I used this map:
map ,w v/\([^ a-z0-9]\|[^ A-Z0-9]\)*<cr>h
the idea is to select
in the words
mysuperTest
MYSUPER_TEST
mysuper_test
to always select the part that says mysuper
but it doesnt work, not sure why
I would use something like the below:
nnoremap ,w v/\C\%#.\([a-z]\+\<bar>[A-Z]\+\)\zs<cr>h
One point to notice is that in a mapping you need to use <bar> (or escape | with an extra backslash) since otherwise | is recognized as a command separator (see :help map-bar.)
Another one to notice is that you want the match to start at the first character outside the word (so you'll land at the end of the word with the h). The visual selection will expand to the start of the match in a search. I suggest using \zs to set the start of the match explicitly (see :help /\zs.)
Finally, beware of 'ignorecase' or 'smartcase' settings. Use \C to explicitly request a case-sensitive match (see :help /\C.)
I also like the idea of using a stronger anchor for the start of the match, so I'm using \%# to match the current cursor position (see :help /\%#), so you're always sure to match the current word only and not end up wandering through the buffer.
Putting it all together:
\C Case-sensitive search
\%# From cursor position
. Skip first character
\( Either one of:
[a-z]\+ One or more lowercase letters
\| (\<bar>) Or:
[A-Z]\+ One or more uppercase letters
\) End group
\zs Set match position here
I'm skipping the first character under the cursor, since in a CamelCase word, the first character won't match capitalization of the remainder of the word.
I kept your original idea of finding the first character after the word then using h to go back one to the left. But that might be a problem if, for example, the word is at the end of the line.
You can actually match the last character of the word instead with something like [a-z]\+\zs[a-z], which will set the start of the match on the last lowercase character. You can do this for both sides of the group (you can have more than one \zs in your pattern, last wins.) If you structure your match that way, you won't need the final h to go back.
I didn't handle numbers, I'll leave those as an exercise to the reader.
Finally, consider there are quite a few corner cases that can make such a mapping quite tricky to get right. Rather than coming up with your own, why not look at plug-ins which add support for handling CamelCase words that have been battle-tested and will cover use cases a lot more advanced than the simple expression you're using here?
There's the excellent vim-scripts/camelcasemotion by Ingo Karkat which sets up a ,w mapping to move to the start of the next CamelCase word, but also i,w to select the current one. You can use powerful combinations such as v3i,w to visually select the current and next two CamelCase words.
You might also check Tim Pope's tpope/vim-abolish which, among other features, defines a set of cr mappings to do coercion from camelCase to MixedCase, snake_case, UPPER_CASE, etc. (Not directly about selecting them, but still related and you might find it useful.)
Related
Most substitution commands in vim perform an action on a full line or a set of lines, but I would like to only do this on part of a line (either from the cursor to end of the line or between set marks).
example
this_is_a_sentence_that_has_underscores = this_is_a_sentence_that_should_not_have_underscores
into
this_is_a_sentence_that_has_underscores = this is a sentence that should not have underscores
This task is very easy to do for the whole line :s/_/ /g, but seems to be much more difficult to only perform the replacement for anything after the =.
Can :substitution perform an action on half of a line?
Two solutions I can think of.
Option one, use the before/after column match atoms \%>123c and \%<456c.
In your example, the following command substitutes underscores only in the second word, between columns 42 and 94:
:s/\%>42c_\%<94c/ /g
Option two, use the Visual area match atom \%V.
In your example, Visual-select the second long word, leave Visual mode, then execute the following substitution:
:s/\%V_/ /g
These regular expression atoms are documented at :h /\%c and :h /\%V respectively.
Look-around
There is a big clue your post already:
only perform the replacement for anything after the =.
This often means using a positive look-behind, \#<=.
:%s/\(=.*\)\#<=_/ /g
This means match all _ that are after the following pattern =.*. Since all look-arounds (look-aheads and look-behinds) are zero width they do not take up space in the match and the replacement is simple.
Note: This is equivalent to (?<=...) in perl speak. See :h perl-patterns.
