I try to split a file by delimeter: "}., but the delimeter is not found and as a result I get only one new file with the same content as the original one. The code is:
with open('okladki_200_01') as fp:
contents = fp.read()
i = 1
for entry in contents.split('"}.'):
f= open("okladka_%s" % i,"w+")
f.write(entry)
f.close()
i += 1
Can you help, please?
EDIT:
The content of the file is like:
{"base64Image":"/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEB\nAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQH/2wBDAQEBAQEBAQEBAQEBAQEBAQEBAQEB\nAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQH/wAARCAusFMADASIA\nAhEBAxEB/8QAHwAAAgIBBQEBAAAAAAAAAAAAAgQAAwUBBgcICQoL/8QAaRAAAQEFBAcDBwgHBQYD\nAwEZAwIBBBESEwAhIiMFFDEyM0FDUVNhBiRCY3GBkQcIFTRSc6GxRGKDk8HR8FRyo+HxCRYlZLPD\ndILTFzWEkp [...] 3aIiVoL1pmNQxjWr27\nPBnhatT94NfdwDzDBz9aSP/Z\n","elementHashcode":-1794239528,"imageOrientation":6,"type":"BOOK"}
{"base64Image":"/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAAEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEB\nAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEB
And I think I just found the problem... HxD viewer displays 0x0A ASCII character as a dot, but it is New Line. So I should look for '"}\n'
Move contents.split('"}.') into its own variable.
lines = contents.split('.}"')
for entry in lines:
...
Code :
with open('textfile') as fp:
contents = fp.read()
i = 1
lines = contents.split('.}"')
for entry in lines:
f= open("textfile_%s" % i,"w+")
f.write(entry)
f.close()
i += 1
fp.close()
Do you actually need to check for brackets? In your case it seems like your input file is already formatted with 1 content = 1 line, so our delimiter could be \n instead and we can use readlines().
Here is a possible solution:
with open('okladki_200_01') as fp:
lines = fp.readlines() # this is a list of strings.
i = 1
for line in lines:
entry = line.lstrip("{").rstrip("}\n") # some clean-up.
f = open("okladka_%s" %i ,"w+")
f.write(entry)
f.close()
i += 1
Related
I need all the strings found in the text file to be found and capitalized. I have found out how to find the string but getting multiple is my issue if you can help me print, where the given string is throughout my code, would be great thanks.
import os
import subprocess
i = 1
string1 = 'biscuit eater'
# opens the text file
# if this is the path where my file resides, f will become an absolute path to it
f = os.path.expanduser("/users/acarroll55277/documents/Notes/new_myfile.txt")
# with this form of open, the wile will automatically close when exiting the code block
txtfile = open (f, 'r')
# print(f.read()) to print the text document in terminal
# this sets variables flag and index to 0
flag = 0
index = 0
# looks through the file line by line
for line in txtfile:
index += 1
#checking if the sting is in the line or not
if string1 in line:
flag = 1
break
# checking condition for sting found or not
if flag == 0:
print('string ' + string1 + ' not found')
else:
print('string ' + string1 + ' found in line ' + str(index))
I believe your approach would work, but it is very verbose and not very Pythonic. Try this out:
import os, subprocess
string1 = 'biscuit eater'
with open(os.path.expanduser("/users/acarroll55277/documents/Notes/new_myfile.txt"), 'r+') as fptr:
matches = list()
[matches.append(i) for i, line in enumerate(fptr.readlines()) if string1 in line.strip()]
fptr.read().replace(string1, string1.title())
if len(matches) == 0: print(f"string {string1} not found")
[print(f"string {string1} found in line {i}") for i in matches]
This will now print out a message for every occurrence of your string in the file. In addition, the file is handled safely and closed automatically at the end of the script thanks to the with statement.
You can use the str.replace-method. So in the line where you find the string, write line.replace(string1, string1.upper(), 1). The last 1 is there to only make the function replace 1 occurence of the string.
