How to know if returning an l-value when using `FALLBACK`? - metaprogramming

How can I know if I actually need to return an l-value when using FALLBACK?
I'm using return-rw but I'd like to only use return where possible. I want to track if I've actually modified %!attrs or have only just read the value when FALLBACK was called.
Or (alternate plan B) can I attach a callback or something similar to my %!attrs to monitor for changes?
class Foo {
has %.attrs;
submethod BUILD { %!attrs{'bar'} = 'bar' }
# multi method FALLBACK(Str:D $name, *#rest) {
# say 'read-only';
# return %!attrs{$name} if %!attrs«$name»:exists;
# }
multi method FALLBACK(Str:D $name, *#rest) {
say 'read-write';
return-rw %!attrs{$name} if %!attrs«$name»:exists;
}
}
my $foo = Foo.new;
say $foo.bar;
$foo.bar = 'baz';
say $foo.bar;

This feels a bit like a X-Y question, so let's simplify the example, and see if that answers helps in your decisions.
First of all: if you return the "value" of a non-existing key in a hash, you are in fact returning a container that will auto-vivify the key in the hash when assigned to:
my %hash;
sub get($key) { return-rw %hash{$key} }
get("foo") = 42;
dd %hash; # Hash %hash = {:foo(42)}
Please note that you need to use return-rw here to ensure the actual container is returned, rather than just the value in the container. Alternately, you can use the is raw trait, which allows you to just set the last value:
my %hash;
sub get($key) is raw { %hash{$key} }
get("foo") = 42;
dd %hash; # Hash %hash = {:foo(42)}
Note that you should not use return in that case, as that will still de-containerize again.
To get back to your question:
I want to track if I've actually modified %!attrs or have only just read the value when FALLBACK was called.
class Foo {
has %!attrs;
has %!unexpected;
method TWEAK() { %!attrs<bar> = 'bar' }
method FALLBACK(Str:D $name, *#rest) is raw {
if %!attrs{$name}:exists {
%!attrs{$name}
}
else {
%!unexpected{$name}++;
Any
}
}
}
This would either return the container found in the hash, or record the access to the unknown key and return an immutable Any.
Regarding plan B, recording changes: for that you could use a Proxy object for that.
Hope this helps in your quest.

Liz's answer is full of useful info and you've accepted it but I thought the following might still be of interest.
How to know if returning an l-value ... ?
Let's start by ignoring the FALLBACK clause.
You would have to test the value. To deal with Scalars, you must test the .VAR of the value. (For non-Scalar values the .VAR acts like a "no op".) I think (but don't quote me) that Scalar|Array|Hash covers all the l-value super-types:
my \value = 42; # Int is an l-value is False
my \l-value-one = $; # Scalar is an l-value is True
my \l-value-too = #; # Array is an l-value is True
say "{.VAR.^name} is an l-value is {.VAR ~~ Scalar|Array|Hash}"
for value, l-value-one, l-value-too
How to know if returning an l-value when using FALLBACK?
Adding "when using FALLBACK" makes no difference to the answer.
How can I know if I actually need to return an l-value ... ?
Again, let's start by ignoring the FALLBACK clause.
This is a completely different question than "How to know if returning an l-value ... ?". I think it's the core of your question.
Afaik, the answer is, you need to anticipate how the returned value will be used. If there's any chance it'll be used as an l-value, and you want that usage to work, then you need to return an l-value. The language/compiler can't (or at least doesn't) help you make that decision.
Consider some related scenarios:
my $baz := foo.bar;
... (100s of lines of code) ...
$baz = 42;
Unless the first line returns an l-value, the second line will fail.
But the situation is actually much more immediate than that:
routine-foo = 42;
routine-foo is evaluated first, in its entirety, before the lhs = rhs expression is evaluated.
Unless the compiler's resolution of the routine-foo call somehow incorporated the fact that the very next thing to happen would be that the lhs will be assigned to, then there would be no way for a singly or multiply dispatched routine-foo to know whether it can safely return an r-value or must return an l-value.
And the compiler's resolution does not incorporate that. Thus, for example:
multi term:<bar> is rw { ... }
multi term:<bar> { ... }
bar = 99; # Ambiguous call to 'term:<bar>(...)'
I can imagine this one day (N years from now) being solved by a combination of allowing = to be an overloadable operator, robust macros that allow overloading of = being available, and routine resolution being modified so the above ambiguous call could do something equivalent to resolving to the is rw multi. But I doubt it will actually come to pass even with N=10. Perhaps there is another way but I can't think of one at the moment.
How can I know if I actually need to return an l-value when using FALLBACK?
Again, adding "when using FALLBACK" makes no difference to the answer.
I want to track if I've actually modified %!attrs or have only just read the value when FALLBACK was called.
When FALLBACK is called it doesn't know what context it's being called in -- r-value or l-value. Any modification comes after it has already returned.
In other words, whatever solution you come up with will being nothing to do per se with FALLBACK (even if you have to use it to implement some other aspect of whatever it is you're trying to do).
(Even if it were, I suspect trying to solve it via FALLBACK itself would just make matters worse. One can imagine writing two FALLBACK multis, one with an is rw trait, but, as explained above, my imagination doesn't stretch to that making any difference any time soon, if ever, and could only happen if the above imaginary things happened (the macros etc.) and the compiler was also modified to pay attention to the two FALLBACK multi variants, and I'm not at all meaning to suggest that that even makes sense.)
Plan B
Or (alternate plan B) can I attach a callback or something similar to my %!attrs to monitor for changes?
As Lizmat notes, that's the realm of Proxys. And thus your next SO question... :)