What about \zs?
\zs will set the start of a match at a certain point. On the face this sounds exactly what is needed. However \zs will not work correctly as it matches the pattern before the \zs first then the following pattern. This means there will only be one match. Look-behinds on the other hand match the part after \#<= then "look behind" to make sure the match is valid which makes it great for multiple replacement scenario.
It should be noted that if you can use \zs not only is it easy to type but it is also more efficient.
Note: \zs is like \K in perl speak.
More ways?!?
As #glts mentioned you can use other zero-width atoms to basically "anchor" your pattern. A list of a few common ways:
\%>a - after the 'a mark
\%V - match inside the visual area
\%>42c - match after column 42
The possible downside of using one of these methods they need you to set marks or count columns. There is nothing wrong with this but it means the substitution will maybe affected by side-effects so repeating the substitution may not work correctly.
For more help see:
:h /\#<=
:h /zero-width
:h perl-patterns
:h /\zs
I come upon one scenario when editing a file in vim and I still haven't found a way to do it quickly in vim way. When editing a call of a function, I offently put my arguments in a wrong order.
anyFunction(arg2, arg1)
When arriving on this situation, I have to find arg2 / delete it / append it before the ')' / deal with the ', ' / etc.
Isn't it a better way to this task quickly ? I am open to any idea (macro/ shortcut / plugin) even if I'd rather have a 'vim only' way of doing this
You need two things:
A text object to quickly select an argument (as they aren't always that simple like in your example). argtextobj plugin (my improved fork here) does this.
Though you can use delete + visual mode + paste + go back + paste, a plugin to swap text makes this much easier. My SwapText plugin or the already mentioned exchange plugin both do that job.
put this mapping in your _vimrc.
" gw : Swap word with next word
nmap <silent> gw :s/\(\%#\w\+\)\(\_W\+\)\(\w\+\)/\3\2\1/<cr><c-o><c-l>
then in normal mode with the cursor anywhere in arg1 type gw to swap parameters
anyFunction(arg1, arg2)
Explanation:-
arg1 the separator (here a comma) and arg2 are put into regexp memories 1 2 3
the substitute reverses them to 3 2 1
Control-O return to last position
Control-L redraw the screen
Note that the separator is any non-alphanumeric character or string e,g whitespace
I actually made a plugin to deal with a exact situation called argumentative.vim. (Sorry for the plug.)
Argumentative.vim provides the following mappings:
[, and ], motions which will go to the previous or next argument
<, and >, to shift an argument left or right
i, and a, argument text objects. e.g. da,, ci, or yi,
So with this plugin you move to the argument in question and then do a <, or >, as many times as needed. It can also take a count e.g. 2>,.
If you have Tim Pope's excellent repeat.vim plugin installed <, and >, become repeatable with the . command.
I would recommend a plugin: vim-exchange for that:
https://github.com/tommcdo/vim-exchange
This is a perfect use for a regular expression search and replace.
You want to find "anyFunction(", then swap anything up to the ',' with anything from the ',' to the ')'. This is fairly straightforward, using [^,]* for "anything up to the ','" and [^)]* for "anything up to the ')'". Use \(...\) to capture each thing, and \1, \2 to refer to those things in the replacement:
:s#anyFunction(\s*\([^,]*\),\s*\([^)]*\)#anyFunction(\2, \1#g
Note how I use \s* to allow any whitespace between the "anyFunction(" and the first thing, and also between the ',' and the second thing.
If you want this to be able to span multiple lines, you can use \_s instead of \s, and capture the whitespace if you want to maintain the multi-line format:
:s#anyFunction(\(\_s*\)\([^,]*\),\(\_s*\)\([^)]*\)#anyFunction(\1\4,\3\2#g
There is also a multi-line variant of [...] collections, for example \_[^,] meaning "anything (even a new line) except for a ',' " which you could use in the pattern if your use case demands it.
For details, consult the help topics for: /\s, /\_s, /\1, /\(, and /[.
