 after a math operation and FALSE = 0. Now going the other direction is not quite the same but as Jeeped once put it, 0 is FALSE and everything else is TRUE. so 3, -3, and 3.14 are all treated as TRUE if using the numerical values as the outcome of a logic check.
=IF(3.14,"THIS NUMBER IS TRUE","ONLY 0 IS FALSE")
So less side tracking and back on point (not sure how much I need to expand to!).
Looking at the table above, you will note in the yellow area, all possible combination for BLANK and NOT BLANK are listed. If you then assign a value to the column the same way binary numbers are (note row A) you can then start generating all the possible numbers
I started by generating the list I needed in E2:E5 for numbers that CHOOSE could work with. I assumed 0 would beat up CHOOSE and cause it to fail. I knew that FALSE+FALSE=0 and I also knew that TRUE+TRUE=2 and that both TRUE+FALSE=1 and FALSE+TRUE=1. I needed a way to distinguish the later two and I knew I needed a total of 4 results. That is when binary counting/conversion whatever you want to call it kicked in. I placed the following formula in D2 and copied down
=SUM((A2<>"")*2+(B2<>""))
Note the brackets around the logic check and
that the logic checks are sent through a math
operation before being summed.
technically speacking it is really:
=SUM((A2<>"")*2+(B2<>"")*1)
however the *1 is not needed
once I had that list generate, it was a simple +1 added to it to get into the 1 to 4 range seen in E2:E5.
Now that I had a way of generating the index number the only thing left to do was to match up the required results/formula with the right combination.
=CHOOSE(SUM((A2<>"")*2+(B2<>""))+1,"A","B","C","D")
Well I felt like I was beating a dead horse there for a bit, so if I over explained, my apologies. If there is something still missing ask for more explination.
UPDATE TID BIT
IF there were more columns to check it may be possible to adjust the choose formula by simply adding the next binary value to the column and making sure there is an appropriate number of results in the choose list. There should be 2^(# of columns to check) options
=CHOOSE(SUM((A2<>"")*4+(A2<>"")*2+(B2<>""))+1,"A","B","C","D","E","F","G","H")
Which kind of beats multiple nested IFs for brevity, but I think I finds the nested IFs easier to understand.
You should be using AND():
=IF(AND(B2<>"",D2<>""),B2*D2,IF(AND(B2<>"",D2=""),B2*C2,IF(AND(B2="",D2<>""),A2*D2,A2*C2)))
You seem to be mixing operators from other programming languages:
In Excel:
AND : binary operator : AND(TRUE, FALSE) => FALSE
& : concatenation : "Hello " & "World" => "Hello World"
I have an Excel file I'm working with. There is a column that contains numbers and text, sometimes it's just one or the other. I'm trying to write a function that scans the left most part of the cell to see if it starts with a number. I thought I had it but apparently not. This is what I had:
=IF(ISNUMBER(LEFT(E8,1)), "True", "False")
This continues to throw me a "false" result even though that particular cell, E8, begins with a "3". What am I missing here?
Try this out:
=IF(ISNUMBER(VALUE(LEFT(E8,1))),"True","False")
Using the IF statement is redundant. The most simple and effective way to achieve your desired result is:
=ISNUMBER(--LEFT(E8,1))
It will automatically return TRUE or FALSE
Note that you can achieve what you require with just the following:
=NOT(ISERROR(LEFT(E8)*1))
If you do not LEFT(E8) evaluates to LEFT(E8,1) and multiplication by 1 throws an error on anything non-numeric
If you need your output as strings then update as per below:
IF(NOT(ISERROR(LEFT(E8)*1)),"True","False")
EDIT
Using ISNUMBER() is a good alternative to NOT(ISERROR())
=ISNUMBER(LEFT(A1)*1)
=IF(ISNUMBER(LEFT(A1)*1),"True","False")
=IFERROR(IF(VALUE(LEFT(E8,1)),"TRUE","FALSE"),"FALSE")
In a spreadsheet I'm using, some of the possibilities for a cell is being blank, having the number zero, or having a non-zero number, or having a string.
If I want to test if the cell is zero, but is not blank, I currently do
=IF(AND(B2=0,LEN(B2)>0),foo,bar)
Is there a way of replacing the two conditionals with one conditional?
You can certainly use the function isblank(B2) instead of testing for length > 0.
But since you're testing for two conditions: not blank, and 0, I don't see how you can avoid two conditionals--unless--you're happy that 0 equates to not blank (which it does), then all you have to test for is 0.
The function you are looking for is the ISBLANK() function.
=IF(AND(ISBLANK(A1)=FALSE,A1=0),"foo","bar")
EDIT:
Sorry I just re-read your question. You're forced to use 2 conditionals because you're checking for two conditions. If you wanted to just use one condition for whatever reason the only way that I can think of is to extract the conditions you are checking into a method and then call it.
So, it becomes
=IF(CheckCellIsOK(A1),"foo","bar")
The method still checks both conditions but you're just hiding that fact.