Related

What is the equivalent of 'pass' from Python?

I want to check if the result from a request is having any issue. I categorize it into two: i) server error, ii) something else that is not a success. The third category is, result actually being a success. However, in the third category, I don't want to do anything.
So, my desirable code is:
if res.status().is_server_error() {
panic!("server error!");
} else if !(res.status.is_success()){
panic!("Something else happened. Status: {:?}", res.status());
} else{
pass;
}
I am aware of other ways to achieve this result: using match, ifs instead of if else if. But I wanted to learn what is the corresponding keyword of pass, like we have in Python. My aim is: if result is successful, just move along, if not, there are two ways to handle that panic.
Behold!
if predicate {
do_things();
} else {
// pass
}
Or even better
if predicate {
do_things();
} // pass
Or as I’ve recently taken to calling it the implicit + pass system
if predicate {
do_things();
}
In all seriousness there is no pass and no need for a pass in rust. As for why it exists in python, check out this answer
Python needs pass because it uses indentation-based blocks, so it requires some syntax to "do nothing". For example, this would be a syntax error in a Python program:
# syntax error - function definition cannot be empty
def ignore(_doc):
# do nothing
count = process_docs(docs, ignore) # just count the docs
The ignore function has to contain a block, which in turn must contain at least one statement. We could insert a dummy statement like None, but Python provides pass which compiles to nothing and signals the intention (to do nothing) to the human reader.
This is not needed in Rust because Rust uses braces for blocks, so one can always create an empty block simply using {}:
// no error - empty blocks are fine
fn ignore(_doc: &Document) {
// do nothing
}
let count = process_docs(docs, ignore); // just count the docs
Of course, in both idiomatic Python and Rust, one would use a closure for something as simple as the above ignore function, but there are still situations where pass and empty blocks are genuinely useful.

Pass by Reference in Haskell?