If you want a more general-purpose mapping to use at every location, you can use the cursor position in your regular expression, rather than keying off the function name. The cursor position in a regular expression is matched using \%# as demonstrated here: http://vim.wikia.com/wiki/Exchanging_adjacent_words
Similar to what Peter Rincker suggested (Argumentative), sideways also does what you describe.
I would like to use tabs in a code that doesn’t use them. What I did until now to implement tabs was pretty handcrafty:
:%s/^ /\t/g
:%s/^\t /\t\t/g
. . .
Question: Is there a way to replace two spaces ( ) by tab (\t) the number of times it was found at the beginning of a line?
There are (at least) three substitution techniques relevant to this case.
1. The first one takes advantage of the preceding-atom matching
syntax to naturally define a step of indentation. According to the
question statement, an indent step is a pair of adjacent space
characters preceded with nothing but spaces from the beginning
of line. Following this definition, one can construct the actual
substitution pattern, right to left:
:%s/\%(^ *\)\#<= /\t/g
Indeed, the pattern designates an occurrence of two literal space
characters, but only when they are preceded by a zero-width match
of the atom just before \#<=, which is the pattern ^ * wrapped in
grouping parentheses \%(, \). These non-capturing parentheses are
used instead of the usual capturing ones, \(, \), since there is no
need in further referring to the matched string of leading spaces. Due
to the g flag, the above :substitute command runs through the
leading spaces pair by pair, and replaces each of them by single tab
character.
2. The second technique takes a different approach. Instead of
matching separate indent levels, one can break each of the lines
starting with space characters down into two lines: one containing
the indenting spaces of the original line, and another holding the
rest of it. After that, it is straightforward to replace all of the pairs
of spaces on the first line, and concatenate the lines back together:
:g/^ /s/^ \+/&\r/|-s/ /\t/g|j!
3. The third idea is to process leading spaces by means of Vim
scripting language. A convenient way of doing that is to use the
substitute with an expression feature of the :substitute command
(see :help sub-replace-\=). When started with \=, the substitute
string of the command enables to substitute the matches of a pattern
with results of evaluation of the expression specified after \=:
:%s#^ \+#\=repeat("\t",len(submatch(0))/2)
If you specifically want to convert spaces into tabs (or vice-versa) at the start of a line, there's the useful :retab command which takes care of that. For example:
:retab! 2 will convert spaces in groups of two to tabs
:set expandtab and then :retab! 2 will convert tabstops (of width 2) back to spaces
See :h :retab (and :h 'ts') for the details.
This is not a general solution for the original problem, but I think it covers the most common use case.
There is no general way of doing this using :s regex's. You can't make the /g modifier look backwards otherwise it'd be unusable, and you can't reliably check that you're at the beginning of the line without looking backwards.
The only way of doing it generally is to loop, like so:
:for i in range(100)
: %s/^\t*\zs /\t/e
:endfor
Which is ugly, slow and highly unrecommended. Use :retab
I’m writing a function that edits a certain environment in LaTeX.
The environment basically looks like this:
\begin{quicktikz}
...some stuff...
\end{quicktikz}
or like this:
\begin*{quicktikz}
...some stuff...
\end{quicktikz}
I want to write a function that toggles between the two, when called from within the environment. Since my Vim knowledge ain’t all that, I’m coming up with a simple solution:
Get cursor position with let save_cursor=getpos(".").
Backward search for \begin{quicktikz} using: ?\\begin{quicktikz}\|\\begin\*{quicktikz}.
Search for the { and move left using: normal 0f{h.
Check if the item under cursor equals *:
if it does, do normal x;
if it doesn’t, do normal a*<esc>.
Restore cursor position using call setpos('.',save_cursor).
I know how to do all of this except for step 3. How can I check if the char under the cursor equals to * or not?
If you know a better way of doing this, sharing this would be welcome.
I think the easiest way to retrieve the char under cursor is:
getline(".")[col(".")-1]
Alternatively, you can do it with strpart()
strpart(getline("."), col(".")-1, 1)
The first expression first calls the function getline() passing "." as
argument which means the line where the cursor is positioned will be returned.
