I have this question.
(Write "your_username.sh" script to create a text file each time you log out. The file should
contain all statements you execute during your session. The name of the text file should have the following naming pattern “Statements-20191104.0225.txt” (20191104
represents the date and 0225 represents the time). All files should be stored in the
~/MyStatements directory.)
I create sh script and call it inside .bash_logout.
This script creates a file and tries to save all history inside it
#!/bin/bash
currentDateTime=$(date +"%Y%m%d.%k%M")
fileName="Statements-$currentDateTime"
touch ~/MyStatements/$fileName
echo $currentDateTime
echo $fileName
history -a "~/MyStatements/$fileName"
history -a newFile.text
A new file created inside "MyStatements" folder but this file doesn't contain any data
Try to redirect your output:
history -a > ~/MyStatements/$fileName
history -a > newFile.text
See Redirect all output to file
Related
I had a directory with 10 files.I need to read each file one by one .If any failure while processing the file then I need to capture that file name to send over the mail and skip the current file and move to the next file in the directory.
I tried like this
for test in $test_path
do
if [ ! -s $test ];then
echo ' failed'
fi
#other codes are here that needs to run with the above input file
done
I am new to Shellscripting.I am working on a poc in which a script should read a log file and then append to a existing file for the purpose of alert.It should work as per below
There will be some predefined format according to which it will decide whether to append in file or not.For example:
WWXXX9999XS message
**XXX** - is a 3 letter acronym (application code) like for **tom** for tomcat application
9999 - is a 4 numeric digit in the range 1001-1999
**E or X** - For notification X ,If open/active alerts already existing for same error code and same message,new alerts will not be raised for existing one.Once you have closed existing alerts,it will raise alarm for new error.There is any change in message for same error code from existing one, it will raise a alarm even though open/active alerts present.
X option is only for drop duplicates on code and message otherwise all alert mechanisms are same.
**S** - is the severity level, I.e 2,3
**message** - is any text that will be displayed
The script will examine the log file, and look for error like cloud server is down,then it would append 'wwclo1002X2 cloud server is down'if its a new alert.
2.If the same alert is coming again,then it should append 'wwclo1002E2 cloud server is down
There are some very handy commands you can use to do this type of File manipulation. I've updated this in response to your comment to allow functionality that will check if the error has already been appended to the new file.
My suggestion would be that there is enough functionality here to warrant saving it in a bash script.
My approach would be to use a combination of less, grep and > to read and parse the file and then append to the new file. First save the following into a bash script (e.g. a file named script.sh)
#!/bin/bash
result=$(less $1 | grep $2)
exists=$(less $3 | grep $2)
if [[ "$exists" == "$result" ]]; then
echo "error, already present in file"
exit 1
else
echo $result >> $3
exit 0
fi
Then use this file in the command passing in the log file as the first argument, the string to search for as the second argument and the target results file as the third argument like this:
./script.sh <logFileName> "errorToSearchFor" <resultsTargetFileName>
Don't forget to run the file you will need to change the permissions - you can do this using:
chmod u+x script.sh
Just to clarify as you have mentioned you are new to scripting - the less command will output the entire file, the | command (an unnamed pipe) will pass this output to the grep command which will then search the file for the expression in quotes and return all lines from the file containing that expression. The output of the grep command is then appended to the new file with >>.
You may need to tailor the expression in quotes after grep to get exactly the output you want from the log file.
The filenames are just placeholders, be sure to update these with the correct file names. Hope this helps!
Note updated > to >> (single angle bracket overwrites, double angle bracket appends
I'm trying to redirect(?) my standard error/output to a text file.
I did my research, but for some reason the online answers are not working for me.
What am I doing wrong?
cd /home/user1/lists/
for dir in $(ls)
do
(
echo | $dir > /root/user1/$dir" "log.txt
) > /root/Desktop/Logs/Update.log
done
I also tried
2> /root/Desktop/Logs/Update.log
1> /root/Desktop/Logs/Update.log
&> /root/Desktop/Logs/Update.log
None of these work for me :(
Help please!
Try this for the basics:
echo hello >> log.txt 2>&1
Could be read as: echo the word hello, redirecting and appending STDOUT to the file log.txt. STDERR (file descriptor 2) is redirected to wherever STDOUT is being pointed. Note that STDOUT is the default and thus there is no "1" in front of the ">>". Works on the current line only.
To redirect and append all output and error of all commands in a script, put this line near the top. It will be in effect for the length of the script instead of doing it on each line:
exec >>log.txt 2>&1
If you are trying to obtain a list of the files in /home/user1/lists, you do not need a loop at all:
ls /home/usr1/lists/ >Update.log
If you are attempting to run every file in the directory as an executable with a newline as its input, and collect the output from all these programs in Update.log, try this:
for file in /home/user1/lists/*; do
echo | "$file"
done >Update.log
(Notice how we avoid the useless use of ls and how there is no redirection inside the loop.)
If you want to create an empty file called *.log.txt for each file in the directory, you would do
for file in /home/user1/lists/*; do
touch "$(basename "$file")"log.txt
done
(Using basename to obtain the file name without the directory part avoids the cd but you could do it the other way around. Generally, we tend to avoid changing the directory in scripts, so that the tool can be run from anywhere and generate output in the current directory.)
If you want to create a file containing a single newline, regardless of whether it already exists or not,
for file in /home/user1/lists/*; do
echo >"$(basename "$file")"log.txt
done
In your original program, you redirect the echo inside the loop, which means that the redirection after done will not receive any output at all, so the created file will be empty.
These are somewhat wild guesses at what you might actually be trying to accomplish, but should hopefully help nudge you slightly in the right direction. (This should properly be a comment, I suppose, but it's way too long and complex.)
Assume you have a file called “heading” as follows
echo "Permissions^V<TAB>^V<TAB>Size^V<TAB>^V<TAB>File Name" > heading
echo "-------------------------------------------------------" >> heading
Write a (single) set of commands that will create a report as follows:
make a list of the names, permissions and size of all the files in your current directory,
matching (roughly) the format of the heading you just created,
put the list of files directly following the heading, and
save it all into a file called “file.list”.
All this is to be done without destroying the heading file.
I need to be able to do this all in a pipleline without altering the file. I can't seem to do this without destroying the file. Can somebody please make a pipe for me?
You can use command group:
{ cat heading; ls -l | sed 's/:/^V<tab>^V<tab>/g'; } > file.list
I have the script that creates some .html and .txt files every day. But now it is only one file html and txt with changed content, I need every day a new html&txt file with date oof creation in the file name like : index_22-05-2013.html , i have these variables in shell script:
DESTINATION_HTML="./daily/html/index_$(date +"%F").html"
DESTINATION_TXT="./daily/txt/index_$(date +"%F").txt"
and a line in shell script that running one python script and creates html file
python `somescript.py` -m ${FILELIST[0]} ${FILELIST[1]} > $DESTINATION_HTML
and i`m getting this file created:
index_$(date +"%F").html
what i must to do to get this file name : index_22-05-2013.html
Sorry, I am not following you, but since
echo "index_$(date +%F).html"
outputs index_2013-08-20.html instead of index_22-05-2013.html which is what you need, you probably want to use this command instead:
echo "index_$(date +%d-%m-%Y).html"
Hope it helps! :)