Coming from a C# background, I would say that the ref keyword is very useful in certain situations where changes to a method parameter are desired to directly influence the passed value for value types of for setting a parameter to null.
Also, the out keyword can come in handy when returning a multitude of various logically unconnected values.
My question is: is it possible to pass a parameter to a function by reference in Haskell? If not, what is the direct alternative (if any)?
There is no difference between "pass-by-value" and "pass-by-reference" in languages like Haskell and ML, because it's not possible to assign to a variable in these languages. It's not possible to have "changes to a method parameter" in the first place in influence any passed variable.
It depends on context. Without any context, no, you can't (at least not in the way you mean). With context, you may very well be able to do this if you want. In particular, if you're working in IO or ST, you can use IORef or STRef respectively, as well as mutable arrays, vectors, hash tables, weak hash tables (IO only, I believe), etc. A function can take one or more of these and produce an action that (when executed) will modify the contents of those references.
Another sort of context, StateT, gives the illusion of a mutable "state" value implemented purely. You can use a compound state and pass around lenses into it, simulating references for certain purposes.
My question is: is it possible to pass a parameter to a function by reference in Haskell? If not, what is the direct alternative (if any)?
No, values in Haskell are immutable (well, the do notation can create some illusion of mutability, but it all happens inside a function and is an entirely different topic). If you want to change the value, you will have to return the changed value and let the caller deal with it. For instance, see the random number generating function next that returns the value and the updated RNG.
Also, the out keyword can come in handy when returning a multitude of various logically unconnected values.
Consequently, you can't have out either. If you want to return several entirely disconnected values (at which point you should probably think why are disconnected values being returned from a single function), return a tuple.
No, it's not possible, because Haskell variables are immutable, therefore, the creators of Haskell must have reasoned there's no point of passing a reference that cannot be changed.
consider a Haskell variable:
let x = 37
In order to change this, we need to make a temporary variable, and then set the first variable to the temporary variable (with modifications).
let tripleX = x * 3
let x = tripleX
If Haskell had pass by reference, could we do this?
The answer is no.
Suppose we tried:
tripleVar :: Int -> IO()
tripleVar var = do
let times_3 = var * 3
let var = times_3
The problem with this code is the last line; Although we can imagine the variable being passed by reference, the new variable isn't.
In other words, we're introducing a new local variable with the same name;
Take a look again at the last line:
let var = times_3
Haskell doesn't know that we want to "change" a global variable; since we can't reassign it, we are creating a new variable with the same name on the local scope, thus not changing the reference. :-(
tripleVar :: Int -> IO()
tripleVar var = do
let tripleVar = var
let var = tripleVar * 3
return()
main = do
let x = 4
tripleVar x
print x -- 4 :(

In Swift: the example below why must I place (let one) next to .Success for the code to work?

In the example below why must I place (let one) next to .Success for the code to work? Why is it not (let = one) or just (one)? I am trying to understand the syntax.
enum Status {
case Success(String)
case Failure(String)
}
let downloadStatus = Status.Failure("Network connection unavailable")
switch downloadStatus {
case .Success(let one):
println(one)
case .Failure(let two):
println(two)
}
This is known as value binding. The value contained in the enum value is temporarily bound to the variable in the case. If you use let the value will be bound to a constant and if you use var it will be bound to a variable.
let downloadStatus = Status.Failure("Network connection unavailable")
switch downloadStatus {
case .Success(let one):
println(one)
case .Failure(var two):
two += "!!!" // two is a var, so I can modify it
println(two)
}
I am trying to understand the syntax
There is nothing to understand. That simply is the syntax for extracting the associated value from an enum case. It's like the masks when you play Calvinball - no one is allowed to question them.
Now, you might object that this syntax is kind of clumsy and annoying. You have to go through the rigmarole of a switch statement just to pull out the associated value?!? That is a perfectly valid complaint, people have been making it since Swift was unveiled in June 2014, and the folks at Apple know that it's kind of weird and may change it in future. But for now, that's the syntax, and that's all there is to know about it.

Is good to call function in other function parameter?

