bash subshell vs vanilla command execution - linux

As far as I know, when you run a command, like
> sleep 3
The shell process will fork another process and run the command with the child process.
However when you do
> (sleep 3)
you launch a subshell and execute the command. Essentially what it does is also fork another process to execute the command and wait the command to complete.
In this case, the behavior of the two commands looks the same, the parent shell will wait the sleep command to complete.
However sometime I noticed things are different with subshell:
For example, if I run some command like:
> virtualbox &
If I accidentally close the terminal the virtualbox will close at the same time. I already screwed my ongoing work several time in this way.
However if I do it this way it the program won't be killed even if I exited the terminal:
> (virtualbox &)
So I am not sure what's going on under the hood? How are the tasks started and managed by the shell with the two different approach?

As others write, using nohup will allow you to run the process without it being terminated when your shell is terminated. What happens in the two cases you describe is the following.
In the virtualbox & case virtualbox becomes a child of your shell. When your controlling terminal is closed all processes associated with it receive a SIGHUP signal, and are terminated.
In the (virtualbox &) case the command is executed within a subshell. When the subshell terminates, the command is disassociated from the shell and the terminal. (You can see this by running ps.) In this case the SIGHUP will not be sent to virtualbox, and therefore your command will not be terminated when the controlling terminal is closed.
The nohup command achieves the same result by specifying that the SIGHUP signal must be ignored.

Related

How do I terminate a command that runs infinitely in shell script?

I have this command in my shell script that runs forever- it wouldn't finish unless I do ctrl-c. I have been trying to look up how to send ctrl-c signal to script and all the answers have been some sort of kill $! or kill$$ or such. My problem is that the command never finishes, so it never goes on to the next command like my "kill" commands or anything else. I have to manually hit the ctrl-C in my terminal for it to even execute kill $!. I'm sure there is a way to work around this but I am not sure what. Thanks in advance!
There are several approaches to this problem. The simplest (but not most robust) is (perhaps) to simply run your long running command in the background:
#!/bin/sh
long-running-command & # run in the background
sleep 5 # sleep for a bit
kill %1 # send SIGTERM to the command if it's still running

How to start C Program on Server to run in background

I have programmed a C program and tested it on my linux computer.
I have uploaded it to my server now and want it to run there the entire time as a background progress.
How is it possible to start a program which will continue to run after i close putty?
Thanks for any help!
you can leave the program running by adding a & to the call
So when you have been executing your code before like this in SSH:
./mycode
you would to it like:
./mycode &
If you want running your program in background you must add the '&' character to command.
./program &
But the process will be associated to the current tty. If you close the current tty (in your case the SSH session) the SIGHUP signal is sent to all processes associated with the tty, causing them finish. You can see the associated tty to one process with ps command.
The disown command can be used to mark jobs so that a SIGHUP signal is not sent to them if the parent shell receives it. Before closing the current tty you can write:
disown %jobID
You can see the jobID enclosed in brackets when you run the program in background. Also you can see the jobID with jobs command.
You can run the command directly so that a SIGHUP signal is not sent to him. For this you can use nohup command.
nohup ./program &
Another way to avoid ending the program with the SIGHUP signal is to catch this signal in the program. In a C program you can do this with signal function that is in signal.h
But if you want run the program as a daemon or server, better write a Systemd service or a System V init script.
In the middle of the executing your program, if you want to run your program in background.
First press ctrl + z then type bg.

What if we close the terminal before finishing the command?

Let me explain better. What is gonna happen if I run a command in Linux and before it's done and you could enter another command I close the terminal. Would it still do the command or not?
Generally, you must expect that closing your terminal will hangup your command. But fear not! Linux has a solution for that too!
To ensure that your command completes, use the nohup argument first. Simply place it before whatever you are trying to do:
nohup ./some_program
nohup ./do_a_thing -frx -file input_file.txt
nohup grep "something" giant_list_of_files/* > temp_file.txt
The nohup command stands for "no hangup" and it will ensure that the command you execute continues to run, even if you close your terminal.
It depends on the process and your environment (job control shell options, VNC, etc). But typically, no. The process will get a "hangup" signal (message) from the operating system, and upon receiving that, will quit.
The nohup command, for example, arranges for processes to ignore the hangup signal from the OS. There are many ways to achieve the same result.
I would say it will abort att the status you are in just before the session close.
If you want to be sure to complete the job, you will need to use the nohup command.
http://en.wikipedia.org/wiki/Nohup
Read about nohups and daemons (-d)...
A good link is [link]What's the difference between nohup and a daemon?
Worth look at screen command, Screen command offers the ability to detach a long running process (or program, or shell-script) from a session and then attach it back at a later time.

