I currently have a column of data with numbers. I want to create a second column which returns TRUE when a set of multiple conditions are TRUE. This column should return FALSE when one or more conditions are FALSE. The conditions are the following:
The number is negative (<= 0)
The number in this list is the closest to zero
The number in this list is not #N/A
The big trouble I'm having is because of these #N/A's in my dataset. I can't get my formula to ignore it. This is the current formula I use in column B, but for some reason I can't get this to work:
=IF(AND(A1<=0;A1=MAX(IF(NOT(IFNA($A$1:$A$300;TRUE));TRUE;FALSE)));TRUE;FALSE)
I suppose something's wrong in my interpretation of the IF(NOT(IFNA(...)) part.
Sorry if it's obvious, but can anyone help me out here?
I would use aggregate because there is an option to exclude NA's:
=IF(ISNA(A1),FALSE,A1=AGGREGATE(14,6,A$1:A$10/(A$1:A$10<0),1))
(this is assuming the number should be equal to the nearest negative number to zero, in other words the highest negative number. In this case you don't need a separate test for the number being negative)
I would use the array formula:
=IF(ISNA(A1),FALSE,IF(A1>0,FALSE,IF(A1=MAX(IF(A:A<0,A:A)),TRUE,FALSE)))
Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key. If this is done correctly, the formula will appear with curly braces around it in the Formula Bar.
Related
=(Countifs(B:B;”*”;F:F;”<>*1”))
Why doesn't this work?
I want to count all the rows in the sheet, except the ones that has a number that ends with 1 in column F. It just count all the rows, even the ones in column F that ends with 1.
How do I exclude those?
edit
Some more information!
This is a sample of the data:
Could be up to 8000 rows some days. Column B always says "Independent instruction" so I'm using that as a base to count all the rows. Column F contain only numbers, or blank cells (meaning a number will be added later). I still want to count those rows as well (that's blank). It's just the rows that has a number in column F that ends with 1 that I want to exclude!
SUMPRODUCT gives a bit more flexibility for criteria that involve more than straightforward string-matching:
=SUMPRODUCT(--(LEN($B:$B)>0),--(RIGHT($F:$F,1)<>"1"))
The array formula:
{=COUNT(IF((F:F<>"")*(MOD(F:F;10)<>1);F:F))}
will count all non empty cells in the conditions of your question.
Don't forget to press Ctrl+Shift+Enter to place the formula.
Why doesn't this work?
Apart from the fact that you have transcribed it incorrectly (i.e. missing =, and smart quotes ”) the 'F' condition in quotes is a Text value, a formatting issue #BigBen has mentioned in connection with the 'B' values.
You say It just count all the rows so, syntactically corrected, your formula must be working on (a) all 'B's populated (with Text) and (b) all 'F's Numeric. As 1 and "1" are not the same, none of your entries in ColumnF will be excluded by your attempt (none end in "1", though presumably some do end in 1).
#Pspl's A works because its condition (for the 'F's) is based on MOD (applies to Number format values) and #jsheeran's A (my preference) because RIGHT is a string function that returns Text format even from a Number format value.
Put another way, with say 1 in F1, =F1="1" returns FALSE (so =F1<>"1" and =F1<>"*1" return TRUE - that would not suit you) whereas =RIGHT(F1)="1" returns TRUE (or, to suit you, RIGHT(F1)<>"1" returns FALSE).
You can try to use a combination of SUM and IF. Remember to adjust the formula to match your Excel formatting, i.e. replace commas (,) with semicolon (;).
This is an array formula (enter with Ctrl+Shift+Enter)
=SUM(IF(MOD($F$2:$F$25,10)<>1,1,0))
Result (updated with your data set):
When pasting the image into merged cells, the error looks like that:
So you need to make sure the formula is pasted into a single (not merged) cell.
Array formula for values greater than 1000:
=SUM(IF((MOD($F$2:$F$25,10)<>1)*($F$2:$F$25>1000),1,0))
Array formula for values less than 1000:
=SUM(IF((MOD($F$2:$F$25,10)<>1)*($F$2:$F$25<1000),1,0))
Example:
I have a spreadsheet that I track my hours. Each cell initially is populated with a formula, i.e. =IF(WORKDAY(B24-1,1,holidays2019)=B24,OFFSET(C24,-1,2),0)
and then as the month progresses I enter my actual time.
In the following excerpt all values through 5/10/2019 are entered.
The formula =SUMIF(C5:C19,NOT(ISFORMULA(C5:C19))) shows zero. I do not understand why this does not work.
I appreciate any help! Column B in my spreadsheet corresponds to the dates shown below and Column C to the time entries.
