I have two columns of raw data, one with 3,000 instances of numbers 0-100 the second with 3,000 instances of numbers 0-4.
I want to be able to extract the number of instances a range in column 1 has a 0 next to it. Then a 1, a 2, a 3, and a 4.
For example, how many times 0-29 in column 1 has a 2 next to it.
This is what COUNTIFS is for
=COUNTIFS(A:A,"<"&30,B:B,2)
Related
Hate asking question about something as simple as an Excel formula, but seem to really need and would appreciate the help.
I have a table where the rows headings contains names and the column headings contains week numbers. Within this table I have differents numbers. Both numbers that are plus and negatives.
I want to count each cell where the row heading matches a specific name and then each cell that has a plus value with a week number less than or equal to a certain week.
I have tried to got it to work with at least some function (without it caring about plus and negative values) but haven't even gotten that to work.
I've tried with:
=SUMPRODUCT((Data!F3:F28=I1)*(Data!I2:BI2="<="&A1)*(Data!I3:BI28))
=SUMIFS(Data!I3:BI28;Data!F3:F28;I1;Data!I2:BI2;"<="&A1)
.............1 2 3 4 5
name1 -1 4 3 1 1
name2 0 0 0 0 0
I want a formula that counts for example every column header with a value less than or equal to (for example) 4, but excludes negatives and vice versa. So for the example above, the result of name1 should be 8; counts week 2, 3 and 4.
For your current example:
Formula in H3:
=SUMPRODUCT((B2:F3>=0)*(B1:F1<=4)*(A2:A3="name1"),B2:F3)
I am creating a spreadsheet with a list of 90 names, these names need to match up for one to one meetings and this will be repeating many times. I need to randomize these pairings and not have any repeated matches.
There are only roughly 4000 combinations of numbers 1-90 giving you a rough total of 44 different rounds of meetings without duplicating any meetings.
I used the below website to generate the possible numbers and pasted them into an excel spreadsheet.
https://numbergenerator.org/randomnumbergenerator/combinations-generator#!numbers=2&lines=5000&low=1&high=90&unique=false&order_matters=false&csv=&oddeven=&oddqty=0&sorted=false&sets=
You are not starting from the first row but from the second row in this example
After this you will have column A with numbers 1-90 going down rows.
Column B will have names.
Column C will have =MOD(ROWS($D$2:D2)-1,90)+1 formula to make numbers 1-90 appear and once you get to 90 they will start back at 1
Column D will have formula =VLOOKUP( LEFT(C3,SEARCH(" ",C3,1))+0, $A$3:$B$92, 2, FALSE) to extract first number that you got from the website.
Column E will have formula =VLOOKUP( MID(C3,SEARCH(" ",C3,1),LEN(C3))+0, $A$3:$B$92, 2, FALSE) to extract second number that you got from the website.
A picture has been attached for clarification.
The aim
I am try to create a formula which will allow specific information from 90 different worksheets, with an example of one such worksheet being below. Each work sheet represents data from a participant.
I want the data from the 90 work sheets to be summarised into the worksheet below.
The problem
The problem is that I need to create a formula that takes counterbalancing into account.
So in cell A3 of the second image I would to record the number of times the value 1 and 3 appears in column I of the first image.
The conditions
However, I would only like the numbers in column I to count if:
a) in column M of image 1 there is a value of 1
and
b) when the number in Column L is 1 and Column K is 1 or 4 OR when the number in Column L is 2 and the number in Column K is 3 or 4.
My attempt
=SUM('[All_memories_301-389_improved.xlsx]Sirma 301:387Yanxin'!$M$2,1*(IF('[All_memories_301-389_improved.xlsx]Sirma 301:387Yanxin'!$L$2,1*(IF('[All_memories_301-389_improved.xlsx]Sirma 301:387Yanxin'!$K$2:$K$41,1,4*(IF('[All_memories_301-389_improved.xlsx]Sirma 301:387Yanxin'!$I$2:$I$54,1,3)))))))
This did not work however and I have spent a long time on this and made changes but I still can't seem to get it to work.