I suppose this:
public static string abc()
{
return "abc";
}
Is better to call this function in this way:
string call = abc();
Console.writeline(call);
Than this?
console.writeline(abc());
is there any reason to prefer one to the other?
Both are valid. However, out of experience I have concluded that the first option is more suitable for readability and ease of maintenance. I can't count how many times I have changed from the "compact" style to the first one as a help for a debugging session.
For example, this style makes it easy to check the correctness intermediate of an intermediate result:
string call = abc();
assert(!call.empty()); // Just an example.
Console.writeline(call);
Also, it helps to make the code more robust later, adding a conditional check before the subsequent action that checks call's value, for example if the design does not guarantee that the condition of the previous assert holds but you still need to check it.
string call = abc();
if (!call.empty())
{
Console.writeline(call);
}
Note also that with this style you will be able to easily inspect the value of call in your debugger.
Given your exact example (one parameter, value not used elsewhere, no side effects), it's just a matter of style. However, it gets more interesting if there are multiple parameters and the methods have side effects. For example:
int counter;
int Inc() { counter += 1; return counter }
void Foo(int a, int b) { Console.WriteLine(a + " " + b); }
void Bar()
{
Foo(Inc(), Inc());
}
What would you expect Foo to print here? Depending on the language there might not even be a predictable result. In this situation, assigning the values to a variable first should cause the compiler (depending on language) to evaluate the calls in a predictable order.
Actually I don't see a difference if you don't have any error checking.
This would make a difference
string call = abc();
# if call is not empty
{
Console.writeline(call);
}
The above method could avoid empty string being written.