Expected Result: 48.9
=SUMPRODUCT(J6:J20,--NOT(ISFORMULA(J6:J20)))
The key to this solution is the -- in front of the NOT(). A boolean that is processed by a math operator gets converted to 1 or 0. --, +0, -0, *1, /1 would have all worked to do the conversion. So now you wind up with an array of values you may want to sum being multiplied by an array of 1 and 0 to indicate the ones you want. The 1 are manual entry and the 0 are your formulas entries.
Now SUMPRODUCT performs array like calculations. As a result avoid using full column/row references inside it or you will wind up with a lot of excess calculations. Adjust the ranges in the answer to suit your needs.
Here's the MSDN definition of the Criteria in =SUMIF
criteria Required. The criteria in the form of a number, expression,
a cell reference, text, or a function that defines which cells will be
added. For example, criteria can be expressed as 32, ">32", B5, "32",
"apples", or TODAY().
Important: Any text criteria or any criteria that includes logical or
mathematical symbols must be enclosed in double quotation marks (").
If the criteria is numeric, double quotation marks are not required.
So, the reason, why your SUMIF returns 0 is, because none of the cells match the criteria, as they return a number and meanwhile they expect FALSE
Another issue here being, that the ISFORMULA will return TRUE, even when a range contains a single formula while all the rest has none. So basically you need to drag the formula down for each cell individually and sum them up only when a value is TRUE
Starting from cell D1:
=ISFORMULA(B1)
And then you can simply sum them up with the formula you provided.
=SUMIF(D1:D16,TRUE,C1:C16)
Obviously, you can hide the column D to make it more aesthetically pleasing.
Your formula fails because the criteria you're matching against, is TRUE/FALSE. Obviously the values in C5:C19 don't contain any booleans, so the sum is 0.
To solve this, you can add the correct criteria in cell D5 and below: =ISFORMULA(C5)
Then use =SUMIF(D5:D19,FALSE,C5:C19) to sum the values in column C.
I have this function:
MATCH(1,(PositionParameter[[#All],[Position Revised]]=$C94)asterisk(PositionParameter[[#All],[Campus Type Short]]=G$3)asterisk(PositionParameter[[#All],[Campus Num Arbitrary]]=G$1),0))
and I can't figure out what it does. I don't know what the asterisks are for. PositionParameter is the name of the worksheet, Position Revised is the name of a column, Campus Type Short is the name of a column, and Campus Num Arbitrary is the name of a column. There is suppose to be an asterisk between the first PositionParameter() and the second PositionParameter(). There is supposed to be another asterisk between the second PositionParameter() and the third PositionParameter(), but it is rendered as an italic. I took the asterisk out and spelled it out. The tooltip tells me this is suppose to return some sort of array, but I can't figure out its components. Can someone explain the asterisks to me? I would appreciate it.
Thanks,
Howard Hong
Your formula returns a single value - the relative position of the first row in the data where all three conditions are met.
It works like this:
Each of these three conditional statements:
PositionParameter[[#All],[Position Revised]]=$C94
PositionParameter[[#All],[Campus Type Short]]=G$3
PositionParameter[[#All],[Campus Num Arbitrary]]=G$1
.....returns an array of TRUE/FALSE values. Multiplying these three arrays together produces a single array of 1/0 values, 1 when all conditions are met in a row, 0 otherwise. This array forms the "lookup array" of the MATCH function
The "lookup value" is 1 so that value is looked up in the lookup array and the result of the MATCH function is the position of the first 1, which corresponds to the first row where all conditions are satisfied.
If there are no rows which meet all three conditions then the result is #N/A
Note that the zero at the end is the third parameter of the MATCH function - zero menas that an exact match must be found.
This is an "array formula" which needs to be confirmed with CTRL+SHIFT+ENTER
Often you would use this in conjunction with INDEX function to return a value from another column in the first row where conditions are satisfied, e.g. using normal cell references
=INDEX(A:A,MATCH(1,(B:B="x")*(C:C="y"),0))
That formula will return the value from column A in the first row where the two specified conditions are met (col B = "x"and col C = "y")
Well, asterisk could be a multiplication symbol or it could be a wildcard in Match. By the looks of the placement, I'd say it's multiplying data from an array or table.
And, um... I don't know what the asterisks are for but I took the asterisk out and spelled it out? Why would you do that? Was it working before you changed it? Where did you find this formula?
Please read [mcve]. Without sample data or other information about the purpose of the formula, I will take a wild guess:
Paste this into the cell:
=MATCH(1,(PositionParameter[[#All],[Position Revised]]=$C94)*(PositionParameter[[#All],[Campus Type Short]]=G$3)*(PositionParameter[[#All],[Campus Num Arbitrary]]=G$1),0))
. . . and assuming it's supposed to be an array, instead of hitting Enter on that cell:
hit: Ctrl+Shift+Enter to create an array formula.
