Let's say I have a text file which contains both alphanumerical values and only numerical values of length 10 digits line by line, like the one shown below:
abcdefgh
0123456789
edf6543jewjew
9876543219
I want to delete all the lines which contains only those random 10 digit numbers, i.e. expected output for the above example is the following:
abcdefgh
edf6543jewjew
How can one do this in Python 3.x?
with open("yourTextFile.txt", "r") as f:
lines = f.readlines()
with open("yourTextFile.txt", "w") as f:
for line in lines:
if not line.strip('\n').isnumeric():
f.write(line)
elif len(line.strip('\n')) != 10:
f.write(line)
Open the input file, read all its lines, filter out the lines that contain only digits, then write the filtered lines back to a new file.
import re
with open(input_file_path) as file:
lines = file.readlines()
output_lines = [line for line in lines if not re.match(r'^[0-9]+$', line.strip('\n'))]
with open(output_file_path, 'w') as file:
file.write('\n'.join(output_lines))
import re
fh=open('Desktop\Python13.txt','r+')
content=fh.readlines()
fh.seek(0)
for line in content:
if re.match(r'[0-9]{10}',line):
content.remove(line)
fh.write(''.join(content))
fh.truncate()
fh.close()
Related
I tried this code with english characters works with no problem but i when i want to test it with kurdish characters it will not add anything to new file
here is my ckb.txt:
چ
چۆنی
باشی
سوپاس
ئاسمان
یاسا
دەنگ
ckbnew.txt is empty textfile which i want to add text from ckb.txt
This is my code:
import unicodedata
f = open('ckb.txt', 'r')
d = open('ckbnew.txt', 'w')
g = f.readlines()
for line in g:
if line.startswith('\u0686') :
d.write(line)
print(line)
I need to split a text file into lines.
I imported the text file into python but print(readline()) prints the whole file.
with open('laxdaela_saga.en.txt', 'r+') as f:
for line in f.readlines():
print(line)
I eventually need to count unique words in the text file and other stats, but one step is to divide into lines. This is the step I'm dealing with.
You can use split() function of Python. It splits the given string into an array based on some pattern.
In your case, the pattern will be newline \n.
so split('\n') should do it.
Try this
with open('laxdaela_saga.en.txt', 'r+') as f:
for line in f.readlines():
x = line.split()
print(x)
Hope this will be of your help.
I have date.txt file where are codes
ex:
1111111111111111
2222222222222222
3333333333333333
4444444444444444
I want to check each code in website.
i tried:
with open('date.txt', 'r') as f:
data = f.readlines()
for line in data:
words = line.split()
send_keys(words)
But this copy only last line to.
I need to make a loop that will be checking line by line until check all
thanks for help
4am is to late 4my little brain..
==
edit:
slove
while lines > 0:
lines = lines - 1
with open('date.txt', 'r') as f:
data = f.readlines()
words = data[lines]
print(words)
Try this I think it will work :
line_1 = file.readline()
line_2 = file.readline()
repeat this for how many lines you would like to read.
One thing to keep in mind is if you print these lines they will all print on the same line.
So basically i have a list in a file and i only want to print the line containing an A
Here is a small part of the list
E5341,21/09/2015,C102,440,E,0
E5342,21/09/2015,C103,290,A,290
E5343,21/09/2015,C104,730,N,0
E5344,22/09/2015,C105,180,A,180
E5345,22/09/2015,C106,815,A,400
So i only want to print the line containing A
Sorry im still new at python,
i gave a try using one "print" to print the whole line but ended up failing guess i will always suck at python
You just have to:
open file
read lines
for each line, split at ","
for each line, if the 5th part of the splitted str is equal to "A", print line
Code:
filepath = 'file.txt'
with open(filepath, 'r') as f:
lines = f.readlines()
for line in lines:
if line.split(',')[4] == "A":
print(line)
Ive a csv file that I would like to get all the rows in one column. Ive tried importing into MS Excel or Formatting it with Notedpad++ . However with each try it considers a piece of data as a new row.
How can I format file with pythons csv module so that it removes a string "BRAS" and corrects the format. Each row is found between a quote " and delimiter is a pipe |.
Update:
"aa|bb|cc|dd|
ee|ff"
"ba|bc|bd|be|
bf"
"ca|cb|cd|
ce|cf"
The above is supposed to be 3 rows, however my editors see them as 5 rows or 6 and so forth.
import csv
import fileinput
with open('ventoya.csv') as f, open('ventoya2.csv', 'w') as w:
for line in f:
if 'BRAS' not in line:
w.write(line)
N.B I get a unicode error when trying to use in python.
return codecs.charmap_decode(input,self.errors,decoding_table)[0]
UnicodeDecodeError: 'charmap' codec can't decode byte 0x8f in position 18: character maps to <undefined>
This is a quick hack for small input files (the content is read to memory).
#!python2
fnameIn = 'ventoya.csv'
fnameOut = 'ventoya2.csv'
with open(fnameIn) as fin, open(fnameOut, 'w') as fout:
data = fin.read() # content of the input file
data = data.replace('\n', '') # make it one line
data = data.replace('""', '|') # split char instead of doubled ""
data = data.replace('"', '') # remove the first and last "
print data
for x in data.split('|'): # split by bar
fout.write(x + '\n') # write to separate lines
Or if the goal is only to fix the extra (unwanted) newline to form a single-column CSV file, the file can be fixed first, and then read through the csv module:
#!python2
import csv
fnameIn = 'ventoya.csv'
fnameFixed = 'ventoyaFixed.csv'
fnameOut = 'ventoya2.csv'
# Fix the input file.
with open(fnameIn) as fin, open(fnameFixed, 'w') as fout:
data = fin.read() # content of the file
data = data.replace('\n', '') # remove the newlines
data = data.replace('""', '"\n"') # add the newlines back between the cells
fout.write(data)
# It is an overkill, but now the fixed file can be read using
# the csv module.
with open(fnameFixed, 'rb') as fin, open(fnameOut, 'wb') as fout:
reader = csv.reader(fin)
writer = csv.writer(fout)
for row in reader:
writer.writerow(row)
For solving this you need not to go to even code.
1: Just open file in Notepad++
2: In first line select from | symble till next line
3: go to replace and replace the selected format with |
Search mode can be normal or extended :)
Well, since the line breaks are consistent, you could go in and do find/replace as suggested, but you could also do a quick conversion with your python script:
import csv
import fileinput
linecount = 0
with open('ventoya.csv') as f, open('ventoya2.csv', 'w') as w:
for line in f:
line = line.rstrip()
# remove unwanted breaks by concatenating pairs of rows
if linecount%2 == 0:
line1 = line
else:
full_line = line1 + line
full_line = full_line.replace(' ','')
# remove spaces from front of 2nd half of line
# if you want comma delimiters, uncomment next line:
# full_line = full_line.replace('|',',')
if 'BRAS' not in full_line:
w.write(full_line + '\n')
linecount += 1
This works for me with the test data, and if you want to change the delimiters while writing to file, you can. The nice thing about doing with code is: 1. you can do it with code (always fun) and 2. you can remove the line breaks and filter content to the written file at the same time.