Best explanation for languages without null

Every so often when programmers are complaining about null errors/exceptions someone asks what we do without null.
I have some basic idea of the coolness of option types, but I don't have the knowledge or languages skill to best express it. What is a great explanation of the following written in a way approachable to the average programmer that we could point that person towards?
The undesirability of having references/pointers be nullable by default
How option types work including strategies to ease checking null cases such as
pattern matching and
monadic comprehensions
Alternative solution such as message eating nil
(other aspects I missed)
I think the succinct summary of why null is undesirable is that meaningless states should not be representable.
Suppose I'm modeling a door. It can be in one of three states: open, shut but unlocked, and shut and locked. Now I could model it along the lines of
class Door
private bool isShut
private bool isLocked
and it is clear how to map my three states into these two boolean variables. But this leaves a fourth, undesired state available: isShut==false && isLocked==true. Because the types I have selected as my representation admit this state, I must expend mental effort to ensure that the class never gets into this state (perhaps by explicitly coding an invariant). In contrast, if I were using a language with algebraic data types or checked enumerations that lets me define
type DoorState =
| Open | ShutAndUnlocked | ShutAndLocked
then I could define
class Door
private DoorState state
and there are no more worries. The type system will ensure that there are only three possible states for an instance of class Door to be in. This is what type systems are good at - explicitly ruling out a whole class of errors at compile-time.
The problem with null is that every reference type gets this extra state in its space that is typically undesired. A string variable could be any sequence of characters, or it could be this crazy extra null value that doesn't map into my problem domain. A Triangle object has three Points, which themselves have X and Y values, but unfortunately the Points or the Triangle itself might be this crazy null value that is meaningless to the graphing domain I'm working in. Etc.
When you do intend to model a possibly-non-existent value, then you should opt into it explicitly. If the way I intend to model people is that every Person has a FirstName and a LastName, but only some people have MiddleNames, then I would like to say something like
class Person
private string FirstName
private Option<string> MiddleName
private string LastName
where string here is assumed to be a non-nullable type. Then there are no tricky invariants to establish and no unexpected NullReferenceExceptions when trying to compute the length of someone's name. The type system ensures that any code dealing with the MiddleName accounts for the possibility of it being None, whereas any code dealing with the FirstName can safely assume there is a value there.
So for example, using the type above, we could author this silly function:
let TotalNumCharsInPersonsName(p:Person) =
let middleLen = match p.MiddleName with
| None -> 0
| Some(s) -> s.Length
p.FirstName.Length + middleLen + p.LastName.Length
with no worries. In contrast, in a language with nullable references for types like string, then assuming
class Person
private string FirstName
private string MiddleName
private string LastName
you end up authoring stuff like
let TotalNumCharsInPersonsName(p:Person) =
p.FirstName.Length + p.MiddleName.Length + p.LastName.Length
which blows up if the incoming Person object does not have the invariant of everything being non-null, or
let TotalNumCharsInPersonsName(p:Person) =
(if p.FirstName=null then 0 else p.FirstName.Length)
+ (if p.MiddleName=null then 0 else p.MiddleName.Length)
+ (if p.LastName=null then 0 else p.LastName.Length)
or maybe
let TotalNumCharsInPersonsName(p:Person) =
p.FirstName.Length
+ (if p.MiddleName=null then 0 else p.MiddleName.Length)
+ p.LastName.Length
assuming that p ensures first/last are there but middle can be null, or maybe you do checks that throw different types of exceptions, or who knows what. All these crazy implementation choices and things to think about crop up because there's this stupid representable-value that you don't want or need.
Null typically adds needless complexity. Complexity is the enemy of all software, and you should strive to reduce complexity whenever reasonable.
(Note well that there is more complexity to even these simple examples. Even if a FirstName cannot be null, a string can represent "" (the empty string), which is probably also not a person name that we intend to model. As such, even with non-nullable strings, it still might be the case that we are "representing meaningless values". Again, you could choose to battle this either via invariants and conditional code at runtime, or by using the type system (e.g. to have a NonEmptyString type). The latter is perhaps ill-advised ("good" types are often "closed" over a set of common operations, and e.g. NonEmptyString is not closed over .SubString(0,0)), but it demonstrates more points in the design space. At the end of the day, in any given type system, there is some complexity it will be very good at getting rid of, and other complexity that is just intrinsically harder to get rid of. The key for this topic is that in nearly every type system, the change from "nullable references by default" to "non-nullable references by default" is nearly always a simple change that makes the type system a great deal better at battling complexity and ruling out certain types of errors and meaningless states. So it is pretty crazy that so many languages keep repeating this error again and again.)