Besides the link above, here is some other reading & practice for you:
Create an array formula
MATCH function
I think certains applications replace certain symbols (that aren't allowed in the application] with words when copying and pasting from Excel to them, but without more information about what happened, I can't say for sure what happened.
Assuming that the * are real and that the formula is entered as an array formula then it should return an array of 0s and 1s.
The formula is looking for Position Revised=C94 AND Campus Type Short =G3 AND Campus Num Arbitrary = G1
It will return a 1 for each row that matches all these conditions and a 0 for each row that does not.
If no rows match the conditions it will return #N/A
When I calculate the median of even numbers for e.g 1,2,3,4,5,6,7,8.. i want the return value to be 5 i.e. the higher value of the two middle values and not the average of 4 & 5. Please help
I don't have Excel, so I can't try it, but I think you should be able to accomplish this with a combination of the LARGE function the COUNT function, and the TRUNC function. For example, if the numbers you are working with are in cells A1 through A8, you should be able to find the answer you want, though technically it's not the median, with the formula
=LARGE(A1:A8,TRUNC(COUNT(A1:A8)/2))
Edit
=LARGE(A1:A8,TRUNC((1+COUNT(A1:A8))/2))
If you know you will always be working with an even number of entries, the call to TRUNC could be omitted.
With data in column A:
=IF(ISODD(COUNT(A:A)),MEDIAN(A:A),ROUNDUP(MEDIAN(A:A),0))
EDIT#1:
Consider the array formula:
=IF(ISODD(COUNT(A:A)),MEDIAN(A:A),MIN(IF(A:A>MEDIAN(A:A),A:A)))
If the number of values is odd, return the median. If the number of value is even, return the smallest value greater than the median.
Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key.
This approach does not require the data to be sorted.
EDIT#2:
This array formula appears to handle Ron's case:
=IF(ISODD(COUNT(A:A)),MEDIAN(A:A),MIN(IF(A:A>=MEDIAN(A:A),A:A)))
It returns the smallest value greater than or equal to the median (for the even case)
But I don't know if this is what the Poster wants.
=LARGE(A1:A9,INT((COUNT(A1:A9)/2)+0.5))
you can use Roundafter the Median
in your case you can type: =ROUND(MEDIAN(B4:I4),0)
lets say that the given range is from B4 to I4 from 1 to 8.
How do I average a list of numbers whose values are greater than 0? I know I can use AVERAGEIF function in Excel
My data is located in A2, A5, A6, A10, A17.
I only want to average it if the data is greater than 0.
Since my data is not an range, I am not able to use AVERAGEIF Function range.
Need some help on this.
EDIT
For example,
I tried with three numbers:
1) 98.068 and 98.954 and 0 so my forumla looked like this:
=AVERAGE(IF(N(OFFSET(A2,{0,5,10},))>0,N(OFFSET(A2,{0,5,10},))))
The answer came out as 99.106. Not sure why.
A few options:
1)=SUM(SUMIF(INDIRECT({"A2","A5","A6","A10","A17"}),">0"))/SUM(COUNTIF(INDIRECT({"A2","A5","A6","A10","A17"}),">0"))
2)=AVERAGE(IF(N(INDIRECT({"A2","A5","A6","A10","A17"}))>0,N(INDIRECT({"A2","A5","A6","A10","A17"}))))
3)
=AVERAGE(IF(N(OFFSET(A2,{0,3,4,8,15},))>0,N(OFFSET(A2,{0,3,4,8,15},))))
2) and 3) must be committed as array formulas**
Regards
(0) A simple method
=SUM(A2*(A2>0),A5*(A5>0),A6*(A6>0),A10*(A10>0),A17*(A17>0))/SUM(A2>0,A5>0,A6>0,A10>0,A17>0)
(4) A more general method
=SUM((A1:A20>0)*A1:A20*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))/
SUM((A1:A20>0)*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))
The second one is an array formula and must be entered with CtrlShiftEnter
If it's possible to have text in the cells rather than numbers, then this should replace the first formula:-
=SUM(N(A2)*(A2>0),N(A5)*(A5>0),N(A6)*(A6>0),N(A10)*(A10>0),N(A17)*(A17>0))/SUM(N(A2)>0,N(A5)>0,N(A6)>0,N(A10)>0,N(A17)>0)
(I haven't used N in the > brackets in the numerator because I reason that if A2 etc. is text, the product will always be zero)
I can't persuade N to work with arrays in the second formula, so at the moment I have the rather lengthy
=SUM((IF(ISNUMBER(A1:A20),A1:A20,0)>0)*IF(ISNUMBER(A1:A20),A1:A20,0)*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))/
SUM((IF(ISNUMBER(A1:A20),A1:A20,0)>0)*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))
but I have tested it on text values and negative numbers and it does seem fine.
The only exception is if one of the cells contains TRUE. In this case the first formula will count it as 1, the second formula will ignore it.