Extra information:
In column I I want to count all the occurrences of 1 and 3 provided the specified conditions are met. The rows are not important, but rather, the column I information for each of the 90 spreadsheets.
New attempt with formula:
=COUNTIFS('[All_memories_301-389_improved.xlsx]381Christie'!$M$2, 1, '[All_memories_301-389_improved.xlsx]381Christie'!$L$2, 1, '[All_memories_301-389_improved.xlsx]381Christie'!$K$2:$K$23, AND(1,4), '[All_memories_301-389_improved.xlsx]381Christie'!$I$2:$I$23, AND(1,3))
I have a list of Excel data set up like this.
Items
1, 11, 3
4, 5, 6
7, 9, 12
15, 13, 4
7, 8, 9, 10, 1
14
1, 3, 7, 9
I want to make a count of each occurring number, so that I end up with a result like this:
Items A2 Column
1 2
2 0
3 2
4 2
5 1
And so on. Are there any formulas I can use to count the frequency of each number?
I've tried using the COUNTIF function, but the formula will often come out as 0 because it can't read each number separately in the cells. Using a Pivot Table created the same results as well.
First split those integer values into their own cell:
Data>>TextToColumns>>Delimited>>Comma>>OK
Second set up a table where 1 through whatever is listed in the rows, then you can use countif() to get the counts.
=COUNTIF($A$2:$E$8,A14)
Where $A$2:$E$8 is the group of cells that was created with Text To Columns, and A14 is the first cell in your list of of 1 to whatever. Copy that down to each row in your list of 1 to whatever and you'll have what you are looking for.
Assumptions Made:
-Your data is all in column A but in multiple rows.
-Each cell in column A has one or more comma separated data sets (as shown above)
In Column D1 Place a Title "Items" and enter your item numbers in column D starting with D2 and continuing.
In Column E use the following Formula
=SUM(COUNTIF($A:$A,D2&","),COUNTIF($A:$A," "&D2),COUNTIF($A:$A,", "&D2 &","),COUNTIF($A:$A,D2))
Explanation:
COUNTIF($A:$A,D2&",*") - finds entries for the specified item that are the first item in a data set with more than one item listed
COUNTIF($A:$A,"* "&D2) - finds entries for the specified item that are the the last item in a data set with more than one item listed
COUNTIF($A:$A,", "&D2 &",") - finds entries for the specified item that are neither the first, nor the last item in a data set with more than one item listed
COUNTIF($A:$A,D2) = Finds entries for a specified item where the data set only contains one item.
I have searched through many similar topics but could find nothing that will do what I need.
I am trying to create a worksheet that will track scores for a darts game.
On Sheet 1 I have two columns that simply tracks each players throws from 501 down to 0
Row 25 is the amount remaining for each player.
In Sheet 2 I have 2 columns. The Column A contains scores that you can check out on, and Column B contains the checkout e.g. (T20, T20, D18). So if the value in row 25 of Sheet 1 matches any of the values in Column A of sheet 2, the I want to display the Value of Column B in the matching row on Sheet 2 Underneath the remaining score on Sheet 1.
Can anyone point me in the right direction?
not sure what you mean exactly, but this formula in row 26 should do the trick:
=index('Sheet 2'!$B:$B;match(A25;'Sheet 2'!$A:$A;0))
if your list separator is comma ,, use that instead of semicolon ;
you might want to use 1 as the third argument of match function, if you want to display the checkout according to the nearest match that is bigger than the number in row 25 and the column A in Sheet 2 is sorted in ascending order (1-9)
or -1 if you want the nearest match that is smaller and column A is sorted in descending order (9-1)
You can use this:
=IFERROR(VLOOKUP(A4, Sheet2!$C$2:$E$65535, 3, FALSE),0)