The nice thing about option types isn't that they're optional. It is that all other types aren't.
Sometimes, we need to be able to represent a kind of "null" state. Sometimes we have to represent a "no value" option as well as the other possible values a variable may take. So a language that flat out disallows this is going to be a bit crippled.
But often, we don't need it, and allowing such a "null" state only leads to ambiguity and confusion: every time I access a reference type variable in .NET, I have to consider that it might be null.
Often, it will never actually be null, because the programmer structures the code so that it can never happen. But the compiler can't verify that, and every single time you see it, you have to ask yourself "can this be null? Do I need to check for null here?"
Ideally, in the many cases where null doesn't make sense, it shouldn't be allowed.
That's tricky to achieve in .NET, where nearly everything can be null. You have to rely on the author of the code you're calling to be 100% disciplined and consistent and have clearly documented what can and cannot be null, or you have to be paranoid and check everything.
However, if types aren't nullable by default, then you don't need to check whether or not they're null. You know they can never be null, because the compiler/type checker enforces that for you.
And then we just need a back door for the rare cases where we do need to handle a null state. Then an "option" type can be used. Then we allow null in the cases where we've made a conscious decision that we need to be able to represent the "no value" case, and in every other case, we know that the value will never be null.
As others have mentioned, in C# or Java for example, null can mean one of two things:
the variable is uninitialized. This should, ideally, never happen. A variable shouldn't exist unless it is initialized.
the variable contains some "optional" data: it needs to be able to represent the case where there is no data. This is sometimes necessary. Perhaps you're trying to find an object in a list, and you don't know in advance whether or not it's there. Then we need to be able to represent that "no object was found".
The second meaning has to be preserved, but the first one should be eliminated entirely. And even the second meaning should not be the default. It's something we can opt in to if and when we need it. But when we don't need something to be optional, we want the type checker to guarantee that it will never be null.
All of the answers so far focus on why null is a bad thing, and how it's kinda handy if a language can guarantee that certain values will never be null.
They then go on to suggest that it would be a pretty neat idea if you enforce non-nullability for all values, which can be done if you add a concept like Option or Maybe to represent types that may not always have a defined value. This is the approach taken by Haskell.
It's all good stuff! But it doesn't preclude the use of explicitly nullable / non-null types to achieve the same effect. Why, then, is Option still a good thing? After all, Scala supports nullable values (is has to, so it can work with Java libraries) but supports Options as well.
Q. So what are the benefits beyond being able to remove nulls from a language entirely?
A. Composition
If you make a naive translation from null-aware code
def fullNameLength(p:Person) = {
val middleLen =
if (null == p.middleName)
p.middleName.length
else
0
p.firstName.length + middleLen + p.lastName.length
}
to option-aware code
def fullNameLength(p:Person) = {
val middleLen = p.middleName match {
case Some(x) => x.length
case _ => 0
}
p.firstName.length + middleLen + p.lastName.length
}
there's not much difference! But it's also a terrible way to use Options... This approach is much cleaner:
def fullNameLength(p:Person) = {
val middleLen = p.middleName map {_.length} getOrElse 0
p.firstName.length + middleLen + p.lastName.length
}
Or even:
def fullNameLength(p:Person) =
p.firstName.length +
p.middleName.map{length}.getOrElse(0) +
p.lastName.length
When you start dealing with List of Options, it gets even better. Imagine that the List people is itself optional:
people flatMap(_ find (_.firstName == "joe")) map (fullNameLength)
How does this work?
//convert an Option[List[Person]] to an Option[S]
//where the function f takes a List[Person] and returns an S
people map f
//find a person named "Joe" in a List[Person].
//returns Some[Person], or None if "Joe" isn't in the list
validPeopleList find (_.firstName == "joe")
//returns None if people is None
//Some(None) if people is valid but doesn't contain Joe
//Some[Some[Person]] if Joe is found
people map (_ find (_.firstName == "joe"))
//flatten it to return None if people is None or Joe isn't found
//Some[Person] if Joe is found
people flatMap (_ find (_.firstName == "joe"))
//return Some(length) if the list isn't None and Joe is found
//otherwise return None
people flatMap (_ find (_.firstName == "joe")) map (fullNameLength)
The corresponding code with null checks (or even elvis ?: operators) would be painfully long. The real trick here is the flatMap operation, which allows for the nested comprehension of Options and collections in a way that nullable values can never achieve.
Since people seem to be missing it: null is ambiguous.
Alice's date-of-birth is null. What does it mean?
Bob's date-of-death is null. What does that mean?
A "reasonable" interpretation might be that Alice's date-of-birth exists but is unknown, whereas Bob's date-of-death does not exist (Bob is still alive). But why did we get to different answers?
Another problem: null is an edge case.
Is null = null?
Is nan = nan?
Is inf = inf?
Is +0 = -0?
Is +0/0 = -0/0?
