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I need to convert 1.22661727081984E+002 to 122.661727081984 using shell script. I have tried it using the below command:
echo "+1.22661727081984E+002" | awk -F"E" 'BEGIN{OFMT="%10.10f"} {print $1 * (10 ^ $2)}'
output:
122.6617270820
It is giving me the output but rounding off the last 4 digits.
I need the output without rounding off the result.
Using Bash's printf:
$ printf "%.14f\n" 1.22661727081984E+002
122.66172708198400
Using awk you can do it on this way:
awk '{ printf("%.100f\n",$1) }'
(assuming the number is first parameter)
Example:
echo "+1.22661727081984E+002"|awk '{ printf("%.100f\n",$1) }'
122.6617270819839973228226881474256515502930000000000000000000000000000000000000000000000000000000000000
(you can limit the number of digits by change the number in front of f)
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This is from a vhost file. This is the output I get
ServerName uat3-dam-something1.prg-dc.brb.com
Hello,
I'm wondering how to cut from this output so only this part remains
something1.prg-dc.brb.com
Keep in mind that "something" could be "something4141411" or "something23". So length operations won't work. Tried with cut command and AWK, but didn't work. I would be happy receive a tips from the bash experts :)
Like this :
grep -o 'something.*' file
or more specific:
grep -oE 'something[0-9]+\..*' file
Output:
something1.prg-dc.brb.com
Could you please try following, written and tested with provided samples only.
awk -F'uat3-dam-' '{print $NF}' Input_file
Description: Making uat3-dam- as field separator and printing last field of it.
2nd solution:
awk 'match($0,/something.*/){print substr($0,RSTART,RLENGTH)}' Input_file
Using:
echo "ServerName uat3-dam-something1.prg-dc.brb.com" |cut -d\- -f3-4
Will return:
something1.prg-dc.brb.com
And if you change the string (as you mention):
echo "ServerName uat3-dam-something111111.prg-dc.brb.com" |cut -d\- -f3-4
It will keep returning:
something111111.prg-dc.brb.com
$ echo 'ServerName uat3-dam-something1.prg-dc.brb.com' | awk -F- '{sub(".*" $2 FS,"")}1'
something1.prg-dc.brb.com
This will work:
echo "ServerName uat3-dam-something1.prg-dc.brb.com" | sed -E 's/.*(something.*)/\1/'
Or, if the string is in a file named file
sed -E 's/.*(something.*)/\1/' file
Explanation:
-E is for extended regex
.*(something.*) means "any char 0 or more times followed by something and any other char 0 or more times".
\1 is used to print only the matching part inside the brackets.
You could also use :
echo ${test#*dam-}
Example :
test="ServerName uat3-dam-something1.prg-dc.brb.com"
echo ${test#*dam-}
which gives:
something1.prg-dc.brb.com
Note that the opposite version would be echo ${test%something*}
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I have an hexadecimal string s and a file f, i need to search the first occurence of that string in the file and save that in a variable with his offset. I thought that the right way to do that is convert the file to hex and search that with a grep. The main problem is that i saw a lot of commands(hexdump,xxd,etc.) to convert but none of them actually work. Any suggestion?
My attempt was like this:
xxd -plain $f > $f
grep "$s" .
output should be like:
> offset:filename
A first approach without any error handling could look like
#!/bin/bash
BINFILE=$1
SEARCHSTRING=$2
HEXSTRING=$(xxd -p ${BINFILE} | tr -d "\n")
echo "${HEXSTRING}"
echo "Searching ${SEARCHSTRING}"
OFFSET=$(grep -aob ${SEARCHSTRING} <<< ${HEXSTRING} | cut -d ":" -f 1)
echo ${OFFSET}:${BINFILE}
I've used xxd here because of Does hexdump respect the endianness of its system?. Please take also note that according How to find a position of a character using grep? grep will return multiple matches, not only the first one. The offset will be counted beginning from 1, not 0. To substract 1 from the variable ${OFFSET} you may use $((${OFFSET}-1)).
I.e. search for the "string" ELF (HEX 454c46) in a system binary will look like
./searchHEX.sh /bin/yes 454c46
7f454c460201010000000000000000000...01000000000000000000000000000000
Searching 454c46
2:/bin/yes
I would use regex for this as well:
The text file:
$ cat tst.txt
1234567890x1fgg0x1cfffrr
A script you can easily change/extend yourself.
#! /bin/bash
part="$(perl -0pe 's/^((?:(?!0(x|X)[0-9a-fA-F]+).)*)(0(x|X)[0-9a-fA-F]+)(.|\n)*/\1:\3\n/g;' tst.txt)"
tmp=${part/:0x*/}
tmp=${#tmp}
echo ${part/*:0x/$tmp:0x} # Echoes 123456789:0x1f
Regex:
^((?:(?!0x[0-9a-fA-F]+).)*) = Search for the first entry that's a hexadecimal number and create a group of it (\1).
(0x[0-9a-fA-F]+) = Make a group of the hexadecimal number (\3).
(.|\n)* = Whatever follows.
Please note that tmp=${part/:0x*/} could cause problems if you have text like :0x before the hexadecimal number that is caught.
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I have a file name test,
it contains a String James Bond 007,
and i want to print only James Bond.
I tried the following commands:
$ strings -n 2 test
$ sed -n '/James/,/Bond/p' test
$ awk '{print substr($1,10)}' test
To print the first two words, you can use awk:
awk '{print $1, $2}' test
To print the first ten characters, you can put the file contents in a variable, then use the bash substring operation:
contents=$(cat test)
echo "${contents:0:10}"
Or in awk:
awk '{print substr($0, 1, 10)}' test
Notice that $0 means the whole line, and you have to give both a starting index and length to substr(). Indexes in awk start at 1 rather than 0.
In sed, /James/,/Bond/ is a line range expression; it processes all the lines starting from a line containing James until a line containing Bond. It doesn't process just part of the lines.
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In my Bash script, I have to change a name to a path address(new address) in a text file:
(MYADDREES) change to ( /home/run1/c1 ) and save it as new file.
I did like this: defined a new variable = new address and tried to replace it in previous address in text file.
I use sed but it has problem.
My script was:
#!/bin/bash
# To debug
set -x
x=`pwd`
echo $x
sed "s/MYADDRESS/$x/g" < sample1.txt > new.txt
exit
The output of pwd is likely to contain / characters, making your sed expression look something like s/MYADDRESS//home/user/somewhere/. This makes it impossible for sed to sort out what should be replaced with what. There are two solutions:
Use a different delimiter for sed:
sed "s,MYADDRESS,$x,g" < sample1.txt > new.txt
...although this will have the same problem if the current path contains a comma character or something else that is a special character for sed, so the more robust approach is to use awk instead:
awk -v curdir="$(pwd)" '{ gsub("MYADDRESS", curdir); print }' < sample1.txt > new.txt
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I am building a AIX bash shell utility whereby i get a dynamic variable with value like status(running).
I just need the string within brakets that is running.
Right now i am able to get the whole word with status along with the brackets using awk print.
Can anyone suggest me how to just extract the running out of it. Thanks.
Let's say:
s='(running)'
Using pure BASH:
echo "${s//[()]/}"
running
Using sed:
echo "$s" | sed 's/[()]//g'
running
Using tr:
tr -d '()' <<< "$s"
running
UPDATE: As per comments by OP:
s='status(running)'
Using sed:
echo "$s" | sed 's/^.*(\(.*\)).*$/\1/g'
running
Using pure BASH:
t="${s#*\(}"
echo "${t%)*}"
running