VBA. Deleting multiple cells in a row if one cell is blank - excel

Question

I have multiple columns in an excel sheet...say A1:D10.
I want to find any blank cells in column C, delete that cell as well as the A,B, and D cells of that same row, then shift up. But only in the range of A1:D10. I have other information in this excel sheet outside this range that I want to perserve in its original position. Therefore I can not use somthing like this:
.SpecialCells(xlCellTypeBlanks).EntireRow.Delete
Nor can I get something like the following to work, because it only shifts the single column up, not all four columns.
Set rng = Range("A1:D10").SpecialCells(xlCellTypeBlanks)
rng.Rows.Delete Shift:=xlShiftUp

Answer 1

If there is no data in columns A to D below row 10 that you don't want to move up, then SpecialCells and Delete Shift Up can be used like this
Sub Demo1()
Dim ws As Worksheet
Dim TestColumn As Long
Dim StartColumn As Long
Dim EndColumn As Long
Dim FirstRow As Long
Dim LastRow As Long
Dim i As Long
Dim rng As Range, arr As Range
' set up reference data
Set ws = ActiveSheet '<~~ update as required
TestColumn = 3 'C
StartColumn = 1 'A
EndColumn = 4 'D
FirstRow = 1
LastRow = 10
Application.ScreenUpdating = False
Application.Calculation = xlCalculationManual
With ws
On Error Resume Next
Set rng = .Range(.Cells(FirstRow, TestColumn), .Cells(LastRow, TestColumn)).SpecialCells(xlCellTypeBlanks)
On Error GoTo 0
If Not rng Is Nothing Then
For Each arr In rng.Areas
arr.EntireRow.Resize(, EndColumn - StartColumn + 1).Delete Shift:=xlShiftUp
Next
End If
End With
Application.ScreenUpdating = True
Application.Calculation = xlCalculationAutomatic
End Sub
If there is data in columns A to D below row 10 that you don't want to move up, then you can use Cut and Paste, like this
Sub Demo()
Dim ws As Worksheet
Dim TestColumn As Long
Dim StartColumn As Long
Dim EndColumn As Long
Dim FirstRow As Long
Dim LastRow As Long
Dim i As Long
' set up reference data
Set ws = ActiveSheet '<~~ update as required
TestColumn = 3 'C
StartColumn = 1 'A
EndColumn = 4 'D
FirstRow = 1
LastRow = 10
Application.ScreenUpdating = False
Application.Calculation = xlCalculationManual
With ws
If IsEmpty(.Cells(LastRow, TestColumn)) Then
.Cells(LastRow, StartColumn).Resize(1, EndColumn - StartColumn + 1).Clear
End If
For i = LastRow - 1 To FirstRow Step -1
If IsEmpty(.Cells(i, TestColumn)) Then
.Range(.Cells(i + 1, StartColumn), .Cells(LastRow, EndColumn)).Cut .Cells(i, StartColumn)
End If
Next
End With
Application.ScreenUpdating = True
Application.Calculation = xlCalculationAutomatic
End Sub

Answer 2

Using Variant Array Method
Sub test2()
Dim rngDB As Range, vDB As Variant
Dim i As Integer, j As Integer, n As Integer
Dim k As Integer
Set rngDB = Range("a1:d10")
vDB = rngDB
n = UBound(vDB, 1)
For i = 1 To n
If IsEmpty(vDB(i, 3)) Then
For j = 1 To 4
If j <> 3 Then
vDB(i, j) = Empty
End If
Next j
End If
Next i
For j = 1 To 4
If j <> 3 Then
For i = 1 To n - 1
For k = i To n - 1
If vDB(k, j) = Empty Then
vDB(k, j) = vDB(k + 1, j)
vDB(k + 1, j) = Empty
End If
Next k
Next i
End If
Next j
rngDB = vDB
End Sub

Answer 3

The below will take care of your requirement by looking for an empty cell in column 3, and deleting the row and shifting up only in that row.
Sub deleteEmptyRow()
Dim i As Integer
For i = 1 To 10
If Cells(i, 3) = "" Then
Range(Cells(i, 1), Cells(i, 4)).delete Shift:=xlUp
End If
Next i
End Sub