i want to display date value like '2020/03/30' as '20200330'
i tried this code
Date.Now.Year & Date.Now.Month & Date.Now.day
but this returns 2020330
how can this return 20200330 ??
You are concatenating numbers, which get implicitly converted to strings.
You could check out Custom date and time format strings.
In your case, this might do just fine: Date.Now.ToString("yyyyMMdd")
By the way, as #jmcilhinney already commented to your question, you could easily find such basic information by using your favorite search engine on the internet...
Related
I'm writing a script to scrape from another website with Python, and I am facing this question that I have yet to figure out a method to resolve it.
So say I have set to replace this particular string with something else.
word_replace_1 = 'dv'
namelist = soup.title.string.replace(word_replace_1,'11dv')
The script works fine, when the titles are dv234,dv123 etc.
The output will be 11dv234, 11dv123.
However if the titles are, dv234, mixed with dvab123, even though I did not set dvab to be replaced with anything, the script is going to replace it to 11dvab123. What should I do here?
Also, if the title is a combination of alphabits,numbers and Korean characters, say DAV123ㄱㄴㄷ,
how exactly should I make it to only spitting out DAV123, and adding - in between alphabits and numbers?
Python - making a function that would add "-" between letters
This gives me the idea to add - in between all characters, but is there a method to add - between character and number?
the only way atm I can think of is creating a table of replacing them, for example something like this
word_replace_3 = 'a1'
word_replace_4 = 'a2'
.......
and then print them out as
namelist3 = soup.title.string.replace(word_replace_3,'a-1').replace(word_replace_4,'a-2')
This is just slow and not efficient. What would be the best method to resolve this?
Thanks.
I have this list and string
list_var=(['4 3/4','6','6 3/4'])
string_var='there are 6 inches of cement inside'
i want to check through and find if any of the elements of the list is in the string
if list_var in strin_var (wont work of course due to the fact its a list but this is what i want to achieve is to compare all of the values and if any match return true)
i tried using any function but this not seem to work i would also like to achieve this without using loops as the code i will be using this in contains extracting data from a lot of files so execution speed is an issue
you will have to iteratre over the list at least once as you are trying a search operation.
is_found = any(True for i in list_var if i in string_var)
works perfectly for this scenario.
I have a parameter called Analyst group in this format :
[Dimension].[Analyst Group].&[Nl.Workplace.Foundation]
I want to pass this parameter to another report, to filter data. Its a multi value parameter. But the other report only accepts it in this format : [KanBan].[Analyst Group].&[Nl.Workplace.Foundation]
So im trying to isolate the "Nl.Workplace.Foundation", so i can do the following thing in the Go To Report parameter expression :="[KanBan].[Analyst Group].&["& --Isolated analyst group-- &"]" to create the desired format.
So what i need is to extract the part between .&[ and ]
But i really have no idea how to isolate that part of the string.
Found a solution! If i just use the Parameter.label instead of Parameter.value it automatically does what i want!
A different solution has been found, but I will still answer the initial question. It could help.
So what i need is to extract the part between .&[ and ]
You could use a regex.
This may not be the fastest way but it can handle most of the situations.
So let's assume you have a string containing:
[Dimension].[Analyst Group].&[Nl.Workplace.Foundation]
And you want to get the following string:
Nl.Workplace.Foundation
Just use the following expression:
=System.Text.RegularExpressions.Regex.Match("[Dimension].[Analyst Group].&[Nl.Workplace.Foundation]", "\.&\[(?<NWF>[^]]+)\]").Groups("NWF").Value
In the expression, replace the input string with your dynamic values, like for example:
=System.Text.RegularExpressions.Regex.Match(Fields!Dimension.Value & "." & Fields!AnalystGroup.Value, "\.&\[(?<NWF>[^]]+)\]").Groups("NWF").Value
I'm keeping the formula as simple as possible so that you can easily adapt it, with, say, handling the case where an input string will not have a match (with the above query it will return #Error).
You could do this by adding an IIF() or better, use a custom function that you can reuse in several places and will reduce the length of your expression.
I have a requirement where I need the pattern ICU uses to format the given date/time.
For example: If I have something like DateFormat.getDateInstance(DateFormat.SHORT, en_US).format(currentDate) gives me 5/3/2015, then I need an API which can tell me that the pattern ICU4J internally using is d/M/yyyy.
I did figure out a solution, all you need to do is convert the DateFormat into a SimpleDateFormat and call toPattern().
((SimpleDateFormat)DateFormat.getDateInstance(DateFormat.SHORT, en_US)).toPattern() returns d/M/y which is what I almost needed.
I want to remove all the characters from a string expect whatever character is between a certain set of characters. So for example I have the input of Grade:2/2014-2015 and I want the output of just the grade, 2.
I'm thinking that I need to use the FIND function to grab whatever is between the : and the / , this also needs to work with double characters such 10 however I believe that it would work so long as the defining values with the FIND function are correct.
Unfortunately I am totally lost on this when using the FIND function however if there is another function that would work better I could probably figure it out myself if I knew what function.
It's not particularly elegant but =MID(A1,FIND(":",A1)+1,FIND("/",A1) - FIND(":",A1) - 1) would work.
MID takes start and length,FIND returns the index of a given character.
Edit:
As pointed out, "Grade:" is fixed length so the following would work just as well:
=MID(A1,7,FIND("/",A1) - 7)
You could use LEFT() to remove "Grade:"
And then use and then use LEFTB() to remove the year.
Look at this link here. This is the way I would go about it.
=SUBSTITUTE(SUBSTITUTE(C4, "Grade:", ""), "/2014-2015", "")
where C4 is the name of your cell.