I have a folder full to zip files. Using linux terminal, I need to find files with a certain string in the zip file name and unzip only them to another folder. I tried the following but no luck.
find /some_folder/ -name "*[temperature]*.zip" | parallel unzip '/some_folder/unzippedfiles/'
First, the pattern is not matching and second, I am not sure if the output could be redirected to another folder. Could someone suggest a fix please? Thanks a advance
/some_folder/ must be absolute path:
find /some_folder/ -name "*temperature*.zip" |
parallel 'mkdir -p /some_folder/unzippedfiles/; cd /some_folder/unzippedfiles/ && unzip'
To find a pattern in file names and unzip to a new folder
find /some_folder/ -name "*temperature*.zip" |
parallel "mkdir -p {//}/unzippedfiles && cd {//}/unzippedfiles && unzip -q {}"
To ignore files with a pattern file names and unzip to a new folder
find /some_folder/ ! -name "*temperature*.zip" |
parallel "mkdir -p {//}/unzippedfiles && cd {//}/unzippedfiles && unzip -q {}"
mkdir -p --> Creates a folder if it does not exist
-q --> quiet mode
{//} --> mydir/mysubdir (In this case, it is /some_folder)
Related
As we know, cp -r source_dir intended_new_directory creates a copy of source directory with a new name. Now I want to do the same but want to exclude a particular file. I have found some related answers here, using tar and rsync, but in those solutions I need to create the destination directory first (using mkdir).
I honestly searched a lot, but didn't find exactly what I want.
So far the best I got is this:
tar -c --exclude=\*.dll --exclude=\*.exe sourceDir | tar -x -C destDir
(from http://www.linuxquestions.org/questions/programming-9/how-to-copy-an-entire-directory-structure-except-certain-files-385321/)
If you have binutils, you could use find to filter next cpio to copy (and create directories) :
find <sourceDir> \( ! -name *.dll \) -a \( ! -name *.exe \) | cpio -dumpv <destDir>
Try this by excluding the file using 'grep -v' ->
cp `ls | grep -v <exclude-file>` <dest-dir>
If the directory is not very large I used to write something like this:
src=path/to/source/directory
dst=path/to/destination/directory
find $src -type f | while read f ; do mkdir -p "$dst/`dirname $f`"; cp "$f" "$dst/$f" ; done
Here we list all regular files in $src, iterate over this list and for each file make a directory in $dst if it does not exist yet (-p option of mkdir), then copy the file to that directory.
The above command will copy all the files. Finally, just use
find $src -type f | grep -v whatever | while ...... # same as above
to filter out the files you don't need (e.g. \.bak$, \.orig$, or whatever files you don't want to copy).
Move all exclude file into home or other directory,copy the directory containing all remaining files to the destination folder then restore all exclude files.
#cd mydirectory
#mv exclude1 exclude2 /home/
#cp mydirectory destination_folder/
#cd /home/
#mv eclude1 exclude2 mydirectory/
I want to create a script called package.sh which should:
Use directory as input parameter (can be relative or absolute pathname)
Recursively identify all sub directories of the input directory and recreate this structure in /tmp/. For example: for an input parameter /home/eddy a directory /tmp/eddy is created.
All the text files and script files below the input directory should be copied to the corresponding directory in /tmp
I am new to bash script so I would like to get some help.
Thanks so much
Something like this then:
#!/bin/bash
cp -r `realpath $1` /tmp
this copies the dir given as the first argument, to /tmp.
But as you say you only want *.txt and *.sh files copied so this should work instead
#!/bin/bash
cp `find $1 -name "*.txt" | xargs realpath` /tmp
cp `find $1 -name "*.sh" | xargs realpath` /tmp
But this doesn't recreate the directory structure like you want so you need cpio for that
#!/bin/bash
find $1 -regextype posix-awk -regex "(.*\.txt|.*\.sh)" | cpio -pdv /tmp
To include the criteria that the .sh files have to have the executable flag set (skip the copy if it is not set) then we have to use two lines:
#!/bin/bash
find $1 -name "*.txt" | cpio -pdv /tmp
find $1 -perm /u=x,g=x,o=x -name "*.sh" | cpio -pdv /tmp
well why not just copy that directory /home/eddy to /tmp? you can use some --exclude flags if you use rsync for copying in order to filter the files you need.
