I have column I as a calulation column and this is what I currently wrote.
and this gives me nothing.
=IF(B2<>""&D2<>"",B2*D2,IF(B2<>""&D2=""&C2<>"",B2*C2,IF(A2<>""&C2<>""&AND(B2&D2=""),A2*C2,IF(A2<>""&C2=""&D2<>""&B2="",A2*D2,A2*C2))))
The logic is if B2 and D2 are not null multiply b2*d2
if B2 is not null and D2 null then b2*c2
If B2 is null and D2 is not null then a2*d2
else a2*c2
Is any ways to make this code work?
Thank you
Alternative ways or rewriting your formula:
=IF(AND(B2<>"",D2<>""),B2*D2,IF(D2="",IF(B2<>"",B2*C2,A2*C2),IF(D2<>"",A2*D2,A2*C2)))
=IF(AND(B2<>"",D2<>""),B2*D2,IF(AND(B2="",D2=""),A2*C2,IF(D2="",B2*C2,A2*D2)))
They will make negligible difference in performance and what not. BruceWayne's answer is probably more readable in terms of following your logic and therefore easier to maintain or understand in the future. The above answers should provide the same results but are a few characters shorter in length.
And as a wacky alternative for thinking potentially outside the box:
=CHOOSE(SUM((B2<>"")*2+(D2<>""))+1,A2*C2,A2*D2,B2*C2,B2*D2)
Expanding (not just my waist size)
I had time on my hands so I was fooling around with the concept of TRUE and FALSE being equal to 1 and 0 when sent through a math operation. When I started looking at the options this reminded me of how a binary number works. Not that I have bgiven it too much thought, but I think it works because the options for each cell are binary or TRUE/FALSE. Since every possible combination was covered with a unique out come, I just had to come up with a formula that would produce unique results. In this case I just took the converting a a binary number approach. The key is TRUE = 1 after a math operation and FALSE = 0. Now going the other direction is not quite the same but as Jeeped once put it, 0 is FALSE and everything else is TRUE. so 3, -3, and 3.14 are all treated as TRUE if using the numerical values as the outcome of a logic check.
=IF(3.14,"THIS NUMBER IS TRUE","ONLY 0 IS FALSE")
So less side tracking and back on point (not sure how much I need to expand to!).
Looking at the table above, you will note in the yellow area, all possible combination for BLANK and NOT BLANK are listed. If you then assign a value to the column the same way binary numbers are (note row A) you can then start generating all the possible numbers
I started by generating the list I needed in E2:E5 for numbers that CHOOSE could work with. I assumed 0 would beat up CHOOSE and cause it to fail. I knew that FALSE+FALSE=0 and I also knew that TRUE+TRUE=2 and that both TRUE+FALSE=1 and FALSE+TRUE=1. I needed a way to distinguish the later two and I knew I needed a total of 4 results. That is when binary counting/conversion whatever you want to call it kicked in. I placed the following formula in D2 and copied down
=SUM((A2<>"")*2+(B2<>""))
Note the brackets around the logic check and
that the logic checks are sent through a math
operation before being summed.
technically speacking it is really:
=SUM((A2<>"")*2+(B2<>"")*1)
however the *1 is not needed
once I had that list generate, it was a simple +1 added to it to get into the 1 to 4 range seen in E2:E5.
Now that I had a way of generating the index number the only thing left to do was to match up the required results/formula with the right combination.
=CHOOSE(SUM((A2<>"")*2+(B2<>""))+1,"A","B","C","D")
Well I felt like I was beating a dead horse there for a bit, so if I over explained, my apologies. If there is something still missing ask for more explination.
UPDATE TID BIT
IF there were more columns to check it may be possible to adjust the choose formula by simply adding the next binary value to the column and making sure there is an appropriate number of results in the choose list. There should be 2^(# of columns to check) options
=CHOOSE(SUM((A2<>"")*4+(A2<>"")*2+(B2<>""))+1,"A","B","C","D","E","F","G","H")
Which kind of beats multiple nested IFs for brevity, but I think I finds the nested IFs easier to understand.
You should be using AND():
=IF(AND(B2<>"",D2<>""),B2*D2,IF(AND(B2<>"",D2=""),B2*C2,IF(AND(B2="",D2<>""),A2*D2,A2*C2)))
You seem to be mixing operators from other programming languages:
In Excel:
AND : binary operator : AND(TRUE, FALSE) => FALSE
& : concatenation : "Hello " & "World" => "Hello World"
Related
Okay so my question is how do i use IF with 3 arguments while one of the arguments is "Ignore blanks".
If A1 is "Escalation_complaint or "Escalation_request" B1 must show "Escalated".
If A1 is any other text, B1 must show "Solved"
If A1 is blank, B1 must remain empty.
Can someone please help me figure this out?
