Not iterable argument - python-3.x

Question

I'm trying to extract a list of names (column 1) which have 'good' in their descriptions (column 2) from an excel by the following code, but I keep recieving this Error:
TypeError: argument of type 'NoneType' is not iterable
import openpyxl
import os
import pprint
os.chdir('C:\\')
wb = openpyxl.load_workbook('Book1.xlsx')
sheet = wb['Sheet1']
row = 1
names = {}
while True:
(name, description) = (sheet.cell(row, 1).value, sheet.cell(row, 2).value)
nameCheck = 'good' in description
if name == None:
break
if nameCheck:
names[name] = description
row = row + 1
pprint.pprint(names)

Answer 1

You get this error because description returns the value None in runtime at the end. You just check if name==None and not description but the line nameCheck= 'good' in description returns None at the end and that is why you get the Nonetype error. To resolve this, use an if condition for the description variable too. Refer the following code.
import openpyxl
import os
import pprint
os.chdir('C:\\')
wb = openpyxl.load_workbook('Book1.xlsx')
sheet = wb['Sheet1']
row = 1
names = {}
while True:
(name, description) = (sheet.cell(row, 1).value, sheet.cell(row, 2).value)
if description is not None:
nameCheck = 'good' in description
if nameCheck:
names[name] = description
if name == None:
break
row = row + 1
pprint.pprint(names)

Answer 2

I solved my problem but I don't know if my understanding of the problem is right or not.
In the code you should only define nameCheck in this way:
nameCheck = 'good' in str(description)
Actually 'description' in "description = sheet.cell(row, 2).value" is not string which could be iterated! So by changing its type to string we can turn it to iterable type.