Using CLI I try to close/send to background a process which loads at startup - the first thing I see is that process and not the regular shell.
Ctrl x/c/z don't work. Kill -9 does (connecting with ssh and send the signal)
If I kill the process (which loads at startup) and then execute it again , it will reapond to each signal.
I try to figure out what could be the problem
I can't post the program's source (related to workplace). Lets say it's a simple printf("hello world\n") , scanf and return. since this program autostart during kernel startup (with inittab script..) is it possible that it starts before the bash shell and thats why it can't recieve these signals?
Related
I have this command in my shell script that runs forever- it wouldn't finish unless I do ctrl-c. I have been trying to look up how to send ctrl-c signal to script and all the answers have been some sort of kill $! or kill$$ or such. My problem is that the command never finishes, so it never goes on to the next command like my "kill" commands or anything else. I have to manually hit the ctrl-C in my terminal for it to even execute kill $!. I'm sure there is a way to work around this but I am not sure what. Thanks in advance!
There are several approaches to this problem. The simplest (but not most robust) is (perhaps) to simply run your long running command in the background:
#!/bin/sh
long-running-command & # run in the background
sleep 5 # sleep for a bit
kill %1 # send SIGTERM to the command if it's still running
I use Leiningen REPL that uses SIGINT to interrupt currently running code and to output a new prompt. The REPL can be stopped using SIGHUP or SIGKILL. I don't actually run anything in the REPL - I just use it for some pre-defined side-effects.
The problem is that IntelliJ IDEA can only send SIGINT when it exits to the processes that it has started. So if I forget to kill a REPL started from IDEA, there'll be a dandling process that I have to kill manually.
Is it possible to write a shell script that starts the REPL, gives it some dummy stdin/stdout (otherwise, REPL immediately quits), and waits for the process to end, while also forwarding it all signals, transforming SIGINT into SIGHUP or SIGKILL?
Open a terminal window and start the REPL inside of it. The process will terminate when you close the terminal window or when you press Ctrl+D (Ctrl+Z on Windows).
You can then minify the terminal window, so it doesn't annoy.
This Python code does what's needed:
from subprocess import call
import sys
try:
call(sys.argv[1:])
except KeyboardInterrupt:
pass
All its parameters are the command line that you want to be executed. The running application will always be closed by SIGINT.
I have programmed a C program and tested it on my linux computer.
I have uploaded it to my server now and want it to run there the entire time as a background progress.
How is it possible to start a program which will continue to run after i close putty?
Thanks for any help!
you can leave the program running by adding a & to the call
So when you have been executing your code before like this in SSH:
./mycode
you would to it like:
./mycode &
If you want running your program in background you must add the '&' character to command.
./program &
But the process will be associated to the current tty. If you close the current tty (in your case the SSH session) the SIGHUP signal is sent to all processes associated with the tty, causing them finish. You can see the associated tty to one process with ps command.
The disown command can be used to mark jobs so that a SIGHUP signal is not sent to them if the parent shell receives it. Before closing the current tty you can write:
disown %jobID
You can see the jobID enclosed in brackets when you run the program in background. Also you can see the jobID with jobs command.
You can run the command directly so that a SIGHUP signal is not sent to him. For this you can use nohup command.
nohup ./program &
Another way to avoid ending the program with the SIGHUP signal is to catch this signal in the program. In a C program you can do this with signal function that is in signal.h
But if you want run the program as a daemon or server, better write a Systemd service or a System V init script.
In the middle of the executing your program, if you want to run your program in background.
First press ctrl + z then type bg.
As far as I know, when you run a command, like
> sleep 3
The shell process will fork another process and run the command with the child process.
However when you do
> (sleep 3)
you launch a subshell and execute the command. Essentially what it does is also fork another process to execute the command and wait the command to complete.
In this case, the behavior of the two commands looks the same, the parent shell will wait the sleep command to complete.
However sometime I noticed things are different with subshell:
For example, if I run some command like:
> virtualbox &
If I accidentally close the terminal the virtualbox will close at the same time. I already screwed my ongoing work several time in this way.
However if I do it this way it the program won't be killed even if I exited the terminal:
> (virtualbox &)
So I am not sure what's going on under the hood? How are the tasks started and managed by the shell with the two different approach?
As others write, using nohup will allow you to run the process without it being terminated when your shell is terminated. What happens in the two cases you describe is the following.
In the virtualbox & case virtualbox becomes a child of your shell. When your controlling terminal is closed all processes associated with it receive a SIGHUP signal, and are terminated.
In the (virtualbox &) case the command is executed within a subshell. When the subshell terminates, the command is disassociated from the shell and the terminal. (You can see this by running ps.) In this case the SIGHUP will not be sent to virtualbox, and therefore your command will not be terminated when the controlling terminal is closed.
The nohup command achieves the same result by specifying that the SIGHUP signal must be ignored.
I'm trying to use a shell script to start a command. I don't care if/when/how/why it finishes. I want the process to start and run, but I want to be able to get back to my shell immediately...
You can just run the script in the background:
$ myscript &
Note that this is different from putting the & inside your script, which probably won't do what you want.
Everyone just forgot disown. So here is a summary:
& puts the job in the background.
Makes it block on attempting to read input, and
Makes the shell not wait for its completion.
disown removes the process from the shell's job control, but it still leaves it connected to the terminal.
One of the results is that the shell won't send it a SIGHUP(If the shell receives a SIGHUP, it also sends a SIGHUP to the process, which normally causes the process to terminate).
And obviously, it can only be applied to background jobs(because you cannot enter it when a foreground job is running).
nohup disconnects the process from the terminal, redirects its output to nohup.out and shields it from SIGHUP.
The process won't receive any sent SIGHUP.
Its completely independent from job control and could in principle be used also for foreground jobs(although that's not very useful).
Usually used with &(as a background job).
nohup cmd
doesn't hangup when you close the terminal. output by default goes to nohup.out
You can combine this with backgrounding,
nohup cmd &
and get rid of the output,
nohup cmd > /dev/null 2>&1 &
you can also disown a command. type cmd, Ctrl-Z, bg, disown
Alternatively, after you got the program running, you can hit Ctrl-Z which stops your program and then type
bg
which puts your last stopped program in the background. (Useful if your started something without '&' and still want it in the backgroung without restarting it)
screen -m -d $command$ starts the command in a detached session. You can use screen -r to attach to the started session. It is a wonderful tool, extremely useful also for remote sessions. Read more at man screen.