I'm making a bash script that should backup all files and dir structure to another dir.
I made the following code to do that:
find . -type f -exec cp {} $HOME/$bdir \; -o -type d -exec mkdir -p {} $HOME/$bdir \; ;
The problem is, is that this only copies the files and not the dir structure.
NOTE: I may not use cp -r, cp -R or something like it because this code is part of an assignment.
I hope somebody can put me in the right direction. ;)
Joeri
EDIT:
I changed it to:
find . -type d -exec mkdir -p $HOME/$bdir/{} \; ;
find . -type f -exec cp {} $HOME/$bdir/{} \; ;
And it works! Ty guys ;)
This sounds like a job for rsync.
You mention that this is an assignment. What are your restrictions? Are you limited to only using find? Does it have to be a single command?
One way to do this is to do it in two find calls. The first call only looks for directories. When a directory is found, mkdir the corresponding directory in the destination hierarchy. The second find call would look for files, and would use a cp command like you currently have.
You can also take each filename, transform the path manually, and use that with the cp command. Here's an example of how to generate the destination filename:
> find . -type f | sed -e "s|^\./|/new/dir/|"
/new/dir/file1.txt
/new/dir/file2.txt
/new/dir/dir1/file1_1.txt
/new/dir/dir1/file1_2.txt
For your purposes, you could write a short bash script that take the source file as input, uses sed to generate the destination filename, and then passes those two paths to cp. The dirname command will return the directory portion of a filename, so mkdir -p $(dirname $destination_path) will ensure that the destination directory exists before you call cp. Armed with a script like that, you can simply have find execute the script for every file it finds.
cd olddir; tar c . | (cd newdir; tar xp)
Can you do your find with "-type d" and exec a "mkdir -p" first, followed by your find that copies the files rather than having it all in one command? It should probably also be mkdir -p $HOME/$bdir/{}.
I have a bunch of zip files, and I'm trying to make a bash script to automate the unzipping of certain files from it.
Things is, although I know the name of the file I want, I don't know the name of the folder it's in; it is one folder depth in
How can I extract these files, preferably discarding the folder?
Here's how to unzip any given file at any depth and junk the folder paths on the way out:
unzip -j somezip.zip *somefile.txt
The -j junks any folder structure in the zip file and the asterisk gives a wildcard to match along any path.
if you're in:
some_directory/
and the zip files are in any number of subdirectories, say:
some_directory/foo
find ./ -name myfile.zip -exec unzip {} -d /directory \;
Edit: As for the second part, removing the directory that contained the zip file I assume?
find ./ -name myfile.zip -exec unzip {} -d /directory \; -exec echo rm -rf `dirname {}` \;
Notice the "echo." That's a sanity check. I always echo first when executing something destructive like rm -rf in a loop/iterative sequence like this. Good luck!
Have you tried unzip somefile.zip "*/blah.txt"?
You can use find to find the file that you need to unzip, and xargs to call unzip:
find /path/to/root/ -name 'zipname.zip' -print0 | xargs -0 unzip
print0 enables the command to work with files or paths that have white space in them. -0 is the option to xargs that makes it work with print0.
I want to create a clone of the structure of our multi-terabyte file server. I know that cp --parents can move a file and it's parent structure, but is there any way to copy the directory structure intact?
I want to copy to a linux system and our file server is CIFS mounted there.
