Query an array in MongoDB - node.js

I have this collection in MongoDB:
{
"_id" : ObjectId("5df013b10a88910018267a89"),
"StockNo" : "33598",
"Description" : "some description",
"detections" : [
{
"lastDetectedOn" : ISODate("2020-01-29T04:36:41.191+0000"),
"lastDetectedBy" : "comp-t",
"_id" : ObjectId("5e3135f68c9e930017de8aec")
},
{
"lastDetectedOn" : ISODate("2019-12-21T18:12:06.571+0000"),
"lastDetectedBy" : "comp-n",
"_id" : ObjectId("5e3135f68c9e930017de8ae9")
},
{
"lastDetectedOn" : ISODate("2020-01-29T07:36:06.910+0000"),
"lastDetectedBy" : "comp-a",
"_id" : ObjectId("5e3135f68c9e930017de8ae7")
}
],
"createdAt" : ISODate("2019-12-10T21:52:49.788+0000"),
"updatedAt" : ISODate("2020-01-29T07:36:22.950+0000"),
"__v" : NumberInt(0)
}
I want to search by StockNo and get the name of the computer that last detected it (lastDetectedBy) only if lastDetectedOn was in the last 5 minutes with Mongoose in node.js with Express.
I also have this collection:
{
"_id" : ObjectId("5df113b10d35670018267a89"),
"InvoiceNo" : "1",
"InvoiceDate" : ISODate("2020-01-14T02:18:11.196+0000"),
"InvoiceContact : "",
"isActive" : true
},
{
"_id" : ObjectId("5df013c90a88910018267a8a"),
"InvoiceNo" : "2",
"InvoiceDate" : ISODate("2020-01-14T02:18:44.279+0000"),
"InvoiceContact : "Bob Smith",
"isActive" : true
},
{
"_id" : ObjectId("5e3096bb8c9e930017dc6e20"),
"InvoiceNo" : "3",
"InvoiceDate" : ISODate("2020-01-14T02:19:50.155+0000"),
"InvoiceContact : "",
"isActive" : true
}
And I want to update all the documents with empty InvoiceContact which has been issued in the last 30 seconds (or any date range between now and sometime in the past) with isActive equals true to isActive equals false. So for example, the first record has been issued in the last 30 seconds without InvoiceContact and isActive is true so this must be updated but the next two records will remain untouched for different reasons, the second record has InvoiceContact and the third record is out of range.

First Part
var mins5 = new Date(ISODate() - 1000* 60 * 5 )
db.getCollection('user').find({$and:[
{ "StockNo":"33598"},
{"detections.lastDetectedOn" : { $gte : mins5 }}
]})
.map(function(list){
var results = [];
list.detections.forEach(function (detections){
if(detections.lastDetectedOn > mins5){
results.push(detections.lastDetectedBy);
}
})
return results;
});
Second Part could be solved by a similar query using update instead of find.

