i have a small dataset which is shown below:
enter image description here
i wrote a for loop that iterates through the values and add them one after another, however it treated the negative values as positive. the final result as you can see is just addition without subtracting the negative. have i done something wrong?
for i = 1 to 28
sum = sum + ws.range("B" & i).value
next i
All suggestion and help are highly appreciated?
Application.Sum(Ws.Range("B1:B28")) will give the correct result. Whether or not you can assign it to a variable by the name of Sum depends upon the capability of that variable to hold the kind of value that results.
Observe that your function starts its loop from B0 which doesn't exist and, therefore, should cause an error if not a crash.
Please take a look at the attached image. I have a long list of items and I've created a common keywords to search in that list. I'm using this formula:
=INDEX(A:A,MATCH((("*"&B2&"*")&("*"&C2&"*")&("*"&D2&"*")&("*"&E2&"*")&("*"&F2&"*")),A:A,0))
The problem that the search is going through the same sequence that I entered.
It gives error if the sequence of the words in the cell is different than the sequence in my formula which make sense.
Is there a way I can search for 3 or more words that are existing in any cell in any sequence?
I am open to using VBA if necessary.
My search results:
Here is the user defined function:
Public Function indexMX(rng As Range, pat1 As Range, pat2 As Range, pat3 As Range, pat4 As Range, pat5 As Range) As Variant
Dim r As Range, rngx As Range, s(1 To 5) As String, Kount As Long, j As Long
s(1) = pat1.Value
s(2) = pat2.Value
s(3) = pat3.Value
s(4) = pat4.Value
s(5) = pat5.Value
Set rngx = Intersect(rng, rng.Parent.UsedRange)
For Each r In rngx
v = r.Value
Kount = 0
For j = 1 To 5
If InStr(1, v, s(j)) > 0 Or s(j) = "" Then Kount = Kount + 1
Next j
If Kount = 5 Then
indexMX = v
Exit Function
End If
Next r
indexMX = "no luck"
End Function
Here is an example of its usage:
As you see, we give the UDF() the address of the column and the addresses of the five keywords and the UDF() finds the first item containing all five words.
If a keyword is blank, it is not used. (so if you want to search for only two keywords, leave the other three blank). If no matches are found the phrase no luck is returned.
User Defined Functions (UDFs) are very easy to install and use:
ALT-F11 brings up the VBE window
ALT-I
ALT-M opens a fresh module
paste the stuff in and close the VBE window
If you save the workbook, the UDF will be saved with it.
If you are using a version of Excel later then 2003, you must save
the file as .xlsm rather than .xlsx
To remove the UDF:
bring up the VBE window as above
clear the code out
close the VBE window
To use the UDF from Excel:
=myfunction(A1)
To learn more about macros in general, see:
http://www.mvps.org/dmcritchie/excel/getstarted.htm
and
http://msdn.microsoft.com/en-us/library/ee814735(v=office.14).aspx
and for specifics on UDFs, see:
http://www.cpearson.com/excel/WritingFunctionsInVBA.aspx
Macros must be enabled for this to work!
EDIT#1:
to remove case sensitivity, replace:
If InStr(1, v, s(j)) > 0 Or s(j) = "" Then Kount = Kount + 1
with:
If InStr(1, LCase(v), LCase(s(j))) > 0 Or s(j) = "" Then Kount = Kount + 1
Yes, it is possible for a single cell to return three matching words from a different cell. The answer in this example uses a formula to return 6 matches. VBA and special array functions are not used.