Your first test must be whether the A1 is empty or not. This must be the first because if you test whether an empty string is contained in another string the answer is always yes. =SEARCH("","Something") returns 1. So, How do you test for an empty cell? I recommend Excel's COUNTA() function but you may prefer testing for "". So, let's say, your first test is this.
=IF(COUNTA(A1), True, False)
Some would say IF(COUNTA(A1)>0, True, False) and that is equivalent. The simple IF(COUNTA(A1) tests for non-zero. Any number other than zero returns True.
So, now you got your basic function. What's supposed to happen if the result is True? What do you want to happen if the result is False? The latter is easy. If the result is False you want a null string returns. So, now your formula looks like this:-
=IF(COUNTA(A1), True, "")
Observe that we simply replaced the False with the desired output. So, what do you want to happen if A1 has something in it, if the first test resulted in True? There are two possibilities. That makes the problem solvable with a single IF. IF A1 has something starting with "Escalation" in it the result should be "escalate", else it should be "solved". So, how do you test for cell content?
=Find("escalation", A1) will not find "Escalation" (with a capital E). Therefore I recommend SEARCH(), which does.
=SEARCH("escalation", A1) should return 1. If it returns 1 your problem is solved because if it returns any other number its not "escalated" but "solved". Unfortunately, there is a third option. It might return an error. In fact it will return an error every time the word isn't found. That gives you a 3-way possibility (1, bigger than 1, or Error) which can't be solved with a single IF. So, I suggest to avoid the error.
=Find("escalation", A1 & "escalation") will find the word "escalation" every time. But it will find it in first position only if the conditions for "Escalate" is met. Therefore the formula for the True condition in the basic formula must be this:-
IF(SEARCH("escalation", A1 & "escalation") = 1, "Escalated", "Solved")
That's it. Assemble the second IF into the first and you're done.
So, using two if(), and minimising the testing you need :
=IF(left(A1,3)="Esc","Escalated",IF(A1="","","Solved"))
Edit: Based on a comment to another answer, if testing for "esc" only could lead to problems then how about:
=IF(left(A1,5)="Escal","Escalated",IF(A1="","","Solved"))
Which will avoid words like "escaped" or "escargot"...
If you know that the text will always be Escalation_complaint or Escalation_request, you can do this with a nested IF query. =IF in Excel takes three parameters: what to verify, result if true, and result if false. You can have another IF statement in the what to do if it returns false section. We can also do an OR() statement to verify both Escalation_complaint and Escalation_request. The result looks like this:
=IF(OR(A1="Escalation_complaint",A1="Escalation_request"),"Escalated",IF(A1="","","Solved"))
The order here is important because you want the "for all other cases" to be in the final IF statement.
If you have a situation where you could also have "Request_escalation" or "complaint_escalation", you should make a more general solution that uses SEARCH or FIND which would allow you to do a more general lookup that allows for more values without having to hardcode them. Here is an example that makes it possible to find the word Escalation anywhere in the cell:
=IF(IFERROR(SEARCH("escalation",A1,1),0)>0, "Escalated", IF(A1="","","Solved"))
Excel have maximum 30 arguments in a formula.
= if (A1=1, "True",if(B1>2,"True", "false"))
Understand this pattern. easy way.
If you no longer understand this, or if your problem has not been resolved, attach a file or screenshot that relates to your problem.
I am trying to do this in excel:
If Original Contract Value is between range of two numbers = Words Here for this example %:
=IF(AND(E8>1000,E8<1500000),"11.94%","11.94%"),IF(AND(E8>1500000,E8<7000000),"13.79","13.79"),IF(AND(E8>7000000,E8<20000000),"16.41%","16.41%")))
Range
1000-1,500,000 11.94%
1.5M-7M 13.79%
7M-20M 16.41%
I keep on getting an error message, can someone help me out?
You've got too many options. Each IF must have one result for TRUE and one for FALSE. In this bit
=IF(AND(E8>1000,E8<1500000),"11.94%","11.94%")
you only need the first result if the statement evalutes to TRUE, if not you want to proceed to the next IF so the second 11.94% is redundant (erroneous).
Try this.
=IF(AND(E8>1000,E8<1500000),11.94%,IF(AND(E8>1500000,E8<7000000),13.79%,IF(AND(E8>7000000,E8<20000000),16.41%,"???")))
You should add a result too if E8 >= 20000000 (where I have put ???) and you don't need the quote marks as you are inserting numbers, not strings.
However, a more efficient way using LOOKUPs is outlined here. This is particularly advantageous if you have many bands. In your example it's six of one and half a dozen of the other.