You could do something like:
find . -type d > dirs.txt
to create the list of directories, then
xargs mkdir -p < dirs.txt
to create the directories on the destination.
cd /path/to/directories &&
find . -type d -exec mkdir -p -- /path/to/backup/{} \;
Here is a simple solution using rsync:
rsync -av -f"+ */" -f"- *" "$source" "$target"
one line
no problems with spaces
preserve permissions
I found this solution there
1 line solution:
find . -type d -exec mkdir -p /path/to/copy/directory/tree/{} \;
I dunno if you are looking for a solution on Linux. If so, you can try this:
$ mkdir destdir
$ cd sourcedir
$ find . -type d | cpio -pdvm destdir
This copy the directories and files attributes, but not the files data:
cp -R --attributes-only SOURCE DEST
Then you can delete the files attributes if you are not interested in them:
find DEST -type f -exec rm {} \;
This works:
find ./<SOURCE_DIR>/ -type d | sed 's/\.\/<SOURCE_DIR>//g' | xargs -I {} mkdir -p <DEST_DIR>"/{}"
Just replace SOURCE_DIR and DEST_DIR.
The following solution worked well for me in various environments:
sourceDir="some/directory"
targetDir="any/other/directory"
find "$sourceDir" -type d | sed -e "s?$sourceDir?$targetDir?" | xargs mkdir -p
This solves even the problem with whitespaces:
In the original/source dir:
find . -type d -exec echo "'{}'" \; > dirs2.txt
then recreate it in the newly created dir:
mkdir -p <../<SOURCEDIR>/dirs2.txt
Substitute target_dir and source_dir with the appropriate values:
cd target_dir && (cd source_dir; find . -type d ! -name .) | xargs -i mkdir -p "{}"
Tested on OSX+Ubuntu.
If you can get access from a Windows machine, you can use xcopy with /T and /E to copy just the folder structure (the /E includes empty folders)
http://ss64.com/nt/xcopy.html
[EDIT!]
This one uses rsync to recreate the directory structure but without the files.
http://psung.blogspot.com/2008/05/copying-directory-trees-with-rsync.html
Might actually be better :)
A python script from Sergiy Kolodyazhnyy
posted on Copy only folders not files?:
#!/usr/bin/env python
import os,sys
dirs=[ r for r,s,f in os.walk(".") if r != "."]
for i in dirs:
os.makedirs(os.path.join(sys.argv[1],i))
or from the shell:
python -c 'import os,sys;dirs=[ r for r,s,f in os.walk(".") if r != "."];[os.makedirs(os.path.join(sys.argv[1],i)) for i in dirs]' ~/new_destination
FYI:
Copy top level folder structure without copying files in linux
How do I copy a directory tree but not the files in Linux?
Another approach is use the tree which is pretty handy and navigating directory trees based on its strong options. There are options for directory only, exclude empty directories, exclude names with pattern, include only names with pattern, etc. Check out man tree
Advantage: you can edit or review the list, or if you do a lot of scripting and create a batch of empty directories frequently
Approach: create a list of directories using tree, use that list as an arguments input to mkdir
tree -dfi --noreport > some_dir_file.txt
-dfi lists only directories, prints full path for each name, makes tree not print the indentation lines,
--noreport Omits printing of the file and directory report at the end of the tree listing, just to make the output file not contain any fluff
Then go to the destination where you want the empty directories and execute
xargs mkdir < some_dir_file.txt
find source/ -type f | rsync -a --exclude-from - source/ target/
Copy dir only with associated permission and ownership
Simple way:
for i in `find . -type d`; do mkdir /home/exemplo/$i; done
cd oldlocation
find . -type d -print0 | xargs -0 -I{} mkdir -p newlocation/{}
You can also create top directories only:
cd oldlocation
find . -maxdepth 1 -type d -print0 | xargs -0 -I{} mkdir -p newlocation/{}
Here is a solution in php that:
copies the directories (not recursively, only one level)
preserves permissions
unlike the rsync solution, is fast even with directories containing thousands of files as it does not even go into the folders
has no problems with spaces
should be easy to read and adjust
Create a file like syncDirs.php with this content:
<?php
foreach (new DirectoryIterator($argv[1]) as $f) {
if($f->isDot() || !$f->isDir()) continue;
mkdir($argv[2].'/'.$f->getFilename(), $f->getPerms());
chown($argv[2].'/'.$f->getFilename(), $f->getOwner());
chgrp($argv[2].'/'.$f->getFilename(), $f->getGroup());
}
Run it as user that has enough rights:
sudo php syncDirs.php /var/source /var/destination