how to handle new page on button click in pupeteer? - node.js

Question

i am using puppeteer in a project to test a web page , in the page i have several buttons that open a new tab in the browser , how can i handle that using puppeteer?
const puppeteer = require('puppeteer');
(async() => {
const browser = await puppeteer.launch({ defaultViewport: null });
const page = await browser.newPage();
// go to the URL
await page.goto('https://example.com/', {waitUntil: 'networkidle'});
await page.click('.btnId'); //opens new tab with Page 2
// handle Page 2
// process Page 2
// close Page 2
// go back to Page 1
browser.close();
})();
how can i handle the page 2 ?

Answer 1

await page.waitFor(3 * 1000) // wait for new page to open
const pages = await browser.pages() // get all pages
const page2 = pages[pages.length - 1] // get the new page
// process the new page
await page2.close()

Answer 2

Hope this helps in solving the problem.
const puppeteer = require('puppeteer');
(async() => {
const browser = await puppeteer.launch({ defaultViewport: null });
const page = await browser.newPage();
// go to the URL
await page.goto('https://example.com/', {waitUntil: 'networkidle'});
await page.click('.btnId'); //opens new tab with Page 2
// you can make this as dynamic as well depends on the website and use case.
const [tabOne, tabTwo] = (await browser.pages());
// use the tabs Page objects properly
console.log("Tab One Title ",await tabOne.title());
// use the tabs Page objects properly
console.log("Tab Two Title ",await tabTwo.title());
// you can use close property for tab when it's done.
browser.close();
})();