So basically i have a list in a file and i only want to print the line containing an A
Here is a small part of the list
E5341,21/09/2015,C102,440,E,0
E5342,21/09/2015,C103,290,A,290
E5343,21/09/2015,C104,730,N,0
E5344,22/09/2015,C105,180,A,180
E5345,22/09/2015,C106,815,A,400
So i only want to print the line containing A
Sorry im still new at python,
i gave a try using one "print" to print the whole line but ended up failing guess i will always suck at python
You just have to:
open file
read lines
for each line, split at ","
for each line, if the 5th part of the splitted str is equal to "A", print line
Code:
filepath = 'file.txt'
with open(filepath, 'r') as f:
lines = f.readlines()
for line in lines:
if line.split(',')[4] == "A":
print(line)
Related
sample input
in parsing a text file .txt = ["'blah.txt'", "'blah1.txt'", "'blah2.txt'" ]
the expected output in another text file out_path.txt
blah.txt
blah1.txt
blah2.txt
Code that I tried, this just appends "[]" to the input file. While I also tried perl one liner replacing double and single quotes.
read_out_fh = open('out_path.txt',"r")
for line in read_out_fh:
for word in line.split():
curr_line = re.findall(r'"(\[^"]*)"', '\n')
print(curr_line)
this happens because while you reading a file it will be taken as string and not as a list even if u kept the formatting of a list. thats why you getting [] while doing re.for line in read_in_fh: here you are taking each letters in the string thats why you are not getting the desired output. so iwrote something first to transform the string into a list. while doing that i also eliminated "" and '' as you mensioned. then wrote it in to a new file example.txt.
Note: change the file name according to your files
read_out_fh = open('file.txt',"r")
for line in read_out_fh:
line=line.strip("[]").replace('"','').replace("'",'').split(", ")
with open("example.txt", "w") as output:
for word in line:
#print(word)
output.write(word+'\n')
example.txt(outputfile)
blah.txt
blah1.txt
blah2.txt
The code below works out for your example you gave in the question:
# Content of textfile.txt:
asdasdasd=["'blah.txt'", "'blah1.txt'", "'blah2.txt'"]asdasdasd
# Code:
import re
read_in_fh = open('textfile.txt',"r")
write_out_fh = open('out_path.txt', "w")
for line in read_in_fh:
find_list = re.findall(r'\[(".*?"*)\]', line)
for element in find_list[0].split(","):
element_formatted = element.replace('"','').replace("'","").strip()
write_out_fh.write(element_formatted + "\n")
write_out_fh.close()
I need to split a text file into lines.
I imported the text file into python but print(readline()) prints the whole file.
with open('laxdaela_saga.en.txt', 'r+') as f:
for line in f.readlines():
print(line)
I eventually need to count unique words in the text file and other stats, but one step is to divide into lines. This is the step I'm dealing with.
You can use split() function of Python. It splits the given string into an array based on some pattern.
In your case, the pattern will be newline \n.
so split('\n') should do it.
Try this
with open('laxdaela_saga.en.txt', 'r+') as f:
for line in f.readlines():
x = line.split()
print(x)
Hope this will be of your help.
Let's say I have a text file which contains both alphanumerical values and only numerical values of length 10 digits line by line, like the one shown below:
abcdefgh
0123456789
edf6543jewjew
9876543219
I want to delete all the lines which contains only those random 10 digit numbers, i.e. expected output for the above example is the following:
abcdefgh
edf6543jewjew
How can one do this in Python 3.x?
with open("yourTextFile.txt", "r") as f:
lines = f.readlines()
with open("yourTextFile.txt", "w") as f:
for line in lines:
if not line.strip('\n').isnumeric():
f.write(line)
elif len(line.strip('\n')) != 10:
f.write(line)
Open the input file, read all its lines, filter out the lines that contain only digits, then write the filtered lines back to a new file.
import re
with open(input_file_path) as file:
lines = file.readlines()
output_lines = [line for line in lines if not re.match(r'^[0-9]+$', line.strip('\n'))]
with open(output_file_path, 'w') as file:
file.write('\n'.join(output_lines))
import re
fh=open('Desktop\Python13.txt','r+')
content=fh.readlines()
fh.seek(0)
for line in content:
if re.match(r'[0-9]{10}',line):
content.remove(line)
fh.write(''.join(content))
fh.truncate()
fh.close()
I have date.txt file where are codes
ex:
1111111111111111
2222222222222222
3333333333333333
4444444444444444
I want to check each code in website.
i tried:
with open('date.txt', 'r') as f:
data = f.readlines()
for line in data:
words = line.split()
send_keys(words)
But this copy only last line to.
I need to make a loop that will be checking line by line until check all
thanks for help
4am is to late 4my little brain..
==
edit:
slove
while lines > 0:
lines = lines - 1
with open('date.txt', 'r') as f:
data = f.readlines()
words = data[lines]
print(words)
Try this I think it will work :
line_1 = file.readline()
line_2 = file.readline()
repeat this for how many lines you would like to read.
One thing to keep in mind is if you print these lines they will all print on the same line.
I have been searching a large directory of text files for files that match a list of words. How do I have python output the word from the list that matches?
This is what I have so far. It writes the file name every time one of the words from the list is found. I want to add the matching word to the line with the file name so I have the file name and 1 matched word each time. How do I do that?
ngwrds= ['words'...]
for filename in os.listdir(os.getcwd()):
with open(filename, 'r') as searchfile:
for line in searchfile:
if any(x in line for x in ngwrds):
with open("keyword.txt", 'a') as out:
out.write(filename + '\n')
The input is a long text file a line might read like this:
The company reported depreciation of $1.20.
The if one of the search words from the list was depreciation then the output file would look like this:
filename depreciation
Thank you.
I am not sure what out is and I can't run your code from where I am but you could try something like this:
ngwrds= ['words'...]
for filename in os.listdir(os.getcwd()):
with open(filename, 'r') as searchfile:
for line in searchfile:
line = line.strip().split(" ")
for word in line:
if word in ngwrds:
out.write(filename + " " + word)
strip gets rid of whitespace on either end of line. split returns a list of the words in line.