How to use Unix regex character with python3 subprocesses run? [duplicate] - python-3.x

Question

This question already has answers here:
subprocess wildcard usage
(3 answers)
Closed 3 years ago.
I'm trying to get the output from a shell command in a Python3 program. I've been looking at the documentation and this is what I've been working with:
sortered=subprocess.run(
# ['sort', time.strftime("%Y")+'*', '|', 'uniq', '-u'], # causes error did not understand * char
#['ls', '-l'], # worked fine
['sort', '2019*'], # gives same error as before
capture_output=True
)
After running the script I get back this error:
$ myscript.py
CompletedProcess(args=['sort', '2019*'], returncode=2, stdout=b'', stderr=b"sort: cannot read: '2019*': No such file or directory\n")
To_Downloadtest1.sh has been created successfully
If I run the command normally using * it works fine.
$ sort 2019*
a file.
a file.
this one is a.
this one is b.
The script is ran from the same directory that the files starting with 2019 are in.
.
├── 2019-A.txt
├── 2019-B.txt
└── myscript.py
What should happen when I run the python script is the output from the command should be put into a variable as a string. This is not happening. The only time I get an error from subprocess.run comes from using * in the command. Otherwise, I get the stdout from subprocess.run correctly. I tried ls -l as a test and it worked correctly. How can I use * with subprocess.run?

Answer 1

The problem here is that you don't have a shell, and so the wildcard does not get expanded.
You can use
sortered = subprocess.run('sort 2019*', shell=True, capture_output=True)
or
import glob
sortered = subprocess.run(['sort'] + glob.glob('2019*'), capture_output=True)
or, of course,
import glob
lines = []
for file in glob.glob('2019*') as handle:
lines.extend(handle.read())
sortered = sorted(lines)