I am having a hierarchy name like a.b.c.d.e in multiple lines along with some text. Now I want to change that as a/b/c/d/e.
I tried %s/\./\//g. It did not work.
Error:Trailing Characters
Plain and simple:
:%substitute~\.~/~g
Related
I'm trying to replace a few character word in one place with the word searched in another. I.e
VARIABLE INT005 SOME TEXT BETWEEN NAME=INT020;
I want the program To copy whats after VARIABLE (INT005 in this case) and paste it after NAME=(here should be again INT005 replaced into the place of INT020)
A regex replacement should work here. Assuming you are only looking to make these replacements on a single line, you may try the following find and replace:
Find: \bVARIABLE (\S+)(.*?)\bNAME=\S+;
Replace: VARIABLE $1$2NAME=$1
Demo
Edit:
If your text could span multiple lines, then either turn on "dot all" mode from Textpad (not sure where you would do that), or use this find version:
\bVARIABLE (\S+)([\s\S]*?)\bNAME=\S+;
I'm trying to do a find and replace in notepad++ where i remove the dashes from a set of numbers and letters formatted as following: aa-aaa-nn-nnnnn
I've considered writing a plugin, but it just seems like too much work to be worth it.
Here's an example of what I have and what I need.
I have this: <ISRC>AB-CED-12-34567</ISRC>
And the result should be: <ISRC>ABCED1234567</ISRC>
I've tried finding (A-Z+)-(A-Z+)-(\d+)-(\d+) and replacing this with \1\2\3\4
but then it can't find the "text". If I knew how to write the darned search codes, I could do this myself, but I just can't find a complete guide anywhere.
You're close, you want to use character class:
Ctrl+H
Find what: ([A-Z]+)-([A-Z]+)-(\d+)-(\d+)
Replace with: $1$2$3$4
Replace all
[A-]+ means one or more uppercase letter, if you want to match also lowercase, use [A-Za-z]+
I'm having a bit of trouble using parenthesis in a vim string. I just need to add a set of parenthesis around 3 digits, but I can't seem to find where I'm suppose to correctly place them. So for example; I would have to place them around a phone number such as: 2015551212.
Right now I have a strings that separates the numbers and puts a hyphen between them. For example; 201 555-1212. So I just need the parenthesis. The final result should look like: (201) 555-1212
The string I have so far is this: s/\(\d\{3}\)\(\d\{3}\)/\1 \2-/g
How might I go about doing this?
Thanks
Just add the parens around the \1 in your replacement.
s/\(\d\{3\}\)\(\d\{3\}\)/(\1) \2-/g
If you want to go in reverse, and change "(800) 555-1212" to "8005551212", you can use something like this:
s/(\(\d\d\d\))\ \(\d\d\d\)-\(\d\d\d\d\)/\1\2\3/g
Instead of the \d\d\d, you could use \d\{3\}, but that is more trouble to type.
I'm trying to use both tabs and newlines as delimiters to read from a .txt file. What I have at the moment is:
Scanner fileScanner = new Scanner(new FileReader("propertys.txt"));
fileScanner.useDelimiter("[\\t\\n]");
I've tried:
fileScanner.useDelimiter("\\t|\\n");
and
fileScanner.useDelimiter("[\\t|\\n]");
I've got no idea what's going wrong, I've searched around a lot and it looks like one of those should be working. Clearly I'm doing something wrong.
fileScanner.useDelimiter("\t|\n");
should work.
If you have two slashes "\n" the first acts as an escape and it won't work right.
For the regular expression used as a parameter in useDelimiter method, you should use newline as \n instead of \\n and tab as \t instead of \\t. From Java Pattern class: http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html.
A part from that, I think you should define you regular expression like, for example, this:
fileScanner.useDelimiter("\\s*[\t\n]\\s*");
to limit strings (\\s) between newline or tab characters.
I am trying to remove words from a line if they contain a specific string. Here is an example of the text:
host-a, host-b, host-c+test, host-d, host-e+test
I want to remove anything that contains +test, to result with:
host-a, host-b, host-d
Likewise, I need to apply this on a line by line basis, not on all lines in the file. It is going to be used within a macro.
How can I do this?
Something like this, maybe?
:%s/\<[-a-z]\++test\>//gc
It will ask for each match if you want to replace it. Hint: set hlsearch will show you the matches.
If you also want to remove the comma, then:
%s/\(,\s\+\)\?\S\++test\>//gc