Related

$merge, $match and $update in one aggregate query

I have data in a collection ex:"jobs". I am trying to copy specific data from "jobs" after every 2 hours to a new collection (which may not exist initially) and also add a new key to the copied data.
I have been trying with this query to copy the data:
db.getCollection("jobs").aggregate([{ $match: { "job_name": "UploadFile", "created_datetime" : {"$gte":"2021-08-18 12:00:00"} } },{"$merge":{into: {coll : "reports"}}}])
But after this, the count in "reports" collection is 0. Also, how can I update the documents (with an extract key "report_name") without using an extra updateMany() query?
The data in jobs collection is as shown:
{
"_id" : ObjectId("60fa8e8283dc22799134dc6f"),
"job_id" : "408a5654-9a89-4c15-82b4-b0dc894b19d7",
"job_name" : "UploadFile",
"data" : {
"path" : "share://LOCALNAS/Screenshot from 2021-07-23 10-34-34.png",
"file_name" : "Screenshot from 2021-07-23 10-34-34.png",
"parent_path" : "share://LOCALNAS",
"size" : 97710,
"md5sum" : "",
"file_uid" : "c4411f10-a745-48d0-a55d-164707b7d6c2",
"version_id" : "c3dfd31a-80ba-4de0-9115-2d9b778bcf02",
"session_id" : "c4411f10-a745-48d0-a55d-164707b7d6c2",
"resource_name" : "Screenshot from 2021-07-23 10-34-34.png",
"metadata" : {
"metadata" : {
"description" : "",
"tag_ids" : [ ]
},
"category_id" : "60eed9ea33c690a0dfc89b41",
"custom_metadata" : [ ]
},
"upload_token" : "upload_token_c5043927484e",
"upload_url" : "/mnt/share_LOCALNAS",
"vfs_action_handler_id" : "91be4282a9ad5067642cdadb75278230",
"element_type" : "file"
},
"user_id" : "60f6c507d4ba6ee28aee5723",
"node_id" : "syeda",
"state" : "COMPLETED",
"priority" : 2,
"resource_name" : "Screenshot from 2021-07-23 10-34-34.png",
"group_id" : "upload_group_0babf8b7ce0b",
"status_info" : {
"progress" : 100,
"status_msg" : "Upload Completed."
},
"error_code" : "",
"error_message" : "",
"created_datetime" : ISODate("2021-07-23T15:10:18.506Z"),
"modified_datetime" : ISODate("2021-07-23T15:10:18.506Z"),
"schema_version" : "1.0.0",
}
Your $match stage contains a condition which takes created_datetime as string while in your sample data it is an ISODate. Such condtion won't return any document, try:
{
$match: {
"job_name": "UploadFile",
"created_datetime": {
"$gte": ISODate("2021-07-01T12:00:00.000Z")
}
}
}
Mongo Playground

$add,$subtract aggregation-framework in mongodb

Hi i am mentioning the sample data
///collection - test////
{
"_id" : {
"date" : ISODate("2020-02-11T17:00:00Z"),
"userId" : ObjectId("5e43e5cdc11f750864f46820"),
"adminId" : ObjectId("5e43de778b57693cd46859eb")
},
"outstanding" : 212.39999999999998,
"totalBill" : 342.4,
"totalPayment" : 130
}
{
"_id" : {
"date" : ISODate("2020-02-11T17:00:00Z"),
"userId" : ObjectId("5e43e73169fe1e3fc07eb7c5"),
"adminId" : ObjectId("5e43de778b57693cd46859eb")
},
"outstanding" : 797.8399999999999,
"totalBill" : 797.8399999999999,
"totalPayment" : 0
}
I need to structure a query which does following things-
I need to calculate the actualOutstanding:[(totalBill+outstanding)-totalPayment],
I need to save this actualOutstanding in the same collection & in the same document according to {"_id" : {"date","userId", "adminId" }}
NOTE: userId is different in both the documents.
Introduced in Mongo version 4.2+ pipelined updates, meaning we can now use aggregate expressions to update documents.
db.collection.updateOne(
{
"adminId" : ObjectId("5e43de778b57693cd46859eb")
'_id."userId" : ObjectId("5e43e73169fe1e3fc07eb7c5"),
'_id.date': ISODate("2020-02-11T18:30:00Z"),
},
[
{ '$set': {
actualOutstanding: {
$subtract:[ {$add: ['$totalBill','$outstanding']},'$totalPayment']
}
} }
]);
For any other Mongo version you have to split it into 2 actions, first query and calculate then update the document with the calculation.

All fields search [duplicate]

