I have a linux centos 7 server and i want Below lines to file with name config.xml using sed command
<vhostMap>
<vhost>google</vhost>
<domain>google.com, www.google.com</domain>
</vhostMap>
i want add this lines after line 10 at config.xml file
i want add this with a command at centos7, its possible?
i have searched and i saw this is possible with sed or awk command
how i can do this with sed or awk command?
GNU sed:
sed '10a <vhostMap>\n <vhost>google</vhost>\n <domain>google.com,www.google.com</domain>\n</vhostMap>' config.xml
Almost the same with awk:
awk '{ print $0 ; if(NR == 10) printf "<vhostMap>\n <vhost>google</vhost>\n <domain>google.com, www.google.com</domain>\n</vhostMap>\n" }' config.xml
This might work for you (GNU sed and shell):
cat <<\! | sed '10r /dev/stdin' file
<vhostMap>
<vhost>google</vhost>
<domain>google.com, www.google.com</domain>
</vhostMap>
!
Place the lines to be appended in a here-doc and append them after line 10 of the file by reading them in as stdin via a pipe.
Related
//ask.census.gov/
//ask.census.gov/
//business.usa.gov/
//directorsblog.blogs.census.gov/
//public.govdelivery.com/accounts/USCENSUS/subscriber/new
//twitter.com/uscensusbureau
//www.calendarwiz.com/calendars/calendar.php?crd=cens1sample&cid[]=31793
//www.census.gov/2017censustests
//www.census.gov/2017censustests/
//www.census.gov/2020census
//www.census.gov/2020census
//www.census.gov/2020census/
//www.census.gov/about.html
//www.census.gov/about.html
I want the lines which have www in them by using sed command
Use sed:
sed -ne '/\/www\./p' file
Or grep:
grep '/www\.' file
Or awk
awk '/\/www\./' file
How to use sed to find lines with the word linux? As later display a first line 10 with the word linux?
EX.:
cat file | sed -e '/linux/!d' -e '10!d' ### I can not display the first 10 lines of the word linux
cat file | sed '/linux/!d' | sed '10!d' ### It is well
How to make it work with one sed?
cat file | sed -e '/linux/!d; ...?; 10!d'
...? - storing of the buffer linux? 10 later cut the lines?
Someone explain to me?
I would use awk:
awk '/linux/ && c<10 {print;c++} c==10 {exit}' file
This might work for you (GNU sed):
sed -nr '/linux/{p;G;/(.*\n){10}/q;h}' file
Print the line if it contains the required string. If the required number of lines has already been printed quit, otherwise store the line and previous lines in the hold space.
You could use perl:
perl -ne 'if (/linux/) {print; ++$a;}; last if $a==10' inputfile
Using GNU sed:
sed -rn "/linux/{p;x;s/^/P/;ta;:a;s/^P{10}$//;x;Tb;Q;:b}" filename
Thanks. You are great. All of the examples look very nice. Wooow :) It is a pity that I can not do that.
I have not seen for 'r' option in sed. I need to learn.
echo -e 'windows\nlinux\nwindows\nlinux\nlinux\nwindows' | sed -nr '/linux/{p;G;/(.*\n){2}/q;h}'
It works very well.
echo -e 'windows\nlinux\nwindows\nlinux\nlinux\nwindows' | sed -nr '/linux/{p;G;/(.*\n){2}/q;h}' | sed '2s/linux/debian/'
Can I ask you one more example? How to get a result at one sed?
I am writing a shell script for linux which takes argument as port no.
inside file following is a line which needs to be updated:
define('NO_OF_PORTS',10);
I need to replace that 10 by the argument passed.
But this should be dynamic, like next time I pass new port no it must get updated.
Using sed:
s="define('NO_OF_PORTS',10);"
n=25
sed "s/\('NO_OF_PORTS',\)[0-9]*/\1$n/" <<< "$s"
define('NO_OF_PORTS',25);
To change inline in the file use:
sed -i.bak "s/\('NO_OF_PORTS',\)[0-9]*/\1$n/" file
You can use sed in the script to edit the file
sed -i s/NO_OF_PORTS\',[0-9]*/NO_OF_PORTS\',$1/ $2
1.txt has
define('NO_OF_PORTS',19)
shell script
#!/bin/sh
echo $1
sed -i -r '/NO_OF_PORTS/ s/'[0-9]+'/'$1'/g' 1.txt
run
linux:/home/test # ./replace_port.sh 78
linux:/home/test # cat 1.txt
define('NO_OF_PORTS',78)
I am trying to extract text between pattern1 (fixed) and pattern2 (this can be p2-1/p2-2).
can you please tell me how to achieve this in a single command?
A file starts with start and ends with either end or close
File1:
======
junktest
data
start
stackoverflow
sed
close
File2:
======
data2
start
stackoverflow
end
I can extract text from File1 with
sed -n "/start/,/close/p"
And from File2 with
sed -n "/start/,/end/p"
I need a single sed command to achieve both..
something like:
sed -n "/start/, /close or end /p"
Both GNU sed and BSD sed:
sed -nE '/start/,/close|end/p' file
This awk looks better
awk '/start/,/end|close/' file
sed -n -E "/Word1/,/Word2-1/p" | sed -n -E "/Word1/,/Word2-2/p"
Easy with awk:
$ awk '/start/{p=1}p{print}/end|close/{p=0}' file
I have file, with lines, contains ip with netmask
a.b.c.d/24
w.x.y.z/32
etc
How to delete delete specific row?
i'm using
sed -ie "s#a.b.c.d/24##g" %filname%
but after the removal is an empty string in file.
It should run inside a script, with ip as parameter and also work in freebsd under sh.
Sed solution
sed -i '/<pattern-to-match-with-proper-escape>/d' data.txt
-i option will change the original file.
Awk solution
awk '!/<pattern-to-match-with-proper-escape>/' data.txt
Using sed:
sed -i '\|a.b.c.d/24|d' file
Command line arg:
For the input being command line argument, say 1st argument($1):
sed -i "\|$1|d" file
Replace $1 with appropriate argument number as is your case.
You should use d (delete) not g. Also do not use s (replacement).
sed -ie '/a.b.c.d\/24/d' %filename%
In a script you should using it in this way
IP=$1
IPA=${IP////\\/}
sed -i /"${IPA}"/d %filename%
And the script parameter should be called in this way:
./script.sh a.b.c.d/24
perl -i -lne 'print unless(/a.b.c.d\/24/)' your_file
or in awk if you donot want to do inplace editing:
awk '$0!~/a.b.c.d\/24/' your_file