What does "&" at the end of a linux command mean?

I am a system administrator and I have been asked to run a linux script to clean the system.
The command is this:
perl script.pl > output.log &
so this command is ending with a & sign, is there any special significance of it?
I have basic knowledge of shell but I have never seen this before.
The & makes the command run in the background.
From man bash:
If a command is terminated by the control operator &, the shell
executes the command in the background in a subshell. The shell does
not wait for the command to finish, and
the return status is 0.
When not told otherwise commands take over the foreground. You only have one "foreground" process running in a single shell session. The & symbol instructs commands to run in a background process and immediately returns to the command line for additional commands.
sh my_script.sh &
A background process will not stay alive after the shell session is closed. SIGHUP terminates all running processes. By default anyway. If your command is long-running or runs indefinitely (ie: microservice) you need to pr-pend it with nohup so it remains running after you disconnect from the session:
nohup sh my_script.sh &
EDIT: There does appear to be a gray area regarding the closing of background processes when & is used. Just be aware that the shell may close your process depending on your OS and local configurations (particularly on CENTOS/RHEL):
https://serverfault.com/a/117157.
In addition, you can use the "&" sign to run many processes through one (1) ssh connections in order to to keep minimum number of terminals. For example, I have one process that listens for messages in order to extract files, the second process listens for messages in order to upload files: Using the "&" I can run both services in one terminal, through single ssh connection to my server.
These processes running through the "&" will also "stay alive" after ssh session is closed. Pretty neat and useful if the ssh connection to the server is interrupted and no terminal multiplexer (screen, tmux, byobu) was used.
I don’t know for sure but I’m reading a book right now and what I am getting is that a program need to handle its signal ( as when I press CTRL-C). Now a program can use SIG_IGN to ignore all signals or SIG_DFL to restore the default action.
Now if you do $ command & then this process running as background process simply ignores all signals that will occur. For foreground processes these signals are not ignored.
If you have a command which executes and doesn't return status 0(control of prompt) quickly.
For example:
command gedit launches the default editor gedit UI.
commandeclipse launches eclipse IDE.
Such commands keep throwing the logs of activities in the terminal and don't return the command prompt.
Question is, how to run such commands in background so that, we will get back command terminal and we can use terminal for other tasks.
Answer is: by appending & after such command.
user#mymachine:~$ <command> &
Examples:
user#mymachine:~$ edit &
user#mymachine:~$ eclipse &

Asynchronous shell commands

I'm trying to use a shell script to start a command. I don't care if/when/how/why it finishes. I want the process to start and run, but I want to be able to get back to my shell immediately...
You can just run the script in the background:
$ myscript &
Note that this is different from putting the & inside your script, which probably won't do what you want.
Everyone just forgot disown. So here is a summary:
& puts the job in the background.
Makes it block on attempting to read input, and
Makes the shell not wait for its completion.
disown removes the process from the shell's job control, but it still leaves it connected to the terminal.
One of the results is that the shell won't send it a SIGHUP(If the shell receives a SIGHUP, it also sends a SIGHUP to the process, which normally causes the process to terminate).
And obviously, it can only be applied to background jobs(because you cannot enter it when a foreground job is running).
nohup disconnects the process from the terminal, redirects its output to nohup.out and shields it from SIGHUP.
The process won't receive any sent SIGHUP.
Its completely independent from job control and could in principle be used also for foreground jobs(although that's not very useful).
Usually used with &(as a background job).
nohup cmd
doesn't hangup when you close the terminal. output by default goes to nohup.out
You can combine this with backgrounding,
nohup cmd &
and get rid of the output,
nohup cmd > /dev/null 2>&1 &
you can also disown a command. type cmd, Ctrl-Z, bg, disown
Alternatively, after you got the program running, you can hit Ctrl-Z which stops your program and then type
bg
which puts your last stopped program in the background. (Useful if your started something without '&' and still want it in the backgroung without restarting it)
screen -m -d $command$ starts the command in a detached session. You can use screen -r to attach to the started session. It is a wonderful tool, extremely useful also for remote sessions. Read more at man screen.

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