Either that or you read the text file as a string and use the replace-method on that entire string. That saves you the trouble of trying to find the occurence manually. In that case, you can write
txtfile = open(f, 'r')
content = txtfile.read()
content = content.replace(string1, string1.upper())
So I have a text file, and I need to define a function to open the file, read through it, and then return and print the number of characters within the file.
So far I've got:
def num_chars_in_file(file):
path = 'planets.txt'
file_handle = open(path)
for text in file_handle:
file = file_handle.readlines()
print(file)
print(f"\nProblem 1: {num_chars_in_file()}")
# I'm not sure where to go from where.
You could create a count variable to store the cumulative total of characters as you iterate over each line, something like this:
def num_chars_in_file():
path = 'planets.txt'
file_handle = open(path)
count = 0
for text in file_handle:
count += len(text.rstrip())
file_handle.close() # Make sure to close the file if you're not using with
return count
print(f"\nProblem 1: {num_chars_in_file()}")
with open('my_words.txt') as infile:
lines=0
words=0
characters=0
for line in infile:
wordslist=line.split()
lines=lines+1
words=words+len(wordslist)
characters += sum(len(word) for word in wordslist)
print(lines)
print(words)
print(characters)
Try this to print number of line, words and characters in the file.
Refer to this similar question more details.
I have date.txt file where are codes
ex:
1111111111111111
2222222222222222
3333333333333333
4444444444444444
I want to check each code in website.
i tried:
with open('date.txt', 'r') as f:
data = f.readlines()
for line in data:
words = line.split()
send_keys(words)
But this copy only last line to.
I need to make a loop that will be checking line by line until check all
thanks for help
4am is to late 4my little brain..
==
edit:
slove
while lines > 0:
lines = lines - 1
with open('date.txt', 'r') as f:
data = f.readlines()
words = data[lines]
print(words)
Try this I think it will work :
line_1 = file.readline()
line_2 = file.readline()
repeat this for how many lines you would like to read.
One thing to keep in mind is if you print these lines they will all print on the same line.
I have data like the example data below in a text file. What I would like to do is search through the text file and return everything between "SpecialStuff" and the next ";", like I've done with the example out put. I'm pretty new to python so any tips are greatly appreciated, would something like .split() work?
Example Data:
stuff:
1
1
1
23
];
otherstuff:
do something
23
4
1
];
SpecialStuff
select
numbers
,othernumbers
words
;
MoreOtherStuff
randomstuff
##123
Example Out Put:
select
numbers
,othernumbers
words
You can try this:
file = open("filename.txt", "r") # This opens the original file
output = open("result.txt", "w") # This opens a new file to write to
seenSpecialStuff = 0 # This will keep track of whether or not the 'SpecialStuff' line has been seen.
for line in file:
if ";" in line:
seenSpecialStuff = 0 # Set tracker to 0 if it sees a semicolon.
if seenSpecialStuff == 1:
output.write(line) # Print if tracker is active
if "SpecialStuff" in line:
seenSpecialStuff = 1 # Set tracker to 1 when SpecialStuff is seen
This returns a file named result.txt that contains:
select
numbers
,othernumbers
words
This code can be improved! Since this is likely a homework assignment, you'll probably want to do more research about how to make this more efficient. Hopefully it can be a useful starting ground for you!
Cheers!
EDIT
If you wanted the code to specifically read the line "SpecialStuff" (instead of lines containing "SpecialStuff"), you could easily change the "if" statements to make them more specific:
file = open("my.txt", "r")
output = open("result.txt", "w")
seenSpecialStuff = 0
for line in file:
if line.replace("\n", "") == ";":
seenSpecialStuff = 0
if seenSpecialStuff == 1:
output.write(line)
if line.replace("\n", "") == "SpecialStuff":
seenSpecialStuff = 1
with open('path/to/input') as infile, open('path/to/output', 'w') as outfile: # open the input and output files
wanted = False # do we want the current line in the output?