The answers are usually "yes", "no", "yes", "yes", "no", "yes" respectively. Crazy "mathematicians" call NaN "nullity" and say it compares equal to itself. SQL treats nulls as not equal to anything (so they behave like NaNs). One wonders what happens when you try to store ±∞, ±0, and NaNs into the same database column (there are 253 NaNs, half of which are "negative").
To make matters worse, databases differ in how they treat NULL, and most of them aren't consistent (see NULL Handling in SQLite for an overview). It's pretty horrible.
And now for the obligatory story:
I recently designed a (sqlite3) database table with five columns a NOT NULL, b, id_a, id_b NOT NULL, timestamp. Because it's a generic schema designed to solve a generic problem for fairly arbitrary apps, there are two uniqueness constraints:
UNIQUE(a, b, id_a)
UNIQUE(a, b, id_b)
id_a only exists for compatibility with an existing app design (partly because I haven't come up with a better solution), and is not used in the new app. Because of the way NULL works in SQL, I can insert (1, 2, NULL, 3, t) and (1, 2, NULL, 4, t) and not violate the first uniqueness constraint (because (1, 2, NULL) != (1, 2, NULL)).
This works specifically because of how NULL works in a uniqueness constraint on most databases (presumably so it's easier to model "real-world" situations, e.g. no two people can have the same Social Security Number, but not all people have one).
FWIW, without first invoking undefined behaviour, C++ references cannot "point to" null, and it's not possible to construct a class with uninitialized reference member variables (if an exception is thrown, construction fails).
Sidenote: Occasionally you might want mutually-exclusive pointers (i.e. only one of them can be non-NULL), e.g. in a hypothetical iOS type DialogState = NotShown | ShowingActionSheet UIActionSheet | ShowingAlertView UIAlertView | Dismissed. Instead, I'm forced to do stuff like assert((bool)actionSheet + (bool)alertView == 1).
The undesirability of having having references/pointers be nullable by default.
I don't think this is the main issue with nulls, the main issue with nulls is that they can mean two things:
The reference/pointer is uninitialized: the problem here is the same as mutability in general. For one, it makes it more difficult to analyze your code.
The variable being null actually means something: this is the case which Option types actually formalize.
Languages which support Option types typically also forbid or discourage the use of uninitialized variables as well.
How option types work including strategies to ease checking null cases such as pattern matching.
In order to be effective, Option types need to be supported directly in the language. Otherwise it takes a lot of boiler-plate code to simulate them. Pattern-matching and type-inference are two keys language features making Option types easy to work with. For example:
In F#:
//first we create the option list, and then filter out all None Option types and
//map all Some Option types to their values. See how type-inference shines.
let optionList = [Some(1); Some(2); None; Some(3); None]
optionList |> List.choose id //evaluates to [1;2;3]
//here is a simple pattern-matching example
//which prints "1;2;None;3;None;".
//notice how value is extracted from op during the match
optionList
|> List.iter (function Some(value) -> printf "%i;" value | None -> printf "None;")
However, in a language like Java without direct support for Option types, we'd have something like:
//here we perform the same filter/map operation as in the F# example.
List<Option<Integer>> optionList = Arrays.asList(new Some<Integer>(1),new Some<Integer>(2),new None<Integer>(),new Some<Integer>(3),new None<Integer>());
List<Integer> filteredList = new ArrayList<Integer>();
for(Option<Integer> op : list)
if(op instanceof Some)
filteredList.add(((Some<Integer>)op).getValue());
Alternative solution such as message eating nil
Objective-C's "message eating nil" is not so much a solution as an attempt to lighten the head-ache of null checking. Basically, instead of throwing a runtime exception when trying to invoke a method on a null object, the expression instead evaluates to null itself. Suspending disbelief, it's as if each instance method begins with if (this == null) return null;. But then there is information loss: you don't know whether the method returned null because it is valid return value, or because the object is actually null. It's a lot like exception swallowing, and doesn't make any progress addressing the issues with null outlined before.
Assembly brought us addresses also known as untyped pointers. C mapped them directly as typed pointers but introduced Algol's null as a unique pointer value, compatible with all typed pointers. The big issue with null in C is that since every pointer can be null, one never can use a pointer safely without a manual check.
In higher-level languages, having null is awkward since it really conveys two distinct notions:
Telling that something is undefined.
Telling that something is optional.
Having undefined variables is pretty much useless, and yields to undefined behavior whenever they occur. I suppose everybody will agree that having things undefined should be avoided at all costs.
The second case is optionality and is best provided explicitly, for instance with an option type.
Let's say we're in a transport company and we need to create an application to help create a schedule for our drivers. For each driver, we store a few informations such as: the driving licences they have and the phone number to call in case of emergency.
In C we could have:
struct PhoneNumber { ... };
struct MotorbikeLicence { ... };
struct CarLicence { ... };
struct TruckLicence { ... };
struct Driver {
char name[32]; /* Null terminated */
struct PhoneNumber * emergency_phone_number;
struct MotorbikeLicence * motorbike_licence;
struct CarLicence * car_licence;
struct TruckLicence * truck_licence;
};