This is the formula:
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUMPRODUCT((IFERROR(SEARCH(FIRST,TARGET),0)>0)*100000+(IFERROR(SEARCH(SECOND,TARGET),0)>0)*20000+(IFERROR(SEARCH(THIRD,TARGET),0)>0)*3000+(IFERROR(SEARCH(FOURTH,TARGET),0)>0)*400+(IFERROR(SEARCH(FIFTH,TARGET),0)>0)*50+(IFERROR(SEARCH(SIXTH,TARGET),0)>0)*6),"1",FIRST&DELIM),"2",SECOND&DELIM),"3",THIRD&DELIM),"4",FOURTH&DELIM),"5",FIFTH&DELIM),"6",SIXTH&DELIM),"0","")
Did you notice the named ranges? FIRST, SECOND, THIRD, etc are individual cells and each one holds a word. We are trying to find those words inside TARGET. If we find the words, then we will write them in this cell holding this formula and each word will be separated by DELIM
The ranges are optional. In the picture below, you'll see cell A2 contains the word "named". This is the first of the six words we're tying to find and it can be expressed as FIRST = "A2" = "named" Inside the formula you'll see that FIRST appears twice. You could replace it with "named" and the cell A2 would become blank but the functionality of the formula would not change.
Even TARGET is optional. It could be written as E1 or typed out word for word.
I don't know why anyone would do that... but it is possible.
DELIM is at cell B2, it is a double space
Now to explain how it works
SEARCH(search for what?, search where?) This is responsible for determining if a match exists or not. If you understand what the named ranges then you've already figured out the syntax is. The location of first letter that of match in TARGET is returned. In this formula it is always 1 If it is not found then the number is 0
IFERROR(value,value) tries to perform the operation. If successful then the result is displayed. If there's an error the second result is displayed. Every IFERROR in this formula is practically the same: IFERROR(SEARCH(FIRST,TARGET),0) It searches inside TARGET trying to find the FIRST word. Result if found is 1 and if not found is 0
It gets a little more complicated from here so lets recap. We're calling SEARCH 6 times. Once for each word we want to find and we're always looking in TARGET. Result will be a 1 if match is found or a 0 if not. Ironically, us humans can put it together and see the match but the formula can't determine which words have been matched without more information
SUMPRODUCT takes the sum (addition) of the product (multiplication) of two or more arrays.
multiply two arrays to get the product
a, b, c * e, f, g = ae, bf, cg
takethe sum of the product to get the SUMPRODUCT
ae + bf + cg`
This is easiest when thought of a price and quantity. If one array is the price of a group of items and the other is quantity of the same group of items, then multiplying the two arrays will create a new array where each element is the cost to buy all items of that type in the group the total, and adding all those numbers give you the total cost you'd pay for all of the items
Here we multiply two arrays:
Qty Price
12.0 0.3
70.0 0.1
20.0 0.4
Multiply them to get the product:
Qty Price Total
12.0 0.3 3.8
70.0 0.1 7.0
20.0 0.4 8.0
Take the sum of the product:
Qty Price Total
12.0 0.3 3.8
70.0 0.1 7.0
20.0 0.4 8.0
18.8 SUMPRODUCT
Lets look at part of the formula:
SUMPRODUCT((IFERROR(SEARCH(FIRST,TARGET),0)>0)*100000+IFERROR(SEARCH(SECOND,TARGET),0)>0)*20000+...
It is easy to see this segment is looking for two words. We know SUMPRODUCT want's to multiply and add arrays. If you're thinking (IFERROR(SEARCH(FIRST,TARGET),0)>0) is an array, you'd be right! It's not an array in the technical sense of the word, but it does evaluate into a single value which can thought of as a 1x1 array, or, a cell. The sharp eyed and quick witted, may have noticed there is something on this array we have mentioned. It's the inequality at the end! Many of you know that you can take numerical values and turn them into boolean by testing them with an inequality. So lets evaluate.... SEARCH for FIRST inside TARGET = 1 because FIRST = "named" which is inside TARGET waaaaaaay in the back and because it wasn't an error we get to keep the 1. Next we do the inequality 1 > 0 = TRUE One is greater than zero and evaluates to TRUE
This is what we have right now
SUMPRODUCT((TRUE*100000+IFERROR(SEARCH(SECOND,TARGET),0)>0)*20000+....