for line in infile:
if line.strip() == "SpecialStuff": # marks the begining of a wanted block
wanted = True
continue
if line.strip() == ";" and wanted: # marks the end of a wanted block
wanted = False
continue
if wanted: outfile.write(line)
Don't use str.split() for that - str.find() is more than enough:
parsed = None
with open("example.dat", "r") as f:
data = f.read() # load the file into memory for convinience
start_index = data.find("SpecialStuff") # find the beginning of your block
if start_index != -1:
end_index = data.find(";", start_index) # find the end of the block
if end_index != -1:
parsed = data[start_index + 12:end_index] # grab everything in between
if parsed is None:
print("`SpecialStuff` Block not found")
else:
print(parsed)
Keep in mind that this will capture everything between those two, including new lines and other whitespace - you can additionally do parsed.strip() to remove leading and trailing whitespaces if you don't want them.
Ive a csv file that I would like to get all the rows in one column. Ive tried importing into MS Excel or Formatting it with Notedpad++ . However with each try it considers a piece of data as a new row.
How can I format file with pythons csv module so that it removes a string "BRAS" and corrects the format. Each row is found between a quote " and delimiter is a pipe |.
Update:
"aa|bb|cc|dd|
ee|ff"
"ba|bc|bd|be|
bf"
"ca|cb|cd|
ce|cf"
The above is supposed to be 3 rows, however my editors see them as 5 rows or 6 and so forth.
import csv
import fileinput
with open('ventoya.csv') as f, open('ventoya2.csv', 'w') as w:
for line in f:
if 'BRAS' not in line:
w.write(line)
N.B I get a unicode error when trying to use in python.
return codecs.charmap_decode(input,self.errors,decoding_table)[0]
UnicodeDecodeError: 'charmap' codec can't decode byte 0x8f in position 18: character maps to <undefined>
This is a quick hack for small input files (the content is read to memory).
#!python2
fnameIn = 'ventoya.csv'
fnameOut = 'ventoya2.csv'
with open(fnameIn) as fin, open(fnameOut, 'w') as fout:
data = fin.read() # content of the input file
data = data.replace('\n', '') # make it one line
data = data.replace('""', '|') # split char instead of doubled ""
data = data.replace('"', '') # remove the first and last "
print data
for x in data.split('|'): # split by bar
fout.write(x + '\n') # write to separate lines
Or if the goal is only to fix the extra (unwanted) newline to form a single-column CSV file, the file can be fixed first, and then read through the csv module:
#!python2
import csv
fnameIn = 'ventoya.csv'
fnameFixed = 'ventoyaFixed.csv'
fnameOut = 'ventoya2.csv'
# Fix the input file.
with open(fnameIn) as fin, open(fnameFixed, 'w') as fout:
data = fin.read() # content of the file
data = data.replace('\n', '') # remove the newlines
data = data.replace('""', '"\n"') # add the newlines back between the cells
fout.write(data)
# It is an overkill, but now the fixed file can be read using
# the csv module.
with open(fnameFixed, 'rb') as fin, open(fnameOut, 'wb') as fout:
reader = csv.reader(fin)
writer = csv.writer(fout)
for row in reader:
writer.writerow(row)
For solving this you need not to go to even code.
1: Just open file in Notepad++
2: In first line select from | symble till next line
3: go to replace and replace the selected format with |
Search mode can be normal or extended :)
Well, since the line breaks are consistent, you could go in and do find/replace as suggested, but you could also do a quick conversion with your python script:
import csv
import fileinput
linecount = 0
with open('ventoya.csv') as f, open('ventoya2.csv', 'w') as w:
for line in f:
line = line.rstrip()
# remove unwanted breaks by concatenating pairs of rows
if linecount%2 == 0:
line1 = line
else:
full_line = line1 + line
full_line = full_line.replace(' ','')
# remove spaces from front of 2nd half of line
# if you want comma delimiters, uncomment next line:
# full_line = full_line.replace('|',',')
if 'BRAS' not in full_line:
w.write(full_line + '\n')
linecount += 1
This works for me with the test data, and if you want to change the delimiters while writing to file, you can. The nice thing about doing with code is: 1. you can do it with code (always fun) and 2. you can remove the line breaks and filter content to the written file at the same time.