As you observe, in any processing over our list of drivers we'll have to check for null pointers. The compiler won't help you, the safety of the program relies on your shoulders.
In OCaml, the same code would look like this:
type phone_number = { ... }
type motorbike_licence = { ... }
type car_licence = { ... }
type truck_licence = { ... }
type driver = {
name: string;
emergency_phone_number: phone_number option;
motorbike_licence: motorbike_licence option;
car_licence: car_licence option;
truck_licence: truck_licence option;
}
Let's now say that we want to print the names of all the drivers along with their truck licence numbers.
In C:
#include <stdio.h>
void print_driver_with_truck_licence_number(struct Driver * driver) {
/* Check may be redundant but better be safe than sorry */
if (driver != NULL) {
printf("driver %s has ", driver->name);
if (driver->truck_licence != NULL) {
printf("truck licence %04d-%04d-%08d\n",
driver->truck_licence->area_code
driver->truck_licence->year
driver->truck_licence->num_in_year);
} else {
printf("no truck licence\n");
}
}
}
void print_drivers_with_truck_licence_numbers(struct Driver ** drivers, int nb) {
if (drivers != NULL && nb >= 0) {
int i;
for (i = 0; i < nb; ++i) {
struct Driver * driver = drivers[i];
if (driver) {
print_driver_with_truck_licence_number(driver);
} else {
/* Huh ? We got a null inside the array, meaning it probably got
corrupt somehow, what do we do ? Ignore ? Assert ? */
}
}
} else {
/* Caller provided us with erroneous input, what do we do ?
Ignore ? Assert ? */
}
}
In OCaml that would be:
open Printf
(* Here we are guaranteed to have a driver instance *)
let print_driver_with_truck_licence_number driver =
printf "driver %s has " driver.name;
match driver.truck_licence with
| None ->
printf "no truck licence\n"
| Some licence ->
(* Here we are guaranteed to have a licence *)
printf "truck licence %04d-%04d-%08d\n"
licence.area_code
licence.year
licence.num_in_year
(* Here we are guaranteed to have a valid list of drivers *)
let print_drivers_with_truck_licence_numbers drivers =
List.iter print_driver_with_truck_licence_number drivers
As you can see in this trivial example, there is nothing complicated in the safe version:
It's terser.
You get much better guarantees and no null check is required at all.
The compiler ensured that you correctly dealt with the option
Whereas in C, you could just have forgotten a null check and boom...
Note : these code samples where not compiled, but I hope you got the ideas.
Microsoft Research has a intersting project called
Spec#
It is a C# extension with not-null type and some mechanism to check your objects against not being null, although, IMHO, applying the design by contract principle may be more appropriate and more helpful for many troublesome situations caused by null references.
Robert Nystrom offers a nice article here:
http://journal.stuffwithstuff.com/2010/08/23/void-null-maybe-and-nothing/
describing his thought process when adding support for absence and failure to his Magpie programming language.
Coming from .NET background, I always thought null had a point, its useful. Until I came to know of structs and how easy it was working with them avoiding a lot of boilerplate code. Tony Hoare speaking at QCon London in 2009, apologized for inventing the null reference. To quote him:
I call it my billion-dollar mistake. It was the invention of the null
reference in 1965. At that time, I was designing the first
comprehensive type system for references in an object oriented
language (ALGOL W). My goal was to ensure that all use of references
should be absolutely safe, with checking performed automatically by
the compiler. But I couldn't resist the temptation to put in a null
reference, simply because it was so easy to implement. This has led to
innumerable errors, vulnerabilities, and system crashes, which have
probably caused a billion dollars of pain and damage in the last forty
years. In recent years, a number of program analysers like PREfix and
PREfast in Microsoft have been used to check references, and give
warnings if there is a risk they may be non-null. More recent
programming languages like Spec# have introduced declarations for
non-null references. This is the solution, which I rejected in 1965.
See this question too at programmers
I've always looked at Null (or nil) as being the absence of a value.
Sometimes you want this, sometimes you don't. It depends on the domain you are working with. If the absence is meaningful: no middle name, then your application can act accordingly. On the other hand if the null value should not be there: The first name is null, then the developer gets the proverbial 2 a.m. phone call.
I've also seen code overloaded and over-complicated with checks for null. To me this means one of two things:
a) a bug higher up in the application tree
b) bad/incomplete design
On the positive side - Null is probably one of the more useful notions for checking if something is absent, and languages without the concept of null will endup over-complicating things when it's time to do data validation. In this case, if a new variable is not initialized, said languagues will usually set variables to an empty string, 0, or an empty collection. However, if an empty string or 0 or empty collection are valid values for your application -- then you have a problem.
Sometimes this circumvented by inventing special/weird values for fields to represent an uninitialized state. But then what happens when the special value is entered by a well-intentioned user? And let's not get into the mess this will make of data validation routines.
If the language supported the null concept all the concerns would vanish.
Vector languages can sometimes get away with not having a null.
The empty vector serves as a typed null in this case.

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