Can you identify the arrays now? We know TRUE is an array, a 1x1. You know the IFERROR bit all the way to the inequality is also an array. Lets evaluate that IFERROR .... Mathematically we should still be working from left to right but trust me, we're ok if we let it slide this once.
IFERROR(SEARCH(SECOND,TARGET),0)>0) SECOND = "array" = 1 = TRUE
Did you follow my short hand? It's ok if you didn't just back up and practice on FIRST until you understand.
Plugging in the value gives us something like this
SUMPRODUCT(TRUE*100000+TRUE*20000+...
SUMPRODUCT is the SUM(addition) of the PRODUCT(multiplication)
So we're adding the stuff we multiply
SUMPRODUCT = (TRUE * 100000) + (TRUE * 20000)
Remember how easy it was to go from 1 > 0 to TRUE. We're "getting all up into that boolean TRUE that" equals 1 Here's a fun fact, -1 is also equal to TRUE. If you've ever seen a formula with a double negative in it like this STUFF(--(MORESTUFF( that's just some Excel wizard person making sure they get a +1 instead of a -1 ... ok, so lets get back on track and evalute
SUMPRODCUT = 1 * 100000 + 1 * 20000+....
SUMPRODCUT = 100000 + 20000+....
SUMPRODCUT = 120000+.....
I know you've been asking about those numbers. One hundred thousand? What's one hundred thousand for? I've been purposefully ignoring until it became convenient to talk about it. And now it's convenient. Go look at the whoooole formula and you'll find a pattern. Those numbers are in a decreasing sequence. Anyone who's ever done bitwise logic can see where this is going.I'm running short on time so I'll cut to the chase. Assume a hypothetical situation where every word was matched. You'd end up with
SUMPRODUCT = 100000 + 20000 + 3000 + 400 + 50 + 6
SUMPRODCUT = 123456
123456 are you pulling my leg? No, I am not. We're almost done so if you're still with me then you're gonna drive it home.
We have a large group of SUBSTITUTE teachers at the front of the line and we gotta get rid of them.
We also have this to contend with :"1",FIRST&DELIM),"2",SECOND&DELIM),"3",THIRD&DELIM),"4",FOURTH&DELIM),"5",FIFTH&DELIM),"6",SIXTH&DELIM),"0","")
Thankfully for us, they are part of the same problem. We worked our way from the middle out.
SUBSTITUTE(SUBSTITUTE(text, old text, new text)
SUBSTITUTE(SUBSTITUTE("123456","1", FIRST & DELIM),"2",SECOND & DELIM)....
Remember at top DELIM was pointing to a cell holding a double space. Each DELIM can be replaced with " " or any other delimiter you want.
SUBSTITUTE(SUBSTITUTE("123456","1", "named" & " "),"2",SECOND & DELIM)...
SUBSTITUTE("named 23456","2",SECOND & DELIM)...
SUBSTITUTE("named 23456","2","array"& " ")...
("named array 3456")... and so on.
Any questions?
Ok, class is dismissed!
I found a snippet of VBA for deleting rows in which the column value contains text.
It seems to work much faster than a loop statement. I looked online to figure out how Specifically xlCellTypeConstants, 22 works.
[D:D].SpecialCells(xlCellTypeConstants, 22).EntireRow.Delete
You're providing the first argument as xlCellTypeConstants, so that means the second parameter can be a bitwise combination of:
xlNumbers = 1
xlTextValues = 2
xlLogical = 4
xlErrors = 16
In your case, you're using a hard-coded number of 22, which is the bitwise equivalent of xlErrors Or xlLogical Or xlTextValues
See this article (Archive) for more details.
This may be really easy for someone who used excel allot in the past but i just can't get the right formula.
I have a large spreadsheet which i need to add a mark up onto but the mark up which adds on is dependent on variables. Unfortunately this result has to go on the end of a already big formula, the ######## represents where the IF statement will be placed.
IF >55 and is square = 15
IF >55 and is not square = 15
IF <55 and is Square = 25
IF <55 and is not square = 30
Cell D2 = has the numerical value
Cell G2 = Has the shapes in it.
