I am trying to fill data in MS Excel. I am given following pattern:
1 2
1
1
2 5
2 5
2
3
3 6
3
4
4
5 4
And I want my output in following format:
1 2
1 2
1 2
2 5
2 5
2 5
3 6
3 6
3 6
4
4
5 4
I tried using if(b2,b2,c1) in column 3. but that doesn't solve the problem for a=3 and a=4.
Any idea how to do this in Excel?
With sorting thus:
(the effect of which in this case is merely to move 6 up once cell) and a blank row above:
=IF(AND(A2<>A1,B2=""),"",IF(B2<>"",B2,C1))
In C2 and copied down should get the result you ask for from the data sample provided.
Related
In excel I have a dataset. This represents how much stock of 2 products is sold in the first, second, third, etc... month of the product being on the shelves (starts in A1):
Month 1 2 3 4 5 6 7 8 9 10 11 12
Product 1 3 5 2 1 6 1 2 4 7 2 1 5
Product 2 2 1 5 6 2 8 2 1 2 3 4 9
However, the first product sales do not always occur in month 1. They occur in month X. Is there a way (not VBA or copy and paste) of shifting the entries right by 'x' so they align with the month.
Example for data above
Product 1 starts in month 2
Product 2 starts in month 5
Month 1 2 3 4 5 6 7 8 9 10 11 12
Product 1 0 3 5 2 1 6 1 2 4 7 2 1 5
Product 2 0 0 0 0 2 1 5 6 2 8 2 1 2 3 4 9
*0 not required (great if possible), but more for illustration
Thanks
I have created a simple example that does the same job. The shown formula is copied over the shown cells in the row of new data. (The number '2' in the formula refers to the column number of the starting data cell which is column B, hence 2.)
I am working on creating a user friendly character sheet for the new Pathfinder Playtest in Excel. I have run into an issue with a section and I have come here for help, not sure if it's the right place.
I want to have a cell return a value from a table (below) based on two other cell's values, e.g., if A1=19 and B1=4th it would pull the number from the appropriate area (3 in this case).
1st 2nd 3rd 4th 5th 6th 7th 8th 9th
1 2
2 3
3 3 2
4 3 3
5 3 3 2
6 3 3 3
7 3 3 3 2
8 3 3 3 3
9 3 3 3 3 2
10 3 3 3 3 3
11 3 3 3 3 3 2
12 3 3 3 3 3 3
13 3 3 3 3 3 3 2
14 3 3 3 3 3 3 3
15 3 3 3 3 3 3 3 2
16 3 3 3 3 3 3 3 3
17 3 3 3 3 3 3 3 3 2
18 3 3 3 3 3 3 3 3 3
19 3 3 3 3 3 3 3 3 3
20 3 3 3 3 3 3 3 3 3
I have tried using the below as well as just Indexing and I can't figure this out. Any help is appreciated, thanks!
=INDEX(P137:X156,MATCH(B2,O137:O156,1),MATCH(A10,P137:P156,1))
=INDEX(O137:O156,MATCH(1,(J125=P137:P156)*(J126=Q137:Q156)*(J127=R137:R156)*(J128=S137:S156)*(J129=T137:T156)*(J130=U137:U156)*(J131=V137:V156)*(J132=W137:W156)*(J133=X137:X156),0))
Let's say your data starts at A1 like image below:
I Added 2 simple cells where user chooses the row and the column. Both cells use data validation lists related to your data, so no wrong info can be entered.
The formula is:
=INDEX($1:$1048576;MATCH($C$25;$A:$A;0);MATCH($C$26;$1:$1;0))
Hope you can adapt this to your needs.
You can download the sample from Google Drive if you wish:
https://drive.google.com/open?id=1QXFmmEPMtJeiHDjKKM0o6kclpMIzaw_i
I have a datafile with 10 columns as given below
ifile.txt
2 4 4 2 1 2 2 4 2 1
3 3 1 5 3 3 4 5 3 3
4 3 3 2 2 1 2 3 4 2
5 3 1 3 1 2 4 5 6 8
I want to add 11th column which will show the standard deviation of each rows along 10 columns. i.e. STDEV(2 4 4 2 1 2 2 4 2 1) and so on.
I am able to do by taking tranpose, then using the following command and again taking transpose
awk '{x[NR]=$0; s+=$1} END{a=s/NR; for (i in x){ss += (x[i]-a)^2} sd = sqrt(ss/NR); print sd}'
Can anybody suggest a simpler way so that I can do it directly along each row.
You can do the same with one pass as well.
awk '{for(i=1;i<=NF;i++){s+=$i;ss+=$i*$i}m=s/NF;$(NF+1)=sqrt(ss/NF-m*m);s=ss=0}1' ifile.txt
Do you mean something like this ?
awk '{for(i=1;i<=NF;i++)s+=$i;M=s/NF;
for(i=1;i<=NF;i++)sd+=(($i-M)^2);$(NF+1)=sqrt(sd/NF);M=sd=s=0}1' file
2 4 4 2 1 2 2 4 2 1 1.11355
3 3 1 5 3 3 4 5 3 3 1.1
4 3 3 2 2 1 2 3 4 2 0.916515
5 3 1 3 1 2 4 5 6 8 2.13542
You just use the fields instead of transposing and using the rows.
1 2 2
4 5 4
3 3 3
0 1 0
1 2 2
4 4 3
4 5 4
4 5 4
3 4 4
3 4 4
4 4 4
3 4 3
I have above three columns in excel,how to find the number that appears more times, for example, first row is 2 (because it has two 2 and one 1)
Assuming your layout is such that the first column is A, second column is B, etc., then you could put the following in cell D1:
=IF(ISNUMBER(MODE(A1:C1)),MODE(A1:C1),0)
This also outputs 0 in case there is a tie. You can replace the 0 with whatever excel expression you want if you don't want ties to result in a 0.
A B ANSWER
1 1 1
3 3 3
1 2 1
2 4 2
4 4 4
5 5 5
6 6 6
i have used this function to get above answer "=IF(ISERROR(MATCH(A2:A8,$B$1:$B$8,0)),"",A2)"
but I need answer like this i have given below (suppose if you take value in A column "1"
Which is repeated only once in column B)
A B ANR
1 1 1
3 3 3
1 2 0
2 4 2
4 4 4
5 5 5
6 6 6
I've just wrapped your formula in a condition that returns 0 where the count of the A value from start to the current row is more than one:
=IF(COUNTIF(A$1:A2,A2)>1,0,IF(ISERROR(MATCH(A2:A8,$B$1:$B$8,0)),"",A2))
.
An alternative formula that gives the same results as above for the sample data provided but may (or may not) suit the additional requirements mentioned in a comment:
=IF(COUNTIF(A$2:A$10,A2)<=COUNTIF(B$2:B$10,A2),A2,IF(COUNTIF(A$2:A2,A2)>COUNTIF(B$2:B$10,A2),0,IF(COUNTIF(A$2:A$10,A2)>COUNTIF(B$2:B2,A2),A2,0)))