Use:
=CHOOSE(MATCH(E8,{1000,1500000,7000000}),11.94%,13.79%,16.41%)
What is the best way to find the right column for the travelled miles using visual basic coding or some excel function and return the price from that column? HLOOKUP can't be used here because the lookup value isn't exact and the ranges in the table are also not with specific intervals (If they were, I could use e.g. FLOOR(travelled miles/100)*100 and find the price with HLOOKUP). Obviously, it's easy to find the price manually with a small table but with a big table computer will be faster.
Note that, if x is between a and b, then MEDIAN(x,a,b)=x. Combine this with some nested IFs:
=IF(MEDIAN(B5,B1,C1-1)=B5,B2,IF(MEDIAN(B5,C1,D1-1)=B5,C2,IF(MEDIAN(B5,D1,E1-1)=B5,D2)))
I'm on my phone, so just done the first three cases, but hopefully you can see how it continues.
(should note you need to remove the dashes for this to work)
Edit:
I also want to answer your question in the comments above. You can use the following to keep the dash, but get a number to work with.
Assume cell A1 has got the value 10-. We can use the FIND function to work out where the - occurs and then use the LEFT function to only return the characters from before the dash:
=LEFT(A1,FIND("-",A1)-1)
This will return the value 10, but it will return it as a string, not a number - basically Excel will think it is text. To force Excel to consider it as a number, we can simply multiply the value by one. Our formula above therefore becomes:
=(LEFT(A1,FIND("-",A1)-1))*1
You may also see people use a double minus sign, like this:
=--LEFT(A1,FIND("-",A1)-1)
I don't recommend this because it's a bit complex, but combining with the formula above would give:
=IF(MEDIAN(B5,--LEFT(B1,FIND("-",B1)-1),--LEFT(C1,FIND("-",C1)-1)-1)=B5,B2,IF(MEDIAN(B5,--LEFT(C1,FIND("-",C1)-1,--LEFT(D1,FIND("-",D1)-1-1)=B5,C2,IF(MEDIAN(B5,--LEFT(D1,FIND("-",D1)-1,--LEFT(E1,FIND("-",E1)-1-1)=B5,D2)))
I wrote an IF formula as follows...
=IF(AB2>=500000,"Platinum",IF(AB2>100000,"Gold",IF(AB2>0,"Silver","")))
This works perfectly fine, however I've been given a new caveat and I haven't been able to figure it out.
If Column labeled Sponsor (see below image) has a value, then it should become a "Platinum" tier.
So pretty much, I'm seeing if it's possible add this additional condition to my existing formula. Any help would be greatly appreciated!
You can just add an OR() to the IF statement that you already have.
=IF(OR(AB2>=500000,AA2<>""),"Platinum",IF(AB2>100000,"Gold",IF(AB2>0,"Silver","")))
=If(LEN(AA2)<> 0,"Platinum",if(AB2>50000,"Platinum .... etc.
However, your logic is going to get a bit twisted with the many nested IFs. You might instead consider using a CHOOSE > MATCH structure, thus:
=IF(LEN(AA2)<> 0,"Platinum",CHOOSE(MATCH(AB2,{0,100000,500000},1),"Silver","Gold","Platinum"))
This formula first checks to see if there's a sponsor, and if there is sets it to "Platinum"; if there isn't it proceeds to the CHOOSE(MATCH.
The MATCH looks for the largest number in the array (i.e., {0, 100000, 500000}) that is less than or equal to the value in AB2, and returns an index number for where it finds the match. The CHOOSE then selects that entry from the list and returns it.
I am looking for a method to match two excel tables.
I basically have two Systems, where the values do not exactly match only some IDs. The values in system 2 are usually 10-20% different from system 1.
Here is how the sheet looks like:
I tried to use vlookup on the IDs and then going hand-by-hand through the values if they match, by using the filter with the ID. However, this takes extremely long and is very cumbersome.
Any recommendation how to match these two tables, much more easily?
I really appreciate your replies!
If you look at a formula for G3 you would be involving D3:E3 and A:B (where A10:B10 are the matching values).
When someone states that they are looking for a percentage, it is helpful to know "a percentage of what...?". You receive a different result if the calculation is ABS(12 - 15)/15 instead of ABS(12 - 15)/12. One may within tolerance and the other may not.
In any event, the formula for G3 would be something like,
=ABS(E3-VLOOKUP(D3,A:B, 2, FALSE))/E3
... or,
=ABS(E3-VLOOKUP(D3,A:B, 2, FALSE))/VLOOKUP(D3,A:B, 2, FALSE)
That produces a result of 0.25% or 0.20% depending on how you calculate the percentage. You could wrap that in an IF statement for a YES/NO text result or use a custom number format like [Color3][>0.2]\NO;;[Color10]\Y\E\S;# which will show a red NO for values greater than 20% and a green YES for values between 0 and 20%. Negative values do not have to be accounted for as the ABS removes them from consideration.
I've only reproduced a minimum of your sample data for demonstration purposes but perhaps you can get an idea on how to proceed from that.