Considering the following example list:
1
2
3
10
11
4
9
8
5
6
what rule would highlight the unsorted elements, so that the following list is achieved:
1
2
3
**10**
**11**
4
**9**
**8**
5
6
You could use a rule based on a formula similar to the following:
=COUNTIF(A2:$A$10,"<"&A1)>0
Related
I seem to run into some python or enumerate bugs that I am not quite sure how to fix it (See here for more details).
Long story short, I desire to see multiple data sets that has a column name of 0,4,6,8,10,12,14.
0 4 6 8 10 12
1 2 5 4 2 1
5 3 0 1 5 10
....
But my current data looks like the following
0 4 2 6 8 10 12
1 2 5 4 2 1
5 3 0 1 5 10
....
Therefore, I would like to add a code that keeps columns based on the index number (including only 0,4,6,8,10,12).
Is there a pandas function that can help with this?
I can use
=COUNTIFS(range1, criteria1, range2, criteria2…) + COUNTIFS(...) etc
Count number of rows with conditions met in two columns
My data is such that the above will require needing approximately 150+ instances of countifs just for one cell. And I need to do this for 10K or so cells.
So wondering if there is another function/way to do this in a more efficient manner? Example of data as follows;
1 2 10 6
2 3 9 4
3 4 8 5
7 6 7 2
4 5 1 6
2 1 6 7
5 6 2 8
2 5 3 10
6 7 2 10
And need to count how many times number 2 & 6 occur on the same row.
EDIT: I also need to do this with any number combination. ie 2&6, 1&6, 5&10 etc.
Thanks
Add a column with a serial no from 1 to n.
Then use a nested if:
SUM(IF(SERIAL_NO = SERIAL NO
IF( IF COLUMN1 =2 AND COLUMN 3 = 6,10))) AS 26
I am trying to fill data in MS Excel. I am given following pattern:
1 2
1
1
2 5
2 5
2
3
3 6
3
4
4
5 4
And I want my output in following format:
1 2
1 2
1 2
2 5
2 5
2 5
3 6
3 6
3 6
4
4
5 4
I tried using if(b2,b2,c1) in column 3. but that doesn't solve the problem for a=3 and a=4.
Any idea how to do this in Excel?
With sorting thus:
(the effect of which in this case is merely to move 6 up once cell) and a blank row above:
=IF(AND(A2<>A1,B2=""),"",IF(B2<>"",B2,C1))
In C2 and copied down should get the result you ask for from the data sample provided.
I have the following file:
BTA Pos KLD
4 79.7011 5.7711028907
4 79.6231 5.7083918219
5 20.9112 4.5559494707
5 50.7354 4.2495580809
5 112.645 4.0936819092
6 72.8212 4.9384741047
6 18.3889 7.3631759258
I want to use AWK or bash commands to sort the second column based on the first column to have the output as follows:
4 79.6231 5.7083918219
4 79.7011 5.7711028907
5 20.9112 4.5559494707
5 50.7354 4.2495580809
5 112.645 4.0936819092
6 18.3889 7.3631759258
6 72.8212 4.9384741047
sort numerically on column one then on column two:
$ sort -nk1,1 -nk2,2 file
BTA POS KLD
4 79.6231 5.7083918219
4 79.7011 5.7711028907
5 20.9112 4.5559494707
5 50.7354 4.2495580809
5 112.645 4.0936819092
6 18.3889 7.3631759258
6 72.8212 4.9384741047
I need to determine the range to apply the Frequency function. Here's what the problem is. On the given sheet, I have subtotals for my data and there is a column which has "Stop" Values.
The data would look something like:
Route1
Order# Stop# Qty
001016 1 5
008912 1 5
062232 2 6
062232 3 2
069930 4 1
1000 4 3
1001 4 4
1001 5 8
1003 8 1
Route 1 Subtotal 6 35
Route2
Order# Stop# Qty
10065 1 5
10076 1 5
10077 2 6
10079 3 2
10087 4 1
10098 4 3
10109 4 4
10171 5 8
10175 8 1
Route 2 Subtotal 6 35
How do I write VBA code for calculating the distinct stop values. I need the distinct count of the stop#. Hence in the example above you can see that the total stops are 6 because 1 stop can have multiple orders and 1 route can have multiple orders/stop. Hope I am making sense here. Let me know how I would write my VBA code for this. Thanks for your help.
For the Stop Subtotal unique count, try this formula (adjust ranges as required):
=COUNT(1/FREQUENCY(B2:B10,B2:B10))