Then we use the so called expr8 or expr-[] (see the help) to retrieve a
single character. The number passed comes from another function, col()
which returns the current cursor column. As indexes start in 0, one is subtracted.
You can use it like
if getline(".")[col(".")-1] == '*'
...
Let me propose an alternative implementation of the technique you describe.
:?\\begin\>\zs\*\=?s//\='*'[submatch(0)!='']/|norm!``
The above command consists of two separate commands chained with | (see
:help :bar) in one line. The first one is a substitution (see :help :s)
performed for each line in the specified range,
?\\begin\>\zs\*\=?
According to the range syntax (see :help :range), this range specifies the
only line, that is the previous line where the \\begin\>\zs\*\= pattern
matches the word begin preceded with a backslash and followed by by optional
star character.1 The \zs atom between parts of the pattern
matching \begin and *, sets the start of the match there. So, the match
of the whole pattern is either empty or contains single star character. This
is not necessary for specifying a line in the range, it is useful for reusing
the same pattern later in the :substitute command, where only that star
character or its empty place should be replaced. For details about the
pattern's syntax see :help /\>, :help /\=, :help /\zs.
The substitution itself,
s//\='*'[submatch(0)!='']/
replaces the first occurrence of the last search pattern (which is set by the
backward search in the range) with a string to which the expression
'*'[submatch(0)!=''] evaluates (see :help sub-replace-\=). As the pattern
matches only an empty string or a star character, the subexpression
submatch(0)!='' evaluates to zero if there is no star after \begin, or to
one otherwise. Zero subscript from the string '*' results in a substring
containing the first character of that one-character string. Index one is
equal to the length of the string, therefore subscript results in an empty
string. Thus, when there is a star after \begin, it gets replaced with an
empty string, when a star is not present, zero-width interval just after
\begin is substituted with *.
The second command,
:norm!``
takes advantage of the fact that :substitute command stores the current
cursor position before it actually starts replacement. The `` movement
command jumps back to the position before the latest jump (which occurs in the
aforementioned substitution command) restoring position of the
cursor.2
1 Be careful with search, since in ranges, as usual, it wraps
around the end of file, when the wrapscan option is enabled (it is turned on
by default).
2 Do not confuse `` with the '' command which moves the
cursor to the first non-blank character in the line of the location before the
latest jump.
In VIM, it's really easy to change a word of text to use uppercase or lowercase:
# in visual mode
# change word to uppercase
gUw
# change word to lowercase
guw
Is there a simple way to modify the word to use initial caps?
Assuming cursor is at the beginning of the word, use
gUl
(if the word was all-lowercase) or
gUllgue
to explicitly make the first letter capital and other lower case.
It's the same that you used, only instead of w (word motion) you use l (one symbol motion).
If the cursor is somewhere in the middle of the word, prepend b (go to the beginning of the word) to the commands above.
You can map some key to do this if you use it often.
I'd suggest moving to the beginning of the word with whatever motion command(s) you want, then pressing ~. This behavior is affected by the tildeop option, see :help ~ and :help tildeop for more info.
Depending on what your use-case is, any of the following may work.
Use ~ to toggle the case of the letter under your cursor.
Use :s/\<\(\w\)\(\w*\)\>/\u\1\L\2/ to search for a word, upper-case the first letter, and lower-case the rest.
guiwgUl to lower-case the word your cursor is on and then upper-case the first letter.
If you're on the word:
bgUl
If you're at the beginning of the word:
gUl
Unpacking that: b goes back one word (or to the beginning of the word you're on), gU upcases over movement, l moves right one character (which will be the first letter in the word).
Side note:
I have a plugin (well, it's not its main purpose though) that is able to convert names between camel case, underscore separated words, etc. Move the cursor on an identifier, and type :NameConvert lower_camel_case for instance (the command supports completion (<tab>, <c-d>) to display all the possible naming schemes)
To install it, you'll need lh-dev, and lh-vim-lib.
There is a function toupper which you can use to make conversion. Even in substitution you can use that. Like find all sentence beginnings, and convert the first character to upper case, as explained here: search and replace