This question already has answers here:
MongoDB Query Help - query on values of any key in a sub-object
(3 answers)
Closed 6 years ago.
This is my data set, which is part of a bigger json code. I want to write a query, which will match all fields inside the value chain.
Dataset:
"value_chain" : {
"category" : "Source, Make & Deliver",
"hpe_level0" : "gift Chain Planning",
"hpe_level1" : "nodemand to Plan",
"hpe_level2" : "nodemand Planning",
"hpe_level3" : "nodemand Sensing"
},
Example:
If someone searches for "gift", the query should scan through all fields, and if there is a match, return the document.
This is something I tried, but didnt work
db.sw_api.find({
value_chain: { $elemMatch: { "Source, Make & Deliver" } }
})
Sounds like you need to create $text index on all the text fields first since it performs a text search on the content of the fields indexed with a text index:
db.sw_api.createIndex({
"value_chain.category" : "text",
"value_chain.hpe_level0" : "text",
"value_chain.hpe_level1" : "text",
"value_chain.hpe_level2" : "text",
"value_chain.hpe_level3" : "text"
}, { "name": "value_chain_text_idx"});
The index you create is a composite index consisting of 5 columns, and mongo will automatically create the text namespace for you by default if you don't override it. With the above, if you don't specify the index name as
db.sw_api.createIndex({
"value_chain.category" : "text",
"value_chain.hpe_level0" : "text",
"value_chain.hpe_level1" : "text",
"value_chain.hpe_level2" : "text",
"value_chain.hpe_level3" : "text"
});
there is a potential error "ns name is too long (127 byte max)" since the text index will look like this:
"you_db_name.sw_api.$value_chain.category_text_value_chain.hpe_level0_text_value_chain.hpe_level1_text_value_chain.hpe_level2_text_value_chain.hpe_level3_text"
Hence the need to give it a name which is not too long if autogenerated by mongo.
Once the index is created, a db.sw_api.getIndexes() query will show you the indexes present:
/* 1 */
[
{
"v" : 1,
"key" : {
"_id" : 1
},
"name" : "_id_",
"ns" : "dbname.sw_api"
},
{
"v" : 1,
"key" : {
"_fts" : "text",
"_ftsx" : 1
},
"name" : "value_chain_text_idx",
"ns" : "dbname.sw_api",
"weights" : {
"value_chain.category" : 1,
"value_chain.hpe_level0" : 1,
"value_chain.hpe_level1" : 1,
"value_chain.hpe_level2" : 1,
"value_chain.hpe_level3" : 1
},
"default_language" : "english",
"language_override" : "language",
"textIndexVersion" : 3
}
]
Once you create the index, you can then do a $text search:
db.sw_api.find({ "$text": { "$search": "gift" } })

Mongo: Group, push and sort

I have a mongodb collection data as per below;I want to group by EmployeedID( i.e 0001) and then sort(by age)
{
"_id" : ObjectId("54d0512191a4da7736e9db43"),
"EmployeeID" : "0001",
"Speciality" : "xxx",
"Code" : "P",
"Age" : 8
}
/* 1 */
{
"_id" : ObjectId("54d0512191a4da7736e9db44"),
"EmployeeID" : "0002",
"Speciality" : "yyyyy",
"Code" : "P",
"Age" : 6
}
/* 2 */
{
"_id" : ObjectId("54d0512191a4da7736e9db45"),
"EmployeeID" : "0001",
"Speciality" : "zzz",
"Code" : "P",
"Age" : 5
}
I know I can group using the following way.
collection.aggregate([
{$match:{"EmployeeId":0001}},
{$group:{"_id":"$EmployeeID",
"speciality":{$push:"$Speciality"},
"Code":{$push:"$Code"},
"Age":{$push:"$Age"}}}
])
But how can I using $sort here? SO my result can be something like below;
[{ "EmployeeID" : "0001",
"speciality" : [ "zzz","xxx"],
"Code" :[ "P","P"],
"Age" : [5,8]
}]
You can sort the document prior to the grouping stage:
collection.aggregate([
{$sort: {_id: -1}},
{$match:{"EmployeeId":0001}},
{$group:{"_id":"$EmployeeID",
"speciality":{$push:"$Speciality"},
"Code":{$push:"$Code"},
"Age":{$push:"$Age"}}}
])
Sorting prior to grouping may exceed mongo's memory when dealing with large collections. Fortunately, you can set allowDiskUse to true to allow mongo to write temporary files.

MongoDB remove the lowest score, node.js

I am trying to remove the lowest homework score.
I tried this,
var a = db.students.find({"scores.type":"homework"}, {"scores.$":1}).sort({"scores.score":1})
but how can I remove this set of data?
I have 200 pieces of similar data below.
{
"_id" : 148,
"name" : "Carli Belvins",
"scores" : [
{
"type" : "exam",
"score" : 84.4361816750119
},
{
"type" : "quiz",
"score" : 1.702113040528119
},
{
"type" : "homework",
"score" : 22.47397850465176
},
{
"type" : "homework",
"score" : 88.48032660881387
}
]
}
you are trying to remove an element but the statement you provided is just to find it.
Use db.students.remove(<query>) instead. Full documentation here

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