=(((100-V2)/100)*U2*D2)+((((100-V2)/100)*U2*D2)/100*##########)
I really recommend you break the formula into cells, but if it's needed to be in one single cell, the formula can be done as well...
IF(D2>55;IF(G2="square";15;15);IF(G2="square";25;30))
So it's gonna be like:
=(((100-V2)/100)*U2*D2)+((((100-V2)/100)*U2*D2)/100*IF(D2>55;IF(G2="square";15;15);IF(G2="square";25;30)))
A little shorter (addresses D2=55):
=15+15*(D2<55)-5*(D2<55)*(G2="Square")
I am not a big fan of the nested ifs in Excel, especially when they contain and/or conditions. The typical formula would look something like:
=if(and(c1,c2),x1,if(and(c3,c4),x2,...
YUCK!
I'm definitely a VBA minimalist, but this does appear to be a good application of it. Make a custom function like:
Function FooBoo(Val As Integer, Shape As String) As Integer
Dim result As Integer
If Val > 55 And Shape = "square" Then
result = 15
ElseIf Val > 55 Then
result = 15
ElseIf Val < 55 And Shape = "square" Then
result = 25
ElseIf Val < 55 Then
result = 30
End If
FooBoo = result
End Function
And then you can call it from within Excel:
=(((100-V2)/100)*U2*D2)+((((100-V2)/100)*U2*D2)/100*FooBoo(val,shape))
If it's part of the workbook itself, it's no less portable than any other Excel formula, and it's more transparent and easier to maintain.
Also, unrelated, but I did note some things in your logic:
15 seems to be the result for values > 55, whether or not it's a square. You really could limit your first condition to values > 55
You haven't defined what happens if the value is exactly 55. Was one of those conditions >= or <=?
I am trying to think of a way to loop through a number of combinations making sure that I go through each available combination without repeat. Let me explain. I have a set of numbers, for example
20,000
25,000
27,000
29,000
and I would like to alter this set of numbers via a loop and copy the new numbers into a different sheet so that my formulas on that sheet can calculate whatever I need them to calculate. For example, the first couple of iterations might look something like this:
1st
20,000 x 1.001
25,000 x 1
27,000 x 1
29,000 x 1
2nd
20,002 x 1.001
25,000 x 1.001
27,000 x 1
29,000 x 1
The first row of numbers should never exceed the second. So 20,000 should only go as high as 25,000.
I was able to set up a system whereby I set up a matrix and then loop through a random set of combinations using =rand() however this does not ensure I hit every combination and also repeats combinations.
Can anyone explain the math behind this and also how I would use a loop to accomplish my goal?
Thank you!
Try starting with smaller numbers.
See if this works for you.
Sub looper()
'First Array
Dim myArray(9) As Double
For i = 1 To 10
myArray(i - 1) = i
Next i
'Second Array
Dim myOtherArray(9) As Double
For i = 1 To 10
myOtherArray(i - 1) = i
Next i
'Loop through each one
For Each slot In myArray
For Each otherSlot In myOtherArray
Debug.Print (slot & " * " & otherSlot & " = " & slot * otherSlot)
Next otherSlot
Next slot
End Sub
GD user1813558,
Your question contains too little detail and is too broadly scoped to be able to provide a accurate answer.
Are your numbers arbitrary (i.e. the ones you provided are 'just'
samples) or will they be fixed as per your indicated numbers ?
Will there always be only 4 numbers ?
Is the distribution of your startnumbers (i.e. their difference
value) always as per your indication 0, +5000, +2000, +2000
Will the results of all 'loops' (or iterations) need to be copied to
a different sheet ? (i.e looping from 20.000 to 25.000 by increments
of 1.001 would require about 223 iterations, and subsequently sheets,
before the result starts exceeding 25.000 ?)
Does a new sheet need to be created for each iteration result or are they
existent or will the result be copied to the same sheet for every iteration ?
In short, please provide a more accurate question.